is it possible to make the |safe template filter conditional on content
I made a custom template filter (ref_href) which converts numbered
references (like [1], [2] etc) into footnote hyperlinks. It works but
requires the |safe filter which is dangerous.
To be actually safe I want to *only* use the |safe filter when the data
contains a numbered reference. Which I cannot do if it is permanently in
the template. In other words, I want to remove the |safe filter from the
template and incorporate it into my custom filter which checks that we
have an integer between the square brackets before doing its work.
Just thinking about it now, I suppose I could put a conditional in the
template ...
{% if "[" in value %}
{{ value | ref_href | safe }}
{% else %}
{{ value }}
{% endif %}
... but that's a lot of typing over dozens of templates. And it isn't
good enough.
Thanks for any secrets
Mike
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Re: is it possible to make the |safe template filter conditional on content
You can certainly write a custom filter. And if you do that, you can divvy
up your value into footnote links and other, and escape the other parts
yourself, returning the result as a safe string.
On Thu, Oct 3, 2013 at 2:55 AM, Mike Dewhirst wrote:
> I made a custom template filter (ref_href) which converts numbered
> references (like [1], [2] etc) into footnote hyperlinks. It works but
> requires the |safe filter which is dangerous.
>
> To be actually safe I want to *only* use the |safe filter when the data
> contains a numbered reference. Which I cannot do if it is permanently in
> the template. In other words, I want to remove the |safe filter from the
> template and incorporate it into my custom filter which checks that we have
> an integer between the square brackets before doing its work.
>
> Just thinking about it now, I suppose I could put a conditional in the
> template ...
>
> {% if "[" in value %}
> {{ value | ref_href | safe }}
> {% else %}
> {{ value }}
> {% endif %}
>
> ... but that's a lot of typing over dozens of templates. And it isn't good
> enough.
>
> Thanks for any secrets
>
> Mike
>
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Re: is it possible to make the |safe template filter conditional on content
On 4/10/2013 12:21am, Bill Freeman wrote:
You can certainly write a custom filter. And if you do that, you can
divvy up your value into footnote links and other, and escape the other
parts yourself, returning the result as a safe string.
So you mean I detect any non-footnote html in the custom filter myself
and convert it to Klingon but add my own html for footnotes and flag all
such fields as safe?
Hadn't thought of that. Might investigate calling the Django safe filter
from within the custom filter ...
Great idea, thanks
Mike
On Thu, Oct 3, 2013 at 2:55 AM, Mike Dewhirst mailto:mi...@dewhirst.com.au>> wrote:
I made a custom template filter (ref_href) which converts numbered
references (like [1], [2] etc) into footnote hyperlinks. It works
but requires the |safe filter which is dangerous.
To be actually safe I want to *only* use the |safe filter when the
data contains a numbered reference. Which I cannot do if it is
permanently in the template. In other words, I want to remove the
|safe filter from the template and incorporate it into my custom
filter which checks that we have an integer between the square
brackets before doing its work.
Just thinking about it now, I suppose I could put a conditional in
the template ...
{% if "[" in value %}
{{ value | ref_href | safe }}
{% else %}
{{ value }}
{% endif %}
... but that's a lot of typing over dozens of templates. And it
isn't good enough.
Thanks for any secrets
Mike
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Re: is it possible to make the |safe template filter conditional on content
On 4/10/2013 9:44am, Mike Dewhirst wrote:
On 4/10/2013 12:21am, Bill Freeman wrote:
You can certainly write a custom filter. And if you do that, you can
divvy up your value into footnote links and other, and escape the other
parts yourself, returning the result as a safe string.
So you mean I detect any non-footnote html in the custom filter myself
and convert it to Klingon but add my own html for footnotes and flag all
such fields as safe?
Hadn't thought of that. Might investigate calling the Django safe filter
from within the custom filter ...
Great idea, thanks
And Django is fantastic too :)
All I need to do is ...
from django.utils.safestring import mark_safe
and return mark_safe(value_with_footnote_href) within my custom filter.
... which means I don't have to use the |safe filter and which makes me
much happier.
Cheers
Mike
Mike
On Thu, Oct 3, 2013 at 2:55 AM, Mike Dewhirst mailto:mi...@dewhirst.com.au>> wrote:
I made a custom template filter (ref_href) which converts numbered
references (like [1], [2] etc) into footnote hyperlinks. It works
but requires the |safe filter which is dangerous.
To be actually safe I want to *only* use the |safe filter when the
data contains a numbered reference. Which I cannot do if it is
permanently in the template. In other words, I want to remove the
|safe filter from the template and incorporate it into my custom
filter which checks that we have an integer between the square
brackets before doing its work.
Just thinking about it now, I suppose I could put a conditional in
the template ...
{% if "[" in value %}
{{ value | ref_href | safe }}
{% else %}
{{ value }}
{% endif %}
... but that's a lot of typing over dozens of templates. And it
isn't good enough.
Thanks for any secrets
Mike
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