Add a middleware class like this:
from django.http import HttpResponseForbidden
from django.template import loader, RequestContext
class Http403(Exception):
pass
class ForbiddenMiddleware:
def process_exception(self, request, exception):
if not isinstance(exception, Http403):
return
try:
template = loader.get_template('403.html')
context = RequestContext(request, {'message':
str(exception)})
return HttpResponseForbidden(template.render(context))
except:
pass # Let Django show the exception
Then you can throw a 403 simply by "raise Http403" in your view
functions.
On 16 Mayıs, 13:42, Bram - Smartelectronix <[EMAIL PROTECTED]>
wrote:
> hey everyone,
>
> looking at the source code this isn't immediately clear to me... What if
> I wanted to make a HttpPermissionError or HttpThisPageIsBeingUpdated or
> ... exception that has it's own template?
>
> This way, from anywhere in the code you could throw your very own
> exception...
>
> Am I correct in assuming this is NOT possible w/out editing the django code?
>
> - bram
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