Re: newforms : how to display as_ul from views.py
On 1/15/07, Ramdas S <[EMAIL PROTECTED]> wrote:
How do I get the templates to render the following form from the views.py
given below as as unordered list, instead of the standard table formt. This
is a simple four fields ContactForms, created out of the table Contacts.
form.as_ul()
Theres also `form.as_p()` and the default `form.as_table()`. You can
either use that to pass your form to your context, or you can call it
directly in the template.
Currently it is emmiting the HTML as as a a table class.
def index(request):
ContactForm = forms.models.form_for_model(Contacts)
if request.method == 'POST':
form = ContactForm( request.POST)
if form.is_valid():
form.save()
return HttpResponse('Message Recd')
else:
form = ContactForm()
t = loader.get_template('contactus.html ')
c = Context({'form': form, })
return HttpResponse(t.render(c))
I can make the template behave the way I want to using CSS. But that is not
the idea...
>
--
Waylan Limberg
[EMAIL PROTECTED]
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Re: newforms : how to display as_ul from views.py
Ramdas, in your template:
{{ form.as_ul }}
--
Jeff Bauer
Rubicon, Inc.
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Re: newforms : how to display as_ul from views.py
maybe I am missing something but why don't you use {{ form.as_ul }} in
your template??
On 1/15/07, Ramdas S <[EMAIL PROTECTED]> wrote:
How do I get the templates to render the following form from the views.py
given below as as unordered list, instead of the standard table formt. This
is a simple four fields ContactForms, created out of the table Contacts.
Currently it is emmiting the HTML as as a a table class.
def index(request):
ContactForm = forms.models.form_for_model(Contacts)
if request.method == 'POST':
form = ContactForm( request.POST)
if form.is_valid():
form.save()
return HttpResponse('Message Recd')
else:
form = ContactForm()
t = loader.get_template('contactus.html ')
c = Context({'form': form, })
return HttpResponse(t.render(c))
I can make the template behave the way I want to using CSS. But that is not
the idea...
>
--
Honza Kr l
E-Mail: [EMAIL PROTECTED]
ICQ#: 107471613
Phone: +420 606 678585
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You received this message because you are subscribed to the Google Groups "Django
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newforms : how to display as_ul from views.py
How do I get the templates to render the following form from the
views.pygiven below as as unordered list, instead of the standard
table formt. This
is a simple four fields ContactForms, created out of the table Contacts.
Currently it is emmiting the HTML as as a a table class.
def index(request):
ContactForm = forms.models.form_for_model(Contacts)
if request.method == 'POST':
form = ContactForm(request.POST)
if form.is_valid():
form.save()
return HttpResponse('Message Recd')
else:
form = ContactForm()
t = loader.get_template('contactus.html')
c = Context({'form': form, })
return HttpResponse(t.render(c))
I can make the template behave the way I want to using CSS. But that is not
the idea...
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups "Django
users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en
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