Re: Comparing percent correct to correct by chance

2001-10-30 Thread Glen Barnett


Donald Burrill [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 On Sun, 28 Oct 2001, Melady Preece wrote:

  Hi.  I want to compare the percentage of correct identifications (taste
  test) to the percentage that would be correct by chance 50%?  (only two
  items being tasted).  Can I use a t-test to compare the percentages?
  What would I use for the s.d. for by chance percentage?  (0?)

 Standard comparison would be the formal Z-test for a proportion;  see
 any elementary stats text.  If you have a reasonably large sample size,
 use the normal approximation to the binomial;  if you have a small
 sample, it may be necessary to use the binomial distribution itself,
 which is considerably more tedious unless you have comprehensive tables.

 Sounds as though you'd wish to test  H0: P = .50  vs.  H1:  P  .50.

I'd kind of expect them to want this one to be one tailed - it would
seem strange to be interested in the circumstance where tastebuds do
worse than chance (well, it'd be kinky and fun, but would it change
your action from no difference? I can conceive of it, but I'd bet not.)

Glen





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Re: Comparing percent correct to correct by chance

2001-10-28 Thread Donald Burrill

On Sun, 28 Oct 2001, Melady Preece wrote:

 Hi.  I want to compare the percentage of correct identifications (taste 
 test) to the percentage that would be correct by chance 50%?  (only two
 items being tasted).  Can I use a t-test to compare the percentages?  
 What would I use for the s.d. for by chance percentage?  (0?)

Standard comparison would be the formal Z-test for a proportion;  see 
any elementary stats text.  If you have a reasonably large sample size, 
use the normal approximation to the binomial;  if you have a small 
sample, it may be necessary to use the binomial distribution itself, 
which is considerably more tedious unless you have comprehensive tables.

Sounds as though you'd wish to test  H0: P = .50  vs.  H1:  P  .50.
For the Z-test, use the S.D. of a proportion associated with the 
hypothesized value (.5):  SD = SQRT(pq/n)  where  p = the hyp. value 
(.5 in this case),  q = 1-p,  n = sample size.

You may want to examine the translation of chance into a proportion of 
.5.  I don't think I know what by chance means in the context of your 
investigation;  certainly .5 is a possible interpretation, but I can 
imagine situations where it would be incorrect.  (For example, if the two 
items are always presented in the same order, and there is a predilection 
in your population to identify the first correctly more frequently than 
the second, just because they're first and second, the chance 
hypothesis might be more properly represented by a number  .5.  This 
problem might be countered if the items were presented in counterbalanced 
order.)
Also, if the respondents know beforehand what the two items are 
(just not which one is which), the situation is different from one in 
which the two items might (so far as the respondents know) come from a 
long-ish array of items.  Thus if the task were to decide between 
chocolate and strawberry, the latter might be mis-identified more 
often if raspberry were [thought to be] a possible alternative.
-- DFB.
 
 Donald F. Burrill [EMAIL PROTECTED]
 184 Nashua Road, Bedford, NH 03110  603-471-7128



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Comparing percent correct to correct by chance

2001-10-28 Thread Melady Preece

Hi.  I want to compare the percentage of correct identifications (taste
test) to the percentage that would be correct by chance 50%?  (only two
items being tasted).  Can I use a t-test to compare the percentages?  What
would I use for the s.d. for by chance percentage?  (0?)

Melady

- Original Message -
From: Donald Burrill [EMAIL PROTECTED]
To: Rich Ulrich [EMAIL PROTECTED]
Cc: Shizuhiko Nishisato [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Wednesday, October 24, 2001 8:20 PM
Subject: Re: Graphics  CORRESPONDENCE ANALYSIS


 On Wed, 24 Oct 2001, Rich Ulrich wrote in part:

  It has been my impression (from google) that CA is more popular
  in European journals than in the US, so there might be better
  sites out there in a language I don't read.

 (CA = correspondence analysis,
  ou en francais  analyse des correspondances)

 In Canada, and to a lesser extent in the U.S., correspondence analysis is
 also known under the name dual scaling.  For references consult
 Professor Emeritus Shizuhiko Nishisato of the University of Toronto:
 Shizuhiko Nishisato [EMAIL PROTECTED].
 -- Don.
  
  Donald F. Burrill [EMAIL PROTECTED]
  184 Nashua Road, Bedford, NH 03110  603-471-7128



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