Re: Normality in Factor Analysis

2001-06-25 Thread Glen Barnett


Robert Ehrlich [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Calculation of eigenvalues and eigenvalues requires no assumption.
 However evaluation of the results IMHO implicitly assumes at least a
 unimodal distribution and reasonably homogeneous variance for the same
 reasons as ANOVA or regression.  So think of th consequencesof calculating
 means and variances of a strongly bimodal distribution where no sample
 ocurrs near the mean and all samples are tens of standard devatiations
 from the mean.

The largest number of standard deviations all data can be from the mean is 1.

To get some data further away than that, some of it has to be less than 1 s.d.
from the mean.

Glen





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M/G/1 model

2001-06-25 Thread *Silvia*

I am studying the M/G/1 model for retrial queues.
I know that 1 in M/G/1 means that there is a single server.
Does anyone can tell me what M and G exactly stand for?
Thanks in advance,
Silvia


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Re: cigs figs

2001-06-25 Thread Herman Rubin

In article [EMAIL PROTECTED],
Rich Ulrich  [EMAIL PROTECTED] wrote:
  - re: some outstandingly confused thinking.  Or writing.

On Sat, 23 Jun 2001 15:25:31 GMT, mackeral@remove~this~first~yahoo.com
(J. Williams) wrote:

[ snip;  Slate reference, etcetera ]
   ... My mother was 91 years
 old when she died  a year ago and chain smoked since her college days.
 She defended the tobacco companies for years saying, it didn't hurt
 me.  She outlived most of her doctors.   Upon quoting statistics and
 research on the subject, her view was that I, like other do gooders
 and non-smokers, wanted to deny smokers their rights.  

What statistics would her view quote?  to show that someone
wants to deny smokers 'their rights'?
[ Hey, I didn't write the sentence ]

NO amount of demographic statistics can PROVE, even
statistically, that smoking is harmful to the person
doing it.  Statistical arguments based on such data
are at most indications, and may even be wrong.  The
woman who died recently at 120, a claimant for the 
title of the oldest living person, gave up smoking at
the age of 114.

I just love it, how a 'natural right'  works out to be *exactly*
what the speaker wants to do.

That is essentially it.  The only meaningful rights are the
rights to do what others do not want you to do.

 And not a whit more.
(Thomas and Scalia are probably going to give us tons 
of that bad philosophy, over the next decades.)

What rights are denied to smokers?  You know, you can't 
build your outhouse right on the riverbank, either.

This only applies to second hand smoke, where the 
rights of others are directly involved.  In some
places, you can build your outhouse right on the
riverbank; the only reason that you cannot or should
not do so generally are that it would threaten others.

Obviously,
 there is a health connection.  How strong that connection is, is what
 makes this a unique statistical conundrum.

How strong is that connection?  Well, quite strong.

Personally, I believe that there is a connection.  But it
is a situation where the prior probabilities of the various
states make a big difference.

I once considered that it might not be so bad to die 9 years
early, owing to smoking, if that cut off years of bad health 
and suffering.  Then I realized, the smoking grants you 
most of the bad health of old age, EARLY.  (You do miss 
the Alzheimer's.)  One day, I might give up smoking my pipe.

Why are you smoking a pipe?  Pipe smokers produce second
hand smoke, and lots of objectionable odors.  Can you cite
any benefits which cigarette smokers cannot also claim?
Everything involves risks and benefits, and the individual
should decide.

What is the statistical conundrum?  I can almost 
imagine an ethical conundrum.  (How strongly can
we legislate, to encourage cyclists to wear helmets?)
I sure don't spot a statistical conundrum.

I see no statistical conundrum, either, but merely a
situation where the regulators are using a very large
amount of prior assumptions to justify the legislation.

Now this does not mean that most of those assumptions may
not be correct, but that this is what they are going by.  I
believe that one MUST use prior assumptions, as otherwise
one will be strongly inconsistent, and it is even possible
that nothing will be done.

-- 
This address is for information only.  I do not claim that these views
are those of the Statistics Department or of Purdue University.
Herman Rubin, Dept. of Statistics, Purdue Univ., West Lafayette IN47907-1399
[EMAIL PROTECTED] Phone: (765)494-6054   FAX: (765)494-0558


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Re: Help with stats please

2001-06-25 Thread Herman Rubin

In article 006901c0fce2$d07c7640$[EMAIL PROTECTED],
Melady Preece [EMAIL PROTECTED] wrote:
Hi.  I am teaching educational statistics for the first time, and although I
can go on at length about complex statistical techniques, I find myself at a
loss with this multiple choice question in my test bank.  I understand why
the range of  (b) is smaller than (a) and (c), but I can't figure out how to
prove that it is smaller than (d).

If you can explain it to me, I will be humiliated, but grateful.


1.  Which one of the following classes had
 the smallest range in IQ scores?

 A)  Class A has a mean IQ of 106
   and a standard deviation of ll.
 B)  Class B has an IQ range from 93
   to 119.
 C)  Class C has a mean IQ of 110
   with a variance of 200.
  D)  Class D has a median IQ of 100
   with Q1 = 90 and Q3 = 110.

The test bank says the answer is b.

Melady


What are the sizes of the classes?

What are the distributions of the scores in the various
classes?

If the scores are random from some probability
distribution, and other than the sample data there is no
additional information about the actual scores, for other
than extremely small classes (10 is large here), not many
absolute statements can be made.  I CAN tell that class C
cannot have a smaller range than 29, because otherwise the
variance cannot be 200, and scores are given as integers.
If they are not integers, it goes down slightly.

Even if the model is the totally untenable normal
distribution, the scores are RANDOM, and the samples need
not look at all normal.

As to what was bothering you, what are the quantiles
of the normal distribution?  
-- 
This address is for information only.  I do not claim that these views
are those of the Statistics Department or of Purdue University.
Herman Rubin, Dept. of Statistics, Purdue Univ., West Lafayette IN47907-1399
[EMAIL PROTECTED] Phone: (765)494-6054   FAX: (765)494-0558


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Re: Marijuana

2001-06-25 Thread David C. Ullrich

On Mon, 25 Jun 2001 09:09:52 GMT, [EMAIL PROTECTED] (Graaagh the
Mighty) wrote:

On Sun, 24 Jun 2001 14:39:06 GMT, [EMAIL PROTECTED] (David C.
Ullrich) sat on a tribble, which squeaked:

[1]That's one scary thing - in fact there are places in
Windows95 where the system _regularly_ creates GPF's;
something to do with thunking or something.

[2]But the scary thing about the quote is that the
guy was advocating _hiding_ AV's in programs we
write instead of fixing them. AV's can be hard to
debug - the eaiest way is to make certain they
don't arise in the first place. And given this
guy's attitude, one of the steps involved in
ensuring that your code contains no hard-to-debug
AV's is making sure you never use anything
he wrote. Hence the sig - it's a public-service
thing.

Sometimes you can have access violations all the 
time and the program still works. (Michael Caracena, 
comp.lang.pascal.delphi.misc 5/1/01)

And yet he never made the connection that maybe Michael Caracena's
code *is* the code in Windows that regularly GPFs...

Um, no. In [1] I wasn't talking about the GPF's that we
see when Windows crashes. I forget the details, but
these are _intentional_ GPF's that don't give error
messages - they're part of how the system works.

As opposed to [2] the GPF's this guy is hiding - these
are not GPF's that are supposed to happen.

(Seriously though -- core parts of Windoze are written in Pascal, and
it is known that Windoze does hide some AVs it commits, especially
those involving reading through a null pointer!)

How do you know some parts are in Pascal, and what does that
have to do with AV's?

-- 
Bill Gates: No computer will ever need more than 640K of RAM. -- 1980
There's nobody getting rich writing software that I know of. -- 1980
This antitrust thing will blow over. -- 1998
Combine neo, an underscore, and one thousand sixty-one to make my hotmail addy.



David C. Ullrich
*
Sometimes you can have access violations all the 
time and the program still works. (Michael Caracena, 
comp.lang.pascal.delphi.misc 5/1/01)


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Re: Help with stats please

2001-06-25 Thread Jerry Dallal

Melady Preece wrote:
 
 Hi.  I am teaching educational statistics for the first time, and although I
 can go on at length about complex statistical techniques, I find myself at a
 loss with this multiple choice question in my test bank.  I understand why
 the range of  (b) is smaller than (a) and (c), but I can't figure out how to
 prove that it is smaller than (d).
 
 If you can explain it to me, I will be humiliated, but grateful.

I'm not sure why you would be humiliated, even if the answer were
obvious. You can't prove the range of (b) is smaller than (d). The
question isn't even worded clearly. (b) says a range of from 93 to
119 They range from 93 to 119 and have a range of 26 (subject to
any typographical errors I might make!), but a range from to is
just...sloppy. If (d) were a small class, say 2 students, the upper
and lower quartiles could be 90 and 110, depending on the precise
definition of quartile being used, and the range would be 20, even
with normality, etc.

 
 1.  Which one of the following classes had
  the smallest range in IQ scores?
 
  A)  Class A has a mean IQ of 106
and a standard deviation of ll.
  B)  Class B has an IQ range from 93
to 119.
  C)  Class C has a mean IQ of 110
with a variance of 200.
   D)  Class D has a median IQ of 100
with Q1 = 90 and Q3 = 110.
 
 The test bank says the answer is b.


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Marijuana and heart attacks and similar research on sex

2001-06-25 Thread Simon, Steve, PhD

Recently, there was an extensive discussion about how to analyze data
involving marijuana use and heart attacks. I just came across an interesting
study that shows how to do a rigorous analysis in a very similar situation,
the risk of heart attacks after sex.

The actual paper appears in JAMA, but there is an excellent summary of it on
the Bandolier web site:

http://www.jr2.ox.ac.uk/bandolier/band30/b30-2.html

This is a fun teaching example.

Steve Simon, [EMAIL PROTECTED], Standard Disclaimer.
STATS: STeve's Attempt to Teach Statistics. http://www.cmh.edu/stats
Watch for a change in servers. On or around June 2001, this page will
move to http://www.childrens-mercy.org/stats 


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Re: M/G/1 model

2001-06-25 Thread apharhus

It's the Kendall notation A/B/C/D/E
A interarrival time distribution
M: exponential
D: deterministic
E: Erlang K
G: General
B Servive time distribution
M: exponential
D: deterministic
E: Erlang K
G: General
C number of parallel servers
D system capacity
E queuing rules
FIFO
LIFO
SIRO (servive in random order)
PRI (priority)
GD 'general discipline)

M/G/1 stand for Exponential interaaival time/general servic time
distribution/ 1 server

Hope this help

JCB
France
- Original Message -
From: *Silvia* [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, June 25, 2001 12:11 PM
Subject: M/G/1 model


 I am studying the M/G/1 model for retrial queues.
 I know that 1 in M/G/1 means that there is a single server.
 Does anyone can tell me what M and G exactly stand for?
 Thanks in advance,
 Silvia


 =
 Instructions for joining and leaving this list and remarks about
 the problem of INAPPROPRIATE MESSAGES are available at
   http://jse.stat.ncsu.edu/
 =



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