If the filter string is invalid, createFilter will throw an
InvalidSyntaxException.
If that does not happen, then the filter string is fine.
From the code snippet, I don't know what the value of the mode variable
is. What you should do is print out filter.toString() and see what the
final filter is.
We also can't see what Dictionary or ServiceReference you are attempting
to match against the filter against. So it is possible the nothing matches
your filter.
Finally, I think the argument to the services console command must be a
valid filter string. -l bundleId is not a valid filter string which is
why you get an exception.
--
BJ Hargrave
Senior Technical Staff Member, IBM
OSGi Fellow and CTO of the OSGi Alliance
hargr...@us.ibm.com
office: +1 386 848 1781
mobile: +1 386 848 3788
From:
prof_trg prof.tar...@gmail.com
To:
equinox-dev@eclipse.org
Date:
2009/11/15 07:30
Subject:
[equinox-dev] some issues in creatingfilters
Sent by:
equinox-dev-boun...@eclipse.org
Hello,
I have some issues in creatingfilters..
in fact, only simple filters are accepted like :
filter = context.createFilter(( + Constants.OBJECTCLASS + = +
IMyInterface.class.getName() + ));
however, the filter has filtered nothing if the syntax is like the
following, :
filter = context.createFilter((( + Constants.OBJECTCLASS + = +
IMyInterface.class.getName() + ) +
( +
mode + = + true+ )));
when I taped the command services -l bundleID , an exception occured;
error in character 1 (...
So w*how can I validate the syntax of filters..and what is the origin of
the
exception in your opinion (the previous syntax seems correct..)
Regards
--
View this message in context:
http://old.nabble.com/some-issues-in-creatingfilters-tp26358700p26358700.html
Sent from the Equinox - Dev mailing list archive at Nabble.com.
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