Re: Quantum theory of measurement

2005-10-13 Thread scerir
From: Ben Goertzel 

 The paradox is as follows:
 One does the EPR thing of creating two particles 
 with opposite spin. [...]

More or less, it is the experiment by Birgit Dopfer
(pdf on this page, unfortunately just in German)
http://www.quantum.univie.ac.at/publications/thesis/





Re: Quantum theory of measurement

2005-10-13 Thread Stephen Paul King

Hi Hal,

   After glancing over that paper it seems to me that Badagnani does not 
distinguish between classical and quantum forms of information. I strongly 
suspect that that is the reason why he thinks his idea would work.


Onward!

Stephen

- Original Message - 
From: Hal Finney [EMAIL PROTECTED]

To: everything-list@eskimo.com
Sent: Wednesday, October 12, 2005 9:59 PM
Subject: RE: Quantum theory of measurement



Now that you are experts on this, try your hand on this FTL
signalling device, http://arxiv.org/abs/quant-ph?0204108.
The author, Daniel Badagnani, is apparently a genuine physicist,
http://cabtep5.cnea.gov.ar/particulas/daniel/pag-db.html.

Hal Finney 




Re: Quantum theory of measurement

2005-10-13 Thread Saibal Mitra
Well, as you can see here:

http://cabtep5.cnea.gov.ar/particulas/daniel/curri/curreng.html

He isn't very experienced yet. I know of some experienced  professors of
have made worse mistakes :)

So, what goes wrong? Well, you don't get an interference pattern at one end
even if you don't detect the photon at the other end. To see this, just
write down the two particle state and add the phase shifts. If the detectors
on the other sides are off, then the two contributions corresponding to the
photon being detected at some position z consist of two orthogonal terms;
one term correpsonds to the other photon in pipe 1 and the other for that
photon in pipe 2

 Suppose that you add a plate to detect the photon on that side as well.
Then the probability that the photon at one end is detected at position z1
and the other is detected at z2 does contain an interference term of the
form:

Cos[delta1(z1) + delta2(z2)]

If you don't detect where photon 2 is absorbed you have to integrate over z2
and the interference term vanishes. To see an interference term you must
keep  z2 fixed. This means that you must consider only those photons for
which the entangled partners were detected at at some fixed z2. But this
means that this value must be communicated by the observer there.

- Original Message - 
From: Hal Finney [EMAIL PROTECTED]
To: everything-list@eskimo.com
Sent: Thursday, October 13, 2005 03:59 AM
Subject: RE: Quantum theory of measurement


 Now that you are experts on this, try your hand on this FTL
 signalling device, http://arxiv.org/abs/quant-ph?0204108.
 The author, Daniel Badagnani, is apparently a genuine physicist,
 http://cabtep5.cnea.gov.ar/particulas/daniel/pag-db.html.

 Hal Finney




Re: ROSS MODEL OF THE UNIVERSE - The Simplest Yet Theory of Everything

2005-10-13 Thread Bruno Marchal


Le 11-oct.-05, à 01:46, John Ross a écrit :


Because there is only one particle (and its  anti-particle) and one
force from which the entire universe is built.  How could there be
anything simpler?



0 particles and 0 forces, no time nor spaces but a web a overlapping 
turing machines' dreams emerging from addition and multiplication ...


John, if you want your theory being a TOE, don't forget to address the 
mind body problem, and to be clear on all your assumptions (ontology, 
epistemology).


Now to be honest I have no idea how neutrinos could be photons. If you 
thrust your idea try (at least) to write a paper with some details.


Bruno


http://iridia.ulb.ac.be/~marchal/



Re: ROSS MODEL OF THE UNIVERSE - The Simplest Yet Theory of Everything

2005-10-13 Thread Russell Standish
Very good! If we ever get around to making a FAQ for this group, this
link should be right up front.

Cheers

On Fri, Oct 14, 2005 at 12:18:19AM +0200, Saibal Mitra wrote:
 You clearly forgot to read this:
 http://insti.physics.sunysb.edu/~siegel/quack.html
 
 

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