I wrote a code to mix two audio streams which is working. However, somehow `avfilter_graph_parse2` is not preserving the pad names
For example, below is a filter spec ``` filter_spec = "abuffer=time_base=1/48000:sample_rate=48000:sample_fmt=fltp:channel_layout=0x3[a0] ; abuffer=time_base=1/48000:sample_rate=48000:sample_fmt=fltp:channel_layout=0x3 [a1]; [a0] [a1] amix=inputs=2, abuffersink"; ``` Below is the code to parse and dump graph ``` if ((ret = avfilter_graph_parse2(filter_graph, filter_spec, &inputs, &outputs)) < 0) { av_log(NULL, AV_LOG_ERROR, "avfilter_graph_parse_ptr failed: %d\n", ret); } if ((ret = avfilter_graph_config(filter_graph, NULL)) < 0) { av_log(NULL, AV_LOG_ERROR, "avfilter_graph_config failed\n"); } char *g = avfilter_graph_dump(filter_graph, NULL); if(g) { av_log(NULL, AV_LOG_ERROR, "Graph: %s\n", g); av_free(g); } ``` and below is the graph dump. ``` Graph: +------------------+ | Parsed_abuffer_0 |default--[48000Hz fltp:stereo]--Parsed_amix_2:input0 | (abuffer) | +------------------+ +------------------+ | Parsed_abuffer_1 |default--[48000Hz fltp:stereo]--Parsed_amix_2:input1 | (abuffer) | +------------------+ +---------------+ Parsed_abuffer_0:default--[48000Hz fltp:stereo]--input0| Parsed_amix_2 |default--[48000Hz fltp:stereo]--Parsed_abuffersink_3:default Parsed_abuffer_1:default--[48000Hz fltp:stereo]--input1| (amix) | +---------------+ +----------------------+ Parsed_amix_2:default--[48000Hz fltp:stereo]--default| Parsed_abuffersink_3 | | (abuffersink) | +----------------------+ ``` As you can see, all the pad names a0, a1, etc gone and they are replaced by `default`, Parsed_abuffersink_3 etc. Is there any way to preserve names? _______________________________________________ ffmpeg-devel mailing list ffmpeg-devel@ffmpeg.org https://ffmpeg.org/mailman/listinfo/ffmpeg-devel To unsubscribe, visit link above, or email ffmpeg-devel-requ...@ffmpeg.org with subject "unsubscribe".