On Mon, 2003-08-11 at 17:49, Constantine wrote:
Hello!
I am writing a script, which involves unzipping some files. I would have
to unzip 4 different zip-files from some directory, and I would need to
unzip them to the directory, which would have the same name in it as the
original zip-file, i.e. I would like to run something like ls *.zip,
have each file name recorded in some variable, and do a loop like unzip
$filename[$i] -d $filename[$i].unzipped/. Can someone help me with the
code? How can I put the results of a command to a variable?
The following assumes you have the bash port installed. Just change the
ARCHIVE_DIR variable to the full path of the directory in which you have
your zip files. Make sure to save this code to a file in ~/bin. I
suggest pasting the following code into ~/bin/munzip.sh.
Then type chmod +x ~/bin/munzip.sh, then rehash, and then
munzip.sh.
**
#!/usr/bin/env bash
ARCHIVE_DIR=~/archive
cd $ARCHIVE_DIR
# you don't need ls *.zip
for zip in *
do
# just for diagnostics
echo $zip
# here's the command you want.
unzip $zip -d $zip.unzipped/
done
exit 0
**
--
Matthew Graybosch
http://www.starbreaker.net
If you take a stand on a dead empty hand,
never let 'em see your cards. --Savatage
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