Re: way way off topic
On Wed, 24 Oct 2012 08:39:55 +0700, Erich Dollansky wrote: Hi, On Tue, 23 Oct 2012 18:13:05 -0700 Gary Kline kl...@thought.org wrote: On Tue, Oct 23, 2012 at 05:52:02PM -0700, Gezeala M. Bacuño II wrote: if/when I ever find that v short exercise, THIS time, il'l remember to 'splain stuff in /* * comments */ your programs are not self-explanatory? That's not modern today anymore. :-) /* * this function is void, * it takes no args, * one of them is not a nickel, * adds minus 1 to the result * and then branches to register #14 */ setpicardcolor(); /* 4 lights! */ :-) -- Polytropon Magdeburg, Germany Happy FreeBSD user since 4.0 Andra moi ennepe, Mousa, ... ___ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to freebsd-questions-unsubscr...@freebsd.org
Re: way way off topic
Hi, On Wed, 24 Oct 2012 10:23:17 +0200 Polytropon free...@edvax.de wrote: On Wed, 24 Oct 2012 08:39:55 +0700, Erich Dollansky wrote: Hi, On Tue, 23 Oct 2012 18:13:05 -0700 Gary Kline kl...@thought.org wrote: On Tue, Oct 23, 2012 at 05:52:02PM -0700, Gezeala M. Bacuño II wrote: if/when I ever find that v short exercise, THIS time, il'l remember to 'splain stuff in /* * comments */ your programs are not self-explanatory? That's not modern today anymore. :-) /* * this function is void, * it takes no args, * one of them is not a nickel, * adds minus 1 to the result * and then branches to register #14 */ setpicardcolor(); /* 4 lights! */ this is so Seventies! Erich ___ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to freebsd-questions-unsubscr...@freebsd.org
Re: way way off topic
On Tue, 23 Oct 2012 15:51:54 -0700, Gary Kline wrote: lets say that x == 15 and y == 16. Q: how much less is x than y? it is not just 1; there was some other way of finding the answer. 6.25% ___ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to freebsd-questions-unsubscr...@freebsd.org
Re: way way off topic
On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote: Gary, On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote: apologies up front for this math type quandary. I had it in a std C program, but 3+ hours of grepping havent found it. I would have bet my last cent that I had a summary Somewhere, but cant find that either. here is the problem as best I can remember it. let's say that john is 8 and his older friend, jim, is 22. how much older is exact percentage terms is jim? That should be 22/8=2.75 Jim is 275% older than John Jim is 175% _older_. Why? Because 100% older means 16 years, as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24). Percentage is always a reference to something else, in this question, Jim's age in relation to John's. The word older means adding percentage, refering to the base value of 8, divided in 100 parts (floating point considerations aside), to finally reach the value 22. If the question would be different, say, What's the percentage of John's age regarding Jim's age? In that case, it would be 8/22=0.3636 being 36%. Obvious: John's age is approximately 1/3 of Jim's age. The easiest way for creating the proper calculation is to refer to the equation percentage * 100 percentage value = base value and resolve it to whatever is required. -- Polytropon Magdeburg, Germany Happy FreeBSD user since 4.0 Andra moi ennepe, Mousa, ... ___ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to freebsd-questions-unsubscr...@freebsd.org
Re: way way off topic
Olivier Nicole olivier.nic...@cs.ait.ac.th wrote: On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote: apologies up front for this math type quandary. I had it in a std C program, but 3+ hours of grepping havent found it. I would have bet my last cent that I had a summary Somewhere, but cant find that either. here is the problem as best I can remember it. let's say that john is 8 and his older friend, jim, is 22. how much older is exact percentage terms is jim? That should be 22/8=2.75 Jim is 275% older than John No, a subtraction is needed if we wish to use the term older. Suppose Jim were 9; the above approach would give 9/8 = 1.125 so Jim is 113% older than John, which is clearly wrong (although one could correctly say in that case that John's age is 113% of Jim's age). I think the OP is probably looking for ((22 - 8) * 100 + (8/2)) / 8 which will give the answer directly as a correctly-rounded integral percentage. (For a fractional percentage, use floats instead of ints and omit the (8/2) part -- but in that case you probably also want to express the ages in something other than whole years.) ___ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to freebsd-questions-unsubscr...@freebsd.org
Re: way way off topic
On Tue, Oct 23, 2012 at 11:31:18AM +0700, Olivier Nicole wrote:
Gary,
On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
apologies up front for this math type quandary. I had it in a std C program,
but 3+ hours of grepping havent found it. I would have bet my last cent
that I
had a summary Somewhere, but cant find that either.
here is the problem as best I can remember it.
let's say that john is 8 and his older friend, jim, is 22.
how much older is exact percentage terms is jim?
That should be 22/8=2.75
Jim is 275% older than John
Olivier
thanks. but this wasn't the formula I remember mousing
down. I'll keep looking.
gary
ps: it was involved; something with three or more steps.
things that I had crammed together in one line of C...
to find the answer I had to find the relative difference {22 - 8} and then
do something with the difference. this isn't any kind of trick or
advanced-cognition; I just thought it was clever [and exact]. it
obviously
works for finding the abs() results in subtraction. it's something I found
on
the web and swipes and save the prose discussion. BZZT: Lost, :-(
if this seems dumb, I plead guilty!
im asking here because -questions is the sharpest list on the net.
--
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Re: way way off topic
On Tue, Oct 23, 2012 at 11:34:36AM +0700, Erich Dollansky wrote:
Hi,
On Mon, 22 Oct 2012 21:20:07 -0700
Gary Kline kl...@thought.org wrote:
apologies up front for this math type quandary. I had it in a std C
program, but 3+ hours of grepping havent found it. I would have bet
my last cent that I had a summary Somewhere, but cant find that
either.
here is the problem as best I can remember it.
let's say that john is 8 and his older friend, jim, is 22.
how much older is exact percentage terms is jim?
to find the answer I had to find the relative difference {22 - 8} and
then do something with the difference. this isn't any kind of trick
or advanced-cognition; I just thought it was clever [and exact].
it obviously works for finding the abs() results in subtraction.
it's something I found on the web and swipes and save the prose
discussion. BZZT: Lost, :-(
It seems that I am also lost. What should abs() do here?
I would multiply the age of john and the difference with 100 and then
divide the result to get the percentage.
Or did I get lost here?
if this seems dumb, I plead guilty!
im asking here because -questions is the sharpest list on the net.
Are you sure?
Erich
LOL. yes!
it's been years since I used the steps to find the accurant amount of
difference. it may not have involved a %. I can only think of one
concrete example.
lets say that x == 15 and y == 16. Q: how much less is x than y?
it is not just 1; there was some other way of finding the answer.
--
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Re: way way off topic
On Tue, Oct 23, 2012 at 08:52:49AM +0200, Polytropon wrote: On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote: Gary, On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote: apologies up front for this math type quandary. I had it in a std C program, but 3+ hours of grepping havent found it. I would have bet my last cent that I had a summary Somewhere, but cant find that either. here is the problem as best I can remember it. let's say that john is 8 and his older friend, jim, is 22. how much older is exact percentage terms is jim? That should be 22/8=2.75 Jim is 275% older than John Jim is 175% _older_. Why? Because 100% older means 16 years, as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24). Percentage is always a reference to something else, in this question, Jim's age in relation to John's. The word older means adding percentage, refering to the base value of 8, divided in 100 parts (floating point considerations aside), to finally reach the value 22. If the question would be different, say, What's the percentage of John's age regarding Jim's age? In that case, it would be 8/22=0.3636 being 36%. Obvious: John's age is approximately 1/3 of Jim's age. The easiest way for creating the proper calculation is to refer to the equation percentage * 100 percentage value = base value and resolve it to whatever is required. I just took a cup's worth of coffee/caffeine to bring me back up! but it seems to me that your logic is about the same as I remember otherwise stated in getting the true differences in ages or speeds [say or cars. x == 200clicks/hr, y == 400 clicks/hour.] or *whatever*. it isn't as easy as it would seem at first thought. -- Polytropon Magdeburg, Germany Happy FreeBSD user since 4.0 Andra moi ennepe, Mousa, ... -- Gary Kline kl...@thought.org http://www.thought.org Public Service Unix Twenty-six years of service to the Unix community. ___ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to freebsd-questions-unsubscr...@freebsd.org
Re: way way off topic
On Tue, Oct 23, 2012 at 08:52:49AM +0200, Polytropon wrote:
On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote:
Gary,
On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
apologies up front for this math type quandary. I had it in a std C
program,
but 3+ hours of grepping havent found it. I would have bet my last cent
that I
had a summary Somewhere, but cant find that either.
here is the problem as best I can remember it.
let's say that john is 8 and his older friend, jim, is 22.
how much older is exact percentage terms is jim?
That should be 22/8=2.75
Jim is 275% older than John
Jim is 175% _older_. Why? Because 100% older means 16 years,
as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24).
Percentage is always a reference to something else, in this
question, Jim's age in relation to John's. The word older
means adding percentage, refering to the base value of 8,
divided in 100 parts (floating point considerations aside),
to finally reach the value 22.
If the question would be different, say, What's the percentage
of John's age regarding Jim's age? In that case, it would be
8/22=0.3636 being 36%. Obvious: John's age is approximately
1/3 of Jim's age.
The easiest way for creating the proper calculation is to refer
to the equation
percentage * 100
percentage value =
base value
and resolve it to whatever is required.
--
Polytropon
Magdeburg, Germany
Happy FreeBSD user since 4.0
Andra moi ennepe, Mousa, ...
yo; I THInk this is it. around line 4542 in my ~/.HowTo file::
%%% find percent inc/dec [increase/decrease] between two numbers.
Always figure the percentage of change relative to the original value!
For instance: * Suppose a certain item used to sell for seventy-five
cents a pound, you see that it's been marked up to eighty-one cents a
pound. What is the percent increase?
First, I have to find the absolute
increase:
Reserved 81 - 75 = 6
The price has gone up six cents. Now I can find the
percentage increase over the original price.
This percentage increase is the relative change: 6/75 = 0.08
...or an 8% increase in price per pound.
So I was wrong about ages or speed; it's the % betwen two ints;
here, the inc/dec [or change] between 75 cents as compared to
an inflated increase of 81 cents.
1. find abs increase: 81-75 = 6;
2 find the % increase over the *original* value. 6.0/75.0
3. percent increase using doubles is 0.08; so a markup of six
cents is an 8% rate.
so: going back to the ages example with john bein 8, jim, 22.
22-8 is 14.
14.0/8.0 = 1.75
175%. jim is 175% times older than john. which is what you found,
polyt. {I'll have to re-read your logic now that im awake..}
Or, how much more, in % is 16t than 15, it is 1.0/15.0 which is 6%.
etc, etc.
Hm. that's 0 for gary, 729 for polytrop!!
Ah, life:: accept no substitutes.
--
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Twenty-six years of service to the Unix community.
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Re: way way off topic
% change = ( (present - past) / past ) * 100
On Tue, Oct 23, 2012 at 5:07 PM, Gary Kline kl...@thought.org wrote:
On Tue, Oct 23, 2012 at 08:52:49AM +0200, Polytropon wrote:
On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote:
Gary,
On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
apologies up front for this math type quandary. I had it in a std C
program,
but 3+ hours of grepping havent found it. I would have bet my last cent
that I
had a summary Somewhere, but cant find that either.
here is the problem as best I can remember it.
let's say that john is 8 and his older friend, jim, is 22.
how much older is exact percentage terms is jim?
That should be 22/8=2.75
Jim is 275% older than John
Jim is 175% _older_. Why? Because 100% older means 16 years,
as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24).
Percentage is always a reference to something else, in this
question, Jim's age in relation to John's. The word older
means adding percentage, refering to the base value of 8,
divided in 100 parts (floating point considerations aside),
to finally reach the value 22.
If the question would be different, say, What's the percentage
of John's age regarding Jim's age? In that case, it would be
8/22=0.3636 being 36%. Obvious: John's age is approximately
1/3 of Jim's age.
The easiest way for creating the proper calculation is to refer
to the equation
percentage * 100
percentage value =
base value
and resolve it to whatever is required.
--
Polytropon
Magdeburg, Germany
Happy FreeBSD user since 4.0
Andra moi ennepe, Mousa, ...
yo; I THInk this is it. around line 4542 in my ~/.HowTo file::
%%% find percent inc/dec [increase/decrease] between two numbers.
Always figure the percentage of change relative to the original value!
For instance: * Suppose a certain item used to sell for seventy-five
cents a pound, you see that it's been marked up to eighty-one cents a
pound. What is the percent increase?
First, I have to find the absolute
increase:
Reserved 81 - 75 = 6
The price has gone up six cents. Now I can find the
percentage increase over the original price.
This percentage increase is the relative change: 6/75 = 0.08
...or an 8% increase in price per pound.
So I was wrong about ages or speed; it's the % betwen two ints;
here, the inc/dec [or change] between 75 cents as compared to
an inflated increase of 81 cents.
1. find abs increase: 81-75 = 6;
2 find the % increase over the *original* value. 6.0/75.0
3. percent increase using doubles is 0.08; so a markup of six
cents is an 8% rate.
so: going back to the ages example with john bein 8, jim, 22.
22-8 is 14.
14.0/8.0 = 1.75
175%. jim is 175% times older than john. which is what you found,
polyt. {I'll have to re-read your logic now that im awake..}
Or, how much more, in % is 16t than 15, it is 1.0/15.0 which is 6%.
etc, etc.
Hm. that's 0 for gary, 729 for polytrop!!
Ah, life:: accept no substitutes.
--
Gary Kline kl...@thought.org http://www.thought.org Public Service Unix
Twenty-six years of service to the Unix community.
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Re: way way off topic
On Tue, Oct 23, 2012 at 05:52:02PM -0700, Gezeala M. Bacuño II wrote:
% change = ( (present - past) / past ) * 100
yeah, this is exactly it for my how much more is 16 than 15
problem. or the ages example.
It's 6.6[bar-over .6]% this is probably close to or exactly
what was the core of my C [argc, *srgv[]] program. my error was in
not understanding the logic that polttropon has given below. if/when
I ever find that v short exercise, THIS time, il'l remember to
'splain stuff in
/*
* comments
*/
On Tue, Oct 23, 2012 at 5:07 PM, Gary Kline kl...@thought.org wrote:
On Tue, Oct 23, 2012 at 08:52:49AM +0200, Polytropon wrote:
On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote:
Gary,
On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
apologies up front for this math type quandary. I had it in a std C
program,
but 3+ hours of grepping havent found it. I would have bet my last
cent that I
had a summary Somewhere, but cant find that either.
here is the problem as best I can remember it.
let's say that john is 8 and his older friend, jim, is 22.
how much older is exact percentage terms is jim?
That should be 22/8=2.75
Jim is 275% older than John
Jim is 175% _older_. Why? Because 100% older means 16 years,
as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24).
Percentage is always a reference to something else, in this
question, Jim's age in relation to John's. The word older
means adding percentage, refering to the base value of 8,
divided in 100 parts (floating point considerations aside),
to finally reach the value 22.
If the question would be different, say, What's the percentage
of John's age regarding Jim's age? In that case, it would be
8/22=0.3636 being 36%. Obvious: John's age is approximately
1/3 of Jim's age.
The easiest way for creating the proper calculation is to refer
to the equation
percentage * 100
percentage value =
base value
and resolve it to whatever is required.
--
Polytropon
Magdeburg, Germany
Happy FreeBSD user since 4.0
Andra moi ennepe, Mousa, ...
yo; I THInk this is it. around line 4542 in my ~/.HowTo file::
%%% find percent inc/dec [increase/decrease] between two numbers.
Always figure the percentage of change relative to the original value!
For instance: * Suppose a certain item used to sell for seventy-five
cents a pound, you see that it's been marked up to eighty-one cents a
pound. What is the percent increase?
First, I have to find the absolute
increase:
Reserved 81 - 75 = 6
The price has gone up six cents. Now I can find the
percentage increase over the original price.
This percentage increase is the relative change: 6/75 = 0.08
...or an 8% increase in price per pound.
So I was wrong about ages or speed; it's the % betwen two ints;
here, the inc/dec [or change] between 75 cents as compared to
an inflated increase of 81 cents.
1. find abs increase: 81-75 = 6;
2 find the % increase over the *original* value. 6.0/75.0
3. percent increase using doubles is 0.08; so a markup of six
cents is an 8% rate.
so: going back to the ages example with john bein 8, jim, 22.
22-8 is 14.
14.0/8.0 = 1.75
175%. jim is 175% times older than john. which is what you found,
polyt. {I'll have to re-read your logic now that im awake..}
Or, how much more, in % is 16t than 15, it is 1.0/15.0 which is 6%.
etc, etc.
Hm. that's 0 for gary, 729 for polytrop!!
Ah, life:: accept no substitutes.
--
Gary Kline kl...@thought.org http://www.thought.org Public Service Unix
Twenty-six years of service to the Unix community.
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Re: way way off topic
Hi, On Tue, 23 Oct 2012 18:13:05 -0700 Gary Kline kl...@thought.org wrote: On Tue, Oct 23, 2012 at 05:52:02PM -0700, Gezeala M. Bacuño II wrote: if/when I ever find that v short exercise, THIS time, il'l remember to 'splain stuff in /* * comments */ your programs are not self-explanatory? Erich ___ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to freebsd-questions-unsubscr...@freebsd.org
way way off topic
apologies up front for this math type quandary. I had it in a std C program,
but 3+ hours of grepping havent found it. I would have bet my last cent that I
had a summary Somewhere, but cant find that either.
here is the problem as best I can remember it.
let's say that john is 8 and his older friend, jim, is 22.
how much older is exact percentage terms is jim?
to find the answer I had to find the relative difference {22 - 8} and then
do something with the difference. this isn't any kind of trick or
advanced-cognition; I just thought it was clever [and exact]. it obviously
works for finding the abs() results in subtraction. it's something I found on
the web and swipes and save the prose discussion. BZZT: Lost, :-(
if this seems dumb, I plead guilty!
im asking here because -questions is the sharpest list on the net.
--
Gary Kline kl...@thought.org http://www.thought.org Public Service Unix
Twenty-six years of service to the Unix community.
___
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Re: way way off topic
Gary,
On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
apologies up front for this math type quandary. I had it in a std C program,
but 3+ hours of grepping havent found it. I would have bet my last cent that
I
had a summary Somewhere, but cant find that either.
here is the problem as best I can remember it.
let's say that john is 8 and his older friend, jim, is 22.
how much older is exact percentage terms is jim?
That should be 22/8=2.75
Jim is 275% older than John
Olivier
to find the answer I had to find the relative difference {22 - 8} and then
do something with the difference. this isn't any kind of trick or
advanced-cognition; I just thought it was clever [and exact]. it obviously
works for finding the abs() results in subtraction. it's something I found on
the web and swipes and save the prose discussion. BZZT: Lost, :-(
if this seems dumb, I plead guilty!
im asking here because -questions is the sharpest list on the net.
--
Gary Kline kl...@thought.org http://www.thought.org Public Service Unix
Twenty-six years of service to the Unix community.
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Re: way way off topic
Hi,
On Mon, 22 Oct 2012 21:20:07 -0700
Gary Kline kl...@thought.org wrote:
apologies up front for this math type quandary. I had it in a std C
program, but 3+ hours of grepping havent found it. I would have bet
my last cent that I had a summary Somewhere, but cant find that
either.
here is the problem as best I can remember it.
let's say that john is 8 and his older friend, jim, is 22.
how much older is exact percentage terms is jim?
to find the answer I had to find the relative difference {22 - 8} and
then do something with the difference. this isn't any kind of trick
or advanced-cognition; I just thought it was clever [and exact].
it obviously works for finding the abs() results in subtraction.
it's something I found on the web and swipes and save the prose
discussion. BZZT: Lost, :-(
It seems that I am also lost. What should abs() do here?
I would multiply the age of john and the difference with 100 and then
divide the result to get the percentage.
Or did I get lost here?
if this seems dumb, I plead guilty!
im asking here because -questions is the sharpest list on the net.
Are you sure?
Erich
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