[Bug middle-end/54544] Option -Wuninitialized does not work as documented with volatile
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54544
Zakhar jimfr06 at gmail dot com changed:
What|Removed |Added
Status|RESOLVED|UNCONFIRMED
Resolution|INVALID |
--- Comment #3 from Zakhar jimfr06 at gmail dot com 2012-09-11 16:41:43 UTC
---
On second thoughs, I reopen the issue!
WHY:
---
The 'correction' of the code above is a contrary to what the function intended
to do and thus breaks its logic: the declaration in the second version of the
code are inconsistent with what the function was intented to. That is because,
I suppose, the message gcc delivers and its correction are not OK with what
really happens.
FURTHER EXPLANATIONS:
-
You are right Andrew, the variable 'bar' is indeed (first version of the code)
a 'pointer to a volatile memory location' (location of an int).
*And that was intended so*.
The code is a simplification of a 'memory protection algorithm' where the int
that is pointed represents the count of threads using a given piece of memory.
This count being accessed from several threads, is indeed volatile as no thread
can assume the value didn't change from last time it read/wrote the value.
(atomic instructions where removed from the code example).
The pointer itself is not at all volatile. Anyway, once it is passed to the
function, it sits on the stack where its value should be unchanged as long a
the function lives, and same goes for the 'bar' automatic variable. I'm not
doing crazy threaded things on variables on the stack of this function!
I was confused by the warning message saying:
'bar' may be used uninitialized in this function
... because the message is indeed confusing. 'bar' is NOT used uninitialized
(as demonstrated) but the *content pointed by 'bar'* could be. I must confess
that I didn't look from far enough to interpret the message this way.
HYPOTHESIS:
---
So could it be that gcc saw that, and warns incorrectly on 'bar' instead of
'*bar'?
If so, yes, because the function receives a pointer to a memory location, the
function itself cannot know whether the location pointed to was initialized or
not. 'bar' gets the same address ( bar = p ) thus, indeed, the location pointed
by 'bar' could be un-initialized.
This could also be coherent with the fact that when we change the function to
static, the warning disappears. Being static, all the callers have to be on the
same source, thus the compiler can check if the callers initialize properly the
content memory pointed to.
But then, shouldn't the message be:
'*bar' may be used uninitialized in this function.
And that would indeed be correct, because '*bar' being the memory pointed to by
bar, could indeed be un-initialized (if the caller didn't initialize it).
And thus, the compiler would do a good job signaling that, as '*bar' (memory
which bar points to) is declared as volatile, but it is NOT an automatic
variable (the pointer is, not the memory pointed to).
My hypothesis is probably wrong, because if gcc warned about un-initialized
memory pointed to, it would have to warn on that:
/*01*/ int
/*02*/ foo( p )
/*03*/ int *p;
/*04*/ {
/*05*/ int foobar;
/*06*/
/*07*/ foobar= *p;
/*08*/
/*09*/ return foobar + 2;
/*10*/ }
(we don't know if '*p' has ever been initialized).
And this short code snipet produces no warning at all, which is fine because a
lot of code do that (passing variable 'by reference'), and it is perfectly
correct not to warn.
CONCLUSION:
--
As previously concluded, it is not strictly a 'bug' as the documentation
perfectly states that in some case the dectection is broken, but I assume this
issue can go in the general thread better wuninitialized.
- either gcc saw that '*bar' is uninitialized and should report that (and not
report the pointer instead)
- or gcc saw 'bar' (the pointer) to be unitialized, and that is a test case
where it can do better work, as we can demonstrate it IS initialized.
VERSION 3 of the code:
-
Of course, NOT to break my program logic, the correct declaration of the
variable should be:
/*09*/ volatile int * volatile bar;
The 1st 'volatile' because indeed the memory we point to MUST be declared as
volatile.
The 2nd 'volatile' to suppress the 'false positive' detection on the pointer.
QUESTION @Andrew:
Should I post something on the general thread better wuninitialized (unless
my deductions are wrong again), or do you attach the use case directly from
this bug report?
[Bug middle-end/54544] Option -Wuninitialized does not work as documented with volatile
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54544
--- Comment #4 from Zakhar jimfr06 at gmail dot com 2012-09-11 21:09:28 UTC
---
MORE
Unfortunately, I don't think the hypothesis of the uninitialized pointed memory
hold. That should prove it if we add:
/*01*/ int fct(volatile int *p);
/*02*/
/*03*/ static int
/*04*/ foo( p )
/*05*/ volatile int * p;
/*06*/ {
/*07*/ volatile int foobar,barfoo;
/*08*/ volatile int flag=0;
/*09*/ volatile int * bar;
/*10*/
/*11*/ do
/*12*/ {
/*13*/ if ( *p )
/*14*/ {
/*15*/ flag= fct( p );
/*16*/ bar = p;
/*17*/ }
/*18*/ if ( fct( p ) ) break;
/*19*/ if ( flag )
/*20*/ {
/*21*/ barfoo = *bar;
/*22*/ if ( bar == (int *)0 ) break;
/*23*/ foobar = *bar;
/*24*/ return foobar + barfoo;
/*25*/ }
/*26*/ }
/*27*/ while ( fct( p ) );
/*28*/
/*29*/ return 0;
/*30*/ }
/*31*/
/*32*/ int
/*33*/ main()
/*34*/ {
/*35*/ int i;
/*35*/
/*37*/ return foo( i );
/*38*/
/*40*/ }
Here 'main' calls the 'foo' function with a pointer to a variable which for
sure is NOT initialized, and there is no warning whatsoever when we compile
with:
$ gcc -O3 -c uninit.c -o /dev/null -Wall
In this example, if we go to line 23, for sure the result of the returned value
is totally unpredictable as it depends on the value of 'i' in the main
function.
'i' is on the stack, and has not been initialized, so it gets any value that
was there previously on the stack!
If we remove 'static' in front of the function, this time we get our warning
back... but probably a 'false positive' on 'bar', and not related to tracking
down pointed memory.
In this new use-case, if we add 'inline' after static (which -O3 should do by
itself here?) we are for sure doing something wrong.
Shouldn't -WUninitialized output something instead of remaining silent?
[Bug c/54544] New: Option -Wuninitialized does not work as documented with volatile
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54544
Bug #: 54544
Summary: Option -Wuninitialized does not work as documented
with volatile
Classification: Unclassified
Product: gcc
Version: 4.6.3
Status: UNCONFIRMED
Severity: minor
Priority: P3
Component: c
AssignedTo: unassig...@gcc.gnu.org
ReportedBy: jimf...@gmail.com
I first filed this bug to Ubuntu Launchpad under the reference 1008090:
https://bugs.launchpad.net/ubuntu/+source/gcc-4.6/+bug/1008090
A the finding of the Ubuntu guys is that it is an upstream bug, I'll just
copy/paste it here (with additional findings).
I classified is as minor as we are talking only of warnings (but still it
is an annoyance) and/or a documentation bug.
==
Versions of Ubuntu and gcc:
-
(Precise amd64, out-of-the-box gcc)
$ LANG=ENG uname -a echo gcc -v
Linux zakhar-desktop 3.2.0-24-generic #39-Ubuntu SMP Mon May 21 16:52:17 UTC
2012 x86_64 x86_64 x86_64 GNU/Linux
Using built-in specs.
COLLECT_GCC=gcc
COLLECT_LTO_WRAPPER=/usr/lib/gcc/x86_64-linux-gnu/4.6/lto-wrapper
Target: x86_64-linux-gnu
Configured with: ../src/configure -v --with-pkgversion='Ubuntu/Linaro
4.6.3-1ubuntu5' --with-bugurl=file:///usr/share/doc/gcc-4.6/README.Bugs
--enable-languages=c,c++,fortran,objc,obj-c++ --prefix=/usr
--program-suffix=-4.6 --enable-shared --enable-linker-build-id
--with-system-zlib --libexecdir=/usr/lib --without-included-gettext
--enable-threads=posix --with-gxx-include-dir=/usr/include/c++/4.6
--libdir=/usr/lib --enable-nls --with-sysroot=/ --enable-clocale=gnu
--enable-libstdcxx-debug --enable-libstdcxx-time=yes --enable-gnu-unique-object
--enable-plugin --enable-objc-gc --disable-werror --with-arch-32=i686
--with-tune=generic --enable-checking=release --build=x86_64-linux-gnu
--host=x86_64-linux-gnu --target=x86_64-linux-gnu
Thread model: posix
gcc version 4.6.3 (Ubuntu/Linaro 4.6.3-1ubuntu5)
WHAT HAPPENS:
Consider the source code below:
/*01*/ int fct(volatile int *p);
/*02*/
/*03*/ int
/*04*/ foo( p )
/*05*/ volatile int *p;
/*06*/ {
/*07*/ volatile int foobar,barfoo;
/*08*/ volatile int flag=0;
/*09*/ volatile int *bar;
/*10*/
/*11*/ do
/*12*/ {
/*13*/ if ( *p )
/*14*/ {
/*15*/ flag= fct( p );
/*16*/ bar = p;
/*17*/ }
/*18*/ if ( fct( p ) ) break;
/*19*/ if ( flag )
/*20*/ {
/*21*/ barfoo = *bar;
/*22*/ if ( bar == (int *)0 ) break;
/*23*/ foobar = *bar;
/*24*/ return foobar + barfoo;
/*25*/ }
/*26*/ }
/*27*/ while ( fct( p ) );
/*28*/
/*29*/ return 0;
/*30*/ }
Compile it and you get:
$ gcc -O3 -c uninit.c -o /dev/null -Wall
uninit.c: In function 'foo':
uninit.c:23:27: warning: 'bar' may be used uninitialized in this function
[-Wuninitialized]
WHAT SHOULD HAPPEN:
--
1) gcc makes a *VERY BAD* job at detecting uninitialized!
Per se, this is not a bug, because it is duly documented that in some
situations, gcc cannot guess.
Here, simple logic proves that the detection is bad:
- you cannot reach lines 21-24 unless flag is not zero.
- flag is initialized to zero, and the only place it can take another value is
line 15, where it gets the result of our external function.
- if we go to line 15, the next line in sequence would initialize 'bar'.
- thus when we go to lines 21-24 'bar' is definitely initialized.
Other strange things about this false detection:
- it warns on line 23, and not on lines 21 or 22 that already use the same
variable BEFORE line 23!
- it stops warning if you remove line 18! This is odd, because line 18 only
breaks out of the flow on certain condition, and as this is before we use the
allegedly uninitialized variable, it can do no harm. One could argue that gcc
can move line 18 up, but I hope it does not... as we don't know whether our
external function has side effect (and no way I know in C to instruct the
compiler it does not!), if it has side effects this would break the behaviour
of the code as fct is already called on line 15, prior to line 18.
2) Apart from that bad detection of uninitialized, the behaviour is *NOT
COMPLIANT with the documentation*.
If you look at the documentation page here:
http://gcc.gnu.org/onlinedocs/gcc/Warning-Options.html
It says:
-Wuninitialized
Warn if an automatic variable is used without first being initialized (...)
(...)
(...) They do not occur for *variables or elements declared volatile*.
As you see, in the code: 'bar' is an automatic variable, 'bar' has been
declared volatile (and as demonstrated in 1: it *IS* initialized!), and gcc
continues to spit out the warning.
CONCLUSION:
---
We do certainly have a bad detection of 'uninitialized'
Plus,
- either we have a
[Bug middle-end/54544] Option -Wuninitialized does not work as documented with volatile
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54544
Zakhar jimfr06 at gmail dot com changed:
What|Removed |Added
Status|UNCONFIRMED |RESOLVED
Resolution||INVALID
--- Comment #2 from Zakhar jimfr06 at gmail dot com 2012-09-10 21:33:15 UTC
---
Oh yes... my bad!
So we replace lines 03 to 09 by
/*03*/ extern int
/*04*/ foo( p )
/*05*/ int * volatile p;
/*06*/ {
/*07*/ volatile int foobar,barfoo;
/*08*/ volatile int flag=0;
/*09*/ int * volatile bar;
now it's volatile pointer and all works fine, no warning whatsoever.
Thank a lot, to have solved that.
I'll markd it as RESOLVED/INVALID then.
Best regards.
