comprehension vs `map'
Dear GHC team,
I would like to write
[rl {ruleMode = AlwaysApply} | rl - rules calc](I)
instead of map (\ rl - rl {ruleMode = AlwaysApply}) $ rules calc (II)
and instead of
let rs = rules calc in [rl {ruleMode = AlwaysApply} | rl - rs] (III).
But is this reliable in GHC that the compiler converts (I) into something
which is not not worse than III ?
What about other implementations?
Regards,
---
Mechveliani
mech...@botik.ru
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Re: [Haskell] Re: ANNOUNCE: GHC version 6.10.3
On 15/05/2009 05:52, Benjamin L.Russell wrote: What happened to the Windows installation section in the corresponding User's Guide? The User's Guide for GHC version 6.10.2 (see http://www.haskell.org/ghc/docs/6.10.2/html/users_guide/index.html) had section 2.2: Installing on Windows (see http://www.haskell.org/ghc/docs/6.10.2/html/users_guide/install-windows.html#winfaq), but this section seems to be missing in the corresponding document for version 6.10.3 (see http://www.haskell.org/ghc/docs/latest/html/users_guide/index.html). Not only that, but the entire chapter 2: Installing GHC seems to be missing. The Installing GHC section was mostly out-of-date and wrong, so I removed it. Some of the material, such as the section on the layout of the tree, has been updated and moved to the GHC Building Guide, here http://hackage.haskell.org/trac/ghc/wiki/Building We also have lots of information on the GHC web site about obtaining and installing GHC, so if we need anything else I think that would be the best place to put it. Cheers, Simon ___ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
RE: comprehension vs `map'
should generate the same code!
| -Original Message-
| From: glasgow-haskell-users-boun...@haskell.org [mailto:glasgow-haskell-users-
| boun...@haskell.org] On Behalf Of Serge D. Mechveliani
| Sent: 15 May 2009 09:00
| To: glasgow-haskell-users@haskell.org
| Subject: comprehension vs `map'
|
| Dear GHC team,
|
| I would like to write
| [rl {ruleMode = AlwaysApply} | rl - rules calc](I)
|
| instead of map (\ rl - rl {ruleMode = AlwaysApply}) $ rules calc (II)
| and instead of
| let rs = rules calc in [rl {ruleMode = AlwaysApply} | rl - rs] (III).
|
| But is this reliable in GHC that the compiler converts (I) into something
| which is not not worse than III ?
| What about other implementations?
|
| Regards,
|
| ---
| Mechveliani
| mech...@botik.ru
|
|
| ___
| Glasgow-haskell-users mailing list
| Glasgow-haskell-users@haskell.org
| http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
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Re: [Haskell] Re: ANNOUNCE: GHC version 6.10.3
On Fri, 15 May 2009 09:16:13 +0100, Simon Marlow marlo...@gmail.com wrote: On 15/05/2009 05:52, Benjamin L.Russell wrote: What happened to the Windows installation section in the corresponding User's Guide? The User's Guide for GHC version 6.10.2 (see http://www.haskell.org/ghc/docs/6.10.2/html/users_guide/index.html) had section 2.2: Installing on Windows (see http://www.haskell.org/ghc/docs/6.10.2/html/users_guide/install-windows.html#winfaq), but this section seems to be missing in the corresponding document for version 6.10.3 (see http://www.haskell.org/ghc/docs/latest/html/users_guide/index.html). Not only that, but the entire chapter 2: Installing GHC seems to be missing. The Installing GHC section was mostly out-of-date and wrong, so I removed it. Some of the material, such as the section on the layout of the tree, has been updated and moved to the GHC Building Guide, here http://hackage.haskell.org/trac/ghc/wiki/Building We also have lots of information on the GHC web site about obtaining and installing GHC, so if we need anything else I think that would be the best place to put it. Ah, I see. I just checked out that section, but although it includes information about building GHC, it doesn't seem to include information about simply installing GHC using a binary. This could become an issue if a new user unfamiliar with the installation suddenly decides to upgrade; it is unclear without that documentation whether it is necessary to uninstall the previous version first. More specifically, section 2.2.2 Moving GHC Around indicates that the entire GHC tree can be freely moved around just by copying the c:/ghc/ghc-version directory (although it is necessary to fix up the links in 'Start/All Programs/GHC/ghc-version' if this is done); however, this information is not evident from the information provided by the Windows installer. This information initially led me to conclude that uninstalling the previous version wasn't necessary to upgrade; without this information, a new user may not be able to determine whether uninstalling a previous version is necessary to upgrade, and could make upgrading more confusing. -- Benjamin L. Russell -- Benjamin L. Russell / DekuDekuplex at Yahoo dot com http://dekudekuplex.wordpress.com/ Translator/Interpreter / Mobile: +011 81 80-3603-6725 Furuike ya, kawazu tobikomu mizu no oto. -- Matsuo Basho^ ___ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
--out-implib when linking shared libraries
Hi, I've just built a Haskell dll on Windows. As part of the process it generated an 14Mb foo.dll, and a 40Mb foo.dll.a. Looking at the flags passed to ld I see --out-implib=foo.dll.a. What is the purpose of the .a file? What might it be needed for? Is it possible to suppress it? I could easily be building 100 of these things and 4Gb of disk for unused files is a little painful. Thanks Neil ___ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
Re: --out-implib when linking shared libraries
On Fri, 2009-05-15 at 15:31 +0100, Neil Mitchell wrote: Hi, I've just built a Haskell dll on Windows. As part of the process it generated an 14Mb foo.dll, and a 40Mb foo.dll.a. Looking at the flags passed to ld I see --out-implib=foo.dll.a. What is the purpose of the .a file? What might it be needed for? Is it possible to suppress it? I'm less familiar with the windows dlls as I've been working on the unix case first, but as I understand it, .lib files serve a dual purpose as static libs and as import libs for corresponding dlls. To add confusion the windows gnu tools use the .dll.a extension rather than .lib which the MS tools use. It looks like what you're getting is an import lib that also contains a full copy of all the code. I think it's possible to have minimal .lib files that do not contain any code and only refer to the corresponding dll. Further, I think recent gnu ld versions can link directly against dlls without using an import lib (though you may still need the import lib if you want to use MSVC to link to your dll). So my suggestion is remove it, if you're linking using gcc it should work. See also: http://www.redhat.com/docs/manuals/enterprise/RHEL-4-Manual/gnu-linker/win32.html Duncan ___ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
