[gmx-users] Re: Glutamate to Alanine Mutation

2013-04-10 Thread Sai Kumar Ramadugu
Prof Mobley,

Sorry to bother you, but do you have any suggestions for my previous post?

Thanks again,
Sai


On Sun, Mar 31, 2013 at 9:52 PM, Sai Kumar Ramadugu sramad...@gmail.comwrote:

 Dear Prof Mobley,

 I have some additional questions in understanding the free energy
 calculations.

 1) When doing a mutation from a larger aminoacid to a smaller one, one
 necessarily ends up with dummy atoms and atoms that have different mass. In
 my case when the glutamate is converted into a glycine or an alanine a
 carbon will become a hydrogen (change in mass) and the rest of the excess
 atoms will become dummies with the mass they had in Glu.

 The change in mass has an effect in the kinetic energy part of the
 Hamiltonian contribution to the free energy and this change is properly
 computed by Gromacs as dKe/dL. However it is clear from this procedure
 that because the dummies have mass, the mass of Ala or Gly will not be the
 correct and therefore dKe/dL would be quite meaningless. I read papers
 that suggest only integrating the potential energy component dV/dL. In
 fact for example, the Amber11 manual indicates that Amber mutations only
 change the potential but keep all masses the same as they were before the
 alchemical change.

 Clearly having dummies with no mass would fix this issue but it would be
 problematic because F=m*a and with m=0 for a given finite F, the
 acceleration on the dummies would be infinite.

 In Monte Carlo all of this is irrelevant because one only computes the
 potential contribution to the free energy difference but in MD the story is
 different. What is the customary approach to deal with this? Just use
 dV/dL and discard dKe/dL?



 2) The g_bar analysis appears to assume that the interpolation between
 states a and b is linear (g_bar issues a warning using the derivative data
 (dH/dlambda) to extrapolate delta H values. This will only work if the
 Hamiltonian is linear in lambda. ). However when using softcore potentials
 lambda also enters in the expression for r. It would appear that the
 interpolation is not really linear even though the LJ transformation also
 looks like
 Va *lambda+ (1- lambda)* Vb
 Nonetheless I see g_bar being used for such transformations. Could you
 shed light on this?

 3) Also it is common to use small lambda spacings (close to lambda=0 and
 lambda=1) but somewhat larger spacing between 0.1 and 0.9. How does g_bar
 handle this? Is the integration and error analysis done correctly even when
 the lambda spacing may be different at different lambda values?

 Thank you for your time.

 Regards
 Sai


 On Tue, Dec 4, 2012 at 5:27 PM, Sai Kumar Ramadugu sramad...@gmail.comwrote:

 Dear Prof Mobley,

 Thank you very much for your time.

 While I was waiting for your opinion on my topology files, I did several
 tests to see what happens.
 The tests I did are:

 1. Mutate only the amino acid (Glutamate -1 charge) and no mutation of K+
 ion, but have positional restraints on the ion.
 2. Mutate only the amino acid (Glutamate -1 charge) and no mutation of K+
 ion and no positional restraints or constraints on the system
 3. The actual simulation that caused me trouble, ie with position
 restraints, constraints and mutating the ion concurrently.

 Finally I decided to use the simulation data from no restraints or
 constraints and no mutation of K+ ion.
 With this approach now I am getting a positive deldelG value for the
 mutation going from Glutamate to Alanine.

 On Mon, Dec 3, 2012 at 4:07 PM, David Mobley dmob...@gmail.com wrote:

 Hi,

 I had a look at your topologies and don't see anything obviously wrong.
 You may however want to check that none of the bonded parameters involving
 the transformed atoms are being unexpectedly perturbed. (In our setups we
 typically repeat the A state parameters in the B state column for the
 bonds, angles, and torsions, as some GROMACS versions would otherwise
 assume these should be turned to zero).


 I read in the gromacs manual that with opls_aa force field, the state A
 parameters are repeated if you dont have any parameters for state B. I saw
 those warnings issued by grompp and in order to avoid any problems I did
 repeat the state A parameters in state B columns as you do it.



 Sorry I can't be more help. I'm pretty swamped on this end.




 I once again, I thank you very much for the time you took for my problem.

 Regards
 Sai





 On Tue, Oct 30, 2012 at 10:35 AM, Sai Kumar Ramadugu 
 sramad...@gmail.com wrote:

 Prof Mobley,

 I just want to add that in the topology file named Ala_charge_off.top,
 I am *turning off* the charges on atoms of alanine 40 residue. The
 total integral of dV/dl from 0 to 1 gave me a value of 274.73 kJ/mol
 and I took the negative of this as this should be same as *turning on*the 
 charges. To justify my approach I did add the partial charges on Ala40
 residue in a separate set of simulations (which finished today morning) and
 the total integral of dV/dl from 0 to 1 gave me

[gmx-users] Re: Glutamate to Alanine Mutation

2013-03-31 Thread Sai Kumar Ramadugu
Dear Prof Mobley,

I have some additional questions in understanding the free energy
calculations.

1) When doing a mutation from a larger aminoacid to a smaller one, one
necessarily ends up with dummy atoms and atoms that have different mass. In
my case when the glutamate is converted into a glycine or an alanine a
carbon will become a hydrogen (change in mass) and the rest of the excess
atoms will become dummies with the mass they had in Glu.

The change in mass has an effect in the kinetic energy part of the
Hamiltonian contribution to the free energy and this change is properly
computed by Gromacs as dKe/dL. However it is clear from this procedure
that because the dummies have mass, the mass of Ala or Gly will not be the
correct and therefore dKe/dL would be quite meaningless. I read papers
that suggest only integrating the potential energy component dV/dL. In
fact for example, the Amber11 manual indicates that Amber mutations only
change the potential but keep all masses the same as they were before the
alchemical change.

Clearly having dummies with no mass would fix this issue but it would be
problematic because F=m*a and with m=0 for a given finite F, the
acceleration on the dummies would be infinite.

In Monte Carlo all of this is irrelevant because one only computes the
potential contribution to the free energy difference but in MD the story is
different. What is the customary approach to deal with this? Just use
dV/dL and discard dKe/dL?



2) The g_bar analysis appears to assume that the interpolation between
states a and b is linear (g_bar issues a warning using the derivative data
(dH/dlambda) to extrapolate delta H values. This will only work if the
Hamiltonian is linear in lambda. ). However when using softcore potentials
lambda also enters in the expression for r. It would appear that the
interpolation is not really linear even though the LJ transformation also
looks like
Va *lambda+ (1- lambda)* Vb
Nonetheless I see g_bar being used for such transformations. Could you shed
light on this?

3) Also it is common to use small lambda spacings (close to lambda=0 and
lambda=1) but somewhat larger spacing between 0.1 and 0.9. How does g_bar
handle this? Is the integration and error analysis done correctly even when
the lambda spacing may be different at different lambda values?

Thank you for your time.

Regards
Sai


On Tue, Dec 4, 2012 at 5:27 PM, Sai Kumar Ramadugu sramad...@gmail.comwrote:

 Dear Prof Mobley,

 Thank you very much for your time.

 While I was waiting for your opinion on my topology files, I did several
 tests to see what happens.
 The tests I did are:

 1. Mutate only the amino acid (Glutamate -1 charge) and no mutation of K+
 ion, but have positional restraints on the ion.
 2. Mutate only the amino acid (Glutamate -1 charge) and no mutation of K+
 ion and no positional restraints or constraints on the system
 3. The actual simulation that caused me trouble, ie with position
 restraints, constraints and mutating the ion concurrently.

 Finally I decided to use the simulation data from no restraints or
 constraints and no mutation of K+ ion.
 With this approach now I am getting a positive deldelG value for the
 mutation going from Glutamate to Alanine.

 On Mon, Dec 3, 2012 at 4:07 PM, David Mobley dmob...@gmail.com wrote:

 Hi,

 I had a look at your topologies and don't see anything obviously wrong.
 You may however want to check that none of the bonded parameters involving
 the transformed atoms are being unexpectedly perturbed. (In our setups we
 typically repeat the A state parameters in the B state column for the
 bonds, angles, and torsions, as some GROMACS versions would otherwise
 assume these should be turned to zero).


 I read in the gromacs manual that with opls_aa force field, the state A
 parameters are repeated if you dont have any parameters for state B. I saw
 those warnings issued by grompp and in order to avoid any problems I did
 repeat the state A parameters in state B columns as you do it.



 Sorry I can't be more help. I'm pretty swamped on this end.




 I once again, I thank you very much for the time you took for my problem.

 Regards
 Sai





 On Tue, Oct 30, 2012 at 10:35 AM, Sai Kumar Ramadugu sramad...@gmail.com
  wrote:

 Prof Mobley,

 I just want to add that in the topology file named Ala_charge_off.top, I
 am *turning off* the charges on atoms of alanine 40 residue. The total
 integral of dV/dl from 0 to 1 gave me a value of 274.73 kJ/mol and I
 took the negative of this as this should be same as *turning on* the
 charges. To justify my approach I did add the partial charges on Ala40
 residue in a separate set of simulations (which finished today morning) and
 the total integral of dV/dl from 0 to 1 gave me a value of -274.705
 kJ/mol.


 Regards
 Sai


 On Sat, Oct 27, 2012 at 11:00 AM, Sai Kumar Ramadugu 
 sramad...@gmail.com wrote:

 Dear Prof Mobley,

 I have attached the topologies for all three steps in presence of
 ligand. The case

[gmx-users] DelG of LJ Transformation Negative Glu---Ala Mutation

2012-09-18 Thread Sai Kumar Ramadugu
Hi Gmx Community,
I am doing Glutamate to Alanine mutation in presence and absence of a
ligand.
The Coulomb transformation is yielding the following results:
Glu---Ala + ligand = 790.109 kJ/mol
Glu---Ala + no ligand = 787.33 kJ/mol

During the LJ transformation

Glu---Ala + ligand = - 24.87 kJ/mol
Glu---Ala + no ligand = - 12.4403


The reason I am asking this is because in experiments, the Glu---Ala
mutation yields a positive deldelG but in TI approach, I am getting a
negative deldelG. The major contribution is from the LJ transformation.
With the above values, the deldelG from TI approach is -9.65 kJ/mol

Is it possible to have a negative deldelG for a mutation like Glutamate
(which is charged) to Alanine (which is neutral)?

If it is system dependent and you need more information than what provided
in this email, I will add in happily. But I am just curious to know your
opinions.

Regards
Sai
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Re: [gmx-users] FEP

2012-06-14 Thread Sai Kumar Ramadugu
Hi Fabian,
I am trying something similar with Glutamate to Alanine mutation.
Does your dummy atoms i.e., DUM1 have a value of 0.0 for sigma and epsilon
during all three steps or only in step 2?

Thanks for the time,

Sai

On Thu, Apr 26, 2012 at 10:43 AM, Fabian Casteblanco 
fabian.castebla...@gmail.com wrote:

 Hello all,

 This is in reply to Michael shirts a while ago on a FEP of a R-CH3 to
 an R-H group.  Below is the orignal email.  I recently tested out
 mutating a CH3-CH3-(3dummy atoms) molecule on both sides in order to
 test out that a peturbation would give you a total of 0.  forcefield
 used was CGenFF

 So for procedure was that I turned the CH3 group on the left to an H
 with 3 dummy atoms and I turned an H and 3 dummy atoms on the right to
 a CH3 group, essentially mutating the molecule to another version of
 itself (should give you a total dG of 0 if it works).

 STEP 1. (uncharging everything except the -CH2 group inbetween both
 sides     CH3-CH2-HD3)  *D are dummy atoms
  [ atoms ]
 ;  nr  type  resnr  residatom  cgnr  chargemasstotal_charge
1CG331 1   SIM   C1 1-0.27
12.0110 CG331   0.00 12.0110
2 HGA3 1   SIM  H11 2 0.09
1.00800 HGA30.00 1.00800
3 HGA3 1   SIM  H12 3 0.09
1.00800 HGA30.00 1.00800
4 HGA3 1   SIM  H13 4 0.09
1.00800 HGA30.00 1.00800
5CG331 1   SIM   C2 5-0.27  12.0110
 CG331
 -0.1812.0110
6 HGA3   1   SIM  H21 6   0.09
7 HGA3   1   SIM  H22 7   0.09
8 HGA3   1   SIM  H23 8   0.09  1.00800
 HGA30.00 1.00800
9  DUM   1   SIM  H31 9   0.00  1.00800
   10  DUM   1   SIM  H3210   0.00  1.00800
   11  DUM   1   SIM  H3311   0.00  1.00800

 STEP 2.  (mutation of groups.   CH3-CH2-HD3 becomes D3H-CH2-CH3)
 [ atoms ]
 ;  nr  type  resnr  residatom  cgnr  chargemasstotal_charge
1CG331  1   SIM   C1  1   0.00
12.0110 HGA30.00   1.00800
2 HGA3  1   SIM  H11  2   0.00
1.00800 DUM 0.00   1.00800
3 HGA3  1   SIM  H12  3   0.00
1.00800 DUM 0.00   1.00800
4 HGA3  1   SIM  H13  4   0.00  1.00800
 DUM
   0.001.00800
5CG331  1   SIM   C2  5  -0.18
6 HGA31   SIM  H21 6  0.09
7 HGA31   SIM  H22 7  0.09
8 HGA31   SIM  H23 8  0.00
1.00800 CG331   0.00   12.0110
9  DUM1   SIM  H31 9  0.00
  1.00800 HGA30.00
  1.00800
   10  DUM1   SIM  H3210  0.00  1.00800
 HGA30.00
  1.00800
   11  DUM1   SIM  H3311  0.00
1.00800 HGA30.00   1.00800

 STEP3.  (opposite of step1)
 [ atoms ]
 ;  nr  type  resnr  residatom  cgnr  chargemasstotal_charge
1 HGA3   1   SIM C1 1 0.00  12.0110
 HGA3
  0.091.00800
2  DUM   1   SIMH11 2 0.00
 1.00800 DUM0.00   1.00800
3  DUM   1   SIMH12 3 0.00
 1.00800 DUM0.00   1.00800
4  DUM   1   SIMH13 4 0.00
 1.00800 DUM0.00   1.00800
5CG331   1   SIM C2 5-0.18
  12.0110 CG331
  -0.27   12.0110
6 HGA3   1   SIM  H21 6   0.09
7 HGA3   1   SIM  H22 7   0.09
8CG331   1   SIM  H23 8   0.00
 1.00800 CG331 -0.27   12.0110
9 HGA3   1   SIM  H31 9   0.00
 1.00800 HGA30.09  1.00800
   10 HGA3   1   SIM  H3210   0.00
 1.00800 HGA30.09  1.00800
   11 HGA3   1   SIM  H3311   0.00
 1.00800 HGA30.09  1.00800

 So in the end, the procedure worked using the g_bar method.  I took 20
 simulations for steps 1 and 3 and 50 simulations for step 2.  Here are
 the results:

 Step1: -37.62 +/- 0
 Step2:  -0.12 +/- 0.24
 Step3:  37.68 +/- 0.13
 TOTAL ~ -0.06 kJ/mol  which is expected

 My question is that I did something similar for a larger molecule (65
 atoms) and someone said before that step 1 and 3 should be very small.
  I'm getting values in the near -20 kJ/mol for step 1 and 3.  I feel
 it should be straightforward since I'm simply uncharging a CH3 group
 and I don't get why I'm getting such a large number.  If it is suppose
 to be very small, 

[gmx-users] Re: Thermodynamic Integration Glu - Ala Mutation

2012-06-07 Thread Sai Kumar Ramadugu
Any suggestions on this topic?
Thanks again for your time.


Dear Gromacs Users,
 I am trying to find out the relative free energy difference of binding of
 a ligand with wild type protein (Glutamate residue) and mutant protein
 (Alanine residue).

 For charge part of the mutation, this is what I'm planning to do:

 ; residue  40 GLU rtp GLU  q -1.0
552   opls_238  40GLU  N  191   -0.514.0067
  opls_238-0.5  14.0067 ; qtot 0.5
553   opls_241  40GLU  H  1910.3  1.008
opls_241 0.3 1.008 ; qtot 0.8
554  opls_224B 40GLU CA191   0.14 12.011
  opls_224B0.14   12.011 ; qtot 0.94
555   opls_140  40GLU HA191   0.06  1.008
 opls_140 0.061.008 ; qtot 1
556   opls_136  40GLU CB192  -0.12 12.011
  opls_135 -0.18   12.011 ; qtot 0.88
557   opls_140  40GLUHB1192   0.06  1.008
  opls_140  0.061.008 ; qtot 0.94
558   opls_140  40GLUHB2192   0.06  1.008
 opls_140  0.061.008 ; qtot 1
559   opls_274  40GLU CG193  -0.22 12.011
 opls_140 0.061.008 ; qtot 0.78
560   opls_140  40GLUHG1193   0.06  1.008
 DUM_1400.0  1.008 ; qtot 0.84
561   opls_140  40GLUHG2193   0.06  1.008
 DUM_1400.0  1.008 ; qtot 0.9
562   opls_271  40GLU CD 1940.7 12.011
 DUM_2710.0 12.011 ; qtot 1.6
563   opls_272  40GLUOE1194   -0.815.9994
 DUM_272   0.0 15.9994 ; qtot 0.8
564   opls_272  40GLUOE2194   -0.815.9994
  DUM_2720.0 15.9994 ; qtot 0
565   opls_235  40GLU  C  1950.5 12.011
 opls_235 0.5 12.011 ; qtot 0.5
566   opls_236  40GLU  O  195   -0.515.9994
  opls_236-0.515.9994 ; qtot 0


 I added the DUM_140, DUM_271,DUM_272 atomtypes in ffnonbonded.itp.
 Further I added the bondtypes, angletypes and dihedraltypes in
 ffbonded.itp for state B.

 In order to maintain the electroneutrality, I am mutating a K+ ion to
 dummy as well. For the K+ going to dummy, I added a DUM_408 atomtype as
 well.

 *The questions I have are as follows:*
 *During the charge mutation will my dummy atoms have sigma and epsilon as
 0.0? Since Ala residue does not have Cgamma, Cdelta and the oxygen as well
 as the Hgamma, all the dummy atoms should have sigma and epsilon as zero.
 Am I correct for this assumption?*
 *Further as I am mutating one ion, I dont want the mutating ion to come
 close to other ions (I have three K+ ions as my protein has -3 charge) as
 well as the protein atoms. Hence I'm having position restraints on the
 three ions. *
 *For the ion that is mutating to dummy, should I have have position
 restraints on dummy atom as well for the B state topology?*

 The section of topology for the K+ going to dummy is as follows:

 [ moleculetype ]
 ; Namenrexcl
 KM   1

 [ atoms ]
 ;   nr   type  resnr residue  atom   cgnr charge   mass  typeB
chargeB  massB
  1  opls-408  1   KMKM1  139.0983
 DUM_408   0.0 39.0983

 #ifdef POSRES_ION
 ; Position restraint for each Potassium ion
 [ position_restraints ]
 ;  i funct   fcxfcyfcz
11   1000   1000   1000   0   0   0
 #endif

 Here I defined the KM as K+ that will go to dummy and other two K+ ions
 are represented as regular K+ ions.
 I'm pasting the regular K+ ion part of the topology below.

 [ moleculetype ]
 ; Namenrexcl
 K   1

 [ atoms ]
 ;   nr   type  resnr residue  atom   cgnr charge   mass  typeB
chargeB  massB
  1  opls_408  1   K   K1  139.0983

 #ifdef POSRES_ION
 ; Position restraint for each Potassium ion
 [ position_restraints ]
 ;  i funct   fcxfcyfcz
11   1000   1000   1000
 #endif

 Let me know if you need more information.

 Thanks for your time,

 Regards
 Sai


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[gmx-users] Thermodynamic Integration Glu - Ala Mutation

2012-05-30 Thread Sai Kumar Ramadugu
Dear Gromacs Users,
I am trying to find out the relative free energy difference of binding of a
ligand with wild type protein (Glutamate residue) and mutant protein
(Alanine residue).

For charge part of the mutation, this is what I'm planning to do:

; residue  40 GLU rtp GLU  q -1.0
   552   opls_238  40GLU  N  191   -0.514.0067
 opls_238-0.5  14.0067 ; qtot 0.5
   553   opls_241  40GLU  H  1910.3  1.008
   opls_241 0.3 1.008 ; qtot 0.8
   554  opls_224B 40GLU CA191   0.14 12.011
 opls_224B0.14   12.011 ; qtot 0.94
   555   opls_140  40GLU HA191   0.06  1.008
opls_140 0.061.008 ; qtot 1
   556   opls_136  40GLU CB192  -0.12 12.011
 opls_135 -0.18   12.011 ; qtot 0.88
   557   opls_140  40GLUHB1192   0.06  1.008
 opls_140  0.061.008 ; qtot 0.94
   558   opls_140  40GLUHB2192   0.06  1.008
opls_140  0.061.008 ; qtot 1
   559   opls_274  40GLU CG193  -0.22 12.011
opls_140 0.061.008 ; qtot 0.78
   560   opls_140  40GLUHG1193   0.06  1.008
DUM_1400.0  1.008 ; qtot 0.84
   561   opls_140  40GLUHG2193   0.06  1.008
DUM_1400.0  1.008 ; qtot 0.9
   562   opls_271  40GLU CD 1940.7 12.011
DUM_2710.0 12.011 ; qtot 1.6
   563   opls_272  40GLUOE1194   -0.815.9994
DUM_272   0.0 15.9994 ; qtot 0.8
   564   opls_272  40GLUOE2194   -0.815.9994
 DUM_2720.0 15.9994 ; qtot 0
   565   opls_235  40GLU  C  1950.5 12.011
opls_235 0.5 12.011 ; qtot 0.5
   566   opls_236  40GLU  O  195   -0.515.9994
 opls_236-0.515.9994 ; qtot 0


I added the DUM_140, DUM_271,DUM_272 atomtypes in ffnonbonded.itp.
Further I added the bondtypes, angletypes and dihedraltypes in ffbonded.itp
for state B.

In order to maintain the electroneutrality, I am mutating a K+ ion to dummy
as well. For the K+ going to dummy, I added a DUM_408 atomtype as well.

*The questions I have are as follows:*
*During the charge mutation will my dummy atoms have sigma and epsilon as
0.0? Since Ala residue does not have Cgamma, Cdelta and the oxygen as well
as the Hgamma, all the dummy atoms should have sigma and epsilon as zero.
Am I correct for this assumption?*
*Further as I am mutating one ion, I dont want the mutating ion to come
close to other ions (I have three K+ ions as my protein has -3 charge) as
well as the protein atoms. Hence I'm having position restraints on the
three ions. *
*For the ion that is mutating to dummy, should I have have position
restraints on dummy atom as well for the B state topology?*

The section of topology for the K+ going to dummy is as follows:

[ moleculetype ]
; Namenrexcl
KM   1

[ atoms ]
;   nr   type  resnr residue  atom   cgnr charge   mass  typeB
   chargeB  massB
 1  opls-408  1   KMKM1  139.0983
DUM_408   0.0 39.0983

#ifdef POSRES_ION
; Position restraint for each Potassium ion
[ position_restraints ]
;  i funct   fcxfcyfcz
   11   1000   1000   1000   0   0   0
#endif

Here I defined the KM as K+ that will go to dummy and other two K+ ions are
represented as regular K+ ions.
I'm pasting the regular K+ ion part of the topology below.

[ moleculetype ]
; Namenrexcl
K   1

[ atoms ]
;   nr   type  resnr residue  atom   cgnr charge   mass  typeB
   chargeB  massB
 1  opls_408  1   K   K1  139.0983

#ifdef POSRES_ION
; Position restraint for each Potassium ion
[ position_restraints ]
;  i funct   fcxfcyfcz
   11   1000   1000   1000
#endif

Let me know if you need more information.

Thanks for your time,

Regards
Sai
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[gmx-users] Glutamate Chi1 Dihedral Not Symmetrical?

2012-05-05 Thread Sai Kumar Ramadugu
Dear Gromacs Users,

I am trying to plot the Ryckaert-Bellemans energy for rotating the chi1
dihedral of glutamate in protein.
I tried to change the ch1 dihedral from 0-360 degrees at increments of 1
degree and saved the pdbs. Then I used the pdb's to obtain the
corresponding gro files and a single topology file.
I used opls force field and no water and a 0 step minimization.

*My em.mdp file:*
*
*
cpp  = /usr/bin/cpp
define   = -DFLEXIBLE
integrator   = steep
nsteps   = 0
constraints  = none
emtol= 1000.0
emstep   = 0.01
nstcomm  = 1
ns_type  = grid
nstlist  = 1
rlist= 0
rcoulomb = 0
rvdw = 0
Tcoupl   = no
Pcoupl   = no
gen_vel  = no
nstxout  = 1
pbc  = no
;energy groups
energygrps = Protein

After the minimization, when I plot the dihedral energy vs dihedral angle,
I do not get a symmetrical curve.
After careful observation of the gro files that I obtained using pdb2gmx,
the 0-180 values are not exactly same as -180-0 degrees or 180-360 degrees.
Is it because of the slightly different values of the dihedral 0-180 and
180-360 that I'm not getting a symmetrical curve or am I doing something
wrong?

I have attached the dihedral energy vs dihedral angle curve.


Regards
Sai
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[gmx-users] Free Energy calcualtions

2012-04-25 Thread Sai Kumar Ramadugu
Hi Gromacs Users,
I want to mutate a glutamate in my protein to alanine in presence of a
ligand.
With glutamate, the protein charge is -3. To neutralize the system, I added
3K+ ions.
Now when I mutate GLU to ALA, the charge in state_B will be +1 (protein -2
+ 3K+).

Right now I'm in the charge part of the mutation. Once this is successful,
I will include the VDW mutation too.

I have added the mutation details of Glu to Ala residue in the topology in
[atoms], [bonds], [angles] and [dihedrals] sections.

After I run the grompp command, the result says that my State_B topology
has +1 charge since I am not including mutation of one K+ ion to neutral K+
ion.
How can I mutate 1 particular K+ to K atom and subsequently to a dummy
atom? Since I'm using OPLS force field, we have ions.itp to be used in the
topology file, changing one K+ is making it troublesome for me to implement
in the topology file.
Any suggestions are helpful.

Thanks for your time.

Regards
Sai
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Re: [gmx-users] Half double pair list method in GROMACS [update]

2011-12-02 Thread Sai Kumar Ramadugu
Hi Stephane  Chris,
I followed all the threads posted by you two.
I have a protein using ff99SB and GLYCAM for sugars. I have a disaccharide
bound to protein. In xleap of AMBERTOOLS, I use the GLYCAM and ff99SB to
generate the topology and coordinate files. I did the tests as Chris'
original posts and by Stephane.
The 1-4 interaction terms match for sugar alone and protein alone with HEDP
method.
When I generate topology and coordinate files with xleap of AMBER, there
are three atom types that are common to protein and sugar. The atom types
for my case are H1, OH and HO.
Since for protein pairtypes using ff99SB, the epsilon has to be divided by
10 and pairs section be replicated five times and for sugar the epsilon in
the pairtypes be divided by six and replicated six times, I am a little
concerned about the three atomtypes that are common.
So what I did was to change the atomtypes of sugar as H1S, OHS HOS for
sugar and H1, OH and HO for protein and I made the changes accordingly in
the pairtypes section for protein and sugar.
Is this a valid approach?
Any suggestion will be helpful.

To make things little more clear:
H1H10.  0.  A   2.47135e-01  6.56888e-02
;originally obtained using amb2gmx.pl
H1S  H1S  0.  0.  A   2.47135e-01  6.56888e-02 ;Glycam
Hydrogen of Sugar ( I changed this so that the common atom types be
separated)

In the ffnonbonded_complex_mod.itp:
;;using combination rule of 2
[ pairtypes ]
;;for protein
H1  H1  1   0.247135000 0.006568880 ;the epsilon is divided
by 10

;;for sugar

 H1S   H1S 1   0.24713500  0.010948133 ;the epsilon is divided
by 6


Thanks for your time,


Regards
Sai


On Mon, Sep 5, 2011 at 11:33 AM, ABEL Stephane 175950
stephane.a...@cea.frwrote:

 Dear All,

 Below a little update and results about the application of half double
 pair list method to scale properly the Coulombic 1-4 interactions in case
 of a system where the AMBER99SB (fudgeLJ=0.5 and fudgeLJ=0.8333) and
 GLYCAM06 (fudgeLJ=1.0 and fudgeLJ=1.0) force fields are combined.

 I have followed the 4 steps described in [1] and used the following values
 in my forcefield.itp file

 [ defaults ]
 ; nbfunccomb-rule   gen-pairs   fudgeLJ fudgeQQ
 1   2   yes 1.0 0.16
 #include ffnonbonded_mod.itp
 ;#include ffnonbonded.itp
 #include ffbonded.itp

 I used two different topology files for the glycolipid (bDM) and the
 peptide. One with (*_mod.itp) with pair list parameters duplicated 6 times
 (bDM) and 5 times (peptide) and with single pair list (*_no_mod.itp) as
 decribed in [1].

 TESTING:

 Three 3 different systems were examined:

 A. A first system containing 1 glycolipid (bDM)  in water cubic box
 B. A second system with 1 peptide in TIP3P water
 C. And a third system with 1 peptide and 1 glycolipid in water cubic box

 To obtain the glycolipid and peptide energy pairs, I did one step of MD in
 NVT ensemble with the *.mdp file given in [2] with different energygrps and
 tc_grps.
 For 1. energygrps and tc_grps = bDM SOL
 For 2. energygrps and tc_grps = Protein SOL
 For 3. energygrps and = Protein bDM SOL

 bDM/water system

 Test_A1

 ## Control with GLYCAM force field fudgeLJ fudgeQQ parameters and  the
 *_no_mod.itp file :
 ##; nbfunccomb-rule   gen-pairs   fudgeLJ fudgeQQ
 ##  1   2   yes 1.0 1.0
 Epot (kJ/mol)Coul-SR  LJ-SRCoul-14  LJ-14
 bDM-bDM   -4.00855e+02   -3.71401e+012.03406e+032.79234e+02

 Test_A2

  with the topology *_mod.itp file and the directive
 ##; nbfunccomb-rule   gen-pairs   fudgeLJ fudgeQQ
 ##  1   2   yes 1.0
 0.16
 Epot (kJ/mol)Coul-SR  LJ-SRCoul-14  LJ-14
 bDM-bDM   -4.00855e+02   -3.71401e+012.03406e+032.79234e+02

 Test_A3

  with the topology *_no_mod.itp file and the directive
 ##; nbfunccomb-rule   gen-pairs   fudgeLJ fudgeQQ
 ##  1   2   yes 1.0
 0.16
 Epot (kJ/mol)Coul-SR  LJ-SRCoul-14  LJ-14
 bDM-bDM   -4.00855e+02   -3.71401e+013.39010e+022.79234e+02

 Coul-14 energy for bDM-bDM in Test_A1 = Coul-14 energy in Test_A2 -- OK !
 Coul-14 energy for bDM-bDM Test_A3 is 6 smaller than Coul-14 energy in
 Test_A1 and Test 2 --- OK !

 peptide/water system

 Test_B1

  Control with AMBER force field fudgeLJ fudgeQQ parameters, the
 *_no_mod.itp file
 ##; nbfunccomb-rule   gen-pairs   fudgeLJ fudgeQQ
 ##  1   2   yes 0.5  0.8333
 Epot (kJ/mol)Coul-SR  LJ-SRCoul-14  LJ-14
 Protein-Protein   -1.49026e+03   -4.12114e+023.80551e+036.55321e+02

 Test_B2

  Control with the peptide *_no_mod.itp file and the directive
 ##; nbfunc

Re: [gmx-users] pulling force vs free energy

2011-11-16 Thread Sai Kumar Ramadugu
I agree with Justin. I have tried myself several SMD simulations for ligand
binding studies. I tried 500 simulations and not sure if they are enough.
Further, the path dependence is very important part.
For different paths that you can try, look at McCammon group's paper in
JACS 128, 3019-3026. There are several other papers too, but this discusses
about various methods that you can try to get the pmf using Jarzynski

On Wed, Nov 16, 2011 at 9:25 AM, Justin A. Lemkul jalem...@vt.edu wrote:



 Vijayaraj wrote:



Message: 4
Date: Wed, 16 Nov 2011 09:34:02 -0500
From: Justin A. Lemkul jalem...@vt.edu mailto:jalem...@vt.edu

Subject: Re: [gmx-users] pulling force vs free energy
To: Discussion list for GROMACS users gmx-users@gromacs.org
mailto:gmx-users@gromacs.org**
Message-ID: 4ec3c9da.7040...@vt.edu 
 mailto:4EC3C9DA.7040400@vt.**edu4ec3c9da.7040...@vt.edu
 

Content-Type: text/plain; charset=ISO-8859-1; format=flowed



Vijayaraj wrote:
  Hi,
 
  What is the relation between pulling force and free energy of
binding.
  can we relate the maximum pulling force with the free energy. for
  example, 2 systems has the maximum pulling force and free energy as
  below from umbrella sampling and g_wham analysis,
 
max. forcefree energy
  system 1  147042
  system 2  164732
 
  system 2 has higher pulling force than system 1 and the free energy
  result is different from this trend.
 

How did you obtain the maximum force, just a single SMD trajectory?
 If so, I
wouldn't put a lot of faith in it necessarily.  Umbrella sampling is
a more
robust method than a single pull.  You can use large numbers of pulling
simulations and apply Jarzynski's equation to calculate free energy,
but there
are distinct caveats (although I suppose there are caveats with any
method).

-Justin


 yes. the max force is obtained from single SMD trajectory. So in this
 case we dont have to worry about the correction between max. force and free
 energy. I found one of my free energy result is 2 times larger than the
 previous result, where they have applied Jarzynski's equation.


 SMD is path-dependent, while a true DeltaG is a path-independent quantity.
 Hence why you cannot easily connect the two.  Convergence in sampling and
 limitations in each technique make it sometimes hard to compare the results
 that others have obtained with other methods.  Proper data collection for
 Jarzynski's method requires exhaustive sampling, which is often hard to
 obtain (not a blind criticism of others' work, just a fact).

 -Justin

 --
 ==**==

 Justin A. Lemkul
 Ph.D. Candidate
 ICTAS Doctoral Scholar
 MILES-IGERT Trainee
 Department of Biochemistry
 Virginia Tech
 Blacksburg, VA
 jalemkul[at]vt.edu | (540) 231-9080
 http://www.bevanlab.biochem.**vt.edu/Pages/Personal/justinhttp://www.bevanlab.biochem.vt.edu/Pages/Personal/justin

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Re: [gmx-users] How to calculate work

2011-11-04 Thread Sai Kumar Ramadugu
Hi Sanku,
I was using the pullf.xvg and multiplying it with pulling rate and time.
f*v*dt = W
and getting the total work for each SMD simulation.

I'm not sure if this is the best/correct way to do it. But from original
Jarzynski's article (PRL (2007) 78(14), 2690-2693) this is what I deduced.
I asked this question but I think very few users of Gromacs do Jarzynski
Equality (JE) to get free energy differences.

If anyone can comment on this, it will be useful for the community.

PS: If you use AMBER, it gives the work profile as the output. You can use
the total work which is printed at the last line of the output and get the
exponential average of beta*W.

PPS: May be you are aware of this issue, but the JE suffers from the fact
that you do the exponential average and the smaller work values determine
everything.


Regards
Sai



On Fri, Nov 4, 2011 at 7:46 PM, Sanku M msank...@yahoo.com wrote:

 Hi,
 I am performing steered MD simulation using gromacs.
  I was wondering how one can get the time profile of the irreversible work
 from the gromacs pull-code out put . From constant pulling-rate SMD, we get
 time profile of force pullf.xvg and pullx.xvg. I wonder does multiplying
 the the value from pullx.xvg and value from pullf.xvg will provide the work
 . Or, will it be force ( obtained from pullf.xvg) multiplied by pulling
 rate multiplied by time ?
 Sanku

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[gmx-users] Jarzynski and PMF

2011-08-02 Thread Sai Kumar Ramadugu
Dear All,

I have tried to calculate the free energy of binding using Jarzynski
equality. I employed the following procedure.

--I did force pulling simulations along Z-direction as exemplified in
Justin's umbrella sampling simulations. I did 50, 250 and 500 pulling
simulations to test the convergence and also two different pulling rates
(2nm/ns and 4nm/ns), two different force
  constants (2000 kJ mol^-1 nm^-2 and 4000 kJ mol^-1 nm^-2).

--From the pulling simulation, I get the pullf.xvg and pullx.xvg.

--I use the force from pullf.xvg and calculate the work at each time step by
multiplying with v*dt and calculate average work for each simulation.

--Once I have the work for each simulation, I calculate the exp(-beta*W) for
each simulation and calculate the average of exp(-beta*W).

--Once I have the average of exp(-beta*W), I calculate the free energy delF
= -kB*T ln(exp(-beta*W)).

The question I have is whether my approach for calculating the work is
correct/feasible or not.
Does the pullf.xvg written by mdrun during a pulling simulation contain the
pull force only?
Do I need to add any corrections?
I'm doing NPT simulations, so can I add the pdV correction as suggested in
one of the paper (Macromolecules, 2008, 41 (6), pp 2283–2289) by Berk Hess?
Or did I understand the paper incorrectly?

For a publication level of work, I'll use NVT ensemble. But for now my
biggest concern is calculation of work.

Any suggestions will be greatly helpful.

Thanks for you time,

Sai Ramadugu
Dept of Chemistry,
University of Iowa.
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[gmx-users] PMF for Carbohydrate-Protein

2011-03-17 Thread Sai Kumar Ramadugu
Dear All,
I'm running set of umbrella sampling simulations to get the PMF of a
disaccharide binding to a protein.
I followed the tutorial provided by Justin and changed the values of
necessary parameters according to my system.
The mdp file for umbrella sampling simulations is as follows:
---
; Pull code
pull= umbrella
pull_geometry   = distance  ; can't get PMF with direction
pull_dim= N N Y
pull_start   = yes
pull_ngroups= 1
pull_group0   = active_site
pull_pbcatom0   = 575
pull_group1   = new
pull_pbcatom1   = 1500
pull_init1 = 0
pull_rate1   = 0.0
pull_k1   = 750   ; kJ mol^-1 nm^-2
pull_nstxout= 1000  ; every 2 ps
pull_nstfout = 1000  ; every 2 ps


Active site in the pull_group0 being the residues in the binding site and
new in the pull_group1 being the disaccharide.
Initially I did an SMD run where I separated the disaccharide from the
binding upto 1.5nm in distance.

When I started running the umbrella sampling simulations, I used the
conformations with approximately 0.1nm difference starting from an
initial separation of 0.3nm between the binding site residues and
disaccharide.
My question is: when I run g_wham and get the profile, the pmf reaches a
plateau, but its not completely horizontal. It drops down a little. Is it
acceptable to have the pmf reach a plateau but not completely horizontal?
In the histogram, the first two windows have good overlap and are narrow
distributions where as the later windows are spread out.
I have tried to decrease the distance from 0.1 nm to 0.05 nm and still the
sampling around 0.5-0.75 of Xi region does not sample well.
Is there anything that you could suggest?

I have uploaded the plots of profile and histograms.

PMF Plot link: http://img801.imageshack.us/i/pmf.png/
Histogram link: http://img217.imageshack.us/i/histoy.png/


Thanks for your time

Sai Ramadugu
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Re: [gmx-users] soft-core

2010-06-14 Thread Sai Kumar Ramadugu
Hi
Well the tutorial in the following website has mentioned about the
importance of sc_alpha and sc-power. Also the manual gives you more
information.
http://www.dillgroup.ucsf.edu/group/wiki/index.php/Free_Energy:_Tutorial.

Regards
Sai

On Sun, Jun 13, 2010 at 6:56 PM, Justin A. Lemkul jalem...@vt.edu wrote:



 fancy2012 wrote:

 Dear GMX users,
 when I generate the input file of MD simulation using grompp, I get this
 error: ERROR: The soft-core power is 0 and can only be 1 or 2. I don't know
 how to figure it out?  Could somebody give me a hand? Thanks very much in
 advance!


 You haven't specified a value for sc-power, so the default of zero is
 taken. Manual section 7.3.23.

 -Justin

  Here is the mdp file:
 cpp =  /lib/cpp
 constraints =  all-bonds
 integrator  =  md
 tinit   =  0.0
 dt  =  0.002   nsteps  =  25000 nstcomm
   =  1
 nstxout =  1
 nstvout =  0
 nstfout  =  0
 nstlog  =  500
 nstenergy   =  250
 nstxtcout   =  1000
 xtc_precision   =  1000
 xtc_grps=  Protein
 nstlist =  5
 energygrps  =  Protein SOL
 ns_type =  grid
 rlist   =  0.9
 coulombtype =  Reaction-Field
 epsilon_r=  78.0
 rcoulomb=  1.4
 rvdw=  1.4
 Tcoupl  =  Berendsen
 tc-grps =  Protein SOL
 ref_t   =  300 300
 tau_t   =  0.1 0.1
 Pcoupl  =  Berendsen
 tau_p   =  1.0
 compressibility =  4.6e-5
 ref_p;=  1.0

 free_energy =  yes
 init_lambda =  0.00
 sc-alpha=  1.51
 All the best,
 fancy



 --
 

 Justin A. Lemkul
 Ph.D. Candidate
 ICTAS Doctoral Scholar
 MILES-IGERT Trainee
 Department of Biochemistry
 Virginia Tech
 Blacksburg, VA
 jalemkul[at]vt.edu | (540) 231-9080
 http://www.bevanlab.biochem.vt.edu/Pages/Personal/justin

 
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Re: [gmx-users] tutorial of free energy calculations

2010-06-08 Thread Sai Kumar Ramadugu
HI
Its not working for me either.
But for free energy tutorials using GROMACS, I think the one written by Prof
Mobley is like Bible.
The link is as follows:
http://www.dillgroup.ucsf.edu/group/wiki/index.php/Free_Energy:_Tutorial

But the one written by Prof Alan Mark (who is now in Queensland Univ,
Australia) is also very useful.
Try searching for it.

Regards
Sai

2010/6/7 fancy2012 fancy2...@yeah.net

 Dear GMX users,
 I don't know why I can't open the tutorial of free energy calculations on
 this website http://www.gromacs.org/Documentation/Tutorials. Can you open
 it? Thanks very much!
 All the best,
 fancy

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Re: [gmx-users] Thr - Met in TI calculation

2010-06-08 Thread Sai Kumar Ramadugu
Hi Fancy,
   The following link shows the change from p-cresol to Toluene. So follow
the steps in the same by converting threonine to methionine.

http://compbio.chemistry.uq.edu.au/education/Free-Energy_Course/0.introduction.html

Regards
Sai

2010/6/5 fancy2012 fancy2...@yeah.net

 Dear GMX users,

 I want to calculate the relative binding free energy between a small
 molecule binding to a protein of Wild Type and Thr - Met using TI, so how
 should I prepare the  topology files of the protein using for TI
 calculation? Any suggestions will be highly appreciated?

 All the best,
 fancy

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Re: [gmx-users] PBC

2010-06-08 Thread Sai Kumar Ramadugu
Hi Morteza,
  I had this problem when I was running a trimeric protein attached to an
oligosaccharide.

*I have used the following command:*

* *

*trjconv  -s .tpr -f .xtc -o   -boxcenter tric -pbc mol*

* *

*but it is not working.*


Do the following. It worked for me.


In the first round, run

trjconv -f *.xtc -s *.tpr -center -boxcenter tric -pbc mol -o 1.xtc

and choose backbone (which is usually 4 from the index) for centring.


In the second round,

use 1.xtc obtained from the first step and run the command as follows


trjconv -f 1.xtc -s *.tpr -center -boxcenter tric -pbc a -o 2.xtc

and this time also choose the backbone for centring.


This should bring back the dimeric protein system in the box. Sometimes the
water molecules around the edge are broken. Hope this is not a big worry.


By the way is your box cubic or truncated octahedron?

My case was a cubic box.


Hope this helps.


Regards

Sai


On Tue, Jun 8, 2010 at 2:23 AM, shahab shariati
shahab.shari...@gmail.comwrote:

 Morteza Khabiri wrote:



 Dear users



 I have a dimer protein in the water box. It was run for 30ns.

 during the simulation dimer split to two monomer. This things happen bc of

 PBC. ( I checked it by vmd pbc option )

 to have a two monomer together during trajectories (for visualization)

 I have used the following command:



 trjconv  -s .tpr -f .xtc -o   -boxcenter tric -pbc mol



 but it is not working.

 Is there any other method or command which I could implement pbc in

 trajectory.



 Thanks in advance



 Morteza







 Shahab Shariati wrote:



 You can use other flags of trjconv command as follows:



 Trjconv –f *.xtc –s **.tpr –o ***.xtc –pbc nojump –ur compact -center







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[gmx-users] Wrapping molecules for octahedron box

2010-05-11 Thread Sai Kumar Ramadugu
Dear Gromacs Users,
   I have a simulation of a protein in Truncated Octahedron box. I want to
calculate the water residence times and mean square displacements (of water)
around the active site residues. We developed our own algorithm for doing
the same.
In earlier simulations I had cubic box and anint() function was working for
the periodic boundary conditions. Now that I have truncated octahedron box,
is there any function to my rescue? I searched the gromacs forum and could
not find any function. Is there any way to circumvent this problem?

Sorry if this is a repost.

Thanks for your time.

Regards
Ying-Hua
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[gmx-users] Large dVpot/dlamda values at lambda = 1

2010-04-15 Thread Sai Kumar Ramadugu
Hi All,
   I'm trying to run free energy simulations for a linkage change in an
oligosaccharide when bound to its protein.
The linkage changes from beta 1-4 to beta 1-3. I followed the tutorial by
Prof Mobley.
For the lambda values I took 0 to 1 at intervals of 0.05. The values of
dVpot/dlambda from 0.00 to 0.95 seem to be in the range of E3-4. But when I
check the values of dVpot/dlambda for lambda = 1, it goes from E2 to E24 at
the end. This is only for the LBFGS minimization.
Does any one suspect a mistake in my topology or my approach?
Thanks for your time.


Sample .log file of lambda = 1 is pasted below.

   Step   Time Lambda
100  100.01.0

   Energies (kJ/mol)
   Bond  AngleProper Dih. Ryckaert-Bell.  LJ-14
1.06593e+048.20816e+032.93142e+024.26304e+038.30759e+03
 Coulomb-14LJ (SR)  Disper. corr.   Coulomb (SR)   Coul. recip.
4.13439e+041.92653e+05   -1.08257e+04   -1.46637e+06   -2.72128e+05
  Potential Pressure (bar)  dVpot/dlambda  dEkin/dlambda  dG/dl constr.
   -1.48359e+06   -4.15979e+03   -1.01327e+150.0e+000.0e+00

   Step   Time Lambda
101  101.01.0

   Energies (kJ/mol)
   Bond  AngleProper Dih. Ryckaert-Bell.  LJ-14
1.06477e+048.21153e+032.93330e+024.26328e+038.31182e+03
 Coulomb-14LJ (SR)  Disper. corr.   Coulomb (SR)   Coul. recip.
4.13437e+041.92648e+05   -1.08257e+04   -1.49776e+06   -2.72128e+05
  Potential Pressure (bar)  dVpot/dlambda  dEkin/dlambda  dG/dl constr.
   -1.51500e+06   -4.33201e+03   -2.78144e+180.0e+000.0e+00

   Step   Time Lambda
103  103.01.0

   Energies (kJ/mol)
   Bond  AngleProper Dih. Ryckaert-Bell.  LJ-14
1.06776e+048.21126e+032.93576e+024.26328e+038.31168e+03
 Coulomb-14LJ (SR)  Disper. corr.   Coulomb (SR)   Coul. recip.
4.13437e+041.92656e+05   -1.08257e+04   -1.76397e+06   -2.72128e+05
  Potential Pressure (bar)  dVpot/dlambda  dEkin/dlambda  dG/dl constr.
   -1.78117e+06   -5.80136e+03   -1.76071e+240.0e+000.0e+00




Regards
Sai
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[gmx-users] Free Energy Calculations for linkage change

2010-04-07 Thread Sai Kumar Ramadugu
Dear All,
   I have an disaccharide bound to a C-type lectin. The sequence of
disaccharide is beta-galactose1-4beta-GlcNAc. The 3'OH and 4'OH  of
beta-galactose coordinate to the Ca2+ at the active site. FRET experiments
have shown that if the disaccharide linkage is changed to
beta-galactose1-3beta-GlcNAc then the binding affinity drops to 20 fold. I
have attached both disaccharides in the figure. The left side residue is
galactose and right side residue is N-Acetylgalactoseamine. .
In order to do a free energy perturbation and find the relative free energy
of binding for these two ligands, I have to slowly change the linkage from
beta1-4 to beta1-3. If you look at the models of both disaccharides from the
figure, to convert the beta 1-4 linked disaccharide to beta 1-3 linked
disaccharide, I have to make the the C1 atom of Galactose attached to O4 of
N-Acetylgalactoseamine as H atom and rest of the galactose residue to dummy
atoms. On the other hand I have to grow the residue from H attached to O3 of
N-acetylgalactoseamine to a galactose. The number of atoms involved is 21
atoms. Further the constraints I have is that the sugar should be bound in
right conformation at the active site. So may be I need distance restraints.
Does my approach make any sense? I have seen some papers by others where
they add a fragment or delete a fragment between two ligands. But in my case
the difference is the linkage between two residues.

Thanks for your time in advance.

Regards
Sai Ramadugu
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[gmx-users] Free Energy Calculations for linkage change in disaccharide

2010-04-07 Thread Sai Kumar Ramadugu
Dear All,

In my previous email the text in the message was not shown. Thats why I'm
writing this again.
I request to see the attachment  of earlier message. I'm sorry for this!!

   I have an disaccharide bound to a C-type lectin. The sequence of
disaccharide is beta-galactose1-4beta-GlcNAc. The 3'OH and 4'OH  of
beta-galactose coordinate to the Ca2+ at the active site. FRET experiments
have shown that if the disaccharide linkage is changed to
beta-galactose1-3beta-GlcNAc then the binding affinity drops to 20 fold. I
have attached both disaccharides in the figure. The left side residue is
galactose and right side residue is N-Acetylgalactoseamine. .
In order to do a free energy perturbation and find the relative free energy
of binding for these two ligands, I have to slowly change the linkage from
beta1-4 to beta1-3. If you look at the models of both disaccharides from the
figure, to convert the beta 1-4 linked disaccharide to beta 1-3 linked
disaccharide, I have to make the the C1 atom of Galactose attached to O4 of
N-Acetylgalactoseamine as H atom and rest of the galactose residue to dummy
atoms. On the other hand I have to grow the residue from H attached to O3 of
N-acetylgalactoseamine to a galactose. The number of atoms involved is 21
atoms. Further the constraints I have is that the sugar should be bound in
right conformation at the active site. So may be I need distance restraints.
Does my approach make any sense? I have seen some papers by others where
they add a fragment or delete a fragment between two ligands. But in my case
the difference is the linkage between two residues.

Thanks for your time in advance.

Regards
Sai
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[gmx-users] free energy calculations for two ligands

2010-03-13 Thread Sai Kumar Ramadugu
Dear All,
   I have a trimeric protein system which binds to two different ligands.
The ligands are oligosaccharides. The difference between the two is first
ligand has beta 1-4 linkage and the second ligand has beta 1-3 linkage
between Galactose (Gal) and N-Acetyl Glucosamine (GlcNAc). Since the linkage
changes I have changes in atoms, bonds, pairs, angles and dihedrals.
In the pair and dihedrals, some of the pairs are present in the first ligand
and not in the second ligand. How do I make the topology for the change from
ligand A to ligand B in the free energy simulations? The same is the case
with dihedrals. Angles, bonds and atoms have no problem. Can someone please
help me in this regard?

Thanks for your time.

Regards
Sai
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