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Now where did you calculate that from?
$dS = \frac{\delta Q}{T}$
Second Law of Thermodynamics, which you just broke. Have a nice day.
The (cold) system where the calculation is done and the (hot) system the
result is transferred only exchange negligible energy and entropy.
No oceans to be boiled off.
Citing the second law of thermodynamics in this context is wrong.
Besides, just citing a physical law and selling that as reasoning is not
the way we argue in physics.
:-)
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