Re: [google-appengine] Help migrating from Files API
As a quick response: uuid1() http://docs.python.org/2/library/uuid.html#uuid.uuid1 may compromise privacy since it creates a UUID containing the computer’s network address. uuid4() http://docs.python.org/2/library/uuid.html#uuid.uuid4 creates a random UUID. Refer to this answer http://stackoverflow.com/a/1785592/1880872 from Stackoverflow for further details. On Sunday, August 2, 2015 at 10:04:33 PM UTC+2, Leon Prouger wrote: Thanks for answering, it should solve my problem. I wonder if it's safer to use uuid1 on GAE, but the collision chance of uuid4 seems small enough for my case. Also I added content type as you advised On Sunday, July 26, 2015 at 7:43:50 PM UTC+3, Alex Martelli wrote: To generate a unique filename, I recommend the technique suggested at http://stackoverflow.com/questions/22156030/google-cloud-storage-create-file-name-automatically . However, on an unrelated note, take care: your code seems to be missing the content_type named parameter to the open call, and you'll probably want to add it, as you did in the previous version in the create call. Alex On Sat, Jul 25, 2015 at 5:44 AM, Leon Prouger leon...@gmail.com wrote: Hey folks, I'm learning the new Cloud Storage and question how to I migrate my app with a least friction. Now I'm using this sample piece of code to save images: from google.appengine.api import images, files def upload(ext, stream): file_name = files.blobstore.create(mime_type=mimetypes.types_map [ext]) with files.open(file_name, 'a') as f: f.write(stream.getvalue()) files.finalize(file_name) return images.get_serving_url(files.blobstore.get_blob_key(file_name)) Which I'm thinking to change to the next: def upload(ext, stream): filename = /images/my_file with gcs.open(filename, 'w') as f: f.write(stream.getvalue()) # Blobstore API requires extra /gs to distinguish against blobstore files. blobstore_filename = '/gs' + filename # This blob_key works with blobstore APIs that do not expect a # corresponding BlobInfo in datastore. blob_key = blobstore.create_gs_key(blobstore_filename) return images.get_serving_url(blob_key) Which seems to work. The problem that in the old version I don't have to worry about filenames, Files API job was to assign me one. Now I need to give a name myself. Any way the new api should do it for me? Or maybe I should just hash the file. -- You received this message because you are subscribed to the Google Groups Google App Engine group. To unsubscribe from this group and stop receiving emails from it, send an email to google-appengi...@googlegroups.com. To post to this group, send email to google-a...@googlegroups.com. Visit this group at http://groups.google.com/group/google-appengine. To view this discussion on the web visit https://groups.google.com/d/msgid/google-appengine/145ce87c-e299-4d7f-8c8c-83f2959b5548%40googlegroups.com https://groups.google.com/d/msgid/google-appengine/145ce87c-e299-4d7f-8c8c-83f2959b5548%40googlegroups.com?utm_medium=emailutm_source=footer . For more options, visit https://groups.google.com/d/optout. -- You received this message because you are subscribed to the Google Groups Google App Engine group. To unsubscribe from this group and stop receiving emails from it, send an email to google-appengine+unsubscr...@googlegroups.com. To post to this group, send email to google-appengine@googlegroups.com. Visit this group at http://groups.google.com/group/google-appengine. To view this discussion on the web visit https://groups.google.com/d/msgid/google-appengine/1c7de523-d9d0-4682-a37e-7312621ed8f1%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
Re: [google-appengine] Help migrating from Files API
Thanks for answering, it should solve my problem. I wonder if it's safer to use uuid1 on GAE, but the collision chance of uuid4 seems small enough for my case. Also I added content type as you advised On Sunday, July 26, 2015 at 7:43:50 PM UTC+3, Alex Martelli wrote: To generate a unique filename, I recommend the technique suggested at http://stackoverflow.com/questions/22156030/google-cloud-storage-create-file-name-automatically . However, on an unrelated note, take care: your code seems to be missing the content_type named parameter to the open call, and you'll probably want to add it, as you did in the previous version in the create call. Alex On Sat, Jul 25, 2015 at 5:44 AM, Leon Prouger leon...@gmail.com javascript: wrote: Hey folks, I'm learning the new Cloud Storage and question how to I migrate my app with a least friction. Now I'm using this sample piece of code to save images: from google.appengine.api import images, files def upload(ext, stream): file_name = files.blobstore.create(mime_type=mimetypes.types_map [ext]) with files.open(file_name, 'a') as f: f.write(stream.getvalue()) files.finalize(file_name) return images.get_serving_url(files.blobstore.get_blob_key(file_name)) Which I'm thinking to change to the next: def upload(ext, stream): filename = /images/my_file with gcs.open(filename, 'w') as f: f.write(stream.getvalue()) # Blobstore API requires extra /gs to distinguish against blobstore files. blobstore_filename = '/gs' + filename # This blob_key works with blobstore APIs that do not expect a # corresponding BlobInfo in datastore. blob_key = blobstore.create_gs_key(blobstore_filename) return images.get_serving_url(blob_key) Which seems to work. The problem that in the old version I don't have to worry about filenames, Files API job was to assign me one. Now I need to give a name myself. Any way the new api should do it for me? Or maybe I should just hash the file. -- You received this message because you are subscribed to the Google Groups Google App Engine group. To unsubscribe from this group and stop receiving emails from it, send an email to google-appengi...@googlegroups.com javascript:. To post to this group, send email to google-a...@googlegroups.com javascript:. Visit this group at http://groups.google.com/group/google-appengine. To view this discussion on the web visit https://groups.google.com/d/msgid/google-appengine/145ce87c-e299-4d7f-8c8c-83f2959b5548%40googlegroups.com https://groups.google.com/d/msgid/google-appengine/145ce87c-e299-4d7f-8c8c-83f2959b5548%40googlegroups.com?utm_medium=emailutm_source=footer . For more options, visit https://groups.google.com/d/optout. -- You received this message because you are subscribed to the Google Groups Google App Engine group. To unsubscribe from this group and stop receiving emails from it, send an email to google-appengine+unsubscr...@googlegroups.com. To post to this group, send email to google-appengine@googlegroups.com. Visit this group at http://groups.google.com/group/google-appengine. To view this discussion on the web visit https://groups.google.com/d/msgid/google-appengine/d539f083-0a1d-4ca5-9b3f-bb69327c196d%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
Re: [google-appengine] Help migrating from Files API
To generate a unique filename, I recommend the technique suggested at http://stackoverflow.com/questions/22156030/google-cloud-storage-create-file-name-automatically . However, on an unrelated note, take care: your code seems to be missing the content_type named parameter to the open call, and you'll probably want to add it, as you did in the previous version in the create call. Alex On Sat, Jul 25, 2015 at 5:44 AM, Leon Prouger leonp...@gmail.com wrote: Hey folks, I'm learning the new Cloud Storage and question how to I migrate my app with a least friction. Now I'm using this sample piece of code to save images: from google.appengine.api import images, files def upload(ext, stream): file_name = files.blobstore.create(mime_type=mimetypes.types_map[ext]) with files.open(file_name, 'a') as f: f.write(stream.getvalue()) files.finalize(file_name) return images.get_serving_url(files.blobstore.get_blob_key(file_name)) Which I'm thinking to change to the next: def upload(ext, stream): filename = /images/my_file with gcs.open(filename, 'w') as f: f.write(stream.getvalue()) # Blobstore API requires extra /gs to distinguish against blobstore files. blobstore_filename = '/gs' + filename # This blob_key works with blobstore APIs that do not expect a # corresponding BlobInfo in datastore. blob_key = blobstore.create_gs_key(blobstore_filename) return images.get_serving_url(blob_key) Which seems to work. The problem that in the old version I don't have to worry about filenames, Files API job was to assign me one. Now I need to give a name myself. Any way the new api should do it for me? Or maybe I should just hash the file. -- You received this message because you are subscribed to the Google Groups Google App Engine group. To unsubscribe from this group and stop receiving emails from it, send an email to google-appengine+unsubscr...@googlegroups.com. To post to this group, send email to google-appengine@googlegroups.com. Visit this group at http://groups.google.com/group/google-appengine. To view this discussion on the web visit https://groups.google.com/d/msgid/google-appengine/145ce87c-e299-4d7f-8c8c-83f2959b5548%40googlegroups.com https://groups.google.com/d/msgid/google-appengine/145ce87c-e299-4d7f-8c8c-83f2959b5548%40googlegroups.com?utm_medium=emailutm_source=footer . For more options, visit https://groups.google.com/d/optout. -- You received this message because you are subscribed to the Google Groups Google App Engine group. To unsubscribe from this group and stop receiving emails from it, send an email to google-appengine+unsubscr...@googlegroups.com. To post to this group, send email to google-appengine@googlegroups.com. Visit this group at http://groups.google.com/group/google-appengine. To view this discussion on the web visit https://groups.google.com/d/msgid/google-appengine/CAE46Be9e6BtR-1pyrKvE_gmkY_q1QmUxDc5gd4rniGWSLMSrLQ%40mail.gmail.com. For more options, visit https://groups.google.com/d/optout.
[google-appengine] Help migrating from Files API
Hey folks, I'm learning the new Cloud Storage and question how to I migrate my app with a least friction. Now I'm using this sample piece of code to save images: from google.appengine.api import images, files def upload(ext, stream): file_name = files.blobstore.create(mime_type=mimetypes.types_map[ext]) with files.open(file_name, 'a') as f: f.write(stream.getvalue()) files.finalize(file_name) return images.get_serving_url(files.blobstore.get_blob_key(file_name)) Which I'm thinking to change to the next: def upload(ext, stream): filename = /images/my_file with gcs.open(filename, 'w') as f: f.write(stream.getvalue()) # Blobstore API requires extra /gs to distinguish against blobstore files. blobstore_filename = '/gs' + filename # This blob_key works with blobstore APIs that do not expect a # corresponding BlobInfo in datastore. blob_key = blobstore.create_gs_key(blobstore_filename) return images.get_serving_url(blob_key) Which seems to work. The problem that in the old version I don't have to worry about filenames, Files API job was to assign me one. Now I need to give a name myself. Any way the new api should do it for me? Or maybe I should just hash the file. -- You received this message because you are subscribed to the Google Groups Google App Engine group. To unsubscribe from this group and stop receiving emails from it, send an email to google-appengine+unsubscr...@googlegroups.com. To post to this group, send email to google-appengine@googlegroups.com. Visit this group at http://groups.google.com/group/google-appengine. To view this discussion on the web visit https://groups.google.com/d/msgid/google-appengine/145ce87c-e299-4d7f-8c8c-83f2959b5548%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
