Calling g_timeout_add_full() from a different thread (note the pthread_create
in the sample bellow) than where gtk_main() is does not work as I expect.
The timeout function only gets called if I generate events by moving the mouse.
If I don't move the mouse, all I see is the timeout is added repeatedly, but
timeout_func does not get called.
I'm afraid there's something I do not understand... and thus, your help would
be appreciated.
#include glib.h
#include gtk/gtk.h
#include gdk/gdk.h
gboolean
timeout_func (gpointer data)
{
static int cnt=0;
cnt ++;
printf(%s %d %p\n, __func__, cnt, (void*)data);
return FALSE;
}
void *
thread_func (void*arg)
{
printf(%s()\n, __func__);
g_timeout_add_full(G_PRIORITY_DEFAULT, 800, timeout_func, 1, NULL);
while (1) {
sleep(2);
printf(%s() add\n, __func__);
g_timeout_add_full(G_PRIORITY_DEFAULT, 800, timeout_func, 2, NULL);
}
}
int
main (int argc, char **argv)
{
pthread_t t;
gtk_init(argc, argv);
GtkWidget *w = gtk_window_new(GTK_WINDOW_TOPLEVEL);
gtk_window_set_title(GTK_WINDOW(w), Hello);
gtk_widget_show_all(w);
pthread_create(t, NULL, thread_func, NULL);
gtk_main();
return 0;
}
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