thanks!
suppose we have
data Tree a = Leaf a | Branch (Tree a) (Tree a) deriving Show
and how I could define a function foo :: a - Tree a that
foo a = Leaf a where a is not a type of Tree
foo b = b where b is one of the type of Tree (Leaf or Branch) ?
The following code seems not working..
foo (Leaf a) = a
foo a = Leaf a
saying 'Couldn't match expected type `a' against inferred type `Btree a''
any idea?
Thanks,
Max
From: Brandon S. Allbery KF8NH
Sent: Thursday, January 01, 2009 7:35 AM
To: Max.cs
Cc: Brandon S. Allbery KF8NH ; beginn...@haskell.org ; haskell-cafe@haskell.org
Subject: Re: [Haskell-cafe] definition of data
On 2009 Jan 1, at 2:32, Max.cs wrote:
data Tree a = a | Branch (Tree a) (Tree a) deriving Show
but it seems not accpetable in haskell ?
You need a constructor in both legs of the type:
data Tree a = Leaf a | Branch (Tree a) (Tree a) deriving Show
--
brandon s. allbery [solaris,freebsd,perl,pugs,haskell] allb...@kf8nh.com
system administrator [openafs,heimdal,too many hats] allb...@ece.cmu.edu
electrical and computer engineering, carnegie mellon universityKF8NH
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