Re: [Haskell-cafe] Should `(flip (^^))` work?
Mauricio wrote: Hi, I tested the expression below and it doesn't work. Is there some way to achieve that (i.e., turning an expression inside parenthesis into an operator)? 2 `(flip (^^))` (3%4) Another solution if you don't like defining extra (-|) and (|-) operators is: > ($2) (flip (^^)) (3%4) The right section of function application is type lifting. The general form of this construction is: > ($x) (f a b c...) y z... Which is equal to (f a b c... x y z...). That is, the construction lets you raise any argument out to before the function, thus making the partially applied function into an infix between |x| and |y x...|. -- Live well, ~wren ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
Re: [Haskell-cafe] Should `(flip (^^))` work?
Derek Elkins wrote: > On Mon, 2008-09-15 at 18:42 -0300, Mauricio wrote: >> Hi, >> >> I tested the expression below >> and it doesn't work. Is there >> some way to achieve that (i.e., >> turning an expression inside >> parenthesis into an operator)? >> >> 2 `(flip (^^))` (3%4) > > No it shouldn't work. The fact that the opening and closing marks are the > same suggests that it shouldn't. You can fake it though. > > x -| f = f x > f |- x = f x > > 2 -| flip (^^) |- (3%4) > Isn't naming the expression 'flip (^^)' much clearer? ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
Re: [Haskell-cafe] Should `(flip (^^))` work?
On Mon, 2008-09-15 at 18:42 -0300, Mauricio wrote: > Hi, > > I tested the expression below > and it doesn't work. Is there > some way to achieve that (i.e., > turning an expression inside > parenthesis into an operator)? > > 2 `(flip (^^))` (3%4) No it shouldn't work. The fact that the opening and closing marks are the same suggests that it shouldn't. You can fake it though. x -| f = f x f |- x = f x 2 -| flip (^^) |- (3%4) ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
[Haskell-cafe] Should `(flip (^^))` work?
Hi, I tested the expression below and it doesn't work. Is there some way to achieve that (i.e., turning an expression inside parenthesis into an operator)? 2 `(flip (^^))` (3%4) Thanks, Maurício ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
