Re: KMOD1 DS8k box

2023-01-20 Thread Seymour J Metz
Any ECKD device will have the associated overhead. Whether the virtual IRG 
corresponds to lost physical storage depends on the implementation. IAC, the 
IRG overhead depends on the block size and on whether keys are present.


--
Shmuel (Seymour J.) Metz
http://mason.gmu.edu/~smetz3


From: IBM Mainframe Discussion List [IBM-MAIN@LISTSERV.UA.EDU] on behalf of 
Michael Watkins [032966e74d0f-dmarc-requ...@listserv.ua.edu]
Sent: Friday, January 20, 2023 9:05 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

I understood Jake's question differently; I thought he was just asking what was 
indicated by what he saw in the DS8k GUI and whether his z/OS capacity could be 
determined from the DS8k GUI. I do not believe it can be.

People familiar with DS8k frames configured as ECKD storage can quibble about 
how much of the magnetic surface actually contains application data until the 
cows come home. All good.

The question I hinted at (sorry, should have clearly asked) was how any of this 
changes as we move from a DS8k with spinning disked RAIDed together to a 
flash-based DS8900F. I ask because I have no experience with DS8900F technology.

Without spinning parts, are there still IRGs, even virtual, when a DS8900F is 
configured as ECKD? An ECKD-configured DS8k still has this 'wasted' space, even 
though the 3390 IRGs do not necessarily correspond to anything phsical on the 
Seagate disks spinning inside the frame. The IRGs exist (I assume) so 
facilitate the DS8k appearing to be a native 3390 to z/OS.

I intended to ask: 'Are all of these inefficienies still mirrored in this next 
generation (DS8900F) for the sake of still appearing to be a native 3390 to 
z/OS?'

-Original Message-
From: IBM Mainframe Discussion List  On Behalf Of 
Allan Staller
Sent: Friday, January 20, 2023 7:33 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

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With IRGs and other "overhead" the usable capacity is about 0.8 GB whis is what 
I use when making "capacity" calculations.

-Original Message-
From: IBM Mainframe Discussion List  On Behalf Of 
Michael Watkins
Sent: Thursday, January 19, 2023 7:38 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

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A 3390 MOD-1 has 1,113 cylinders. Each 3390 cylinder has 15 tracks. Each 3390 
track has 56,664 bytes.

1,113 x 15 x 56,664 = 946,005,480

There are 946,005,480 bytes in a 3390 MOD-1 disk drive. Or roughly 0.946 GB.

The PC-compatible disk drives in your DS8k frame have a fixed block 
architecture (FBA) which, after being RAIDed together (RAID is 'Redundant Array 
of Independent Disks'), create virtual FBA volumes consisting of multiple 1GB 
(1,000,000,000) extents. These extents are 'raw' storage.
However, z/OS only recognizes count key data (CKD) formatted tracks and native 
3390 drives (with a multiple platters on a single spindle) have not been 
manufactured in this century.
To remedy this, when the DS8k frame is installed, each 1 GB FBA extent is 
configured as 1,113 CKD cylinders. Larger virtual 3390s are then constructed 
from these configured extents.

Not exactly sure what you're looking at in the DS8k GUI, but '1.99Kmod1' sounds 
like '1.99 k mod1' 3390s, or 1.99 x 1000 x 946,005,480 bytes. Or 
1,882,550,905,200 bytes. Or 1.88 TB

Notice that almost 5.4% of the raw storage has been 'lost' when the FBA disk is 
configured as CKD storage. Now add the space 'lost' to VTOCs, VTOC indices, 
VVDSs, and unused space, both within the boundaries of an allocated data set 
and the free space on each 3390 volume. The remainder is data. Not sure how the 
all-flash DS8900F works as far as configuring and 'lost' space.

-Original Message-
From: IBM Mainframe Discussion List  On Behalf Of 
Mike Schwab
Sent: Thursday, January 19, 2023 3:59 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

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system.
DO NOT click links or open attachments unless you expect them from the sender 
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Re: KMOD1 DS8k box

2023-01-20 Thread Michael Watkins
I understood Jake's question differently; I thought he was just asking what was 
indicated by what he saw in the DS8k GUI and whether his z/OS capacity could be 
determined from the DS8k GUI. I do not believe it can be.

People familiar with DS8k frames configured as ECKD storage can quibble about 
how much of the magnetic surface actually contains application data until the 
cows come home. All good.

The question I hinted at (sorry, should have clearly asked) was how any of this 
changes as we move from a DS8k with spinning disked RAIDed together to a 
flash-based DS8900F. I ask because I have no experience with DS8900F technology.

Without spinning parts, are there still IRGs, even virtual, when a DS8900F is 
configured as ECKD? An ECKD-configured DS8k still has this 'wasted' space, even 
though the 3390 IRGs do not necessarily correspond to anything phsical on the 
Seagate disks spinning inside the frame. The IRGs exist (I assume) so 
facilitate the DS8k appearing to be a native 3390 to z/OS.

I intended to ask: 'Are all of these inefficienies still mirrored in this next 
generation (DS8900F) for the sake of still appearing to be a native 3390 to 
z/OS?'

-Original Message-
From: IBM Mainframe Discussion List  On Behalf Of 
Allan Staller
Sent: Friday, January 20, 2023 7:33 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

CAUTION: This email originated from outside of the Texas Comptroller's email 
system.
DO NOT click links or open attachments unless you expect them from the sender 
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Classification: Confidential

With IRGs and other "overhead" the usable capacity is about 0.8 GB whis is what 
I use when making "capacity" calculations.

-Original Message-
From: IBM Mainframe Discussion List  On Behalf Of 
Michael Watkins
Sent: Thursday, January 19, 2023 7:38 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

[CAUTION: This Email is from outside the Organization. Unless you trust the 
sender, Don't click links or open attachments as it may be a Phishing email, 
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See 
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A 3390 MOD-1 has 1,113 cylinders. Each 3390 cylinder has 15 tracks. Each 3390 
track has 56,664 bytes.

1,113 x 15 x 56,664 = 946,005,480

There are 946,005,480 bytes in a 3390 MOD-1 disk drive. Or roughly 0.946 GB.

The PC-compatible disk drives in your DS8k frame have a fixed block 
architecture (FBA) which, after being RAIDed together (RAID is 'Redundant Array 
of Independent Disks'), create virtual FBA volumes consisting of multiple 1GB 
(1,000,000,000) extents. These extents are 'raw' storage.
However, z/OS only recognizes count key data (CKD) formatted tracks and native 
3390 drives (with a multiple platters on a single spindle) have not been 
manufactured in this century.
To remedy this, when the DS8k frame is installed, each 1 GB FBA extent is 
configured as 1,113 CKD cylinders. Larger virtual 3390s are then constructed 
from these configured extents.

Not exactly sure what you're looking at in the DS8k GUI, but '1.99Kmod1' sounds 
like '1.99 k mod1' 3390s, or 1.99 x 1000 x 946,005,480 bytes. Or 
1,882,550,905,200 bytes. Or 1.88 TB

Notice that almost 5.4% of the raw storage has been 'lost' when the FBA disk is 
configured as CKD storage. Now add the space 'lost' to VTOCs, VTOC indices, 
VVDSs, and unused space, both within the boundaries of an allocated data set 
and the free space on each 3390 volume. The remainder is data. Not sure how the 
all-flash DS8900F works as far as configuring and 'lost' space.

-Original Message-
From: IBM Mainframe Discussion List  On Behalf Of 
Mike Schwab
Sent: Thursday, January 19, 2023 3:59 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

CAUTION: This email originated from outside of the Texas Comptroller's email 
system.
DO NOT click links or open attachments unless you expect them from the sender 
and know the content is safe.

 846,236,160 bytes * 1990 M1s is 1,684,009,958,400 bytes.

On Thu, Jan 19, 2023 at 3:53 AM Mike Schwab  wrote:

3390-1 is 846,236,160 bytes.  Divide by 1000 or 1024 three times for a Gigabyte 
factor, or four times for a Terabyte conversion factor.

On Thu, Jan 19, 2023 at 1:29 AM Jake Anderson  wrote:

Hello

I was going through the storage usage in DS8K Gui login And I can see the 
utilization of CKD Pool is given as 1.99Kmod1

Is there a way to convert these value in Terabyte?

Jake

--
Mike A Schwab, Springfield IL USA
Where do Forest Rangers

Re: KMOD1 DS8k box

2023-01-20 Thread Allan Staller
Classification: Confidential

With IRGs and other "overhead" the usable capacity is about 0.8 GB whis is what 
I use when making "capacity" calculations.

-Original Message-
From: IBM Mainframe Discussion List  On Behalf Of 
Michael Watkins
Sent: Thursday, January 19, 2023 7:38 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

[CAUTION: This Email is from outside the Organization. Unless you trust the 
sender, Don't click links or open attachments as it may be a Phishing email, 
which can steal your Information and compromise your Computer.]

See 
https://apc01.safelinks.protection.outlook.com/?url=https%3A%2F%2Fwww.ibm.com%2Fdocs%2Fen%2Fzvse%2F6.2%3Ftopic%3DSSB27H_6.2.0%2Ffe6rf_optimizing_casize_disksizes.htm=05%7C01%7Callan.staller%40HCL.COM%7C7c799a3966fb4479bd1508dafa226a7d%7C189de737c93a4f5a8b686f4ca9941912%7C0%7C0%7C638097323032761646%7CUnknown%7CTWFpbGZsb3d8eyJWIjoiMC4wLjAwMDAiLCJQIjoiV2luMzIiLCJBTiI6Ik1haWwiLCJXVCI6Mn0%3D%7C3000%7C%7C%7C=1wsfScFEfiVR5dw2MXTEwU9dywSrr4STCYnLUgmcXMM%3D=0

A 3390 MOD-1 has 1,113 cylinders. Each 3390 cylinder has 15 tracks. Each 3390 
track has 56,664 bytes.

1,113 x 15 x 56,664 = 946,005,480

There are 946,005,480 bytes in a 3390 MOD-1 disk drive. Or roughly 0.946 GB.

The PC-compatible disk drives in your DS8k frame have a fixed block 
architecture (FBA) which, after being RAIDed together (RAID is 'Redundant Array 
of Independent Disks'), create virtual FBA volumes consisting of multiple 1GB 
(1,000,000,000) extents. These extents are 'raw' storage.
However, z/OS only recognizes count key data (CKD) formatted tracks and native 
3390 drives (with a multiple platters on a single spindle) have not been 
manufactured in this century.
To remedy this, when the DS8k frame is installed, each 1 GB FBA extent is 
configured as 1,113 CKD cylinders. Larger virtual 3390s are then constructed 
from these configured extents.

Not exactly sure what you're looking at in the DS8k GUI, but '1.99Kmod1' sounds 
like '1.99 k mod1' 3390s, or 1.99 x 1000 x 946,005,480 bytes. Or 
1,882,550,905,200 bytes. Or 1.88 TB

Notice that almost 5.4% of the raw storage has been 'lost' when the FBA disk is 
configured as CKD storage. Now add the space 'lost' to VTOCs, VTOC indices, 
VVDSs, and unused space, both within the boundaries of an allocated data set 
and the free space on each 3390 volume. The remainder is data. Not sure how the 
all-flash DS8900F works as far as configuring and 'lost' space.

-Original Message-
From: IBM Mainframe Discussion List  On Behalf Of 
Mike Schwab
Sent: Thursday, January 19, 2023 3:59 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

CAUTION: This email originated from outside of the Texas Comptroller's email 
system.
DO NOT click links or open attachments unless you expect them from the sender 
and know the content is safe.

 846,236,160 bytes * 1990 M1s is 1,684,009,958,400 bytes.

On Thu, Jan 19, 2023 at 3:53 AM Mike Schwab  wrote:

3390-1 is 846,236,160 bytes.  Divide by 1000 or 1024 three times for a Gigabyte 
factor, or four times for a Terabyte conversion factor.

On Thu, Jan 19, 2023 at 1:29 AM Jake Anderson  wrote:

Hello

I was going through the storage usage in DS8K Gui login And I can see the 
utilization of CKD Pool is given as 1.99Kmod1

Is there a way to convert these value in Terabyte?

Jake

--
Mike A Schwab, Springfield IL USA
Where do Forest Rangers go to get away from it all?

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Re: KMOD1 DS8k box

2023-01-19 Thread Michael Watkins
I could be wrong, but I suspect that any information you get from the GUI will 
simply tell you how much of the raw storage has been configured as volumes that 
can be used by the operating systems connected to your DS8k. The GUI cannot 
make sense of the data on the volumes. To the GUI, I think those volumes appear 
to be no more than a stream of zeros and ones. It cannot tell the difference 
between unused space and data. To ascertain the utilization of those volumes, 
you must use the commands or utilities executed on the operating systems that 
know them as data. 

-Original Message-
From: IBM Mainframe Discussion List  On Behalf Of 
Jake Anderson
Sent: Thursday, January 19, 2023 11:40 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

CAUTION: This email originated from outside of the Texas Comptroller's email 
system.
DO NOT click links or open attachments unless you expect them from the sender 
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Is there a command or facility within DS8K to generate storage array 
utilization report ?

On Thu, Jan 19, 2023, 5:51 PM Paul Gorlinsky  wrote:

> This is the theoretical maximum… not realistic… the available usable 
> space is 100% determined by the blksize and optional key size… zOS use 
> at most
> 1/2 track blocking … it you force a 32760 block size you will waste 
> about 12k per track… safe numbers are about 90% for estimating
>
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>

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Re: KMOD1 DS8k box

2023-01-19 Thread Jake Anderson
Is there a command or facility within DS8K to generate storage array
utilization report ?

On Thu, Jan 19, 2023, 5:51 PM Paul Gorlinsky  wrote:

> This is the theoretical maximum… not realistic… the available usable space
> is 100% determined by the blksize and optional key size… zOS use at most
> 1/2 track blocking … it you force a 32760 block size you will waste about
> 12k per track… safe numbers are about 90% for estimating
>
> --
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> send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN
>

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Re: KMOD1 DS8k box

2023-01-19 Thread Paul Gorlinsky
This is the theoretical maximum… not realistic… the available usable space is 
100% determined by the blksize and optional key size… zOS use at most 1/2 track 
blocking … it you force a 32760 block size you will waste about 12k per track… 
safe numbers are about 90% for estimating

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Re: KMOD1 DS8k box

2023-01-19 Thread Michael Watkins
See 
https://www.ibm.com/docs/en/zvse/6.2?topic=SSB27H_6.2.0/fe6rf_optimizing_casize_disksizes.htm

A 3390 MOD-1 has 1,113 cylinders. Each 3390 cylinder has 15 tracks. Each 3390 
track has 56,664 bytes.

1,113 x 15 x 56,664 = 946,005,480

There are 946,005,480 bytes in a 3390 MOD-1 disk drive. Or roughly 0.946 GB.

The PC-compatible disk drives in your DS8k frame have a fixed block 
architecture (FBA) which, after being RAIDed together (RAID is 'Redundant Array 
of Independent Disks'), create virtual FBA volumes consisting of multiple 1GB 
(1,000,000,000) extents. These extents are 'raw' storage.
However, z/OS only recognizes count key data (CKD) formatted tracks and native 
3390 drives (with a multiple platters on a single spindle) have not been 
manufactured in this century.
To remedy this, when the DS8k frame is installed, each 1 GB FBA extent is 
configured as 1,113 CKD cylinders. Larger virtual 3390s are then constructed 
from these configured extents.

Not exactly sure what you're looking at in the DS8k GUI, but '1.99Kmod1' sounds 
like '1.99 k mod1' 3390s, or 1.99 x 1000 x 946,005,480 bytes. Or 
1,882,550,905,200 bytes. Or 1.88 TB

Notice that almost 5.4% of the raw storage has been 'lost' when the FBA disk is 
configured as CKD storage. Now add the space 'lost' to VTOCs, VTOC indices, 
VVDSs, and unused space, both within the boundaries of an allocated data set 
and the free space on each 3390 volume. The remainder is data. Not sure how the 
all-flash DS8900F works as far as configuring and 'lost' space.

-Original Message-
From: IBM Mainframe Discussion List  On Behalf Of 
Mike Schwab
Sent: Thursday, January 19, 2023 3:59 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box

CAUTION: This email originated from outside of the Texas Comptroller's email 
system.
DO NOT click links or open attachments unless you expect them from the sender 
and know the content is safe.

 846,236,160 bytes * 1990 M1s is 1,684,009,958,400 bytes.

On Thu, Jan 19, 2023 at 3:53 AM Mike Schwab  wrote:

3390-1 is 846,236,160 bytes.  Divide by 1000 or 1024 three times for a 
Gigabyte factor, or four times for a Terabyte conversion factor.

On Thu, Jan 19, 2023 at 1:29 AM Jake Anderson  wrote:

Hello

I was going through the storage usage in DS8K Gui login And I can 
see the utilization of CKD Pool is given as 1.99Kmod1

Is there a way to convert these value in Terabyte?

Jake

--
Mike A Schwab, Springfield IL USA
Where do Forest Rangers go to get away from it all?

--
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Re: KMOD1 DS8k box

2023-01-19 Thread Mike Schwab
 846,236,160 bytes * 1990 M1s is 1,684,009,958,400 bytes.

On Thu, Jan 19, 2023 at 3:53 AM Mike Schwab  wrote:
>
> 3390-1 is 846,236,160 bytes.  Divide by 1000 or 1024 three times for a
> Gigabyte factor, or four times for a Terabyte conversion factor.
>
> On Thu, Jan 19, 2023 at 1:29 AM Jake Anderson  
> wrote:
> >
> > Hello
> >
> > I was going through the storage usage in DS8K Gui login And I can see the
> > utilization of CKD Pool is given as 1.99Kmod1
> >
> > Is there a way to convert these value in Terabyte?
> >
> > Jake
> >
> > --
> > For IBM-MAIN subscribe / signoff / archive access instructions,
> > send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN
>
>
>
> --
> Mike A Schwab, Springfield IL USA
> Where do Forest Rangers go to get away from it all?



-- 
Mike A Schwab, Springfield IL USA
Where do Forest Rangers go to get away from it all?

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Re: KMOD1 DS8k box

2023-01-19 Thread Mike Schwab
3390-1 is 846,236,160 bytes.  Divide by 1000 or 1024 three times for a
Gigabyte factor, or four times for a Terabyte conversion factor.

On Thu, Jan 19, 2023 at 1:29 AM Jake Anderson  wrote:
>
> Hello
>
> I was going through the storage usage in DS8K Gui login And I can see the
> utilization of CKD Pool is given as 1.99Kmod1
>
> Is there a way to convert these value in Terabyte?
>
> Jake
>
> --
> For IBM-MAIN subscribe / signoff / archive access instructions,
> send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN



-- 
Mike A Schwab, Springfield IL USA
Where do Forest Rangers go to get away from it all?

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KMOD1 DS8k box

2023-01-18 Thread Jake Anderson
Hello

I was going through the storage usage in DS8K Gui login And I can see the
utilization of CKD Pool is given as 1.99Kmod1

Is there a way to convert these value in Terabyte?

Jake

--
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