Re: [Image-SIG] Converting to zebra (ZPL) format
Hi Peter, despite Fredik's lengthy and carefull answer, I think that is not what you were asking for - his program is suitable to print images inpout inline inside a Python program as sequences of 0 and 1's. But I think you were asking for a way to print a generic image read from a disk file. I can code that for you, if you wish so - just write me if no one else mailed yu a complete answer, and tell me more details about the images you want to print, maximum width of the printer, and stuff like that. I also did nt understand if the Hexadecimal data you send to the printer is actual ASCII - i.e. You send a real "F" character to get four dots "", or if you send a 15 decimal value standing for 0x0F ANd please, do confirm that you have PIL installed (call a interactive Python shell and type 'import Image' there if you are not sure). Regards, JS -><- On Friday 17 June 2005 01:22, Peter Dempsey wrote: > Hi folks, I'm a newbie to python so please be gentle. > > I want to convert an image to a format suitable for use in a Zebra > label printer. The data sent to the printer consists of a string of > hex characters. Each byte converts to a binary set of dots on the > label. > > FF becomes > A5 becomes 10100101 > > So a string like this becomes a right-angle triangle... > > 18,3^m > F0FFFFF00000F0FF > > The 18 says how many bytes in the image, 3 says how many bytes wide > the image is. So the string above becomes... > > F0-> > FF-> > FFF000-> > 00-> > F0-> > FF-> > > I'm sure it's a simple task, I mean, the image is converted to a > hex representation of the raw image. > > I've had some success doing it the hard way with python, importing > a pcx image and going through it byte by byte but I'm sure there's > an easier way. > > Any suggestions would be super. > > I don't have my code here at home. I can post it tomorrow if it > helps. > > Thanks, > > Peter > ___ > Image-SIG maillist - Image-SIG@python.org > http://mail.python.org/mailman/listinfo/image-sig ___ Image-SIG maillist - Image-SIG@python.org http://mail.python.org/mailman/listinfo/image-sig
Re: [Image-SIG] Converting CMYK JPG image to RGB
I know the problem you mention, but I also thought that a recent version of
PIL fixed it... I could be wrong though.
However - the other option would be to use ICC profiles to do color
conversion. If you want REALLY accurate conversion, this is the way to go.
I wrote a wrapper module called pyCMS that uses the littleCMS library to do
ICC conversions. See: http://www.cazabon.com/pyCMS
Kevin.
- Original Message -
From: "marc birot" <[EMAIL PROTECTED]>
To:
Sent: Friday, June 17, 2005 6:01 AM
Subject: [Image-SIG] Converting CMYK JPG image to RGB
> Hello,
>
> I'm trying to convert CMYK Jpg files to RGB Jpg files using
> (Image.open("cmyk_image.jpg").convert("RGB"))...
> The result shows very wrong colours.
>
> After checking the Image-SIG archives (Aug 2004) i found the following :
>
> "...Older versions of Photoshop generated broken CMYK files, and PIL
> attempts to compensate for this. try commenting out the following lines
> in PIL/JpegImagePlugin.py, and let me know if it helps:
> if self.mode == "CMYK" and self.info.has_key("adobe"):
>rawmode = "CMYK;I" # Photoshop 2.5 is broken! ..."
>
> Well, i tried and it does not work. The result i get is close to a
> 'negative' of the original picture ( not too close).
>
> Any suggestion to help on this problem ? :)
>
> Marc
> ___
> Image-SIG maillist - Image-SIG@python.org
> http://mail.python.org/mailman/listinfo/image-sig
>
>
___
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[Image-SIG] Converting CMYK JPG image to RGB
Hello,
I'm trying to convert CMYK Jpg files to RGB Jpg files using
(Image.open("cmyk_image.jpg").convert("RGB"))...
The result shows very wrong colours.
After checking the Image-SIG archives (Aug 2004) i found the following :
"...Older versions of Photoshop generated broken CMYK files, and PIL
attempts to compensate for this. try commenting out the following lines
in PIL/JpegImagePlugin.py, and let me know if it helps:
if self.mode == "CMYK" and self.info.has_key("adobe"):
rawmode = "CMYK;I" # Photoshop 2.5 is broken! ..."
Well, i tried and it does not work. The result i get is close to a
'negative' of the original picture ( not too close).
Any suggestion to help on this problem ? :)
Marc
___
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Re: [Image-SIG] Extended Mail
> Encrypted message is available. Unknown command - "ENCRYPTED". Try HELP. Summary of resource utilization --- CPU time:0.000 secDevice I/O:4 Overhead CPU:0.000 secPaging I/O:0 CPU model: 933MHz Pentium III 256k (1152M) Job origin: image-sig@PYTHON.ORG ___ Image-SIG maillist - Image-SIG@python.org http://mail.python.org/mailman/listinfo/image-sig
Re: [Image-SIG] Converting to zebra (ZPL) format
Peter Dempsey wrote:
> Hi folks, I'm a newbie to python so please be gentle.
>
> I want to convert an image to a format suitable for use in a Zebra label
> printer. The data sent to the printer consists of a string of hex characters.
> Each byte converts to a binary set of dots on the label.
>
> FF becomes
> A5 becomes 10100101
>
> So a string like this becomes a right-angle triangle...
>
> 18,3^m
> F0FFFFF00000F0FF
>
> The 18 says how many bytes in the image, 3 says how many bytes wide the image
> is. So the string above becomes...
>
> F0 ->
> FF ->
> FFF000 ->
> 00 ->
> F0 ->
> FF ->
>
> I'm sure it's a simple task, I mean, the image is converted to a hex
> representation of the raw image.
>
> I've had some success doing it the hard way with python, importing a pcx image
> and going through it byte by byte but I'm sure there's an easier way.
>
> Any suggestions would be super.
how about:
import Image
#
# step 1) convert example to pil image
data = (
"",
"",
"",
"",
"",
"",
)
height = len(data)
width = len(data[0])
im = Image.new("1", (width, height), 0)
# convert data to list of values
pixels = []
for row in data:
pixels.extend([1-int(ch) for ch in row])
im.putdata(pixels)
#
# step 2) convert it back to a hex string
data = im.tostring("raw", "1;I")
size = len(data)
data = ["%02X" % ord(byte) for byte in data]
print "%d,%d^m" % (size, (im.size[0]+7)/8)
print "".join(data)
# end
things to notice:
- step 1 can of course be replaced with some other way
to create a mode "1" image
- mode "1" images treat "1" as white and "0" as black.
- the tostring arguments are a bit magical. some info can
be found here: http://effbot.org/imagingbook/decoder.htm
- [blah for blah in blah] is a list comprehension. if you're
using Python 2.4, you can omit the brackets (which turns
it into a generator expression, but the result is the same)
- (blah+7)/8 converts the number of pixels to a number of
bytes, rounding up to the nearest byte. to be future safe,
you might wish to use "//" instead of "/".
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