[PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
On 2011-06-05, Felipe Pena wrote:
> Reading our bug tracker I noticed a good feature request [1] from 2009
> which points to an interesting feature that I think makes sense for
> us, since we are now working with $f() using objects and strings, and
> the array('class', 'method') is an old known for call_user_func()-like
> functions.
>
> So, I wrote a patch [2] that allow such behavior to be consistent with
> arrays. See some examples:
>
> class Hello {
>public function world($x) {
> echo "Hello, $x\n"; return $this;
>}
> }
>
> $f = array('Hello','world');
> var_dump($f('you'));
>
> $f = array(new Hello, 'foo');
> $f();
>
> All such calls match with the call_user_func() behavior related to
> magic methods, static & non-static methods.
>
> The array to be a valid callback should be a 2-element array, and it
> must be for the first element object/string and for the second string
> only. (just like our zend_is_callable() check and opcodes related to
> init call)
>
> Any thoughts?
Huge +1 from me -- having to do constructs like the following have been
a huge headache for me:
if (is_callable($callback)) {
if (is_object($callback) || is_string($callback)) {
return $callback($arg);
}
return call_user_func($callback, $arg)
}
This would simplify that tremendously:
if (is_callable($callback)) {
return $callback($arg);
}
--
Matthew Weier O'Phinney
Project Lead| matt...@zend.com
Zend Framework | http://framework.zend.com/
PGP key: http://framework.zend.com/zf-matthew-pgp-key.asc
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[PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
Hi,
Hi all,
Reading our bug tracker I noticed a good feature request [1] from
2009 which
points to an interesting feature that I think makes sense for us,
since we
are now working with $f() using objects and strings, and the
array('class',
'method') is an old known for call_user_func()-like functions.
So, I wrote a patch [2] that allow such behavior to be consistent
with
arrays. See some examples:
class Hello {
public function world($x) {
echo "Hello, $x\n"; return $this;
}
}
$f = array('Hello','world');
var_dump($f('you'));
$f = array(new Hello, 'foo');
$f();
All such calls match with the call_user_func() behavior related to
magic
methods, static & non-static methods.
The array to be a valid callback should be a 2-element array, and it
must be
for the first element object/string and for the second string only.
(just
like our zend_is_callable() check and opcodes related to init call)
Any thoughts?
what happens if I use this code.
class Foo {
public $bar;
public function __construct() {
$this->bar = array($this, 'baz');
$this->bar();
}
public function bar() {
echo 'bar';
}
public function baz() {
echo 'baz';
}
}
new Foo();
What is the output of this snippet?
Are there the same rules as for closures?
Christian
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Re: [PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
Hi,
2011/6/8 Christian Kaps
> Hi,
>
>
> Hi all,
>> Reading our bug tracker I noticed a good feature request [1] from 2009
>> which
>> points to an interesting feature that I think makes sense for us, since we
>> are now working with $f() using objects and strings, and the
>> array('class',
>> 'method') is an old known for call_user_func()-like functions.
>>
>> So, I wrote a patch [2] that allow such behavior to be consistent with
>> arrays. See some examples:
>>
>> class Hello {
>> public function world($x) {
>> echo "Hello, $x\n"; return $this;
>> }
>> }
>>
>> $f = array('Hello','world');
>> var_dump($f('you'));
>>
>> $f = array(new Hello, 'foo');
>> $f();
>>
>> All such calls match with the call_user_func() behavior related to magic
>> methods, static & non-static methods.
>>
>> The array to be a valid callback should be a 2-element array, and it must
>> be
>> for the first element object/string and for the second string only. (just
>> like our zend_is_callable() check and opcodes related to init call)
>>
>> Any thoughts?
>>
>>
>
> what happens if I use this code.
>
> class Foo {
>
> public $bar;
>
> public function __construct() {
>
> $this->bar = array($this, 'baz');
> $this->bar();
> }
>
> public function bar() {
> echo 'bar';
> }
>
> public function baz() {
> echo 'baz';
> }
> }
>
> new Foo();
>
> What is the output of this snippet?
>
> Are there the same rules as for closures?
>
> Christian
>
>
Yes, the same rules.
--
Regards,
Felipe Pena
Re: [PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
On Wed, 8 Jun 2011 08:57:48 -0300, Felipe Pena wrote:
Hi,
2011/6/8 Christian Kaps
Hi,
what happens if I use this code.
class Foo {
public $bar;
public function __construct() {
$this->bar = array($this, 'baz');
$this->bar();
}
public function bar() {
echo 'bar';
}
public function baz() {
echo 'baz';
}
}
new Foo();
What is the output of this snippet?
Are there the same rules as for closures?
Christian
Yes, the same rules.
Hi,
I think for the sake of consistency it should be possible to use the
following code.
class Bar {
public function __construct($dispatcher) {
$dispatcher->addEventListener('onUpdate', $this->onUpdate);
}
public function onUpdate() {}
}
If a property $onUpdate exists then it will be ignored. The same rules
as for Closures or for array callbacks.
Christian
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Re: [PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
2011/6/8 Christian Kaps
> On Wed, 8 Jun 2011 08:57:48 -0300, Felipe Pena wrote:
>
>> Hi,
>>
>> 2011/6/8 Christian Kaps
>>
>> Hi,
>>>
>>>
>>> what happens if I use this code.
>>>
>>> class Foo {
>>>
>>> public $bar;
>>>
>>> public function __construct() {
>>>
>>> $this->bar = array($this, 'baz');
>>> $this->bar();
>>> }
>>>
>>> public function bar() {
>>> echo 'bar';
>>> }
>>>
>>> public function baz() {
>>> echo 'baz';
>>> }
>>> }
>>>
>>> new Foo();
>>>
>>> What is the output of this snippet?
>>>
>>> Are there the same rules as for closures?
>>>
>>> Christian
>>>
>>>
>>> Yes, the same rules.
>>
>
> Hi,
>
> I think for the sake of consistency it should be possible to use the
> following code.
>
> class Bar {
>
>public function __construct($dispatcher) {
>
>$dispatcher->addEventListener('onUpdate', $this->onUpdate);
>}
>
>public function onUpdate() {}
> }
>
> If a property $onUpdate exists then it will be ignored. The same rules as
> for Closures or for array callbacks.
>
>
> Christian
>
>
>
>
It works in the same way:
class foo {
public function __construct() {
$this->bar = function () { return 1; };
// $this->bar(); // error
$x = $this->bar;
$x(); // ok
$this->bar = array($this, 'baz');
// $this->bar(); // error
$x = $this->bar;
$x(); // ok
}
public function baz() {
echo 'baz';
}
}
--
Regards,
Felipe Pena
Re: [PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
On Wed, Jun 8, 2011 at 2:46 PM, Felipe Pena wrote:
> class foo {
> public function __construct() {
> $this->bar = function () { return 1; };
> // $this->bar(); // error
> $x = $this->bar;
> $x(); // ok
>
> $this->bar = array($this, 'baz');
> // $this->bar(); // error
> $x = $this->bar;
> $x(); // ok
> }
> public function baz() {
> echo 'baz';
> }
> }
What he meant was passing an existing method as a callback if you
don't invoke it, i.e. passing "$this->bar" instead of array($this,
"bar"). I don't know how hard it'd be to achieve, but it sounds pretty
awesome to me.
Cheers
--
Jordi Boggiano
@seldaek :: http://seld.be/
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Re: [PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
On Wed, 8 Jun 2011 09:46:26 -0300, Felipe Pena wrote:
It works in the same way:
class foo {
public function __construct() {
$this->bar = function () { return 1; };
// $this->bar(); // error
$x = $this->bar;
$x(); // ok
$this->bar = array($this, 'baz');
// $this->bar(); // error
$x = $this->bar;
$x(); // ok
}
public function baz() {
echo 'baz';
}
}
OK, my mistake. I thought a property which holds a closure can be
called directly.
Thanks for clarification.
Christian
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Re: [PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
On Wed, 8 Jun 2011 15:39:59 +0200, Jordi Boggiano wrote:
On Wed, Jun 8, 2011 at 2:46 PM, Felipe Pena
wrote:
class foo {
public function __construct() {
$this->bar = function () { return 1; };
// $this->bar(); // error
$x = $this->bar;
$x(); // ok
$this->bar = array($this, 'baz');
// $this->bar(); // error
$x = $this->bar;
$x(); // ok
}
public function baz() {
echo 'baz';
}
}
What he meant was passing an existing method as a callback if you
don't invoke it, i.e. passing "$this->bar" instead of array($this,
"bar"). I don't know how hard it'd be to achieve, but it sounds
pretty
awesome to me.
Cheers
Yep, just what I meant.
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Re: [PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
Will this work:
array('foo', 'bar')('arg1', 'arg2')
?
On Wed, Jun 8, 2011 at 3:48 PM, Christian Kaps
wrote:
> On Wed, 8 Jun 2011 15:39:59 +0200, Jordi Boggiano wrote:
>>
>> On Wed, Jun 8, 2011 at 2:46 PM, Felipe Pena wrote:
>>>
>>> class foo {
>>> public function __construct() {
>>> $this->bar = function () { return 1; };
>>> // $this->bar(); // error
>>> $x = $this->bar;
>>> $x(); // ok
>>>
>>> $this->bar = array($this, 'baz');
>>> // $this->bar(); // error
>>> $x = $this->bar;
>>> $x(); // ok
>>> }
>>> public function baz() {
>>> echo 'baz';
>>> }
>>> }
>>
>> What he meant was passing an existing method as a callback if you
>> don't invoke it, i.e. passing "$this->bar" instead of array($this,
>> "bar"). I don't know how hard it'd be to achieve, but it sounds pretty
>> awesome to me.
>>
>> Cheers
>
> Yep, just what I meant.
>
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>
>
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Re: [PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
2011/7/14 Rune Kaagaard :
> Will this work:
>
> array('foo', 'bar')('arg1', 'arg2')
>
> ?
>
No, and it isn't supposed to either.
--
Regards,
Felipe Pena
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