[jQuery] Ajax Problem

[saiful.ha...@gmail.com]

hi all,

I have 2 file

rating.js
$(document).ready(function() {
  var behav = function(){
$(.rating_class).hover(function(){
  $(#tooltip_star).css({visibility:visible, top:($
(this).offset().top - 60), left:($(this).offset().left+$(this).width
()+ 2)});
  $.ajax({
type: POST,
url: $(this).attr(href),
success: function(msg){
  $(#tooltip_star).html(msg);
}
  });
}, function(){
  $(#tooltip_star).css(visibility,hidden);
}).ajaxStart(function(){
  $(#tooltip_star).html(table class=\table_animation
\trtdimg style=\text-align:center\ src=\/resource/images/
loading.gif\/td/tr/table);
});

$(.rating_class).click(function(){
  location = $(this).attr(href).replace(ajax_, );
  return false;
});
  }

  behav();
});

there is just call function behav(); to run all sintax in this file,

and i have some ajax sintax in other file file this

$(document).ready(function() {

var mainApp = function(page){
  $.ajax({
type: POST,
url: ?= base_url();?product/related/?= $idProduct ?
/+page,
success: function(msg){
  $(#displayRelated).html(msg);
  behav();
}
  });
}

mainApp(1);

});

But i get some error in my firebug like this

behav is not defined
success()()6 (line 652)
success()jquery-1.2.6.js (line 2818)
onreadystatechange()()jquery-1.2.6.js (line 2773)
[Break on this error] behav();

my question is, why my function behav() in rating.js can't called from
success: function(msg){...}, there is need something like global
function?

thang's

~ saiful haqqi ~

[jQuery] double $().read()

[saiful.ha...@gmail.com]

hi all,

can we put double $().read() declare? cos i am using tab-ui not in all
page, just in one page only?
is has trick's for this happen

~ saiful haqqi ~

[jQuery] Get TD Position [X, Y]

[saiful.ha...@gmail.com]

hi all,

I want make simple sub menu, id mouse over the column of table will
show the div with some text finally.
can i get the XY position foreach column in table?!

JQuery Code

$(.left_menu_td).mouseover(function(){
$(#sub_menu).css({top:this.position().top,
left:this.position.left, display:block});
});

HTML code
div id=left_menu
table class=left_menu_table
trtd class=left_menu_tdOne/td/tr
trtd class=left_menu_tdTwo/td/tr
trtd class=left_menu_tdThree/td/tr
/table
/div

div id=sub_menu style=position:absolute;display:none Sub Menu
from Column /div

I am always get undefine this.position().top, can i get jquery object
for each column?

~ saiful haqqi ~

[jQuery] mouseout problem

[saiful.ha...@gmail.com]

hi all,

i has a litle problem when using $(IdElement).shie(slow); this my
code

my JQuery
$(document).ready(function() {
$(#text_span).mouseover(function(){ $(isPopUp).show(slow);});
$(#isPopUp).mouseover(function(){$(#isPopUp).css(display,
block);});
$(#isPopUp).mouseout(function(){$(#isPopUp).hide(slow);});
}

My HTML

div id=isPopUp style=display:none
divimg src=some source/div
div
a href=aone/abr
a href=atwo/abr
a href=atree/abr
a href=afour/abr
/div
/div

span id=text_spanshow the div/div

when my cursor over in text_span, the div showed and that is true.
But, the problem when my cursor over the image the div just gone, hide
with slow.

Where is my incorrect sintax?

When i change the hide(slow) to hide() only, all be fine :(

thang's for help

[jQuery] Newbie question

[saiful.ha...@gmail.com]

hi all,

is jquery have function like findXY(element) or scroll position?
sorry not finish read all document about jquery

~ saiful haqqi ~