[jQuery] Re: Data containing ? at the start getting converted to jsonp.... by ajax() call

2007-12-06 Thread Ben Bennett 

Is this the wrong forum for this question?  Should I take it to the
dev list or put it in the bug tracker?

Thanks,

-ben

On Dec 4, 2:00 pm, Ben Bennett [EMAIL PROTECTED] wrote:
 This is my first post so I really should thank everyone for a
 fanatastic library.

 However, I think I have found a bug...

 Using jQuery 1.2.1, if I have:

 $.ajax({
   type: POST,
   url: test.html,
   dataType: json,
   data: {query: queryString},

 });

 When queryString starts with a ? it will get converted to
 jsonp1231234124...

 This is clearly happening because of the code at line 2226 of the full
 release version:
 // Build temporary JSONP function
 if ( s.dataType == json  (s.data 
 s.data.match(jsre) || s.url.match(jsre)) ) {
 jsonp = jsonp + jsc++;

 // Replace the =? sequence both in the query
 string and the data
 if ( s.data )
 s.data = s.data.replace(jsre, = +
 jsonp);
 s.url = s.url.replace(jsre, = + jsonp);

 ...

 But I see no way to prevent that from happening.

 Now... one might suggest that I should avoid a leading ? in my option
 names.  But I am taking them from input boxes and ? is a valid thing
 for a user to type.  Unfortunately there seems to be no good way to
 escape the string to prevent this behavior (without teaching the
 called code how to unescape it).

 Also, the docs don't mention that the =? escaping happens to a json
 dataType... I see it for jsonp.

 Is this behavior intentional?  If so, there should be a way to
 suppress it or at a way for the calling code to escape the values to
 cause a leading ? to be passed to the server.

 -ben

[jQuery] Re: Data containing ? at the start getting converted to jsonp.... by ajax() call

2007-12-06 Thread Benjamin Sterling 
Ben, (its like talking to myself)
Put cache:true into your ajax call, the ? is to prevent caching.

On 12/6/07, Ben Bennett [EMAIL PROTECTED] wrote:


 Is this the wrong forum for this question?  Should I take it to the
 dev list or put it in the bug tracker?

 Thanks,

 -ben

 On Dec 4, 2:00 pm, Ben Bennett [EMAIL PROTECTED] wrote:
  This is my first post so I really should thank everyone for a
  fanatastic library.
 
  However, I think I have found a bug...
 
  Using jQuery 1.2.1, if I have:
 
  $.ajax({
type: POST,
url: test.html,
dataType: json,
data: {query: queryString},
 
  });
 
  When queryString starts with a ? it will get converted to
  jsonp1231234124...
 
  This is clearly happening because of the code at line 2226 of the full
  release version:
  // Build temporary JSONP function
  if ( s.dataType == json  (s.data 
  s.data.match(jsre) || s.url.match(jsre)) ) {
  jsonp = jsonp + jsc++;
 
  // Replace the =? sequence both in the query
  string and the data
  if ( s.data )
  s.data = s.data.replace(jsre, = +
  jsonp);
  s.url = s.url.replace(jsre, = + jsonp);
 
  ...
 
  But I see no way to prevent that from happening.
 
  Now... one might suggest that I should avoid a leading ? in my option
  names.  But I am taking them from input boxes and ? is a valid thing
  for a user to type.  Unfortunately there seems to be no good way to
  escape the string to prevent this behavior (without teaching the
  called code how to unescape it).
 
  Also, the docs don't mention that the =? escaping happens to a json
  dataType... I see it for jsonp.
 
  Is this behavior intentional?  If so, there should be a way to
  suppress it or at a way for the calling code to escape the values to
  cause a leading ? to be passed to the server.
 
  -ben




-- 
Benjamin Sterling
http://www.KenzoMedia.com
http://www.KenzoHosting.com
http://www.benjaminsterling.com

[jQuery] Re: Data containing ? at the start getting converted to jsonp.... by ajax() call

2007-12-06 Thread Ben Bennett 

Sadly. That doesn't do it either.

I am deliberately trying to send a ? (since the bug occurred when a
user typed it into an input box that I use as the basis of an AJAX
request).  The bug occurs because jQuery is treating =? as a special
string, but it can happen for mundane reasons, and there is no way to
disable the behavior.

-ben

On Dec 6, 11:30 am, Benjamin Sterling
[EMAIL PROTECTED] wrote:
 Ben, (its like talking to myself)
 Put cache:true into your ajax call, the ? is to prevent caching.

 On 12/6/07, Ben Bennett [EMAIL PROTECTED] wrote:





  Is this the wrong forum for this question?  Should I take it to the
  dev list or put it in the bug tracker?

  Thanks,

  -ben

  On Dec 4, 2:00 pm, Ben Bennett [EMAIL PROTECTED] wrote:
   This is my first post so I really should thank everyone for a
   fanatastic library.

   However, I think I have found a bug...

   Using jQuery 1.2.1, if I have:

   $.ajax({
 type: POST,
 url: test.html,
 dataType: json,
 data: {query: queryString},

   });

   When queryString starts with a ? it will get converted to
   jsonp1231234124...

   This is clearly happening because of the code at line 2226 of the full
   release version:
   // Build temporary JSONP function
   if ( s.dataType == json  (s.data 
   s.data.match(jsre) || s.url.match(jsre)) ) {
   jsonp = jsonp + jsc++;

   // Replace the =? sequence both in the query
   string and the data
   if ( s.data )
   s.data = s.data.replace(jsre, = +
   jsonp);
   s.url = s.url.replace(jsre, = + jsonp);

   ...

   But I see no way to prevent that from happening.

   Now... one might suggest that I should avoid a leading ? in my option
   names.  But I am taking them from input boxes and ? is a valid thing
   for a user to type.  Unfortunately there seems to be no good way to
   escape the string to prevent this behavior (without teaching the
   called code how to unescape it).

   Also, the docs don't mention that the =? escaping happens to a json
   dataType... I see it for jsonp.

   Is this behavior intentional?  If so, there should be a way to
   suppress it or at a way for the calling code to escape the values to
   cause a leading ? to be passed to the server.

   -ben

 --
 Benjamin 
 Sterlinghttp://www.KenzoMedia.comhttp://www.KenzoHosting.comhttp://www.benjaminsterling.com

[jQuery] Re: Data containing ? at the start getting converted to jsonp.... by ajax() call

2007-12-06 Thread Benjamin Sterling 
I am doing something encodeURIComponent(url) in a wordpress plugin, would
that help?

On 12/6/07, Ben Bennett [EMAIL PROTECTED] wrote:


 Sadly. That doesn't do it either.

 I am deliberately trying to send a ? (since the bug occurred when a
 user typed it into an input box that I use as the basis of an AJAX
 request).  The bug occurs because jQuery is treating =? as a special
 string, but it can happen for mundane reasons, and there is no way to
 disable the behavior.

 -ben

 On Dec 6, 11:30 am, Benjamin Sterling
 [EMAIL PROTECTED] wrote:
  Ben, (its like talking to myself)
  Put cache:true into your ajax call, the ? is to prevent caching.
 
  On 12/6/07, Ben Bennett [EMAIL PROTECTED] wrote:
 
 
 
 
 
   Is this the wrong forum for this question?  Should I take it to the
   dev list or put it in the bug tracker?
 
   Thanks,
 
   -ben
 
   On Dec 4, 2:00 pm, Ben Bennett [EMAIL PROTECTED] wrote:
This is my first post so I really should thank everyone for a
fanatastic library.
 
However, I think I have found a bug...
 
Using jQuery 1.2.1, if I have:
 
$.ajax({
  type: POST,
  url: test.html,
  dataType: json,
  data: {query: queryString},
 
});
 
When queryString starts with a ? it will get converted to
jsonp1231234124...
 
This is clearly happening because of the code at line 2226 of the
 full
release version:
// Build temporary JSONP function
if ( s.dataType == json  (s.data 
s.data.match(jsre) || s.url.match(jsre)) ) {
jsonp = jsonp + jsc++;
 
// Replace the =? sequence both in the query
string and the data
if ( s.data )
s.data = s.data.replace(jsre, = +
jsonp);
s.url = s.url.replace(jsre, = + jsonp);
 
...
 
But I see no way to prevent that from happening.
 
Now... one might suggest that I should avoid a leading ? in my
 option
names.  But I am taking them from input boxes and ? is a valid thing
for a user to type.  Unfortunately there seems to be no good way to
escape the string to prevent this behavior (without teaching the
called code how to unescape it).
 
Also, the docs don't mention that the =? escaping happens to a json
dataType... I see it for jsonp.
 
Is this behavior intentional?  If so, there should be a way to
suppress it or at a way for the calling code to escape the values to
cause a leading ? to be passed to the server.
 
-ben
 
  --
  Benjamin
 Sterlinghttp://www.KenzoMedia.comhttp://www.KenzoHosting.comhttp://www.benjaminsterling.com




-- 
Benjamin Sterling
http://www.KenzoMedia.com
http://www.KenzoHosting.com
http://www.benjaminsterling.com

[jQuery] Re: Data containing ? at the start getting converted to jsonp.... by ajax() call

2007-12-06 Thread Ben Bennett 

Sadly... no.

If I were to do that then I would get double escaped data...

The code that converts an object to a serialized form is already
calling encodeURIComponent on the key names and the values... (see
http://dev.jquery.com/browser/trunk/jquery/src/ajax.js line 454ish)

-ben

On Dec 6, 3:27 pm, Benjamin Sterling
[EMAIL PROTECTED] wrote:
 I am doing something encodeURIComponent(url) in a wordpress plugin, would
 that help?

 On 12/6/07, Ben Bennett [EMAIL PROTECTED] wrote:





  Sadly. That doesn't do it either.

  I am deliberately trying to send a ? (since the bug occurred when a
  user typed it into an input box that I use as the basis of an AJAX
  request).  The bug occurs because jQuery is treating =? as a special
  string, but it can happen for mundane reasons, and there is no way to
  disable the behavior.

  -ben

  On Dec 6, 11:30 am, Benjamin Sterling
  [EMAIL PROTECTED] wrote:
   Ben, (its like talking to myself)
   Put cache:true into your ajax call, the ? is to prevent caching.

   On 12/6/07, Ben Bennett [EMAIL PROTECTED] wrote:

Is this the wrong forum for this question?  Should I take it to the
dev list or put it in the bug tracker?

Thanks,

-ben

On Dec 4, 2:00 pm, Ben Bennett [EMAIL PROTECTED] wrote:
 This is my first post so I really should thank everyone for a
 fanatastic library.

 However, I think I have found a bug...

 Using jQuery 1.2.1, if I have:

 $.ajax({
   type: POST,
   url: test.html,
   dataType: json,
   data: {query: queryString},

 });

 When queryString starts with a ? it will get converted to
 jsonp1231234124...

 This is clearly happening because of the code at line 2226 of the
  full
 release version:
 // Build temporary JSONP function
 if ( s.dataType == json  (s.data 
 s.data.match(jsre) || s.url.match(jsre)) ) {
 jsonp = jsonp + jsc++;

 // Replace the =? sequence both in the query
 string and the data
 if ( s.data )
 s.data = s.data.replace(jsre, = +
 jsonp);
 s.url = s.url.replace(jsre, = + jsonp);

 ...

 But I see no way to prevent that from happening.

 Now... one might suggest that I should avoid a leading ? in my
  option
 names.  But I am taking them from input boxes and ? is a valid thing
 for a user to type.  Unfortunately there seems to be no good way to
 escape the string to prevent this behavior (without teaching the
 called code how to unescape it).

 Also, the docs don't mention that the =? escaping happens to a json
 dataType... I see it for jsonp.

 Is this behavior intentional?  If so, there should be a way to
 suppress it or at a way for the calling code to escape the values to
 cause a leading ? to be passed to the server.

 -ben

   --
   Benjamin
  Sterlinghttp://www.KenzoMedia.comhttp://www.KenzoHosting.comhttp://www.benjam...

 --
 Benjamin 
 Sterlinghttp://www.KenzoMedia.comhttp://www.KenzoHosting.comhttp://www.benjaminsterling.com

[jQuery] Re: Data containing ? at the start getting converted to jsonp.... by ajax() call

2007-12-04 Thread Scott Trudeau 
? is a reserved character in URLs (it separates the domain from the GET
parameters) and must be encoded if it's data.

http://www.blooberry.com/indexdot/html/topics/urlencoding.htm

Scott

On Dec 4, 2007 2:00 PM, Ben Bennett [EMAIL PROTECTED] wrote:


 This is my first post so I really should thank everyone for a
 fanatastic library.

 However, I think I have found a bug...

 Using jQuery 1.2.1, if I have:

 $.ajax({
  type: POST,
  url: test.html,
  dataType: json,
  data: {query: queryString},
 });

 When queryString starts with a ? it will get converted to
 jsonp1231234124...

 This is clearly happening because of the code at line 2226 of the full
 release version:
// Build temporary JSONP function
if ( s.dataType == json  (s.data 
 s.data.match(jsre) || s.url.match(jsre)) ) {
jsonp = jsonp + jsc++;

// Replace the =? sequence both in the query
 string and the data
if ( s.data )
s.data = s.data.replace(jsre, = +
 jsonp);
s.url = s.url.replace(jsre, = + jsonp);

 ...

 But I see no way to prevent that from happening.

 Now... one might suggest that I should avoid a leading ? in my option
 names.  But I am taking them from input boxes and ? is a valid thing
 for a user to type.  Unfortunately there seems to be no good way to
 escape the string to prevent this behavior (without teaching the
 called code how to unescape it).

 Also, the docs don't mention that the =? escaping happens to a json
 dataType... I see it for jsonp.

 Is this behavior intentional?  If so, there should be a way to
 suppress it or at a way for the calling code to escape the values to
 cause a leading ? to be passed to the server.

 -ben




-- 
--
Scott Trudeau
scott.trudeau AT gmail DOT com
http://sstrudeau.com/
AIM: sodthestreets

[jQuery] Re: Data containing ? at the start getting converted to jsonp.... by ajax() call

2007-12-04 Thread Ben Bennett 

Thanks for thinking about this.  However the items in the data object
are being escaped automatically for me (since I have not set the
processData option to false).  So if I escape it, then it is double
escaped on the wire.

Note that if the ? does not appear at the start of the string then it
is correctly escaped and transmitted across the wire.

Also, the regular expression being used to find the strings to change
looks for both =? and =%3F (the escaped form).

This behavior is present in the latest svn version of the code too:
  http://dev.jquery.com/browser/trunk/jquery/src/ajax.js

-ben

On Dec 4, 2:43 pm, Scott Trudeau [EMAIL PROTECTED] wrote:
 ? is a reserved character in URLs (it separates the domain from the GET
 parameters) and must be encoded if it's data.

 http://www.blooberry.com/indexdot/html/topics/urlencoding.htm

 Scott

 On Dec 4, 2007 2:00 PM, Ben Bennett [EMAIL PROTECTED] wrote:





  This is my first post so I really should thank everyone for a
  fanatastic library.

  However, I think I have found a bug...

  Using jQuery 1.2.1, if I have:

  $.ajax({
   type: POST,
   url: test.html,
   dataType: json,
   data: {query: queryString},
  });

  When queryString starts with a ? it will get converted to
  jsonp1231234124...

  This is clearly happening because of the code at line 2226 of the full
  release version:
 // Build temporary JSONP function
 if ( s.dataType == json  (s.data 
  s.data.match(jsre) || s.url.match(jsre)) ) {
 jsonp = jsonp + jsc++;

 // Replace the =? sequence both in the query
  string and the data
 if ( s.data )
 s.data = s.data.replace(jsre, = +
  jsonp);
 s.url = s.url.replace(jsre, = + jsonp);

  ...

  But I see no way to prevent that from happening.

  Now... one might suggest that I should avoid a leading ? in my option
  names.  But I am taking them from input boxes and ? is a valid thing
  for a user to type.  Unfortunately there seems to be no good way to
  escape the string to prevent this behavior (without teaching the
  called code how to unescape it).

  Also, the docs don't mention that the =? escaping happens to a json
  dataType... I see it for jsonp.

  Is this behavior intentional?  If so, there should be a way to
  suppress it or at a way for the calling code to escape the values to
  cause a leading ? to be passed to the server.

  -ben

 --
 --
 Scott Trudeau
 scott.trudeau AT gmail DOT comhttp://sstrudeau.com/
 AIM: sodthestreets