[jQuery] Re: Frustrating Scope Question with getJSON
I'd ideally just like the function to return the shortUrl from the
json results but can't seem to get it anywhere but the callback
function.
...
$.getJSON(http://api.bit.ly/shorten?version=2.0.1longUrl=;
+ url + login= + apiLogin + apiKey= + apiKey, function(data){
shortURL = data.results[url].shortUrl;
});
return shortURL;
You're returning shortURL from the function before $.getJSON has
returned! The shortenURL function can't run synchronously and return
the URL if it's calling an asynchronous ajax method. Instead of
returning the URL, the function should pass in a callback.
[jQuery] Re: Frustrating Scope Question with getJSON
I've tried that and still can't seem to get the data into any sort of usable scope.
[jQuery] Re: Frustrating Scope Question with getJSON
On Sep 19, 11:34 am, Bill H dysfunct...@gmail.com wrote: I've tried that and still can't seem to get the data into any sort of usable scope. The problem is that while you may be understanding scope, you are not understanding asynchronous calls the $.getJSON call doesn't return anything Whatever you are wanting to do with shortURL needs to be done inside, or at least kicked off from inside, the getJSON's success event
[jQuery] Re: Frustrating Scope Question with getJSON
In other words, you have to redesign your shortenURL function, like this:
function shortenURL( url, callback ) {
var apiKey = 'APIKEY';
var apiLogin = 'LOGIN';
$.getJSON(
http://api.bit.ly/shorten?version=2.0.1longUrl=;
+ url + login= + apiLogin + apiKey= + apiKey,
function( data ) {
callback( data.results[url].shortUrl );
}
);
}
and call it like this:
shortenURL( 'http://www.example.com/', function( url ) {
alert( 'Short URL is: ' + url );
});
-Mike
On Sat, Sep 19, 2009 at 10:00 AM, MorningZ morni...@gmail.com wrote:
On Sep 19, 11:34 am, Bill H dysfunct...@gmail.com wrote:
I've tried that and still can't seem to get the data into any sort of
usable scope.
The problem is that while you may be understanding scope, you are not
understanding asynchronous calls the $.getJSON call doesn't
return anything
Whatever you are wanting to do with shortURL needs to be done
inside, or at least kicked off from inside, the getJSON's success event
