[jQuery] Re: nth-child(n) not working for me - I didn't see my previous post

2008-09-18 Thread kcharles

You rock!
That was it.
-Kevin


[jQuery] Re: nth-child(n) not working for me - I didn't see my previous post

2008-09-17 Thread ricardobeat

You're not really referencing the 'n' variable you just defined, as
you're passing a string.

var n = 2;
$(#filterTable tbody tr td:nth-child(+n+)).each(function(){


On Sep 17, 2:24 pm, kcharles [EMAIL PROTECTED] wrote:
 I switch between var n = 2; nth-child(n) and nth-child(2) and get
 different behavior.
 Any suggestions/work arounds?
 Thanks!

 Here is the code:

 html
 head
 titlenth child/title
 script type=text/javascript src=jquery.js/script
 script type=text/javascript
 //Add input box for each column

 $(function(){
          var n = 2;
 //       $(#filterTable tbody tr td:nth-child(2)).each(function(){
          $(#filterTable tbody tr td:nth-child(n)).each(function(){
                  $(this).append(this row);
          });

 });

 /script
 /head
 body

 table id=filterTable  width=580 border=1
 thead
 tr
 thNumber/th
 thLetter/th
 thMore/th
 /tr
 /thead

 tbody
 tr
 td1/td
 tdA/td
 tdA/td
 /tr

 tr
 td2/td
 tdA/td
 tdB/td
 /tr

 tr
 td3/td
 tdB/td
 td3/td
 /tr

 tr
 td4/td
 tdB/td
 tdD/td

 /tr
 /tbody
 /table

 /body
 /html