[jQuery] Re: urgent json parsing error!!!! very important
My guess is that you're not building an extension for twitter that
will run on their site, so you're violating the cross domain request
rule. You cannot directly request from twitter.com, you'd have to
proxy through a page on your site (some page that forwarded this
request to twitter and returned the same result) or you can use jsonp
to achieve the same effect, which is probably what you're looking for.
Hopefully this will help you.
$(document).ready(function(){
$.ajax( {
url:
'http://twitter.com/friendships/exists.json?user_a='+
usera + 'user_b=' + userb,
dataType: jsonp,
success: function(data)
{
if(data == true)
{
var newDiv =
'ptrue/p';
}
$('#content').append(newDiv);
}
})});
On Sat, Jun 6, 2009 at 3:47 AM, grand_unifierjijodasgu...@gmail.com wrote:
!-- this is the javascript json parser function --
script type=text/javascript src=../jquery-1.2.6.min.js
/script
script type=text/javascript
$(document).ready(function()
{
$('form#search').bind(submit, function(e)
{
e.preventDefault();
$('#content').html('');
var query1 = urlencode($('input[name=user_a]').val
()); //userA
var query2 = urlencode($('input
[name=user_b]').val()); //userB
$.getJSON('http://twitter.com/friendships/exists.json?
user_a='+query1+'user_b='+query2,
function(data)
{
if(data.text == 'true')
{
var newDiv = 'ptrue/p';
}
$('#content').append(newDiv);
});
});
});
function urlencode(str) {
return escape(str).replace(/\+/g,'%2B').replace(/%20/g,
'+').replace(/\*/g, '%2A').replace(/\//g, '%2F').replace(/@/g, '%40');
}
});
/script
!-- javascript ends here --
i dont understand wats wron wth this code...could anyone plz correct
itplzits very frustratin...
any help wil be appreciated...
[jQuery] Re: urgent json parsing error!!!! very important
It's not a cross-domain security issue, it's a JSONP issue (maybe an
authentication issue). Twitter's API allows you to make GET requests
which are returned as JSON with an option to specify a callback
function. Afaik it doesn't support JSONP however. You can add
callback=some_function and the response will be:
some_function(true)
In a cross-domain getJSON call jQuery appends the response to the
document in a SCRIPT tag (no ajax involved). The problem may be that
this is an API call that requires authentication. I say 'may' because
it looks like you can hit the URL in the browser (try Chrome) and get
the response back without setting the auth header. (try
http://twitter.com/friendships/exists.json?user_a=cnnuser_b=cnnicallback=foobar)
My first suggestion is create a global callback function, then append
that function name to the URL (as above).
On Jun 6, 1:39 pm, Aaron Gundel aaron.gun...@gmail.com wrote:
My guess is that you're not building an extension for twitter that
will run on their site, so you're violating the cross domain request
rule. You cannot directly request from twitter.com, you'd have to
proxy through a page on your site (some page that forwarded this
request to twitter and returned the same result) or you can use jsonp
to achieve the same effect, which is probably what you're looking for.
Hopefully this will help you.
$(document).ready(function(){
$.ajax( {
url:
'http://twitter.com/friendships/exists.json?user_a='+
usera + 'user_b=' + userb,
dataType: jsonp,
success: function(data)
{
if(data == true)
{
var newDiv =
'ptrue/p';
}
$('#content').append(newDiv);
}
})});
On Sat, Jun 6, 2009 at 3:47 AM, grand_unifierjijodasgu...@gmail.com wrote:
!-- this is the javascript json parser function --
script type=text/javascript src=../jquery-1.2.6.min.js
/script
script type=text/javascript
$(document).ready(function()
{
$('form#search').bind(submit, function(e)
{
e.preventDefault();
$('#content').html('');
var query1 = urlencode($('input[name=user_a]').val
()); //userA
var query2 = urlencode($('input
[name=user_b]').val()); //userB
$.getJSON('http://twitter.com/friendships/exists.json?
user_a='+query1+'user_b='+query2,
function(data)
{
if(data.text == 'true')
{
var newDiv = 'ptrue/p';
}
$('#content').append(newDiv);
});
});
});
function urlencode(str) {
return escape(str).replace(/\+/g,'%2B').replace(/%20/g,
'+').replace(/\*/g, '%2A').replace(/\//g, '%2F').replace(/@/g, '%40');
}
});
/script
!-- javascript ends here --
i dont understand wats wron wth this code...could anyone plz correct
itplzits very frustratin...
any help wil be appreciated...
