[jQuery] Re: using replaceWith to overwrite a stylesheet, dynamically set styles
I should specify that I have tested the css, it works. It could be a
caching problem but I've set my cache-control to no-cache and the
expires header comfortably in the past. So I'm wondering if there is
some problem with registering new styles when they are dynamically
loaded after page load.
The current browser I'm testing on is Firefox.
On Feb 17, 7:38 am, pantagruel rasmussen.br...@gmail.com wrote:
Hi,
I want to do the following:
function CheckCurrentDataStream(){
window.setTimeout (CheckCurrentDataStream(), 2);
$(#statuscss).replaceWith('link rel=stylesheet href=http://
localhost:8080/statuschangealert.php type=text/css /');
}
The css I'm getting either is empty or it has a style in it changing
the color of a certain link to let people know that there is waiting
data for them to get.
The thing is when I replace the stylesheet my new styles do not
register. Is there a method to force the styles to be evaluated, or
should I instead use script insertion instead of css insertion?
[jQuery] Re: using replaceWith to overwrite a stylesheet, dynamically set styles
Ok, I solved the problem with using !important on the rule. But after
some more looking at the technique it is probably better to use script
insertion anyway.
On Feb 17, 7:38 am, pantagruel rasmussen.br...@gmail.com wrote:
Hi,
I want to do the following:
function CheckCurrentDataStream(){
window.setTimeout (CheckCurrentDataStream(), 2);
$(#statuscss).replaceWith('link rel=stylesheet href=http://
localhost:8080/statuschangealert.php type=text/css /');
}
The css I'm getting either is empty or it has a style in it changing
the color of a certain link to let people know that there is waiting
data for them to get.
The thing is when I replace the stylesheet my new styles do not
register. Is there a method to force the styles to be evaluated, or
should I instead use script insertion instead of css insertion?
