Re: [JUG-Indonesia] [ask]split string d J2ME??

2008-08-12 Terurut Topik Robertus Lilik Haryanto
Yup, emang gak ada split kok...
Coba pake StringTokenizer yg pernah gw kirim...

2008/8/13 timotius sakti <[EMAIL PROTECTED]>

>   Di J2ME ngga ada method split() pada String, kurasa Felix memberikan
> example untuk memanfaatkan kemampuan split() di J2SE .
>
> - Timo
>
> visit my blog:
> http://nomoreac.wordpress.com
>
> --- On *Wed, 8/13/08, Thomas Edwin Santosa <
> [EMAIL PROTECTED]>* wrote:
>
>
>  
>



-- 
Robertus Lilik Haryanto
Phone: +62-817-008-0078
Yahoo: secangkirkopipanas
Articles: http://ilmukomputer.com/author/lilik.haryanto
Blog: http://secangkirkopipanas.wordpress.com/
Motto: You Can If You Want

-
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Re: [JUG-Indonesia] [ask]split string d J2ME??

2008-08-12 Terurut Topik timotius sakti
Di J2ME ngga ada method split() pada String, kurasa Felix memberikan example 
untuk memanfaatkan kemampuan split() di J2SE .

- Timo

visit my blog:

http://nomoreac.wordpress.com

--- On Wed, 8/13/08, Thomas Edwin Santosa <[EMAIL PROTECTED]> wrote:
From: Thomas Edwin Santosa <[EMAIL PROTECTED]>
Subject: Re: [JUG-Indonesia] [ask]split string d J2ME??
To: jug-indonesia@yahoogroups.com
Date: Wednesday, August 13, 2008, 1:14 AM











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Felix Halim wrote:

> import java.util.*;

> 

> public class Split {

>   public static void main(String[ ] args){

>   String s = "[EMAIL PROTECTED]@# [EMAIL PROTECTED]@ [EMAIL 
> PROTECTED]";

> 

>   String[] ss = s.split("@#| [EMAIL PROTECTED]"); // pake regex 
> aja

> 

>   for (String x : ss) System.out.println( x);

>   }

> }

> 



di JME ada?



- --

Salam/Regards,

Thomas

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Re: [JUG-Indonesia] [ask]split string d J2ME??

2008-08-12 Terurut Topik Thomas Wiradikusuma
IMO, String.split hanya ada di 1.4+, gak ada di CLDC.



salam hangat,
Thomas Wiradikusuma
Follow me in Twitter! http://www.twitter.com/wiradikusuma
http://wiradikusuma.blogspot.com/2008/07/malikat-pencabut-nyawanya-thomas.html 
  <-- ternyata gw punya musuh :D




On 13 Agu 08, at 11:35, Felix Halim wrote:

> import java.util.*;
>
> public class Split {
>   public static void main(String[] args){
>   String s = "[EMAIL PROTECTED]@[EMAIL PROTECTED]@[EMAIL 
> PROTECTED]";
>
>   String[] ss = s.split("@#|[EMAIL PROTECTED]"); // pake regex aja
>
>   for (String x : ss) System.out.println(x);
>   }
> }
>
> Felix Halim



Re: [JUG-Indonesia] [ask]split string d J2ME??

2008-08-12 Terurut Topik Thomas Edwin Santosa
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Felix Halim wrote:
> import java.util.*;
> 
> public class Split {
>   public static void main(String[] args){
>   String s = "[EMAIL PROTECTED]@[EMAIL PROTECTED]@[EMAIL 
> PROTECTED]";
> 
>   String[] ss = s.split("@#|[EMAIL PROTECTED]"); // pake regex aja
> 
>   for (String x : ss) System.out.println(x);
>   }
> }
> 

di JME ada?

- --
Salam/Regards,
Thomas
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Re: [JUG-Indonesia] [ask]split string d J2ME??

2008-08-12 Terurut Topik Felix Halim
import java.util.*;

public class Split {
public static void main(String[] args){
String s = "[EMAIL PROTECTED]@[EMAIL PROTECTED]@[EMAIL 
PROTECTED]";

String[] ss = s.split("@#|[EMAIL PROTECTED]"); // pake regex aja

for (String x : ss) System.out.println(x);
}
}

Felix Halim

On Mon, Aug 11, 2008 at 7:02 PM, Surya <[EMAIL PROTECTED]> wrote:
> wadu bingung juga sekali liat d j2me nggak ad fungsi split dari
> library standardny.
>
> ak puny kasus gni :
>
> String list = "";
>
> list += btAdd + "@#" + nm + "@#" + dt + "[EMAIL PROTECTED]";
>
> aku mo split berdasarkan sparator "@#" dan "[EMAIL PROTECTED]".
> kendalanya pasti pas split "[EMAIL PROTECTED]" index ke 2 ny pst null;
>
> code yg ak pakai buat split:
>
> public void setToListHistoryPrivate(String lg) throws
> RecordStoreException {
>listPrivateHistory = new ListPrivateHistory(parent);
>String[] listSplit2;
>String[] listSplit1 = split1(lg);
>for (int i = 0; i < listSplit1.length; i++) {
>listSplit2 = split2(listSplit1[i]);
>listPrivateHistory.addItem(listSplit2[0], listSplit2[1],
> listSplit2[2]);
>}
>}
>
> private String[] split1(String original) {
>Vector nodes = new Vector();
>String separator = "[EMAIL PROTECTED]";
>
>// Parse nodes into vector
>int index = original.indexOf(separator);
>while (index >= 0) {
>nodes.addElement(original.substring(0, index));
>original = original.substring(index + separator.length());
>index = original.indexOf(separator);
>}
>// Get the last node
>nodes.addElement(original);
>
>// Create splitted string array
>String[] result = new String[nodes.size()];
>if (nodes.size() > 0) {
>for (int loop = 0; loop < nodes.size(); loop++) {
>result[loop] = (String) nodes.elementAt(loop);
>System.out.println(result[loop]);
>}
>
>}
>
>return result;
>}
>
> private String[] split2(String original) {
>Vector nodes = new Vector();
>String separator = "@#";
>
>// Parse nodes into vector
>int index = original.indexOf(separator);
>while (index >= 0) {
>nodes.addElement(original.substring(0, index));
>original = original.substring(index + separator.length());
>index = original.indexOf(separator);
>}
>// Get the last node
>nodes.addElement(original);
>
>// Create splitted string array
>String[] result = new String[nodes.size()];
>if (nodes.size() > 0) {
>for (int loop = 0; loop < nodes.size(); loop++) {
>result[loop] = (String) nodes.elementAt(loop);
>System.out.println(result[loop]);
>}
>
>}
>
>return result;
>}
>
> mohon bantuannya...
> penasaran soalny
>
>
> 
>
> Kalau mau keluar dari mailing list ini, caranya kirim sebuah email ke [EMAIL 
> PROTECTED]
>
> Jangan lupa, website JUG Indonesia adalah http://www.jug.or.id
>
> Yahoo! Groups Links
>
>
>
>


Re: [JUG-Indonesia] [ask]split string d J2ME??

2008-08-11 Terurut Topik timotius sakti
import java.util.*;
public class Test {

    public static Vector mySplit(String input,String []delim) {
        String temp = input + delim[0];
        Vector ret = new Vector();
        int i=0;
        String target = "";
        while(i= temp.length()) continue;
                boolean match = true;
                for(int k=0,m=i;khttp://nomoreac.wordpress.com

--- On Mon, 8/11/08, Surya <[EMAIL PROTECTED]> wrote:
From: Surya <[EMAIL PROTECTED]>
Subject: [JUG-Indonesia]  [ask]split string d J2ME??
To: jug-indonesia@yahoogroups.com
Date: Monday, August 11, 2008, 7:02 AM











wadu bingung juga sekali liat d j2me nggak ad fungsi split dari

library standardny.



ak puny kasus gni :



String list = "";



list += btAdd + "@#" + nm + "@#" + dt + "[EMAIL PROTECTED]";



aku mo split berdasarkan sparator "@#" dan "[EMAIL PROTECTED]".

kendalanya pasti pas split "[EMAIL PROTECTED]" index ke 2 ny pst null;



code yg ak pakai buat split:



public void setToListHistoryPri vate(String lg) throws

RecordStoreExceptio n {

listPrivateHistory = new ListPrivateHistory( parent);

String[] listSplit2;

String[] listSplit1 = split1(lg);

for (int i = 0; i < listSplit1.length; i++) {

listSplit2 = split2(listSplit1[ i]);

listPrivateHistory. addItem(listSpli t2[0], listSplit2[1] ,

listSplit2[2] );

}

}



private String[] split1(String original) {

Vector nodes = new Vector();

String separator = "[EMAIL PROTECTED]";



// Parse nodes into vector

int index = original.indexOf( separator) ;

while (index >= 0) {

nodes.addElement( original. substring( 0, index));

original = original.substring( index + separator.length( ));

index = original.indexOf( separator) ;

}

// Get the last node

nodes.addElement( original) ;



// Create splitted string array

String[] result = new String[nodes. size()];

if (nodes.size( ) > 0) {

for (int loop = 0; loop < nodes.size() ; loop++) {

result[loop] = (String) nodes.elementAt( loop);

System.out.println( result[loop] );

}



}



return result;

}



private String[] split2(String original) {

Vector nodes = new Vector();

String separator = "@#";



// Parse nodes into vector

int index = original.indexOf( separator) ;

while (index >= 0) {

nodes.addElement( original. substring( 0, index));

original = original.substring( index + separator.length( ));

index = original.indexOf( separator) ;

}

// Get the last node

nodes.addElement( original) ;



// Create splitted string array

String[] result = new String[nodes. size()];

if (nodes.size( ) > 0) {

for (int loop = 0; loop < nodes.size() ; loop++) {

result[loop] = (String) nodes.elementAt( loop);

System.out.println( result[loop] );

}



}



return result;

}



mohon bantuannya.. .

penasaran soalny




  




 

















  

Re: [JUG-Indonesia] [ask]split string d J2ME??

2008-08-11 Terurut Topik Robertus Lilik Haryanto
Yup



2008/8/12 Abdul Arfan <[EMAIL PROTECTED]>

>   itu diambil dari source code java ya?
>
> 2008/8/12 Robertus Lilik Haryanto <[EMAIL 
> PROTECTED]
> >:
>
> > Coba pake class StringTokenizer berikut...
> > Semoga membantu
> >
> >
>
> --
> Abdul Arfan
> http://arfan86.blogspot.com
>  
>



-- 
Robertus Lilik Haryanto
Phone: +62-817-008-0078
Yahoo: secangkirkopipanas
Articles: http://ilmukomputer.com/author/lilik.haryanto
Blog: http://secangkirkopipanas.wordpress.com/
Motto: You Can If You Want

-
Mau ngobrol-ngobrol seputar pemrograman? Kunjungi
http://www.secangkirkopipanas.org
JavaME Group Indonesia: [EMAIL PROTECTED]


Re: [JUG-Indonesia] [ask]split string d J2ME??

2008-08-11 Terurut Topik Abdul Arfan
itu diambil dari source code java ya?



2008/8/12 Robertus Lilik Haryanto <[EMAIL PROTECTED]>:
> Coba pake class StringTokenizer berikut...
> Semoga membantu
>
>


-- 
Abdul Arfan
http://arfan86.blogspot.com


Re: [JUG-Indonesia] [ask]split string d J2ME??

2008-08-11 Terurut Topik Robertus Lilik Haryanto
Coba pake class StringTokenizer berikut...
Semoga membantu



2008/8/11 Ifnu bima <[EMAIL PROTECTED]>

>   aduh bikin yang susah banged nih, yang gampang2 aja deh heheh
>
> alrogitmanya gini nih :
> Vector result = new Vector();
> char separator = ';';
> String current;
> for(int i=0;i
> if(string.charAt(i)!=separator){
> current += string.charAt(i);
> } else {
> result.add(current);
> current = "";
> }
>
> }
>
> --
> Senior Engineer @ ArtiVisi Intermedia
> Java Training Center
> See our course @ artivisi.com
>
> http://ifnu.artivisi.com
> +62 856 9211 8687
> regards
>  
>



-- 
Robertus Lilik Haryanto
Phone: +62-817-008-0078
Yahoo: secangkirkopipanas
Articles: http://ilmukomputer.com/author/lilik.haryanto
Blog: http://secangkirkopipanas.wordpress.com/
Motto: You Can If You Want

-
Mau ngobrol-ngobrol seputar pemrograman? Kunjungi
http://www.secangkirkopipanas.org
JavaME Group Indonesia: [EMAIL PROTECTED]


StringTokenizer.java
Description: Binary data


Re: [JUG-Indonesia] [ask]split string d J2ME??

2008-08-11 Terurut Topik Ifnu bima
aduh bikin yang susah banged nih, yang gampang2 aja deh heheh

alrogitmanya gini nih :
Vector result = new Vector();
char separator = ';';
String current;
for(int i=0;ihttp://ifnu.artivisi.com
+62 856 9211 8687
regards


[JUG-Indonesia] [ask]split string d J2ME??

2008-08-11 Terurut Topik Surya
wadu bingung juga sekali liat d j2me nggak ad fungsi split dari
library standardny.

ak puny kasus gni :

String list = "";

list += btAdd + "@#" + nm + "@#" + dt + "[EMAIL PROTECTED]";

aku mo split berdasarkan sparator "@#" dan "[EMAIL PROTECTED]".
kendalanya pasti pas split "[EMAIL PROTECTED]" index ke 2 ny pst null;

code yg ak pakai buat split:

public void setToListHistoryPrivate(String lg) throws
RecordStoreException {
listPrivateHistory = new ListPrivateHistory(parent);
String[] listSplit2;
String[] listSplit1 = split1(lg);
for (int i = 0; i < listSplit1.length; i++) {
listSplit2 = split2(listSplit1[i]);
listPrivateHistory.addItem(listSplit2[0], listSplit2[1],
listSplit2[2]);
}
}

private String[] split1(String original) {
Vector nodes = new Vector();
String separator = "[EMAIL PROTECTED]";

// Parse nodes into vector
int index = original.indexOf(separator);
while (index >= 0) {
nodes.addElement(original.substring(0, index));
original = original.substring(index + separator.length());
index = original.indexOf(separator);
}
// Get the last node
nodes.addElement(original);

// Create splitted string array
String[] result = new String[nodes.size()];
if (nodes.size() > 0) {
for (int loop = 0; loop < nodes.size(); loop++) {
result[loop] = (String) nodes.elementAt(loop);
System.out.println(result[loop]);
}

}

return result;
}

private String[] split2(String original) {
Vector nodes = new Vector();
String separator = "@#";

// Parse nodes into vector
int index = original.indexOf(separator);
while (index >= 0) {
nodes.addElement(original.substring(0, index));
original = original.substring(index + separator.length());
index = original.indexOf(separator);
}
// Get the last node
nodes.addElement(original);

// Create splitted string array
String[] result = new String[nodes.size()];
if (nodes.size() > 0) {
for (int loop = 0; loop < nodes.size(); loop++) {
result[loop] = (String) nodes.elementAt(loop);
System.out.println(result[loop]);
}

}

return result;
}

mohon bantuannya...
penasaran soalny