[julia-users] How to know the size of a large array stored in a csv file (greater than RAM
How to know the size of a large array stored in a csv file (greater than RAM , I can not use readcsv. After that I want to apply the open (file, size, size) Paul
Re: [julia-users] Re: How to know the size of a large array stored in a csv file (greater than RAM
W dniu 2015-06-15 o 15:13, Ian Hellström pisze: Would it be possible/feasible to introduce external data frames (like in Revolution Analytics R), so that we can work with data that does not fit into memory? Just an idea... this Idea is a stream (open ) but firs I mus know size of data . Do You know another way? Paul
Re: [julia-users] Re: How to know the size of a large array stored in a csv file (greater than RAM
This way:
how many rows/line
o=open("storage2.txt")
nol=0
while readline(o)!=""
nol+=1
end
nol
close(o)
how anay regular col ?
o=open("storage2.txt")
cnt=0
for line=eachline(o)
cnt=max(cnt, length(split(line, "\t")))
end
close(o)
cnt
Paul
W dniu poniedziałek, 15 czerwca 2015 21:31:41 UTC+2 użytkownik paul analyst
napisał:
>
> W dniu 2015-06-15 o 15:13, Ian Hellström pisze:
> > Would it be possible/feasible to introduce external data frames (like in
> Revolution Analytics R), so that we can work with data that does not fit
> into memory? Just an idea...
> this Idea is a stream (open ) but firs I mus know size of data .
> Do You know another way?
> Paul
>
>
[julia-users] How to read any lines with stream open(file)
If o is stream o=open(file) how to read any line ?e.g. 15 julia> readline(o,15) ERROR: MethodError: `readline` has no method matching readline(::IOStream, ::Int64)SYSTEM: show(lasterr) caused error Paul
Re: [julia-users] Re: How to read any lines with stream open(file)
Unfrtunatly can`t run, (in Julia 3.6 the same)
_
_ _ _(_)_ | A fresh approach to technical computing
(_) | (_) (_)| Documentation: http://docs.julialang.org
_ _ _| |_ __ _ | Type "help()" for help.
| | | | | | |/ _` | |
| | |_| | | | (_| | | Version 0.4.0-dev+2847 (2015-01-21 18:34 UTC)
_/ |\__'_|_|_|\__'_| | Commit fc61385 (146 days old master)
|__/ | x86_64-w64-mingw32
julia> f = open("temp.txt","w")
IOStream()
julia> for i in 1:20 write(f, "$i\n") end
julia> close(f)
julia> readline(open("temp.txt"), 15)
ERROR: MethodError: `readline` has no method matching
readline(::IOStream, ::Int64)SYSTEM: show(lasterr) caused an
error
julia> readline(open("temp.txt"))
"1\n"
julia> readline(open("temp.txt"))
"1\n"
julia> readlines(open("temp.txt"))
20-element Array{Union(ASCIIString,UTF8String),1}:
"1\n"
"2\n"
"3\n"
"4\n"
"5\n"
"6\n"
"7\n"
"8\n"
"9\n"
"10\n"
"11\n"
"12\n"
"13\n"
"14\n"
"15\n"
"16\n"
"17\n"
"18\n"
"19\n"
"20\n"
Paul
W dniu 2015-06-16 o 19:49, Tom Breloff pisze:
You could create your own:
|
julia> Base.readline(s, i::Int) = (for (j,line) in
enumerate(eachline(s)); if j==i; return line; end; end; error("not
enough lines"))
readline (generic function with 4 methods)
julia> f = open("/tmp/tmp.txt", "w")
IOStream()
julia> for i in 1:20 write(f, "$i\n") end
julia> close(f)
julia> readline(open("/tmp/tmp.txt"), 15)
"15\n"
julia> readline(open("/tmp/tmp.txt"), 25)
ERROR: not enough lines
in readline at none:1
|
On Tuesday, June 16, 2015 at 12:17:28 PM UTC-4, paul analyst wrote:
If o is stream
o=open(file)
how to read any line ?e.g. 15
julia> readline(o,15)
ERROR: MethodError: `readline` has no method matching
readline(::IOStream, ::Int64)SYSTEM: show(lasterr) caused
error
Paul
Re: [julia-users] Re: How to read any lines with stream open(file)
Ok, sorry, i don`t see 1 line:)
|Base.readline(s, i::Int) = (for (j,line) in enumerate(eachline(s)); if
j==i; return line; end; end; error("not enough lines"))
Is oK ,big thx
Paul
|
W dniu 2015-06-17 o 11:27, Paul Analyst pisze:
Unfrtunatly can`t run, (in Julia 3.6 the same)
_
_ _ _(_)_ | A fresh approach to technical computing
(_) | (_) (_)| Documentation: http://docs.julialang.org
_ _ _| |_ __ _ | Type "help()" for help.
| | | | | | |/ _` | |
| | |_| | | | (_| | | Version 0.4.0-dev+2847 (2015-01-21 18:34 UTC)
_/ |\__'_|_|_|\__'_| | Commit fc61385 (146 days old master)
|__/ | x86_64-w64-mingw32
julia> f = open("temp.txt","w")
IOStream()
julia> for i in 1:20 write(f, "$i\n") end
julia> close(f)
julia> readline(open("temp.txt"), 15)
ERROR: MethodError: `readline` has no method matching
readline(::IOStream, ::Int64)SYSTEM: show(lasterr) caused an
error
julia> readline(open("temp.txt"))
"1\n"
julia> readline(open("temp.txt"))
"1\n"
julia> readlines(open("temp.txt"))
20-element Array{Union(ASCIIString,UTF8String),1}:
"1\n"
"2\n"
"3\n"
"4\n"
"5\n"
"6\n"
"7\n"
"8\n"
"9\n"
"10\n"
"11\n"
"12\n"
"13\n"
"14\n"
"15\n"
"16\n"
"17\n"
"18\n"
"19\n"
"20\n"
Paul
W dniu 2015-06-16 o 19:49, Tom Breloff pisze:
You could create your own:
|
julia> Base.readline(s, i::Int) = (for (j,line) in
enumerate(eachline(s)); if j==i; return line; end; end; error("not
enough lines"))
readline (generic function with 4 methods)
julia> f = open("/tmp/tmp.txt", "w")
IOStream()
julia> for i in 1:20 write(f, "$i\n") end
julia> close(f)
julia> readline(open("/tmp/tmp.txt"), 15)
"15\n"
julia> readline(open("/tmp/tmp.txt"), 25)
ERROR: not enough lines
in readline at none:1
|
On Tuesday, June 16, 2015 at 12:17:28 PM UTC-4, paul analyst wrote:
If o is stream
o=open(file)
how to read any line ?e.g. 15
julia> readline(o,15)
ERROR: MethodError: `readline` has no method matching
readline(::IOStream, ::Int64)SYSTEM: show(lasterr) caused
error
Paul
Re: [julia-users] Re: How to read any lines with stream open(file)
Is another way [1:end-1] to lost "\n" on the end of line?
julia> readline(open("temp.txt"))[1:end]
"1\n"
julia> readline(open("temp.txt"))[1:end-1]
"1"
Paul
W dniu 2015-06-17 o 11:33, Paul Analyst pisze:
Ok, sorry, i don`t see 1 line:)
|Base.readline(s, i::Int) = (for (j,line) in enumerate(eachline(s));
if j==i; return line; end; end; error("not enough lines"))
Is oK ,big thx
Paul
|
W dniu 2015-06-17 o 11:27, Paul Analyst pisze:
Unfrtunatly can`t run, (in Julia 3.6 the same)
_
_ _ _(_)_ | A fresh approach to technical computing
(_) | (_) (_)| Documentation: http://docs.julialang.org
_ _ _| |_ __ _ | Type "help()" for help.
| | | | | | |/ _` | |
| | |_| | | | (_| | | Version 0.4.0-dev+2847 (2015-01-21 18:34 UTC)
_/ |\__'_|_|_|\__'_| | Commit fc61385 (146 days old master)
|__/ | x86_64-w64-mingw32
julia> f = open("temp.txt","w")
IOStream()
julia> for i in 1:20 write(f, "$i\n") end
julia> close(f)
julia> readline(open("temp.txt"), 15)
ERROR: MethodError: `readline` has no method matching
readline(::IOStream, ::Int64)SYSTEM: show(lasterr) caused an
error
julia> readline(open("temp.txt"))
"1\n"
julia> readline(open("temp.txt"))
"1\n"
julia> readlines(open("temp.txt"))
20-element Array{Union(ASCIIString,UTF8String),1}:
"1\n"
"2\n"
"3\n"
"4\n"
"5\n"
"6\n"
"7\n"
"8\n"
"9\n"
"10\n"
"11\n"
"12\n"
"13\n"
"14\n"
"15\n"
"16\n"
"17\n"
"18\n"
"19\n"
"20\n"
Paul
W dniu 2015-06-16 o 19:49, Tom Breloff pisze:
You could create your own:
|
julia> Base.readline(s, i::Int) = (for (j,line) in
enumerate(eachline(s)); if j==i; return line; end; end; error("not
enough lines"))
readline (generic function with 4 methods)
julia> f = open("/tmp/tmp.txt", "w")
IOStream()
julia> for i in 1:20 write(f, "$i\n") end
julia> close(f)
julia> readline(open("/tmp/tmp.txt"), 15)
"15\n"
julia> readline(open("/tmp/tmp.txt"), 25)
ERROR: not enough lines
in readline at none:1
|
On Tuesday, June 16, 2015 at 12:17:28 PM UTC-4, paul analyst wrote:
If o is stream
o=open(file)
how to read any line ?e.g. 15
julia> readline(o,15)
ERROR: MethodError: `readline` has no method matching
readline(::IOStream, ::Int64)SYSTEM: show(lasterr) caused
error
Paul
[julia-users] read(STDIN,Char); in Win ,
in win
julia> x= read(STDIN,Char)
t
't'
julia>
julia>
julia> x
't'
julia>
becose is \r and \n
How to do correctly ?
for i=1:10println(i)println("if number is ok press 'y' ")read(STDIN,Char);end
I nead to vave control the code in any steps on while . This while jump 1 >
4 > 7 >10 :/
How do it ?
Paul
Re: [julia-users] read(STDIN,Char); in Win ,
Why ? Mayby any user can help me ?
Paul
W dniu poniedziałek, 22 czerwca 2015 20:34:51 UTC+2 użytkownik Stefan
Karpinski napisał:
>
> C'mon, please stop starting new threads about this.
>
> On Mon, Jun 22, 2015 at 2:27 PM, paul analyst > wrote:
>
>> in win
>> julia> x= read(STDIN,Char)
>> t
>> 't'
>>
>> julia>
>>
>> julia>
>>
>> julia> x
>> 't'
>>
>> julia>
>>
>> becose is \r and \n
>>
>> How to do correctly ?
>>
>> for i=1:10println(i)println("if number is ok press 'y' ")read(STDIN,Char);end
>>
>> I nead to vave control the code in any steps on while . This while jump 1
>> > 4 > 7 >10 :/
>> How do it ?
>> Paul
>>
>
>
Re: [julia-users] read(STDIN,Char); in Win ,
I now it. But how to do the code usefull ?
Paul
W dniu poniedziałek, 22 czerwca 2015 20:41:23 UTC+2 użytkownik Stefan
Karpinski napisał:
>
> You're on Windows – the line end is two characters, not one, so you have
> to check for both characters:
>
> http://blog.codinghorror.com/the-great-newline-schism/
>
> On Mon, Jun 22, 2015 at 2:37 PM, paul analyst > wrote:
>
>> Why ? Mayby any user can help me ?
>> Paul
>>
>>
>> W dniu poniedziałek, 22 czerwca 2015 20:34:51 UTC+2 użytkownik Stefan
>> Karpinski napisał:
>>>
>>> C'mon, please stop starting new threads about this.
>>>
>>> On Mon, Jun 22, 2015 at 2:27 PM, paul analyst
>>> wrote:
>>>
>>>> in win
>>>> julia> x= read(STDIN,Char)
>>>> t
>>>> 't'
>>>>
>>>> julia>
>>>>
>>>> julia>
>>>>
>>>> julia> x
>>>> 't'
>>>>
>>>> julia>
>>>>
>>>> becose is \r and \n
>>>>
>>>> How to do correctly ?
>>>>
>>>> for i=1:10println(i)println("if number is ok press 'y'
>>>> ")read(STDIN,Char);end
>>>>
>>>> I nead to vave control the code in any steps on while . This while jump 1
>>>> > 4 > 7 >10 :/
>>>> How do it ?
>>>> Paul
>>>>
>>>
>>>
>
[julia-users] Nan is readed as NaN but is the name of cat. How to read this data ?
Nan is readed as NaN but Nan is the name of cat. How to read this data ?
How to find the cat ?
I have data.txt file , UTF8
Lucycat
Fliperdog
Miadog
Nancat
Snupydog
julia> data=readd
readdir readdlm
julia> data=readdlm("data.txt",'\t')
5x2 Array{Any,2}:
"Lucy""cat"
"Fliper" "dog"
"Mia" "dog"
NaN "cat"
"Snupy" "dog"
julia> unique(data[:,1])
5-element Array{Any,1}:
"Lucy"
"Fliper"
"Mia"
NaN
"Snupy"
julia> findin(data[:,1],["Fliper"])
1-element Array{Int32,1}:
2
julia> findin(data[:,1],["Nan"])
0-element Array{Int32,1}
Paul
[julia-users] Re: Nan is readed as NaN but is the name of cat. How to read this data ?
Orginal file here
Paul
W dniu środa, 24 czerwca 2015 09:24:58 UTC+2 użytkownik paul analyst
napisał:
>
> Nan is readed as NaN but Nan is the name of cat. How to read this data ?
> How to find the cat ?
> I have data.txt file , UTF8
>
> Lucycat
> Fliperdog
> Miadog
> Nancat
> Snupydog
>
> julia> data=readd
> readdir readdlm
> julia> data=readdlm("data.txt",'\t')
> 5x2 Array{Any,2}:
> "Lucy""cat"
> "Fliper" "dog"
> "Mia" "dog"
> NaN "cat"
> "Snupy" "dog"
>
> julia> unique(data[:,1])
> 5-element Array{Any,1}:
> "Lucy"
> "Fliper"
> "Mia"
> NaN
> "Snupy"
>
> julia> findin(data[:,1],["Fliper"])
>
> 1-element Array{Int32,1}:
> 2
>
> julia> findin(data[:,1],["Nan"])
> 0-element Array{Int32,1}
>
> Paul
>
>Lucycat
Fliper dog
Mia dog
Nan cat
Snupy dog
[julia-users] Re: Nan is readed as NaN but is the name of cat. How to read this data ?
orginal file here Lucycat Fliper dog Mia dog Nan cat Snupy dog
Re: [julia-users] Re: Nan is readed as NaN but is the name of cat. How to read this data ?
Wow!
julia> a=readdlm("data.txt", '\t', ASCIIString)
5x2 Array{ASCIIString,2}:
"Lucy""cat"
"Fliper" "dog"
"Mia" "dog"
"Nan" "cat"
"Snupy" "dog"
julia> unique(a[:,1])
5-element Array{ASCIIString,1}:
"Lucy"
"Fliper"
"Mia"
"Nan"
"Snupy"
julia> findin(a,"Nan")
0-element Array{Int32,1}
julia> findin(a[:,1],["Nan"])
1-element Array{Int32,1}:
4
julia>
Re: [julia-users] Re: Nan is readed as NaN but is the name of cat. How to read this data ?
Is better, If ia have file coded UTF8 , use readdlm("data.txt",
'\t',UTF8String) ?
Paul
W dniu 2015-06-24 o 14:52, Avik Sengupta pisze:
Interesting problem! :)
Try:
readlm("data.txt", '\t', ASCIIString)
On Wednesday, 24 June 2015 03:24:58 UTC-4, paul analyst wrote:
Nan is readed as NaN but Nan is the name of cat. How to read this
data ? How to find the cat ?
I have data.txt file , UTF8
Lucycat
Fliperdog
Miadog
Nancat
Snupydog
julia> data=readd
readdir readdlm
julia> data=readdlm("data.txt",'\t')
5x2 Array{Any,2}:
"Lucy""cat"
"Fliper" "dog"
"Mia" "dog"
NaN "cat"
"Snupy" "dog"
julia> unique(data[:,1])
5-element Array{Any,1}:
"Lucy"
"Fliper"
"Mia"
NaN
"Snupy"
julia> findin(data[:,1],["Fliper"])
1-element Array{Int32,1}:
2
julia> findin(data[:,1],["Nan"])
0-element Array{Int32,1}
Paul
[julia-users] Is ready to function returning the greater variable?
Is ready to function returning the greater variable? x = 1 y = 2 fun (x, y) y Paul
[julia-users] Re: Is ready to function returning the greater variable?
Big thx , I tried maximum(x,y) P. W dniu piątek, 26 czerwca 2015 12:36:20 UTC+2 użytkownik Kristoffer Carlsson napisał: > > It is hard to understand your question but the function max(x,y) returns > the greater of x and y. > > On Friday, June 26, 2015 at 12:33:34 PM UTC+2, paul analyst wrote: >> >> Is ready to function returning the greater variable? >> >> x = 1 >> y = 2 >> fun (x, y) >> y >> >> Paul >> >
[julia-users] How to insert new row/ egsisitng vector into array ?
Is posible insert new row (egsisitng vector) into array ? wihout hcat
etc. ?
Is something like insert! in iter ?
julia> a=rand(5,5)
5x5 Array{Float64,2}:
0.613346 0.864493 0.495873 0.571237 0.948809
0.688794 0.168175 0.732427 0.0516122 0.439683
0.740090.491623 0.0662683 0.160219 0.708842
0.0678776 0.601627 0.425847 0.329719 0.108245
0.689865 0.233258 0.171292 0.487139 0.452603
julia> insert!(a,3,1,zeros(5))
ERROR: `insert!` has no method matching insert!(::Array{Float64,2},
::Int32, ::Int32, ::Array{Float64,1})
julia> insert!(a,[:,3],,zeros(5))
ERROR: syntax: unexpected ,
Paul?
[julia-users] Win 7, How by one click on .bat file run the Julia and perform some script automatically ?
Win 7
How by one click on .bat file run the Julia and perform some script
automatically ?
for example. include("file.jl")
My file.bat(below) run julia bat not started the script "test.jl"
bin\julia.exe
include("test.jl")
Paul
Re: [julia-users] Re: Win 7, How by one click on .bat file run the Julia and perform some script automatically ?
I read the manual:
-L, --load Load right after boot on all processors
but
bin\julia.exe -L, test.jl
bin\julia.exe -L, "test.jl"
bin\julia.exe -L, 'test.jl'
not work
Paul
W dniu 2015-07-02 o 16:12, Scott Jones pisze:
You'll need to pass that on the command line to julia, bin\julia -help
will give you a list of all the command line options you can use.
On Thursday, July 2, 2015 at 9:14:50 AM UTC-4, paul analyst wrote:
Win 7
How by one click on .bat file run the Julia and perform some
script automatically ?
for example. include("file.jl")
My file.bat(below) run julia bat not started the script "test.jl"
bin\julia.exe
include("test.jl")
Paul
Re: [julia-users] Re: Win 7, How by one click on .bat file run the Julia and perform some script automatically ?
BIG Thx, but not works, My Julia on win 7/64: Version 0.3.8 (2015-04-30 23:40 UTC) Official http://julialang.org/ release i686-w64-mingw32 *it is strange that:* bin\julia.exe -p 2 working bin\julia.exe -q working bin\julia.exe -h NO!! just on the moment (+-0.1 sek , I can`t read ) consloe is and close himself bin\julia.exe test.jl NO!! just on the moment (+-0.1 sek , I can`t read ) consloe is and close himself Paul W dniu 2015-07-02 o 16:53, Tony Kelman pisze: bin\julia.exe test.jl
Re: [julia-users] Re: Win 7, How by one click on .bat file run the Julia and perform some script automatically ?
Thanks
test.jl
a=rand(10)
writecsv("a.txt", a)
script run !!!
But console sey: "press any kay to continue..." after press cloused :/
my.bat :
bin\julia.exe test.jl
pause
Paul
W dniu 2015-07-02 o 17:48, Tony Kelman pisze:
Does the test script do anything? You could add "pause" at the end of
the batch file to avoid the console window closing after completion.
There's a difference between interactive commands that start up a REPL
that waits for input, vs script commands that close when they're finished.
Re: [julia-users] Re: Win 7, How by one click on .bat file run the Julia and perform some script automatically ?
I have:
bin\julia.exe -L test.jl
without ","
Paul
W dniu 2015-07-02 o 18:34, Paul Analyst pisze:
Thanks
test.jl
a=rand(10)
writecsv("a.txt", a)
script run !!!
But console sey: "press any kay to continue..." after press cloused :/
my.bat :
bin\julia.exe test.jl
pause
Paul
W dniu 2015-07-02 o 17:48, Tony Kelman pisze:
Does the test script do anything? You could add "pause" at the end of
the batch file to avoid the console window closing after completion.
There's a difference between interactive commands that start up a
REPL that waits for input, vs script commands that close when they're
finished.
[julia-users] How from dimensional array cut out no more than the first 15 characters of each line, without loop. is posible it ?
How from dimensional array cut out no more than the first 15 characters of
each line, without loop. is posible it ?
I have :
julia> A
3-element Array{Any,1}:
"Lorem ipsum dolor sit amet consectetur adipiscing elit sed do eiusmod
tempor incididunt ut labore et dolore magn
a aliqua. "
"Ut enim ad minim veniam quis nostrud exercitation ullamco laboris nisi ut
aliquip ex ea commodo consequat. "
"Duis aute irure dolor in reprehenderit in voluptate velit esse cillum
dolore eu fugiat nulla pariatur. Excepteur
sint occaecat cupidatat non proident sunt in culpa qui officia deserunt
mollit anim id est laborum."
But i need
julia> A
3-element Array{Any,1}:
"Lorem ipsum dolor
a aliqua. "
"Ut enim ad minim
"Duis aute irure d
sint occaecat cupi
Re: [julia-users] Re: How from dimensional array cut out no more than the first 15 characters of each line, without loop. is posible it ?
Thx Tom, nice !!! Paul W dniu 2015-07-02 o 21:13, Tom Breloff pisze: | map(x->x[1:min(length(x),15)],A) |
[julia-users] How rotate a cube f1 to its edges are parallel to another cube (f2) ?
How rotate a cube f1 to its edges are parallel to another cube (f2) ?
I have two 3 dimensional orthogonal sets of the 1444 observation in each.
julia> size(f1)
(1444,3)
julia> size(f2)
(1444,3)
cor in each are real 0,
julia> cor(f1)
3x3 Array{Float64,2}:
1.0 -2.39743e-16 3.8112e-16
-2.39743e-16 1.0 -2.02954e-16
3.8112e-16 -2.02954e-16 1.0
julia> cor(f2)
3x3 Array{Float64,2}:
1.0 -5.55883e-17 1.76522e-17
-5.55883e-17 1.0 1.70523e-15
1.76522e-17 1.70523e-15 1.0
There are also orthogonal: angle in degrees matrix of f1
3x3 Array{Float64,2}:
0.0 90.0 90.0
90.0 0.0 90.0
90.0 90.0 0.0
angle in degrees matrix of f2
3x3 Array{Float64,2}:
0.0 90.0 90.0
90.0 0.0 90.0
90.0 90.0 0.0
but angle in degrees betwen f1 and f2 are:
90.6388 91.4539 88.8789
92.2294 90.6144 89.2666
88.8462 89.6773 92.377
angle in degrees betwen f2 and f1 are:
90.6388 92.2294 88.8462
91.4539 90.6144 89.6773
88.8789 89.2666 92.377
How rotate one of the cube to edges f1 are parallel to f2 ?
first col f1 parallele to first col of f2 . etc...
Paul
[julia-users] How rotate a cube f1 to its edges are parallel to another cube (f2) ?
How rotate a cube f1 to its edges are parallel to another cube (f2) ?
I have two 3 dimensional orthogonal sets of the 1444 observation in each.
julia> size(f1)
(1444,3)
julia> size(f2)
(1444,3)
cor in each are real 0,
julia> cor(f1)
3x3 Array{Float64,2}:
1.0 -2.39743e-16 3.8112e-16
-2.39743e-16 1.0 -2.02954e-16
3.8112e-16 -2.02954e-16 1.0
julia> cor(f2)
3x3 Array{Float64,2}:
1.0 -5.55883e-17 1.76522e-17
-5.55883e-17 1.0 1.70523e-15
1.76522e-17 1.70523e-15 1.0
There are also orthogonal: angle in degrees matrix of f1
3x3 Array{Float64,2}:
0.0 90.0 90.0
90.0 0.0 90.0
90.0 90.0 0.0
angle in degrees matrix of f2
3x3 Array{Float64,2}:
0.0 90.0 90.0
90.0 0.0 90.0
90.0 90.0 0.0
but angle in degrees betwen f1 and f2 are:
90.6388 91.4539 88.8789
92.2294 90.6144 89.2666
88.8462 89.6773 92.377
angle in degrees betwen f2 and f1 are:
90.6388 92.2294 88.8462
91.4539 90.6144 89.6773
88.8789 89.2666 92.377
How rotate one of the cube to edges f1 are parallel to f2 ?
first col f1 parallele to first col of f2 . etc...
Paul
[julia-users] How to find the index of array containing some text (substring)
Is array A
julia> A=["aaa","aab","aac","aba"]
4-element Array{ASCIIString,1}:
"aaa"
"aab"
"aac"
"aba"
How to How to find the index this arrary containing "b" ?
julia> find(A,"b")
ERROR: `find` has no method matching find(::Array{ASCIIString,1},
::ASCIIString)
julia> getindex(A,"b")
ERROR: `getindex` has no method matching getindex(::Array{ASCIIString,1},
::ASCIIString)
julia> search(A,"b")
ERROR: `search` has no method matching search(::Array{ASCIIString,1},
::ASCIIString)
julia> search(A,"b")
ERROR: `search` has no method matching search(::Array{ASCIIString,1},
::ASCIIString)
Paul
Re: [julia-users] Re: How to find the index of array containing some text (substring)
Big Thx , but "b",i in oposit order must like below... i,"b"
But my aray is 2261-element Array{Any,1}: , the trick working only
with Array{ASCIIString,1}: , How convert Array Any to Array ASCIIString ?
julia> [contains("b",i) for i in A]
4-element Array{Any,1}:
false
false
false
false
julia> A
4-element Array{ASCIIString,1}:
"aaa"
"aab"
"aac"
"aba"
julia> [contains(i,"b") for i in A]
4-element Array{Any,1}:
false
true
false
true
W dniu 2015-07-08 o 19:58, Eduardo Lenz pisze:
[contains("b",i) for i in A]
Re: [julia-users] Re: How to find the index of array containing some text (substring)
thx, bat no:)
In my array are digits too. I must Some loop to preapere .
Paul
julia> A2 = map( (x)->convert(ASCIIString,x), A)
ERROR: `convert` has no method matching convert(::Type{ASCIIString},
::Float64)
in convert at base.jl:13
in anonymous at none:1
in map at base.jl:189
W dniu 2015-07-08 o 20:35, Eduardo Lenz pisze:
A2 = map( (x)->convert(ASCIIString,x), A)
Re: [julia-users] Re: How to find the index of array containing some text (substring)
if i read data like String is ok , but is problem with digit:)
data=readcsv("file.txt",UTF8String)
Paweł
W dniu 2015-07-08 o 20:40, Paul Analyst pisze:
thx, bat no:)
In my array are digits too. I must Some loop to preapere .
Paul
julia> A2 = map( (x)->convert(ASCIIString,x), A)
ERROR: `convert` has no method matching convert(::Type{ASCIIString},
::Float64)
in convert at base.jl:13
in anonymous at none:1
in map at base.jl:189
W dniu 2015-07-08 o 20:35, Eduardo Lenz pisze:
A2 = map( (x)->convert(ASCIIString,x), A)
Re: [julia-users] Re: How to find the index of array containing some text (substring)
julia> A2 = map( (x)->convert(ASCIIString, string(x)), A) ERROR: invalid ASCII sequence in convert at ascii.jl:101 in bytestring at string.jl:644 in convert at ascii.jl:120 in anonymous at none:1 in map at base.jl:189 But after readcsv(file, UTF8 String) works! THX Paul W dniu 2015-07-08 o 20:46, Eduardo Lenz pisze: A2 = map( (x)->convert(ASCIIString, string(x)), A)
[julia-users] Is @@ reservd word in Julia ? Can I use @@ in data?
Is @@ reservd word in Julia ? Can I use @@ in data? Paul
[julia-users] How to find last somethink in vector ?
How to find last somethink in vector ? how to find index of last "1" 1 0 0 1 0 0 0 1 1 0 0 0 0 0 Paul
Re: [julia-users] Re: How from dimensional array cut out no more than the first 15 characters of each line, without loop. is posible it ?
This
|
map(x->x[1:min(length(x),15)],A)
This is ok, but now i must take only last char from any row this array
A. How do it ?
julia> map(x->x[length(x)],A)
ERROR: BoundsError()
in next at utf8.jl:56
in anonymous at none:1
in map_to! at abstractarray.jl:1311
in anonymous at none:1
in map at abstractarray.jl:1331
julia> map(x->x[end],A)
ERROR: BoundsError()
in next at utf8.jl:56
in anonymous at none:1
in map_to! at abstractarray.jl:1311
in anonymous at none:1
in map at abstractarray.jl:1331
Paul
|
W dniu 2015-07-02 o 21:13, Tom Breloff pisze:
Try:
|
map(x->x[1:min(length(x),15)],A)
|
On Thursday, July 2, 2015 at 3:06:33 PM UTC-4, paul analyst wrote:
How from dimensional array cut out no more than the first 15
characters of each line, without loop. is posible it ?
I have :
julia> A
3-element Array{Any,1}:
"Lorem ipsum dolor sit amet consectetur adipiscing elit sed do
eiusmod tempor incididunt ut labore et dolore magn
a aliqua. "
"Ut enim ad minim veniam quis nostrud exercitation ullamco
laboris nisi ut aliquip ex ea commodo consequat. "
"Duis aute irure dolor in reprehenderit in voluptate velit esse
cillum dolore eu fugiat nulla pariatur. Excepteur
sint occaecat cupidatat non proident sunt in culpa qui officia
deserunt mollit anim id est laborum."
But i need
julia> A
3-element Array{Any,1}:
"Lorem ipsum dolor
a aliqua. "
"Ut enim ad minim
"Duis aute irure d
sint occaecat cupi
[julia-users] HDF5 file id biger then txt. What wrong?
I have data in txt file, some milons like this:
0,0,2,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,2,0,0,0,2,0,0,0,0,1
0,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1
Coding win1250.
size of dane.txt is 1.3 GB
D=readcsv("dane.txt")
k,l=size(D)
using HDF5, JLD
hfi=h5open("D.h5","w")
close(hfi)
fid = h5open("D.h5","r+")
g = fid["/"]
dset1 = d_create(g, "/D", datatype(Int64), dataspace(k,l))
dset1[:,:]=D
close(fid)
After save to h5 file the file has 6.3 GB ? Why new file is 4 times biger?
Paul
[julia-users] Is some Autocorrelation function in Julia?
*Is some Autocorrelation function in Julia?Paul*
[julia-users] How quickly compute the density of the vector in the selected range?
Hi, How quickly computethe density of the vector in the selected range? I have vec=[0 0 0 1 0 1 0 1 1 0] I am lookking for function computing "density" of this vector on selelcted range i.e. 5 elements : foo(vec,5) result: [0.2 0.2 0.2 0.2 0.2 0.6 0.6 0.6 0.6 0.6] mean first 5 elements is 0.2 mean second 5 elements is 0.6 etc... I need somthing fast to vry long vectors Paul
Re: [julia-users] How quickly compute the density of the vector in the selected range?
Nice way, thx. paull W dniu niedziela, 16 sierpnia 2015 18:25:02 UTC+2 użytkownik Tim Holy napisał: > > If you want a running density, look into > c = cumsum(v) > density = c[6:end] - c[1:end-5] > > If you want in blocks, reshape to a matrix and take the mean along > dimension > 1. > > --Tim > > On Sunday, August 16, 2015 09:08:23 AM paul analyst wrote: > > Hi, > > How quickly computethe density of the vector in the selected range? > > I have vec=[0 0 0 1 0 1 0 1 1 0] > > I am lookking for function computing "density" of this vector on > selelcted > > range i.e. 5 elements : > > > > foo(vec,5) > > result: > > [0.2 0.2 0.2 0.2 0.2 0.6 0.6 0.6 0.6 0.6] > > > > mean first 5 elements is 0.2 > > > > mean second 5 elements is 0.6 > > > > etc... > > I need somthing fast to vry long vectors > > Paul > >
Re: [julia-users] Re: different eigen value ordering from eigs
Sample m,v=eig(B) return m,v where m and v are from smalest do bigest
value. First eigen value and eigenvec are on the last position
You must flip/flop both:
v=fliplr(v);m=flipud(m)
julia> A=rand(4,4)
4x4 Array{Float64,2}:
0.661782 0.366042 0.149729 0.445334
0.658829 0.376393 0.0998171 0.637071
0.851418 0.876499 0.748640.544398
0.0921396 0.522684 0.384848 0.853703
julia> B=cor(A)
4x4 Array{Float64,2}:
1.00.308153 0.18808-0.858457
0.308153 1.00.988595 -0.0151858
0.188080.988595 1.0 0.0563374
-0.858457 -0.0151858 0.0563374 1.0
julia> m,v=eig(B)
([4.44089e-16,0.109119,1.70604,2.18484],
4x4 Array{Float64,2}:
0.207923 0.6822 0.509621 -0.481308
-0.712208 0.0744095 -0.368759 -0.592655
0.65762 -0.269323 -0.432141 -0.555208
0.130629 0.675671 -0.646187 0.32992 )
julia> m
4-element Array{Float64,1}:
4.44089e-16
0.109119
1.70604
2.18484
W dniu 2015-08-23 o 22:45, Edward Chen pisze:
Would there be any reason to suspect that the ordering of the
eigenvalues and the eigenvectors are different? I am doing a
side-by-side comparison with the eig function in MATLAB and it seems
to give a different ordering of vectors for the same matrix.
On Saturday, April 26, 2014 at 5:15:21 PM UTC-4, Ethan Anderes wrote:
Paul:
Sorry, I don't think I can help you there. I don't have any
observational errors, just numerical error in the matrix.
[julia-users] How parallel count and save the results ?
How parallel count and save the results ? I have a large matrix A saved in the file hdf5 10 ^ 7 x 10 ^ 3. Each column was converted to the write down in the matrix B of the same size. Each column independently. The calculations are tedious but not borne by the processor. How does this process do parallel? Paul
[julia-users] @parallel and HDF5 is posible to work together?
@parallel and HDF5 is posible to work together?
julia> addprocs(6)
6-element Array{Any,1}:
2
3
4
5
6
7
julia> @parallel for i=1:l
dset=fid["punkts"*string(i)]
f=vec(h5read("F.h5","F",(:,i)));
.
end
WARNING: Module HDF5 not defined on process 2
WARNING: Module HDF5 not defined on process 3
julia> close(fid)
julia> fatal error on 3: WARNING: Module HDF5 not defined on process 6
WARNING: Module HDF5 not defined on process 7
WARNING: Module HDF5 not defined on process 4
fatal error on 6: fatal error on fatal error on 74: : WARNING: Module HDF5
not defined on process 5
fatal error on 5: ERROR: HDF5 not defined
in deserialize at serialize.jl:377
in handle_deserialize at serialize.jl:352
in deserialize at serialize.jl:506
in handle_deserialize at serialize.jl:352
Paul
Re: [julia-users] Re: @parallel and HDF5 is posible to work together?
Thanak lot Nils,
Unfortunatly like below:
julia> addprocs(7)
7-element Array{Any,1}:
2
3
4
5
6
7
8
julia> import HDF5
julia> @everywhere using HDF5
julia> @parallel for i=1:l
dset=fid["punkty"*string(i)]
f=vec(h5read("F.h5","F",(:,i)));
...
println(i)
end
julia> close(fid)
julia> toc()
elapsed time: 18.801164342 seconds
18.801164342
julia> exception on 2: ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
exception on 4: exception on 6: exception on 5: exception on exception
on 3: exception on 8: 7: ERROR: File or o
ect has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
W dniu 2015-09-01 o 22:14, Nils Gudat pisze:
As the warning says, the module is not defined on the workers. Do
addprocs()
import HDF5
@everywhere using HDF5
Re: [julia-users] Re: @parallel and HDF5 is posible to work together?
*what wrong?*
fid = h5open("data.h5","r+")
this code work :
import HDF5
@everywhere using HDF5
@parallel for i=1:l
#dset=fid["punkty"*string(i)]
f=vec(h5read("F.h5","F",(:,i)));
#dset[:,:]=f*rand()
println(i)
end
close(fid)
this code do not work:
*
*fid = h5open("data.h5","r+")
@parallel for i=1:l
* dset=fid["punkty"*string(i)]*
f=vec(h5read("F.h5","F",(:,i)));
#dset[:,:]=f*rand()
println(i)
end*
ERROR: File or object has been closedn exception on 236: 4:
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
: ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
julia> close(fiexception on dexception on 58: ): ERROR: File or object
has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
7: julia> ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
close(fid)**
**
*Paul
W dniu 2015-09-04 o 19:44, Paul Analyst pisze:
Thanak lot Nils,
Unfortunatly like below:
julia> addprocs(7)
7-element Array{Any,1}:
2
3
4
5
6
7
8
julia> import HDF5
julia> @everywhere using HDF5
julia> @parallel for i=1:l
dset=fid["punkty"*string(i)]
f=vec(h5read("F.h5","F",(:,i)));
...
println(i)
end
julia> close(fid)
julia> toc()
elapsed time: 18.801164342 seconds
18.801164342
julia> exception on 2: ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
exception on 4: exception on 6: exception on 5: exception on exception
on 3: exception on 8: 7: ERROR: File or o
ect has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
ERROR: File or object has been closed
in o_open at C:\Users\SAMSUNG2\.julia\v0.3\HDF5\src\plain.jl:696
(repeats 2 times)
W dniu 2015-09-01 o 22:14, Nils Gudat pisze:
As the warning says, the module is not defined on the workers. Do
addprocs()
import HDF5
@everywhere using HDF5
[julia-users] how to apply vector on diagonal of matrix ?
a=rand(5) b=zeros(5,5) how to apply a on diagonal b ? Paul
[julia-users] Re: how to apply vector on diagonal of matrix ?
b- not is zeros sometimes... c= diagm(a) b=b+c. Thx Paul W dniu wtorek, 20 maja 2014 16:17:11 UTC+2 użytkownik Oliver Lylloff napisał: > > Hi Paul, > > if b is just zeros, then b = diagm(a). > > Best, > Oliver > > > > Den tirsdag den 20. maj 2014 15.04.33 UTC+2 skrev paul analyst: >> >> a=rand(5) >> b=zeros(5,5) >> how to apply a on diagonal b ? >> Paul >> >
Re: [julia-users] Re: how to apply vector on diagonal of matrix ?
I have arrays about 10k*10k. Is faster by loop? Paul W dniu 2014-05-20 17:18, Oliver Lylloff pisze: Yes, and for larger arrays it might be beneficial to write in a loop: a = rand(1000); b = rand(1000,1000); for i = 1:length(a) b[i,i] = b[i,i] + a[i]; end Den tirsdag den 20. maj 2014 16.48.30 UTC+2 skrev paul analyst: b- not is zeros sometimes... c= diagm(a) b=b+c. Thx Paul W dniu wtorek, 20 maja 2014 16:17:11 UTC+2 użytkownik Oliver Lylloff napisał: Hi Paul, if b is just zeros, then b = diagm(a). Best, Oliver Den tirsdag den 20. maj 2014 15.04.33 UTC+2 skrev paul analyst: a=rand(5) b=zeros(5,5) how to apply a on diagonal b ? Paul
[julia-users] How quickly calculate distances arrays etc.
How quickly calculate distances arrays etc. This is an array of quotients, on the diagonal must be zero. Are there any features that quickly count this type of arrays? Data in F... k=size(F,2); O=zeros(k,k); for o=0:k-2; for i=1:k-1-o j=i+1+o; O[i,j]=sum(F[:,i])/sum(F[:,j]); O[j,i]=1/O[i,j]; end; end; Paul
[julia-users] when the loop variable takes on values from a vector?
I have some vector : 1 4 56 67 99 and some loop: for i F(i) do somethink end How to assign a variable (i) only value from a vector? Paul
Re: [julia-users] when the loop variable takes on values from a vector?
if vector a=[1, 4, 56, 67, 99] cod is for i in a F(i) end ? Paul ? W dniu poniedziałek, 26 maja 2014 19:09:03 UTC+2 użytkownik Jameson napisał: > > for i in [1, 4, 56, 67, 99] > F(i) > end > > On Mon, May 26, 2014 at 12:52 PM, paul analyst > > > wrote: > > I have some vector : 1 4 56 67 99 > > > > and some loop: > > > > for i > > F(i) do somethink > > end > > > > How to assign a variable (i) only value from a vector? > > > > Paul >
Re: [julia-users] when the loop variable takes on values from a vector?
Thx, W dniu poniedziałek, 26 maja 2014 19:23:24 UTC+2 użytkownik Jameson napisał: > > yes, unless i did not understand the question correctly > > On Mon, May 26, 2014 at 1:15 PM, paul analyst > > > wrote: > > if vector a=[1, 4, 56, 67, 99] > > > > cod is > > > > for i in a > > F(i) > > end > > ? > > Paul ? > > > > W dniu poniedziałek, 26 maja 2014 19:09:03 UTC+2 użytkownik Jameson > napisał: > >> > >> for i in [1, 4, 56, 67, 99] > >> F(i) > >> end > >> > >> On Mon, May 26, 2014 at 12:52 PM, paul analyst > wrote: > >> > I have some vector : 1 4 56 67 99 > >> > > >> > and some loop: > >> > > >> > for i > >> > F(i) do somethink > >> > end > >> > > >> > How to assign a variable (i) only value from a vector? > >> > > >> > Paul >
[julia-users] How quickly and automatically find the cut-off point of vectors with long tails ?
How quickly and automatically cut off long tails We have often sorted vectors with long tails. How quickly and automatically find the cut-off point where the graph flattens? Vectors are long and have a variety of unpleasant characteristics. Simple sample: a=[5 3 2 1.5 1.1 1 0.8 0.25 0.2 0.16] b=[156 125 112 101 89 88 56 66 62 61] Paul
[julia-users] Re: How quickly and automatically find the cut-off point of vectors with long tails ?
W dniu wtorek, 27 maja 2014 12:19:09 UTC+2 użytkownik Yuuki Soho napisał: > > The simplest way to do it is probably to use a quantile: > > > a=[5 3 2 1.5 1.1 1 0.8 0.25 0.2 0.16] > > q = quantile(vec(a),0.1) > > a = a[1:cut] > > > Does not work always, distributions are different. > How to find the number of elements of the vector from which the chart is > getting flat (where is the beginning of the tail?) > Paul >
[julia-users] Re: How quickly and automatically find the cut-off point of vectors with long tails ?
Does not work always, distributions are different. How to find the number of elements of the vector from which the chart is getting flat (where is the beginning of the tail?) Paul W dniu wtorek, 27 maja 2014 12:19:09 UTC+2 użytkownik Yuuki Soho napisał: > > The simplest way to do it is probably to use a quantile: > > > a=[5 3 2 1.5 1.1 1 0.8 0.25 0.2 0.16] > > q = quantile(vec(a),0.1) > > a = a[1:cut] > > >
Re: [julia-users] Re: How quickly and automatically find the cut-off point of vectors with long tails ?
Thanks for the cool link. Generally this is the point where the tangential tilt is 45 degrees. Paul W dniu wtorek, 27 maja 2014 15:06:25 UTC+2 użytkownik Harlan Harris napisał: > > Paul, I don't believe that this is a well-posed question. Determining what > is the tail of a distribution and what isn't is very much > problem-dependent. "getting flat" depends entirely on the scale of your > data, and isn't meaningful. You could do what people constructing boxplots > do, and use some multiple of the inter-quartile range from the median, but > that still depends on the source, distribution, and meaning of your data. > In any case, you'd be better off asking this somewhere like CrossValidated ( > http://stats.stackexchange.com/) -- this isn't a Julia question. > > > On Tue, May 27, 2014 at 8:22 AM, paul analyst > > wrote: > >> Does not work always, distributions are different. >> How to find the number of elements of the vector from which the chart is >> getting flat (where is the beginning of the tail?) >> Paul >> >> >> W dniu wtorek, 27 maja 2014 12:19:09 UTC+2 użytkownik Yuuki Soho napisał: >> >>> The simplest way to do it is probably to use a quantile: >>> >>> >>> a=[5 3 2 1.5 1.1 1 0.8 0.25 0.2 0.16] >>> >>> q = quantile(vec(a),0.1) >>> >>> a = a[1:cut] >>> >>> >>> >
Re: [julia-users] Re: How quickly and automatically find the cut-off point of vectors with long tails ?
Big thx, it is good way, Intresting is also this dagr = diff(a) ./ diff(gradient(x)) and another offset avg ... Paul W dniu wtorek, 27 maja 2014 17:37:41 UTC+2 użytkownik Tomas Lycken napisał: > > If you have the y-values in a sorted vector, and the x-values in another > sorted vector (or if they're just the index you don't need them), you can > get the discrete derivative by using diff: > > da = diff(a) ./ diff(x) > > Now, the tangential tilt is less than 45 degrees whenever that derivative > is larger than -1, so > > a[da .< -1] > > will give you the portion of a for which the slope is steeper than 45 > degrees. (I might be off by one here, so you might want to experiment a > little and see if you need to include one more, or one less, data point to > get exactly what you want...) > > // T > > On Tuesday, May 27, 2014 4:53:52 PM UTC+2, paul analyst wrote: >> >> Thanks for the cool link. >> Generally this is the point where the tangential tilt is 45 degrees. >> Paul >> >> W dniu wtorek, 27 maja 2014 15:06:25 UTC+2 użytkownik Harlan Harris >> napisał: >>> >>> Paul, I don't believe that this is a well-posed question. Determining >>> what is the tail of a distribution and what isn't is very much >>> problem-dependent. "getting flat" depends entirely on the scale of your >>> data, and isn't meaningful. You could do what people constructing boxplots >>> do, and use some multiple of the inter-quartile range from the median, but >>> that still depends on the source, distribution, and meaning of your data. >>> In any case, you'd be better off asking this somewhere like CrossValidated ( >>> http://stats.stackexchange.com/) -- this isn't a Julia question. >>> >>> >>> On Tue, May 27, 2014 at 8:22 AM, paul analyst wrote: >>> >>>> Does not work always, distributions are different. >>>> How to find the number of elements of the vector from which the chart is >>>> getting flat (where is the beginning of the tail?) >>>> Paul >>>> >>>> >>>> W dniu wtorek, 27 maja 2014 12:19:09 UTC+2 użytkownik Yuuki Soho >>>> napisał: >>>> >>>>> The simplest way to do it is probably to use a quantile: >>>>> >>>>> >>>>> a=[5 3 2 1.5 1.1 1 0.8 0.25 0.2 0.16] >>>>> >>>>> q = quantile(vec(a),0.1) >>>>> >>>>> a = a[1:cut] >>>>> >>>>> >>>>> >>>
[julia-users] Code running back? what happens?
Code running back? what happens? I have a array FS julia> println(sum(FS)); 9.8267205e7 julia> l,m=size(FS); julia> FSbis=FS; julia> julia> julia> for i=1:l; #println(i) if w[i]==1 us=hcat(F[i,:]',[1:1:m]); us=sortrows(us, by=x->x[1],rev=true); for j=1:m if in(us[j,2],Su) FSbis[i,us[j,2]]=us[j,2]; break end; end; end; end; julia> julia> println(sum(FSbis)); 1.03295914e8 julia> julia> println(sum(FS)); 1.03295914e8 after the code array FSbis changing and well. But the array FS too is changing! Why? Compare sum(FS) before and after. Paul
[julia-users] Re: Code running back? what happens?
Thx, I'm surprised. I suspect, and I did: a = ones (5,5) b = a b = b +3 a == b false That is not the case for small and large objects? This is not OK :/ W dniu środa, 28 maja 2014 21:11:12 UTC+2 użytkownik Patrick O'Leary napisał: > > > FSbis=FS > > This binds the identifier FSbis to the same memory that FS is bound to, so > the identifiers are aliases for one another. > > If you want FSbis to start out initialized to the same values as those in > FS, but be a separate container, use `FSbis = copy(FS)`. > > On Wednesday, May 28, 2014 2:07:38 PM UTC-5, paul analyst wrote: >> >> Code running back? what happens? >> I have a array FS >> >> >> julia> println(sum(FS)); >> 9.8267205e7 >> >> julia> l,m=size(FS); >> >> julia> FSbis=FS; >> >> julia> >> >> julia> >> >> julia> for i=1:l; #println(i) >>if w[i]==1 us=hcat(F[i,:]',[1:1:m]); >>us=sortrows(us, by=x->x[1],rev=true); >>for j=1:m >>if in(us[j,2],Su) FSbis[i,us[j,2]]=us[j,2]; break end; >>end; >>end; >>end; >> >> julia> >> >> julia> println(sum(FSbis)); >> 1.03295914e8 >> >> julia> >> >> julia> println(sum(FS)); >> 1.03295914e8 >> >> >> after the code array FSbis changing and well. But the array FS too is >> changing! Why? Compare sum(FS) before and after. >> Paul >> >
Re: [julia-users] Code running back? what happens?
I see, but what is the difference between: b [2,3] = 3 and b = b.+2 Paul W dniu 2014-05-30 10:11, Tomas Lycken pisze: @Paul, Try julia> a = ones(5,5); julia> b = a; julia> b[2,3] = 2; julia> a == b true On Wednesday, May 28, 2014 9:22:26 PM UTC+2, Jameson wrote: b+3 is not the same as a (or b, from the prior stage, for that matter). It doesn't matter whether a and b are numbers or matrices, large or small On Wednesday, May 28, 2014, paul analyst > wrote: Thx, I'm surprised. I suspect, and I did: a = ones (5,5) b = a b = b +3 a == b false That is not the case for small and large objects? This is not OK :/ W dniu środa, 28 maja 2014 21:11:12 UTC+2 użytkownik Patrick O'Leary napisał: > FSbis=FS This binds the identifier FSbis to the same memory that FS is bound to, so the identifiers are aliases for one another. If you want FSbis to start out initialized to the same values as those in FS, but be a separate container, use `FSbis = copy(FS)`. On Wednesday, May 28, 2014 2:07:38 PM UTC-5, paul analyst wrote: Code running back? what happens? I have a arrayFS julia> println(sum(FS)); 9.8267205e7 julia> l,m=size(FS); julia> FSbis=FS; julia> julia> julia> for i=1:l; #println(i) if w[i]==1 us=hcat(F[i,:]',[1:1:m]); us=sortrows(us, by=x->x[1],rev=true); for j=1:m if in(us[j,2],Su) FSbis[i,us[j,2]]=us[j,2]; break end; end; end; end; julia> julia> println(sum(FSbis)); 1.03295914e8 julia> julia> println(sum(FS)); 1.03295914e8 after the code arrayFSbis changing and well. But the array FS too is changing! Why? Compare sum(FS) before and after. Paul
[julia-users] Parallel, strange behavior of the loop after changing the value to a variable, 6 time slower
D:\install\Julia\Julia 0.3.0-prerelease-win64-ver3\Julia 0.3.0-prerelease
ver 3>bin\julia.exe -p 8
_
_ _ _(_)_ | A fresh approach to technical computing
(_) | (_) (_)| Documentation: http://docs.julialang.org
_ _ _| |_ __ _ | Type "help()" to list help topics
| | | | | | |/ _` | |
| | |_| | | | (_| | | Version 0.3.0-prerelease+2599 (2014-04-11 23:52
UTC)
_/ |\__'_|_|_|\__'_| | Commit bf7096c (50 days old master)
|__/ | x86_64-w64-mingw32
julia> procs()
9-element Array{Int64,1}:
1
2
3
4
5
6
7
8
9
julia> tic();
julia> nheads = @parallel (+) for i=1:2
int(randbool())
end
16468
julia> toc()
elapsed time: 2.77418807 seconds
2.77418807
julia>exit()
D:\install\Julia\Julia 0.3.0-prerelease-win64-ver3\Julia 0.3.0-prerelease
ver 3>bin\julia.exe -p 8
_
_ _ _(_)_ | A fresh approach to technical computing
(_) | (_) (_)| Documentation: http://docs.julialang.org
_ _ _| |_ __ _ | Type "help()" to list help topics
| | | | | | |/ _` | |
| | |_| | | | (_| | | Version 0.3.0-prerelease+2599 (2014-04-11 23:52
UTC)
_/ |\__'_|_|_|\__'_| | Commit bf7096c (50 days old master)
|__/ | x86_64-w64-mingw32
julia> k=2
2
julia> tic();
julia> nheads = @parallel (+) for i=1:k
int(randbool())
end
99989022
julia> toc()
elapsed time: 18.631674663 seconds
18.631674663
julia>
What hapend ?
Paul
Re: [julia-users] Parallel, strange behavior of the loop after changing the value to a variable, 6 time slower
*julia> const k=2;ERROR: cannot declare k constant; it already has
a value:/Paul*
W dniu niedziela, 1 czerwca 2014 16:13:27 UTC+2 użytkownik Andreas Noack
Jensen napisał:
>
> This is the usual problem with global variables in Julia. If you define k
> by
>
> const k=2
>
> the timing results should be similar.
>
>
> 2014-06-01 16:09 GMT+02:00 paul analyst >
> :
>
>>
>> D:\install\Julia\Julia 0.3.0-prerelease-win64-ver3\Julia 0.3.0-prerelease
>> ver 3>bin\julia.exe -p 8
>>_
>>_ _ _(_)_ | A fresh approach to technical computing
>> (_) | (_) (_)| Documentation: http://docs.julialang.org
>>_ _ _| |_ __ _ | Type "help()" to list help topics
>> | | | | | | |/ _` | |
>> | | |_| | | | (_| | | Version 0.3.0-prerelease+2599 (2014-04-11 23:52
>> UTC)
>> _/ |\__'_|_|_|\__'_| | Commit bf7096c (50 days old master)
>> |__/ | x86_64-w64-mingw32
>>
>> julia> procs()
>> 9-element Array{Int64,1}:
>> 1
>> 2
>> 3
>> 4
>> 5
>> 6
>> 7
>> 8
>> 9
>>
>> julia> tic();
>>
>> julia> nheads = @parallel (+) for i=1:2
>>int(randbool())
>>end
>> 16468
>>
>> julia> toc()
>> elapsed time: 2.77418807 seconds
>> 2.77418807
>>
>> julia>exit()
>>
>>
>> D:\install\Julia\Julia 0.3.0-prerelease-win64-ver3\Julia 0.3.0-prerelease
>> ver 3>bin\julia.exe -p 8
>>_
>>_ _ _(_)_ | A fresh approach to technical computing
>> (_) | (_) (_)| Documentation: http://docs.julialang.org
>>_ _ _| |_ __ _ | Type "help()" to list help topics
>> | | | | | | |/ _` | |
>> | | |_| | | | (_| | | Version 0.3.0-prerelease+2599 (2014-04-11 23:52
>> UTC)
>> _/ |\__'_|_|_|\__'_| | Commit bf7096c (50 days old master)
>> |__/ | x86_64-w64-mingw32
>>
>> julia> k=2
>> 2
>>
>> julia> tic();
>>
>> julia> nheads = @parallel (+) for i=1:k
>>int(randbool())
>>end
>> 99989022
>>
>> julia> toc()
>> elapsed time: 18.631674663 seconds
>> 18.631674663
>>
>> julia>
>>
>> What hapend ?
>>
>> Paul
>>
>>
>>
>
>
> --
> Med venlig hilsen
>
> Andreas Noack Jensen
>
Re: [julia-users] Parallel, strange behavior of the loop after changing the value to a variable, 6 time slower
After restart julia :
D:\install\Julia\Julia 0.3.0-prerelease-win64-ver3\Julia 0.3.0-prerelease
ver 3>bin\julia.exe -p 8
_
_ _ _(_)_ | A fresh approach to technical computing
(_) | (_) (_)| Documentation: http://docs.julialang.org
_ _ _| |_ __ _ | Type "help()" to list help topics
| | | | | | |/ _` | |
| | |_| | | | (_| | | Version 0.3.0-prerelease+2599 (2014-04-11 23:52
UTC)
_/ |\__'_|_|_|\__'_| | Commit bf7096c (50 days old master)
|__/ | x86_64-w64-mingw32
julia> const k=2
2
julia> tic();
julia> nheads = @parallel (+) for i=1:k
int(randbool())
end
exception on exception on 3: 4: ERROR: ERROR: exception on exception on 2:
exception on 7: ERROR: 5:
ERROR: ERROR: exception on k not defined6: exception on ERROR:
in anonymous at no file:1379
8k: not definedERROR:
in anonymous at no file:1379
k not definedk not defined
in anonymous at no file:1379
in anonymous at no file:1379
k not definedk not definedk not defined
in anonymous at no file:1379
in anonymous at no file:1379
in anonymous at no file:1379exception on
9: ERROR: k not defined
in anonymous at no file:1379
ERROR: no method +(UndefVarError, UndefVarError)
in mr_pairwise at reduce.jl:534
julia> toc()
elapsed time: 2.493525081 seconds
2.493525081
julia>
W dniu niedziela, 1 czerwca 2014 16:27:14 UTC+2 użytkownik paul analyst
napisał:
>
>
>
>
>
> *julia> const k=2;ERROR: cannot declare k constant; it already has
> a value:/Paul*
> W dniu niedziela, 1 czerwca 2014 16:13:27 UTC+2 użytkownik Andreas Noack
> Jensen napisał:
>>
>> This is the usual problem with global variables in Julia. If you define k
>> by
>>
>> const k=20000
>>
>> the timing results should be similar.
>>
>>
>> 2014-06-01 16:09 GMT+02:00 paul analyst :
>>
>>>
>>> D:\install\Julia\Julia 0.3.0-prerelease-win64-ver3\Julia
>>> 0.3.0-prerelease ver 3>bin\julia.exe -p 8
>>>_
>>>_ _ _(_)_ | A fresh approach to technical computing
>>> (_) | (_) (_)| Documentation: http://docs.julialang.org
>>>_ _ _| |_ __ _ | Type "help()" to list help topics
>>> | | | | | | |/ _` | |
>>> | | |_| | | | (_| | | Version 0.3.0-prerelease+2599 (2014-04-11
>>> 23:52 UTC)
>>> _/ |\__'_|_|_|\__'_| | Commit bf7096c (50 days old master)
>>> |__/ | x86_64-w64-mingw32
>>>
>>> julia> procs()
>>> 9-element Array{Int64,1}:
>>> 1
>>> 2
>>> 3
>>> 4
>>> 5
>>> 6
>>> 7
>>> 8
>>> 9
>>>
>>> julia> tic();
>>>
>>> julia> nheads = @parallel (+) for i=1:2
>>>int(randbool())
>>>end
>>> 16468
>>>
>>> julia> toc()
>>> elapsed time: 2.77418807 seconds
>>> 2.77418807
>>>
>>> julia>exit()
>>>
>>>
>>> D:\install\Julia\Julia 0.3.0-prerelease-win64-ver3\Julia
>>> 0.3.0-prerelease ver 3>bin\julia.exe -p 8
>>>_
>>>_ _ _(_)_ | A fresh approach to technical computing
>>> (_) | (_) (_)| Documentation: http://docs.julialang.org
>>>_ _ _| |_ __ _ | Type "help()" to list help topics
>>> | | | | | | |/ _` | |
>>> | | |_| | | | (_| | | Version 0.3.0-prerelease+2599 (2014-04-11
>>> 23:52 UTC)
>>> _/ |\__'_|_|_|\__'_| | Commit bf7096c (50 days old master)
>>> |__/ | x86_64-w64-mingw32
>>>
>>> julia> k=2
>>> 2
>>>
>>> julia> tic();
>>>
>>> julia> nheads = @parallel (+) for i=1:k
>>>int(randbool())
>>>end
>>> 99989022
>>>
>>> julia> toc()
>>> elapsed time: 18.631674663 seconds
>>> 18.631674663
>>>
>>> julia>
>>>
>>> What hapend ?
>>>
>>> Paul
>>>
>>>
>>>
>>
>>
>> --
>> Med venlig hilsen
>>
>> Andreas Noack Jensen
>>
>
[julia-users] pmap(eig,M) . How to separate result of pmap ?
julia> M = {cor(rand(4,4)) for i=1:2}
2-element Array{Any,1}:
4x4 Array{Float64,2}:
1.0 -0.227554 0.507924 -0.800516
-0.227554 1.00.220113 0.75924
0.507924 0.220113 1.0 -0.272765
-0.800516 0.75924 -0.272765 1.0
4x4 Array{Float64,2}:
1.0 -0.65399 -0.619397 -0.132602
-0.653991.0 -0.188752 0.818691
-0.619397 -0.188752 1.0 -0.680177
-0.132602 0.818691 -0.680177 1.0
julia> P=pmap(eig,M)
2-element Array{Any,1}:
([-2.0e-16,0.340329,1.3362,2.32347],
4x4 Array{Float64,2}:
0.445323 0.628389 -0.283962 -0.571121
-0.485061 0.445037 -0.623672 0.421533
0.08456 -0.637878 -0.711606 -0.282095
0.747832 -0.0134082 -0.154970.645409)
([1.77636e-15,0.0237017,1.77733,2.19897],
4x4 Array{Float64,2}:
0.670874 -0.0224424 0.702664 -0.235982
0.5131470.521253 -0.261832 0.629618
0.534381 -0.427716 -0.640692 -0.347864
0.0323244 -0.73814 0.164988 0.653364)
julia> P[1]
([-2.0e-16,0.340329,1.3362,2.32347],
4x4 Array{Float64,2}:
0.445323 0.628389 -0.283962 -0.571121
-0.485061 0.445037 -0.623672 0.421533
0.08456 -0.637878 -0.711606 -0.282095
0.747832 -0.0134082 -0.154970.645409)
julia> P[2]
([1.77636e-15,0.0237017,1.77733,2.19897],
4x4 Array{Float64,2}:
0.670874 -0.0224424 0.702664 -0.235982
0.5131470.521253 -0.261832 0.629618
0.534381 -0.427716 -0.640692 -0.347864
0.0323244 -0.73814 0.164988 0.653364)
How can you separate results, eigenvalues and eigenvectors?
The first and subsequent lines array P [1] and P [2]
Re: [julia-users] pmap(eig,M) . How to separate result of pmap ?
Thx, OK, its work.
It is eigenvaluse of first array : [x[1] for x in P][1]
But ?:
julia> [x[i] for x in P][i]=pmap(eig,M)
ERROR: i not defined
in anonymous at no file
this no wor. How automaticly preapre m1,v1; m2,v2; m3,v3 lik in typical
[m,v] = eig(R)
Paul
W dniu niedziela, 1 czerwca 2014 17:03:58 UTC+2 użytkownik Andreas Noack
Jensen napisał:
>
> You can use a complehensen. To get a vector of the vectors of the
> eigenvalues you could write [x[1] for x in P]. If you want to collect them
> into a matrix, you could write hcat([x[1] for x in P]...)
>
>
> 2014-06-01 16:56 GMT+02:00 paul analyst >
> :
>
>> julia> M = {cor(rand(4,4)) for i=1:2}
>> 2-element Array{Any,1}:
>> 4x4 Array{Float64,2}:
>> 1.0 -0.227554 0.507924 -0.800516
>> -0.227554 1.00.220113 0.75924
>> 0.507924 0.220113 1.0 -0.272765
>> -0.800516 0.75924 -0.272765 1.0
>> 4x4 Array{Float64,2}:
>> 1.0 -0.65399 -0.619397 -0.132602
>> -0.653991.0 -0.188752 0.818691
>> -0.619397 -0.188752 1.0 -0.680177
>> -0.132602 0.818691 -0.680177 1.0
>>
>> julia> P=pmap(eig,M)
>>
>> 2-element Array{Any,1}:
>> ([-2.0e-16,0.340329,1.3362,2.32347],
>> 4x4 Array{Float64,2}:
>> 0.445323 0.628389 -0.283962 -0.571121
>> -0.485061 0.445037 -0.623672 0.421533
>> 0.08456 -0.637878 -0.711606 -0.282095
>> 0.747832 -0.0134082 -0.154970.645409)
>> ([1.77636e-15,0.0237017,1.77733,2.19897],
>> 4x4 Array{Float64,2}:
>> 0.670874 -0.0224424 0.702664 -0.235982
>> 0.5131470.521253 -0.261832 0.629618
>> 0.534381 -0.427716 -0.640692 -0.347864
>> 0.0323244 -0.73814 0.164988 0.653364)
>>
>> julia> P[1]
>> ([-2.0e-16,0.340329,1.3362,2.32347],
>> 4x4 Array{Float64,2}:
>> 0.445323 0.628389 -0.283962 -0.571121
>> -0.485061 0.445037 -0.623672 0.421533
>> 0.08456 -0.637878 -0.711606 -0.282095
>> 0.747832 -0.0134082 -0.154970.645409)
>>
>> julia> P[2]
>> ([1.77636e-15,0.0237017,1.77733,2.19897],
>> 4x4 Array{Float64,2}:
>> 0.670874 -0.0224424 0.702664 -0.235982
>> 0.5131470.521253 -0.261832 0.629618
>> 0.534381 -0.427716 -0.640692 -0.347864
>> 0.0323244 -0.73814 0.164988 0.653364)
>>
>> How can you separate results, eigenvalues and eigenvectors?
>> The first and subsequent lines array P [1] and P [2]
>>
>>
>
>
> --
> Med venlig hilsen
>
> Andreas Noack Jensen
>
[julia-users] How to read and change the content of web pages to the vector ?
How to read and change the content of web pages to the vector ["word1", " word2", "word3", ",,,", "wordlast"]? Paul
Re: [julia-users] How to calculate all Euclidean distances between two sets of points in a 3-dimensional space
It is there. If D aand D1 ar two arrays with vectors in columns You have
this in Distance package.
julia> r = pairwise(Euclidean(), D,D1)
4x4 Array{Float64,2}:
4579.3 4528.87 2650.71 7326.62
5658.24 3646.92 2587.83 7348.04
5729.42 4581.69 1941.65 7266.23
5733.62 4656.58 2488.6 5902.54
in paresecs too ;)
Paul
W dniu środa, 4 czerwca 2014 14:50:35 UTC+2 użytkownik Carlos Baptista
napisał:
>
> Yes I have seen it. I tried something with the function pairwise, but I
> did not really get what I want. If I have two sets of sizes N and M
> respectively, I expect as return value a matrix of size NxM. What I got out
> of pairwise is smaller than that.
>
Re: [julia-users] How to read and change the content of web pages to the vector ?
Any help ? How to read and change the content of web pages to the vector ["word1", "word2", "word3", ",,,", "wordlast"]? W dniu 2014-06-04 12:47, paul analyst pisze: How to read and change the content of web pages to the vector ["word1", "word2", "word3", ",,,", "wordlast"]? Paul
Re: [julia-users] How to read and change the content of web pages to the vector ?
nice will be in 2 varaints: 1 All inside html 2. Only text displayed by browser Paul W dniu 2014-06-04 18:23, John Myles White pisze: I don't really understand what you mean by web page. -- John On Jun 4, 2014, at 9:20 AM, Paul Analyst wrote: Any help ? How to read and change the content of web pages to the vector ["word1", "word2", "word3", ",,,", "wordlast"]? W dniu 2014-06-04 12:47, paul analyst pisze: How to read and change the content of web pages to the vector ["word1", "word2", "word3", ",,,", "wordlast"]? Paul
[julia-users] Dynamic creation and naming of variables, what wrong?
dynamic creation and naming of variables, what wrong?
I need 100 new variables : m1 to m 100
julia> for i=1:100
"m" * string(i)=readcsv(string("m",i,".txt"))
end
ERROR: syntax: "#" is not a valid function argument name
Re: [julia-users] Re: Dynamic creation and naming of variables, what wrong?
Big txh, it works,
but now i heve 100 arrays (in real more... ) with 99 empty columns. Is
posible read m1 , m2 to vector , not to array ?
Paul
W dniu środa, 4 czerwca 2014 19:22:11 UTC+2 użytkownik Bob Nnamtrop napisał:
>
> Sorry I left out the function call:
>
> for i=1:100
> eval(parse("m$i = readcsv(\"m$i.txt\")"))
> end
>
>
>
> On Wed, Jun 4, 2014 at 11:16 AM, Bob Nnamtrop > wrote:
>
>> Or closer to the syntax of the original loop:
>>
>> for i=1:100
>> eval(parse("m$i = \"m$i.txt\""))
>> end
>>
>> Bob
>>
>>
>>
>> On Wed, Jun 4, 2014 at 11:13 AM, Patrick O'Leary > > wrote:
>>
>>> First, you probably would be better off with an array, rather than 100
>>> variables with numeric postfixes. You can use push!() for this.
>>>
>>> Second, the error is because Julia is trying to parse the left hand side
>>> as an attempt to define a function, using the shortened f(x) = y function
>>> definition syntax. Here, f is *, and the literal `"m" * string(i)` is being
>>> interpreted as the name of its argument, but this is not a valid identifier.
>>>
>>> Finally, although you almost certainly don't want to do what you're
>>> trying to do, you can if you separate creation of the symbol from
>>> evaluation:
>>>
>>> var_name = symbol("m" * string(i))
>>> @eval $var_name = readcsv(string("m", i, ".txt"))
>>>
>>>
>>> On Wednesday, June 4, 2014 11:36:37 AM UTC-5, paul analyst wrote:
>>>>
>>>> dynamic creation and naming of variables, what wrong?
>>>>
>>>> I need 100 new variables : m1 to m 100
>>>>
>>>> julia> for i=1:100
>>>>"m" * string(i)=readcsv(string("m",i,".txt"))
>>>>end
>>>> ERROR: syntax: "#" is not a valid function argument name
>>>>
>>>
>>
>
Re: [julia-users] Re: Dynamic creation and naming of variables, what wrong?
Sorry, is ok , i have vectors ..
Paul
W dniu środa, 4 czerwca 2014 20:09:46 UTC+2 użytkownik paul analyst napisał:
>
> Big txh, it works,
> but now i heve 100 arrays (in real more... ) with 99 empty columns. Is
> posible read m1 , m2 to vector , not to array ?
> Paul
>
> W dniu środa, 4 czerwca 2014 19:22:11 UTC+2 użytkownik Bob Nnamtrop
> napisał:
>>
>> Sorry I left out the function call:
>>
>> for i=1:100
>> eval(parse("m$i = readcsv(\"m$i.txt\")"))
>> end
>>
>>
>>
>> On Wed, Jun 4, 2014 at 11:16 AM, Bob Nnamtrop
>> wrote:
>>
>>> Or closer to the syntax of the original loop:
>>>
>>> for i=1:100
>>> eval(parse("m$i = \"m$i.txt\""))
>>> end
>>>
>>> Bob
>>>
>>>
>>>
>>> On Wed, Jun 4, 2014 at 11:13 AM, Patrick O'Leary
>>> wrote:
>>>
>>>> First, you probably would be better off with an array, rather than 100
>>>> variables with numeric postfixes. You can use push!() for this.
>>>>
>>>> Second, the error is because Julia is trying to parse the left hand
>>>> side as an attempt to define a function, using the shortened f(x) = y
>>>> function definition syntax. Here, f is *, and the literal `"m" *
>>>> string(i)`
>>>> is being interpreted as the name of its argument, but this is not a valid
>>>> identifier.
>>>>
>>>> Finally, although you almost certainly don't want to do what you're
>>>> trying to do, you can if you separate creation of the symbol from
>>>> evaluation:
>>>>
>>>> var_name = symbol("m" * string(i))
>>>> @eval $var_name = readcsv(string("m", i, ".txt"))
>>>>
>>>>
>>>> On Wednesday, June 4, 2014 11:36:37 AM UTC-5, paul analyst wrote:
>>>>>
>>>>> dynamic creation and naming of variables, what wrong?
>>>>>
>>>>> I need 100 new variables : m1 to m 100
>>>>>
>>>>> julia> for i=1:100
>>>>>"m" * string(i)=readcsv(string("m",i,".txt"))
>>>>>end
>>>>> ERROR: syntax: "#" is not a valid function argument name
>>>>>
>>>>
>>>
>>
Re: [julia-users] How to read and change the content of web pages to the vector ?
sample: http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";> http://www.kurshtml.edu.pl/html/html,html.html> xmlns="http://www.w3.org/1999/xhtml"; xml:lang="pl" lang="pl"> http://www.kurshtml.edu.pl/html/head,html.html>> http://www.kurshtml.edu.pl/html/meta,html.html> http-equiv="Content-Type" content="text/html; charset=iso-8859-2" /> http://www.kurshtml.edu.pl/html/meta,html.html> name="Description" content="description about page" /> http://www.kurshtml.edu.pl/html/meta,html.html> name="Keywords" content="bee, fly,monky" /> http://www.kurshtml.edu.pl/html/title,html.html>>page about insectshttp://www.kurshtml.edu.pl/html/title,html.html>> http://www.kurshtml.edu.pl/html/head,html.html>> http://www.kurshtml.edu.pl/html/body,html.html>> *Insects* (fromLatin <http://en.wikipedia.org/wiki/Latin> /insectum/, acalque <http://en.wikipedia.org/wiki/Calque> ofGreek <http://en.wikipedia.org/wiki/Ancient_Greek> ἔντομον [/éntomon/], "cut into sections") are aclass <http://en.wikipedia.org/wiki/Class_%28biology%29> ofinvertebrates <http://en.wikipedia.org/wiki/Invertebrate> within thearthropod <http://en.wikipedia.org/wiki/Arthropod> phylum that have achitinous <http://en.wikipedia.org/wiki/Chitin> exoskeleton <http://en.wikipedia.org/wiki/Exoskeleton>, a three-part body (head <http://en.wikipedia.org/wiki/Head>,thorax <http://en.wikipedia.org/wiki/Thorax_%28insect_anatomy%29> andabdomen <http://en.wikipedia.org/wiki/Abdomen>), three pairs of jointedlegs <http://en.wikipedia.org/wiki/Arthropod_leg>,compound eyes <http://en.wikipedia.org/wiki/Compound_eye> and one pair ofantennae <http://en.wikipedia.org/wiki/Antenna_%28biology%29>. They are among the most diverse groups ofanimals <http://en.wikipedia.org/wiki/Animal> on the planet, including more than a million describedspecies <http://en.wikipedia.org/wiki/Species> and representing more than half of all known living organisms.^[2] <http://en.wikipedia.org/wiki/Insect#cite_note-Chapman-2> ^[3] <http://en.wikipedia.org/wiki/Insect#cite_note-3>The number ofextant <http://en.wikipedia.org/wiki/Extant_taxon> species is estimated at between six and ten million,^[2] <http://en.wikipedia.org/wiki/Insect#cite_note-Chapman-2> ^[4] <http://en.wikipedia.org/wiki/Insect#cite_note-4> ^[5] <http://en.wikipedia.org/wiki/Insect#cite_note-number-5>and potentially represent over 90% of the differing animal life forms on Earth.^[6] <http://en.wikipedia.org/wiki/Insect#cite_note-6>Insects may be found in nearly allenvironments <http://en.wikipedia.org/wiki/Natural_environment>, although only a small number of species reside in the oceans, a habitat dominated by another arthropod group,crustaceans <http://en.wikipedia.org/wiki/Crustacean>. http://www.kurshtml.edu.pl/html/body,html.html>> http://www.kurshtml.edu.pl/html/html,html.html>> i need somthing like : Insects (from Latin insectum, a calque of Greek µ?? [éntomon], "cut into ... although only a small number of species reside in the oceans, a habitat dominated by another arthropod group, crustaceans W dniu 2014-06-05 07:15, John Myles White pisze: I'm still lost. Do you want to print out the text for an HTML table to STDOUT? -- John On Jun 4, 2014, at 9:33 AM, Kevin Squire <mailto:kevin.squ...@gmail.com>> wrote: I would think "web page" = "HTML document". On Wednesday, June 4, 2014, John Myles White mailto:johnmyleswh...@gmail.com>> wrote: I don't really understand what you mean by web page. -- John > On Jun 4, 2014, at 9:20 AM, Paul Analyst > wrote: > > > Any help ? > How to read and change the content of web pages to the vector ["word1", "word2", "word3", ",,,", "wordlast"]? > > W dniu 2014-06-04 12:47, paul analyst pisze: >> How to read and change the content of web pages to the vector ["word1", "word2", "word3", ",,,", "wordlast"]? >> >> Paul >
[julia-users] Error Pkg.add("LightXML"), where is problem ?on my comp or on server?
A fresh approach to technical computing
Documentation: http://docs.julialang.org
Type "help()" to list help topics
Version 0.3.0-prerelease+2599 (2014-04-11 23:52 UTC)
Commit bf7096c (54 days old master)
x86_64-w64-mingw32
julia> Pkg.add("LightXML")
INFO: Cloning cache of LightXML from
git://github.com/lindahua/LightXML.jl.git
INFO: Installing LightXML v0.1.6
INFO: Building LibCURL
WARNING: skipping
repodata/0363c7383794a00bf1c007bcd1bb47709f416fb86f80852c5915931f67fc3739-primary.
xml.gz, not in cache
INFO: Updating WinRPM package list
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory/
/repodata/repomd.xml
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory/
/repodata/dd159986229fa87a6b80b82e1658883175ac9678031564d766bc4a824c3e4c03-primary.xml.gz
WARNING: encounted invalid data while parsing repomd
===[ ERROR: LibCURL
]===
no method alloc_request(IOBuffer, Uint64)
while loading C:\Users\SAMSUNG2\.julia\LibCURL\deps\build.jl, in expression
starting on line 13
INFO: Building LightXML
INFO: Updating WinRPM package list
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory/
/repodata/repomd.xml
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory/
/repodata/dd159986229fa87a6b80b82e1658883175ac9678031564d766bc4a824c3e4c03-primary.xml.gz
WARNING: encounted invalid data while parsing repomd
==[ ERROR: LightXML
]===
no method alloc_request(IOBuffer, Uint64)
while loading C:\Users\SAMSUNG2\.julia\LightXML\deps\build.jl, in
expression starting on line 11
[ BUILD ERRORS
]
WARNING: LightXML and LibCURL had build errors.
- packages with build errors remain installed in C:\Users\SAMSUNG2\.julia
- build a package and all its dependencies with `Pkg.build(pkg)`
- build a single package by running its `deps/build.jl` script
INFO: Package database updated
julia> Pkg.add("LightXML")
INFO: Nothing to be done
julia> Pkg.update()
INFO: Updating METADATA...
INFO: Updating Distributions...
INFO: Computing changes...
INFO: No packages to install, update or remove
julia> using LightXML
ERROR: could not load module
C:\Users\SAMSUNG2\.julia\WinRPM\deps\usr\x86_64-w64-mingw32\sys-root\mi
ngw\bin\libxml2-2: no error
in dlopen at c.jl:19
in include at boot.jl:244
in include_from_node1 at loading.jl:128
in include_from_node1 at loading.jl:124
while loading C:\Users\SAMSUNG2\.julia\LightXML\src\clib.jl, in expression
starting on line 4
while loading C:\Users\SAMSUNG2\.julia\LightXML\src\LightXML.jl, in
expression starting on line 24
julia> Pkg.update()
INFO: Updating METADATA...
INFO: Updating Distributions...
INFO: Computing changes...
INFO: No packages to install, update or remove
julia> Pkg.add("LightXML")
INFO: Nothing to be done
julia> using LightXML
julia> xdoc = parse_file("ex1.xml")
ERROR: parse_file not defined
julia> xdoc = parse_file("ex1.xml")
ERROR: parse_file not defined
julia> par
parentparse_bin parse_hex parse_string parseip
parentindexes parse_file parse_int parsefloat partitions
parse parse_floatparse_oct parseint
julia> xdoc = parse("ex1.xml")
:(ex1.xml)
julia> using LightXML
julia> xdoc = parse_file("ex1.xml")
ERROR: parse_file not defined
julia>
Re: [julia-users] Error Pkg.add("LightXML"), where is problem ?on my comp or on server?
..)
instead.
in depwarn at deprecated.jl:36
INFO: Downloading: libidn
INFO: Extracting: libidn
WARNING: readsfrom(cmd,args...) is deprecated, use open(cmd,"r",args...)
instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use open(cmd,"r",args...)
instead.
in depwarn at deprecated.jl:36
INFO: Downloading: mozilla-nspr
INFO: Extracting: mozilla-nspr
WARNING: readsfrom(cmd,args...) is deprecated, use open(cmd,"r",args...)
instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use open(cmd,"r",args...)
instead.
in depwarn at deprecated.jl:36
INFO: Downloading: libcurl
INFO: Extracting: libcurl
WARNING: readsfrom(cmd,args...) is deprecated, use open(cmd,"r",args...)
instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use open(cmd,"r",args...)
instead.
in depwarn at deprecated.jl:36
INFO: Success
julia> Pkg.update()
INFO: Updating METADATA...
INFO: Updating Distributions...
INFO: Computing changes...
INFO: No packages to install, update or remove
julia> Pkg.add("LightXML")
INFO: Nothing to be done
julia> using Li
LibCURL LibExpat LightXML
julia> using LightXML
ERROR: could not load module
C:\Users\SAMSUNG2\.julia\WinRPM\deps\usr\x86_64-w64-mingw32\sys-root\mi
ngw\bin\libxml2-2: no error
in dlopen at c.jl:19
in include at boot.jl:244
in include_from_node1 at loading.jl:128
in include_from_node1 at loading.jl:124
while loading C:\Users\SAMSUNG2\.julia\LightXML\src\clib.jl, in
expression starting on line 4
while loading C:\Users\SAMSUNG2\.julia\LightXML\src\LightXML.jl, in
expression starting on line 24
julia>
Paul
W dniu 2014-06-05 15:45, Jameson Nash pisze:
Version 0.3.0-prerelease+2599 (2014-04-11 23:52 UTC)
Commit bf7096c (54 days old master)
your version of 0.3 is too old. either switch to 0.2, or update your
copy of 0.3 more frequently
(note: after calling using XXX, future calls to using XXX are a no-op,
even if the initial attempt halted with an error)
On Thu, Jun 5, 2014 at 6:55 AM, paul analyst <mailto:paul.anal...@mail.com>> wrote:
A fresh approach to technical computing
Documentation: http://docs.julialang.org
Type "help()" to list help topics
Version 0.3.0-prerelease+2599 (2014-04-11 23:52 UTC)
Commit bf7096c (54 days old master)
x86_64-w64-mingw32
julia> Pkg.add("LightXML")
INFO: Cloning cache of LightXML from
git://github.com/lindahua/LightXML.jl.git
<http://github.com/lindahua/LightXML.jl.git>
INFO: Installing LightXML v0.1.6
INFO: Building LibCURL
WARNING: skipping
repodata/0363c7383794a00bf1c007bcd1bb47709f416fb86f80852c5915931f67fc3739-primary.
xml.gz, not in cache
INFO: Updating WinRPM package list
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory/
/repodata/repomd.xml
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory/
/repodata/dd159986229fa87a6b80b82e1658883175ac9678031564d766bc4a824c3e4c03-primary.xml.gz
WARNING: encounted invalid data while parsing repomd
===[ ERROR: LibCURL
]===
no method alloc_request(IOBuffer, Uint64)
while loading C:\Users\SAMSUNG2\.julia\LibCURL\deps\build.jl, in
expression starting on line 13
INFO: Building LightXML
INFO: Updating WinRPM package list
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory/
/repodata/repomd.xml
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory/
/repodata/dd159986229fa87a6b80b82e1658883175ac9678031564d766bc4a824c3e4c03-primary.xml.gz
WARNING: encounted invalid data while parsing repomd
==[ ERROR: LightXML
]===
no method alloc_request(IOBuffer, Uint64)
while loading C:\Users\SAMSUNG2\.julia\LightXML\deps\build.jl, in
expression starting on line 11
[ BUILD ERRORS
]
WARNING: LightXML and LibCURL had build errors.
- packages with build errors remain installed in
C:\Users\SAMSUNG2\.julia
- build a package and all its dependencies with `Pkg.build(pkg)`
- build a single package by running its `deps/build.jl` script
INFO: Package database updated
julia> Pkg.add("LightXML")
INFO: Nothing to be done
julia> Pkg.upd
Re: [julia-users] Error Pkg.add("LightXML"), where is problem ?on my comp or on server?
julia> Pkg.build("LightXML")
INFO: Building LibCURL
INFO: Updating WinRPM package list
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory//
repodata/repomd.xml
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win64/openSUSE_Factory//
repodata/repomd.xml
INFO: Building LightXML
INFO: Packages to install: zlib, libxml2
INFO: Downloading: zlib
INFO: Extracting: zlib
INFO: Downloading: libxml2
INFO: Extracting: libxml2
INFO: Success
julia> using LightXML
julia> xdoc = parse_file("ex1.xml")
ERROR: parse_file not defined
file is in this dir...
Paul
W dniu 2014-06-05 17:21, Isaiah Norton pisze:
try Pkg.build("LightXML")
On Thu, Jun 5, 2014 at 11:03 AM, Paul Analyst <mailto:paul.anal...@mail.com>> wrote:
new verison and new errors (mu Julia is not instaled on drive C,
is on D )
_
_ _ _(_)_ | A fresh approach to technical computing
(_) | (_) (_)| Documentation: http://docs.julialang.org
_ _ _| |_ __ _ | Type "help()" to list help topics
| | | | | | |/ _` | |
| | |_| | | | (_| | | Version 0.3.0-prerelease+3431
(2014-06-03 20:06 UTC)
_/ |\__'_|_|_|\__'_| | Commit 1769118* (1 day old master)
|__/ | x86_64-w64-mingw32
julia> Pkg.a
add available
julia> Pkg.ad
ERROR: ad not defined
julia> Pkg.add("LightXML")
INFO: Nothing to be done
INFO: METADATA is out-of-date - you may not have the latest
version of LightXML
INFO: Use `Pkg.update()` to get the latest versions of your packages
julia> Pkg.update()
INFO: Updating METADATA...
INFO: Updating cache of Color...
INFO: Updating cache of WinRPM...
INFO: Updating Distributions...
INFO: Computing changes...
INFO: Upgrading Color: v0.2.9 => v0.2.10
INFO: Upgrading WinRPM: v0.0.13 => v0.0.14
INFO: Building LibCURL
INFO: Updating WinRPM package list
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory//
repodata/repomd.xml
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory//
repodata/dd159986229fa87a6b80b82e1658883175ac9678031564d766bc4a824c3e4c03-primary.xml.gz
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win64/openSUSE_Factory//
repodata/repomd.xml
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win64/openSUSE_Factory//
repodata/8e1eaed4d2891f27e5be81856ffe0cacea6b5b296ea9641908a3733bfaacbf37-primary.xml.gz
INFO: Packages to install: libgpg-error-lang, libgpg-error,
libgcc, libsqlite3-0, libintl, libgcrypt
, libidn-lang, zlib, libssh2, mozilla-nss, libidn, mozilla-nspr,
libcurl
INFO: Downloading: libgpg-error-lang
INFO: Extracting: libgpg-error-lang
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
INFO: Downloading: libgpg-error
INFO: Extracting: libgpg-error
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
INFO: Downloading: libgcc
INFO: Extracting: libgcc
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
INFO: Downloading: libsqlite3-0
INFO: Extracting: libsqlite3-0
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
INFO: Downloading: libintl
INFO: Extracting: libintl
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
INFO: Downloading: libgcrypt
INFO: Extracting: libgcrypt
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at depreca
Re: [julia-users] Error Pkg.add("LightXML"), where is problem ?on my comp or on server?
the most usefull way:)
Big Thx, working
Paul
W dniu 2014-06-05 17:33, Isaiah Norton pisze:
Probably need to restart Julia. Otherwise, no idea. It works for me on
Windows.
On Thu, Jun 5, 2014 at 11:24 AM, Paul Analyst <mailto:paul.anal...@mail.com>> wrote:
julia> Pkg.build("LightXML")
INFO: Building LibCURL
INFO: Updating WinRPM package list
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory//
repodata/repomd.xml
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win64/openSUSE_Factory//
repodata/repomd.xml
INFO: Building LightXML
INFO: Packages to install: zlib, libxml2
INFO: Downloading: zlib
INFO: Extracting: zlib
INFO: Downloading: libxml2
INFO: Extracting: libxml2
INFO: Success
julia> using LightXML
julia> xdoc = parse_file("ex1.xml")
ERROR: parse_file not defined
file is in this dir...
Paul
W dniu 2014-06-05 17:21, Isaiah Norton pisze:
try Pkg.build("LightXML")
On Thu, Jun 5, 2014 at 11:03 AM, Paul Analyst
mailto:paul.anal...@mail.com>> wrote:
new verison and new errors (mu Julia is not instaled on drive
C, is on D )
_
_ _ _(_)_ | A fresh approach to technical computing
(_) | (_) (_)| Documentation:
http://docs.julialang.org
_ _ _| |_ __ _ | Type "help()" to list help topics
| | | | | | |/ _` | |
| | |_| | | | (_| | | Version 0.3.0-prerelease+3431
(2014-06-03 20:06 UTC)
_/ |\__'_|_|_|\__'_| | Commit 1769118* (1 day old master)
|__/ | x86_64-w64-mingw32
julia> Pkg.a
add available
julia> Pkg.ad
ERROR: ad not defined
julia> Pkg.add("LightXML")
INFO: Nothing to be done
INFO: METADATA is out-of-date - you may not have the latest
version of LightXML
INFO: Use `Pkg.update()` to get the latest versions of your
packages
julia> Pkg.update()
INFO: Updating METADATA...
INFO: Updating cache of Color...
INFO: Updating cache of WinRPM...
INFO: Updating Distributions...
INFO: Computing changes...
INFO: Upgrading Color: v0.2.9 => v0.2.10
INFO: Upgrading WinRPM: v0.0.13 => v0.0.14
INFO: Building LibCURL
INFO: Updating WinRPM package list
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory//
repodata/repomd.xml
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win32/openSUSE_Factory//
repodata/dd159986229fa87a6b80b82e1658883175ac9678031564d766bc4a824c3e4c03-primary.xml.gz
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win64/openSUSE_Factory//
repodata/repomd.xml
INFO: Downloading
http://download.opensuse.org/repositories/windows:/mingw:/win64/openSUSE_Factory//
repodata/8e1eaed4d2891f27e5be81856ffe0cacea6b5b296ea9641908a3733bfaacbf37-primary.xml.gz
INFO: Packages to install: libgpg-error-lang, libgpg-error,
libgcc, libsqlite3-0, libintl, libgcrypt
, libidn-lang, zlib, libssh2, mozilla-nss, libidn,
mozilla-nspr, libcurl
INFO: Downloading: libgpg-error-lang
INFO: Extracting: libgpg-error-lang
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
INFO: Downloading: libgpg-error
INFO: Extracting: libgpg-error
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
INFO: Downloading: libgcc
INFO: Extracting: libgcc
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
INFO: Downloading: libsqlite3-0
INFO: Extracting: libsqlite3-0
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
in depwarn at deprecated.jl:36
WARNING: readsfrom(cmd,args...) is deprecated, use
open(cmd,"r",args...) instead.
Re: [julia-users] Re: How to read and change the content of web pages to the vector ?
Thx James, i will try Paul. W dniu 2014-06-09 19:04, James Porter pisze: https://github.com/porterjamesj/GumboParser.jl
[julia-users] How use two contition to filtred array?
How use two conditions to filtred array? Left and right side this code separatly are good. But how use booth conditions in filter ? (take rows with <1 and >500 in col 2) klient[klient[:,2].<=10;:] & klient[klient[:,2].>500;:] Paul
[julia-users] Re: How use two contition to filtred array?
Is ok , big thx. How to join another condition but another vector of the same lengths as "client"? Prerequisite: anothervector = 0 julia> klient[ 500 .< klient[:,2] .<= 10 anothervector=0,:] ERROR: syntax: unexpected comma in matrix expression Paul W dniu wtorek, 10 czerwca 2014 20:50:03 UTC+2 użytkownik Andrea Pagnani napisał: > > I think > > klient[ 500 .< klient[:,2] .<= 10,:] > > should work > > Andrea > > On Tuesday, June 10, 2014 8:41:17 PM UTC+2, paul analyst wrote: >> >> How use two conditions to filtred array? >> >> Left and right side this code separatly are good. But how use booth >> conditions in filter ? (take rows with <1 and >500 in col 2) >> >> klient[klient[:,2].<=10;:] & klient[klient[:,2].>500;:] >> >> Paul >> >
[julia-users] How to find the index of maximum but omitting to check any field eg not x [5,7]
I have a random vector x = rand (10) how to find the index of maximum but omitting to check any field eg not x [ 5,7] some like: indmax y = (x [but not read [5,7]]) Paul
[julia-users] How Delete row or col of array? like deleteat! in vectors
a=rand(5,5) how Delete row(s) or col(s) of array ? Paul
[julia-users] Re: How to find the index of maximum but omitting to check any field eg not x [5,7]
No sugestion ? Paul W dniu poniedziałek, 16 czerwca 2014 14:06:23 UTC+2 użytkownik paul analyst napisał: > > I have a random vector x = rand (10) > how to find the index of maximum but omitting to check any field eg not x > [5,7] > some like: > indmax y = (x [but not read [5,7]]) > Paul >
Re: [julia-users] Re: How to find the index of maximum but omitting to check any field eg not x [5,7]
Big thx, it work, Paul W dniu 2014-06-16 21:24, Dahua Lin pisze: |u =trues(length(x)) u[[5,7]]=false ir =0 vr =-Inf fori =1:length(x) ifu[i]&&x[i]>vr ir =i vr =x[i] end end |
Re: [julia-users] Re: How Delete row or col of array? like deleteat! in vectors
Thx, for this info But not about items I need delete some rows ... How fast delete rows in arrray, one [3,:]or more [[2,4],:] ? Paul W dniu 2014-06-16 21:22, Stefan Schwarz pisze: deleting in place a matrix is not supported and does not make sense. why is that? you've for instance a 5x5 matrix and you want to delete an item. deleteat! shifts subsequent items to fill the resulting gap, so you're loosing dimensionality. basically what you can do is this: a = deleteat!(a[1:end], 1) which is deleting item at position 1. if you want to bring that back into a matrix representation the problems rear up. what dimension you'll have afterwards? 6x4? if you delete another one you'll have 23 elements left, which is really hard to bring into a 2D shape. in the end you've to come up with your own scheme with deleting an item at (i, j). deleting an item and presuming deleting means zeroing it out: a[2,2] = convert(eltype(a), 0) deleting the 2nd column: a[:,2] = convert(eltype(a), 0) deleting the 1st row: a[1, 1:end] = convert(eltype(a), 0) don't know if this tackles your question, but hope this helps.
Re: [julia-users] Re: How Delete row or col of array? like deleteat! in vectors
Is possible or not ? Delete rows in array ? Paul W dniu 2014-06-17 07:49, Paul Analyst pisze: Thx, for this info But not about items I need delete some rows ... How fast delete rows in arrray, one [3,:]or more [[2,4],:] ? Paul W dniu 2014-06-16 21:22, Stefan Schwarz pisze: deleting in place a matrix is not supported and does not make sense. why is that? you've for instance a 5x5 matrix and you want to delete an item. deleteat! shifts subsequent items to fill the resulting gap, so you're loosing dimensionality. basically what you can do is this: a = deleteat!(a[1:end], 1) which is deleting item at position 1. if you want to bring that back into a matrix representation the problems rear up. what dimension you'll have afterwards? 6x4? if you delete another one you'll have 23 elements left, which is really hard to bring into a 2D shape. in the end you've to come up with your own scheme with deleting an item at (i, j). deleting an item and presuming deleting means zeroing it out: a[2,2] = convert(eltype(a), 0) deleting the 2nd column: a[:,2] = convert(eltype(a), 0) deleting the 1st row: a[1, 1:end] = convert(eltype(a), 0) don't know if this tackles your question, but hope this helps.
Re: [julia-users] Re: How Delete row or col of array? like deleteat! in vectors
number removal line is dynamic. This time 4 then maybe 2 maybe 3 etc Question now : How to construct fromvector [1:10] new vector without [2,4] like this [1,3,5:10] Paul W dniu 2014-06-18 12:53, Tim Holy pisze: A = rand(5,5) A = A[[1:2,3:5], :] --Tim On Wednesday, June 18, 2014 11:26:36 AM Paul Analyst wrote: Is possible or not ? Delete rows in array ? Paul W dniu 2014-06-17 07:49, Paul Analyst pisze: Thx, for this info But not about items I need delete some rows ... How fast delete rows in arrray, one [3,:]or more [[2,4],:] ? Paul W dniu 2014-06-16 21:22, Stefan Schwarz pisze: deleting in place a matrix is not supported and does not make sense. why is that? you've for instance a 5x5 matrix and you want to delete an item. deleteat! shifts subsequent items to fill the resulting gap, so you're loosing dimensionality. basically what you can do is this: a = deleteat!(a[1:end], 1) which is deleting item at position 1. if you want to bring that back into a matrix representation the problems rear up. what dimension you'll have afterwards? 6x4? if you delete another one you'll have 23 elements left, which is really hard to bring into a 2D shape. in the end you've to come up with your own scheme with deleting an item at (i, j). deleting an item and presuming deleting means zeroing it out: a[2,2] = convert(eltype(a), 0) deleting the 2nd column: a[:,2] = convert(eltype(a), 0) deleting the 1st row: a[1, 1:end] = convert(eltype(a), 0) don't know if this tackles your question, but hope this helps.
Re: [julia-users] Re: How Delete row or col of array? like deleteat! in vectors
Ok, txh,
A have lot of long vectors. Is it good time or look for something faster?
julia> a=[1:1:10^6];
julia> b=[1:10:10^6];
julia> @time setdiff(a,b)
elapsed time: 1.339431633 seconds (252659008 bytes allocated, 14.36% gc
time)
90-element Array{Int64,1}:
Paul
W dniu 2014-06-18 13:38, Tim Holy pisze:
setdiff
--Tim
On Wednesday, June 18, 2014 01:29:05 PM Paul Analyst wrote:
number removal line is dynamic. This time 4 then maybe 2 maybe 3 etc
Question now :
How to construct fromvector [1:10] new vector without [2,4] like this
[1,3,5:10]
Paul
W dniu 2014-06-18 12:53, Tim Holy pisze:
A = rand(5,5)
A = A[[1:2,3:5], :]
--Tim
On Wednesday, June 18, 2014 11:26:36 AM Paul Analyst wrote:
Is possible or not ? Delete rows in array ?
Paul
W dniu 2014-06-17 07:49, Paul Analyst pisze:
Thx, for this info
But not about items I need delete some rows ...
How fast delete rows in arrray, one [3,:]or more [[2,4],:] ?
Paul
W dniu 2014-06-16 21:22, Stefan Schwarz pisze:
deleting in place a matrix is not supported and does not make sense.
why is that?
you've for instance a 5x5 matrix and you want to delete an item.
deleteat! shifts subsequent items to fill the resulting gap, so you're
loosing dimensionality.
basically what you can do is this:
a = deleteat!(a[1:end], 1)
which is deleting item at position 1.
if you want to bring that back into a matrix representation the
problems rear up.
what dimension you'll have afterwards? 6x4?
if you delete another one you'll have 23 elements left, which is
really hard to bring
into a 2D shape.
in the end you've to come up with your own scheme with deleting an
item at (i, j).
deleting an item and presuming deleting means zeroing it out:
a[2,2] = convert(eltype(a), 0)
deleting the 2nd column:
a[:,2] = convert(eltype(a), 0)
deleting the 1st row:
a[1, 1:end] = convert(eltype(a), 0)
don't know if this tackles your question, but hope this helps.
Re: [julia-users] Re: How Delete row or col of array? like deleteat! in vectors
Thanks, but I'm an analyst market, not a programmer;/ Still, I really like
Julia. Historically, only SPSS. I can so deeply programmed? Any tips?
Paul
W dniu środa, 18 czerwca 2014 14:51:03 UTC+2 użytkownik Tim Holy napisał:
>
> If you left them as ranges rather than converting them to vectors (if that
> fits
> your usual usage case), it would be possible to have a special version of
> setdiff operating on ranges that would be much faster. Would be great if
> you
> could write & submit that.
>
> --Tim
>
> On Wednesday, June 18, 2014 02:40:59 PM Paul Analyst wrote:
> > Ok, txh,
> >
> > A have lot of long vectors. Is it good time or look for something
> faster?
> >
> > julia> a=[1:1:10^6];
> >
> > julia> b=[1:10:10^6];
> >
> > julia> @time setdiff(a,b)
> > elapsed time: 1.339431633 seconds (252659008 bytes allocated, 14.36% gc
> > time)
> > 90-element Array{Int64,1}:
> >
> > Paul
> >
> > W dniu 2014-06-18 13:38, Tim Holy pisze:
> > > setdiff
> > >
> > > --Tim
> > >
> > > On Wednesday, June 18, 2014 01:29:05 PM Paul Analyst wrote:
> > >> number removal line is dynamic. This time 4 then maybe 2 maybe 3 etc
> > >>
> > >> Question now :
> > >> How to construct fromvector [1:10] new vector without [2,4] like this
> > >> [1,3,5:10]
> > >>
> > >> Paul
> > >>
> > >> W dniu 2014-06-18 12:53, Tim Holy pisze:
> > >>> A = rand(5,5)
> > >>> A = A[[1:2,3:5], :]
> > >>>
> > >>> --Tim
> > >>>
> > >>> On Wednesday, June 18, 2014 11:26:36 AM Paul Analyst wrote:
> > >>>> Is possible or not ? Delete rows in array ?
> > >>>> Paul
> > >>>>
> > >>>> W dniu 2014-06-17 07:49, Paul Analyst pisze:
> > >>>>> Thx, for this info
> > >>>>> But not about items I need delete some rows ...
> > >>>>>
> > >>>>> How fast delete rows in arrray, one [3,:]or more [[2,4],:] ?
> > >>>>>
> > >>>>> Paul
> > >>>>>
> > >>>>> W dniu 2014-06-16 21:22, Stefan Schwarz pisze:
> > >>>>>> deleting in place a matrix is not supported and does not make
> sense.
> > >>>>>>
> > >>>>>> why is that?
> > >>>>>>
> > >>>>>> you've for instance a 5x5 matrix and you want to delete an item.
> > >>>>>> deleteat! shifts subsequent items to fill the resulting gap, so
> > >>>>>> you're
> > >>>>>> loosing dimensionality.
> > >>>>>>
> > >>>>>> basically what you can do is this:
> > >>>>>> a = deleteat!(a[1:end], 1)
> > >>>>>>
> > >>>>>> which is deleting item at position 1.
> > >>>>>>
> > >>>>>> if you want to bring that back into a matrix representation the
> > >>>>>> problems rear up.
> > >>>>>>
> > >>>>>> what dimension you'll have afterwards? 6x4?
> > >>>>>> if you delete another one you'll have 23 elements left, which is
> > >>>>>> really hard to bring
> > >>>>>> into a 2D shape.
> > >>>>>>
> > >>>>>> in the end you've to come up with your own scheme with deleting
> an
> > >>>>>> item at (i, j).
> > >>>>>>
> > >>>>>> deleting an item and presuming deleting means zeroing it out:
> > >>>>>> a[2,2] = convert(eltype(a), 0)
> > >>>>>>
> > >>>>>> deleting the 2nd column:
> > >>>>>> a[:,2] = convert(eltype(a), 0)
> > >>>>>>
> > >>>>>> deleting the 1st row:
> > >>>>>> a[1, 1:end] = convert(eltype(a), 0)
> > >>>>>>
> > >>>>>> don't know if this tackles your question, but hope this helps.
>
>
Re: [julia-users] Re: How Delete row or col of array? like deleteat! in vectors
Great lesson thanks, I'll try :)
Paul
W dniu 2014-06-18 16:51, Tim Holy pisze:
On Wednesday, June 18, 2014 06:06:24 AM paul analyst wrote:
>Thanks, but I'm an analyst market, not a programmer;/ Still, I really like
>Julia. Historically, only SPSS. I can so deeply programmed? Any tips?
Yes, with Julia it's easy to reach in "deep." First you might want to look at
existing methods for setdiff:
julia> methods(setdiff)
# 3 methods for generic function "setdiff":
setdiff(a::IntSet,b::IntSet) at intset.jl:90
setdiff(a::Set{T},b::Set{T}) at set.jl:73
setdiff(a,b) at array.jl:1352
From this, personally I'd guess the implementation in array.jl will be closest
to what you want. So open up an editor and look at the implementation in
base/array.jl (I'll add a few comments to help you):
# from array.jl, line 1352:
function setdiff(a, b)
# The first few lines initialize an empty output Vector
# with the correct element type,
# and convert b to a Set so that it's fast to test whether
# an element of a can be found in b.
args_type = promote_type(eltype(a), eltype(b))
bset = Set(b)
ret = Array(args_type,0)
# seen is to make sure we return just the unique values in a
seen = Set()
for a_elem in a # loop over all the elements in a
# test that we haven't seen a_elem before,
# and that it's not present in b
if !in(a_elem, seen) && !in(a_elem, bset)
push!(ret, a_elem) # keep the element
push!(seen, a_elem)# mark it as seen
end
end
ret# return the result
end
That's it!
For implementing your own version, start like this:
import Base.setdiff
function setdiff(a::Ranges, b::Ranges)
# code goes here
end
This means your version will be called whenever both inputs are Range-type
objects.
For the actual implementation, here's another hint: you probably noticed that
most of the "magic" was taken care of by the "in" function. Why not check to
see whether there are any methods already defined for Range objects? If so, you
can expect that they might be more efficient that for Sets. Also, you probably
don't have to worry about "seen" because the elements of the range are
guaranteed to be unique (if step(a) != 0). So, you could almost cut-and-paste
that implementation for arrays, but delete all the parts that deal with Sets.
Once you've developed the code, try posting it here for comments. Eventually
you might want to learn git, but let's take one step at a time:-).
--Tim
[julia-users] how to get vec with index (position) of a particular value (eg 1) in vector
How to Do a vector indicating the position of a particular value (eg 1) in another vector? by this question: (1)? [0 0 1 01] expected vector [3,5] Paul
[julia-users] How to convert vector to a series of possible pairs of elements ?
How to convert vector to a series of possible pairs of elements ? [1,2,3] I expect [1,1] [1,2] [1,3] [2,1] [2,2] [2,3] [3,1] [3,2] [3,3]
Re: [julia-users] Re: How to convert vector to a series of possible pairs of elements ?
Thank you.
Do loops is the fastest way? I have a lot of such vectors ... Is it
ready, optimized command from combinatorics?
Paul
W dniu 2014-06-19 21:55, Ethan Anderes pisze:
… I probably should not have been sloppy about the typing the
comprehensions in my previous answer. I think this is probably better
|julia> x = [1,2,3]
3-element Array{Int64,1}:
1
2
3
julia> pairs_any = [[i,j] for i in x, j in x] |> vec
9-element Array{Any,1}:
[1,1]
[2,1]
[3,1]
[1,2]
[2,2]
[3,2]
[1,3]
[2,3]
[3,3]
julia> pairs_int = Vector{eltype(x)}[[i,j] for i in x, j in x] |> vec
9-element Array{Array{Int64,1},1}:
[1,1]
[2,1]
[3,1]
[1,2]
[2,2]
[3,2]
[1,3]
[2,3]
[3,3]
|
btw, I’m a bit puzzled what Array{Array{T,1},1} means when T is not
defined. This is what I get when I did the sloppy version
|julia> pairs_T = Vector[[i,j] for i in x, j in x] |> vec
9-element Array{Array{T,1},1}:
[1,1]
[2,1]
[3,1]
[1,2]
[2,2]
[3,2]
[1,3]
[2,3]
[3,3]
julia> T
ERROR: T not defined
|
On Thursday, June 19, 2014 12:49:21 PM UTC-7, Ethan Anderes wrote:
Comprehensions will give you what you want
|x = [1,2,3]
pairs = Vector[[i,j] for i in x, j in x] |> vec
|
On Thursday, June 19, 2014 12:16:32 PM UTC-7, paul analyst wrote:
How to convert vector to a series of possible pairs of
elements ?
[1,2,3]
I expect
[1,1] [1,2] [1,3] [2,1] [2,2] [2,3] [3,1] [3,2] [3,3]
[julia-users] Please help, I can't to deploy a simple parallelization .
Despite many attempts, I can't to deploy a simple parallelization and ask
for help on a specific the example.
Array WS can be broken down into clones, and at the finish may then add
them, but WS is great and it would be better without cloning it.
D=readcsv("D.txt");
k,l=size(D)
10,1
WS=zeros(l,l);
Dt=int(D.>0);
for i=1:k;
kosz=findin(Dt[i,:],1);
for o in kosz,p in kosz;
para=[o,p];
#println(para);
WS[para[1],para[2]]+=1;
println(i);
end;
end;
Paul
[julia-users] Sort error, How to find reserved word in big text ?
I have a very long vector (5*10^6 ) with the words in a foreign language. I
can not sort
julia> sort (y1u)
ERROR: no method isless (Float64, substring {UTF8String})
in the sort! at sort.jl: 233
in the sort! at sort.jl: 277
in next at string.jl: 630
Probably there is a word reserved for Julia. How to find them? Where is the
list
of such words?
Paul
[julia-users] how use find ?
I need all indexes where a[:] >5
julia> a=rand(10)*10
10-element Array{Float64,1}:
4.84005
8.29994
8.8531
3.42319
2.60318
7.25313
0.816263
4.44463
6.71836
4.65337
julia> a.>5
10-element BitArray{1}:
false
true
true
false
false
true
false
false
true
false
julia> find(a.>5,a)
ERROR: no method find(BitArray{1}, Array{Float64,1})
julia> find([a.>5],a)
ERROR: no method find(BitArray{1}, Array{Float64,1})
julia>
Re: [julia-users] Sort error, How to find reserved word in big text ?
What about "space" ?
the data:
a,a,conj+interj+prep:nom+qub
aa,aa,interj
AA,AA,subst:pl:acc:m3+subst:pl:acc:n2+subst:pl:acc:p1+subst:pl:dat:m3+subst:pl:dat:n2+subst:pl:dat:p1+subst:pl:gen:m3+subst:pl:gen:n2+subst:pl:gen:p1+subst:pl:inst:m3+subst:pl:inst:n2+subst:pl:inst:p1+subst:pl:loc:m3+subst:pl:loc:n2+subst:pl:loc:p1+subst:pl:nom:m3+subst:pl:nom:n2+subst:pl:nom:p1+subst:pl:voc:m3+subst:pl:voc:n2+subst:pl:voc:p1+subst:sg:acc:m3+subst:sg:acc:n2+subst:sg:dat:m3+subst:sg:dat:n2+subst:sg:gen:m3+subst:sg:gen:n2+subst:sg:inst:m3+subst:sg:inst:n2+subst:sg:loc:m3+subst:sg:loc:n2+subst:sg:nom:m3+subst:sg:nom:n2+subst:sg:voc:m3+subst:sg:voc:n2
aa,*ad acta*,brev:npun
Aachen,Aachen,subst:pl:acc:m3+subst:pl:acc:n2+subst:pl:dat:m3+subst:pl:dat:n2+subst:pl:gen:m3+subst:pl:gen:n2+subst:pl:inst:m3+subst:pl:inst:n2+subst:pl:loc:m3+subst:pl:loc:n2+su
in line 5 Error
julia> for i=1:k, j=1:l
yp[i,j]=parse(y[i,j]; raise=true)
println(i)
end
1
1
2
2
3
3
4
ERROR: ParseError("extra token \"acta\" after end of expression")
in parse at string.jl:1221
in parse at string.jl:1234
Paul
W dniu 2014-07-12 21:08, Stefan Karpinski pisze:
Yes, parse(str; raise=true) is the kind of thing I mean. How does Inf
get turned into a floating-point value if you're not doing any
parsing? If you just read the input as strings using readlines then
Inf will just be a string like all the other data.
On Sat, Jul 12, 2014 at 11:58 AM, programista wpf
mailto:programista...@gmail.com>> wrote:
no prasing,
for what is parsing ? Like : parse(str; raise=true) ?
Paul ?
W dniu 2014-07-12 19:59, Stefan Karpinski pisze:
You probably shouldn't be parsing these the way you're parsing
them. Are you using parse?
On Sat, Jul 12, 2014 at 9:56 AM, mailto:programista...@gmail.com>> wrote:
Not,
i found this:
it was row with "inf"
inerwacjom
*Inf*
infam
infama
how to defend against such cases? I have a dynamic
dictionaries from the network.
Paul
W dniu sobota, 12 lipca 2014 18:14:39 UTC+2 użytkownik Stefan
Karpinski napisał:
The problem here seems to be that you're comparing types
of values that are incomparable like a float and a string.
On Sat, Jul 12, 2014 at 7:17 AM, paul analyst
wrote:
I have a very long vector (5*10^6 ) with the words in
a foreign language. I can not sort
julia> sort (y1u)
ERROR: no method isless (Float64, substring
{UTF8String})
in the sort! at sort.jl: 233
in the sort! at sort.jl: 277
in next at string.jl: 630
Probably there is a word reserved for Julia. How to
find them? Where is the list of such words?
Paul
Re: [julia-users] Sort error, How to find reserved word in big text ?
At first I did and it was a problem with the "Inf". I realized that
parse a cure for "Inf" and the like.
Paul
W dniu 2014-07-13 08:57, Stefan Karpinski pisze:
You should NOT use parse to parse your data. Is that how you're doing it?
On Sat, Jul 12, 2014 at 11:54 PM, Paul Analyst <mailto:paul.anal...@mail.com>> wrote:
What about "space" ?
the data:
a,a,conj+interj+prep:nom+qub
aa,aa,interj
AA,AA,subst:pl:acc:m3+subst:pl:acc:n2+subst:pl:acc:p1+subst:pl:dat:m3+subst:pl:dat:n2+subst:pl:dat:p1+subst:pl:gen:m3+subst:pl:gen:n2+subst:pl:gen:p1+subst:pl:inst:m3+subst:pl:inst:n2+subst:pl:inst:p1+subst:pl:loc:m3+subst:pl:loc:n2+subst:pl:loc:p1+subst:pl:nom:m3+subst:pl:nom:n2+subst:pl:nom:p1+subst:pl:voc:m3+subst:pl:voc:n2+subst:pl:voc:p1+subst:sg:acc:m3+subst:sg:acc:n2+subst:sg:dat:m3+subst:sg:dat:n2+subst:sg:gen:m3+subst:sg:gen:n2+subst:sg:inst:m3+subst:sg:inst:n2+subst:sg:loc:m3+subst:sg:loc:n2+subst:sg:nom:m3+subst:sg:nom:n2+subst:sg:voc:m3+subst:sg:voc:n2
aa,*ad acta*,brev:npun
Aachen,Aachen,subst:pl:acc:m3+subst:pl:acc:n2+subst:pl:dat:m3+subst:pl:dat:n2+subst:pl:gen:m3+subst:pl:gen:n2+subst:pl:inst:m3+subst:pl:inst:n2+subst:pl:loc:m3+subst:pl:loc:n2+su
in line 5 Error
julia> for i=1:k, j=1:l
yp[i,j]=parse(y[i,j]; raise=true)
println(i)
end
1
1
2
2
3
3
4
ERROR: ParseError("extra token \"acta\" after end of expression")
in parse at string.jl:1221
in parse at string.jl:1234
Paul
W dniu 2014-07-12 21:08, Stefan Karpinski pisze:
Yes, parse(str; raise=true) is the kind of thing I mean. How does
Inf get turned into a floating-point value if you're not doing
any parsing? If you just read the input as strings using
readlines then Inf will just be a string like all the other data.
On Sat, Jul 12, 2014 at 11:58 AM, programista wpf
mailto:programista...@gmail.com>> wrote:
no prasing,
for what is parsing ? Like : parse(str; raise=true) ?
Paul ?
W dniu 2014-07-12 19:59, Stefan Karpinski pisze:
You probably shouldn't be parsing these the way you're
parsing them. Are you using parse?
On Sat, Jul 12, 2014 at 9:56 AM, mailto:programista...@gmail.com>> wrote:
Not,
i found this:
it was row with "inf"
inerwacjom
*Inf*
infam
infama
how to defend against such cases? I have a dynamic
dictionaries from the network.
Paul
W dniu sobota, 12 lipca 2014 18:14:39 UTC+2 użytkownik
Stefan Karpinski napisał:
The problem here seems to be that you're comparing
types of values that are incomparable like a float
and a string.
On Sat, Jul 12, 2014 at 7:17 AM, paul analyst
wrote:
I have a very long vector (5*10^6 ) with the
words in a foreign language. I can not sort
julia> sort (y1u)
ERROR: no method isless (Float64, substring
{UTF8String})
in the sort! at sort.jl: 233
in the sort! at sort.jl: 277
in next at string.jl: 630
Probably there is a word reserved for Julia. How
to find them? Where is the list of such words?
Paul
Re: [julia-users] Sort error, How to find reserved word in big text ?
ok,
now :
julia> data=readcsv("data.txt");
julia> du=unique(data[:,1]);
julia> dus=sort(du);
ERROR: no method isless(Float64, SubString{UTF8String})
in sort! at sort.jl:233
in sort! at sort.jl:277
in next at string.jl:630
julia>
because the data is "inf". How you defend against such situations?
Paul
W dniu 2014-07-13 09:03, John Myles White pisze:
parse isn’t a cure for anything. parse interprets inputs under the
assumption that they are valid Julia code. Your data isn’t valid Julia
code, so you should not use parse.
— John
On Jul 13, 2014, at 12:01 AM, Paul Analyst <mailto:paul.anal...@mail.com>> wrote:
At first I did and it was a problem with the "Inf". I realized that
parse a cure for "Inf" and the like.
Paul
W dniu 2014-07-13 08:57, Stefan Karpinski pisze:
You should NOT use parse to parse your data. Is that how you're
doing it?
On Sat, Jul 12, 2014 at 11:54 PM, Paul Analyst
mailto:paul.anal...@mail.com>> wrote:
What about "space" ?
the data:
a,a,conj+interj+prep:nom+qub
aa,aa,interj
AA,AA,subst:pl:acc:m3+subst:pl:acc:n2+subst:pl:acc:p1+subst:pl:dat:m3+subst:pl:dat:n2+subst:pl:dat:p1+subst:pl:gen:m3+subst:pl:gen:n2+subst:pl:gen:p1+subst:pl:inst:m3+subst:pl:inst:n2+subst:pl:inst:p1+subst:pl:loc:m3+subst:pl:loc:n2+subst:pl:loc:p1+subst:pl:nom:m3+subst:pl:nom:n2+subst:pl:nom:p1+subst:pl:voc:m3+subst:pl:voc:n2+subst:pl:voc:p1+subst:sg:acc:m3+subst:sg:acc:n2+subst:sg:dat:m3+subst:sg:dat:n2+subst:sg:gen:m3+subst:sg:gen:n2+subst:sg:inst:m3+subst:sg:inst:n2+subst:sg:loc:m3+subst:sg:loc:n2+subst:sg:nom:m3+subst:sg:nom:n2+subst:sg:voc:m3+subst:sg:voc:n2
aa,*ad acta*,brev:npun
Aachen,Aachen,subst:pl:acc:m3+subst:pl:acc:n2+subst:pl:dat:m3+subst:pl:dat:n2+subst:pl:gen:m3+subst:pl:gen:n2+subst:pl:inst:m3+subst:pl:inst:n2+subst:pl:loc:m3+subst:pl:loc:n2+su
in line 5 Error
julia> for i=1:k, j=1:l
yp[i,j]=parse(y[i,j]; raise=true)
println(i)
end
1
1
2
2
3
3
4
ERROR: ParseError("extra token \"acta\" after end of expression")
in parse at string.jl:1221
in parse at string.jl:1234
Paul
W dniu 2014-07-12 21:08, Stefan Karpinski pisze:
Yes, parse(str; raise=true) is the kind of thing I mean. How
does Inf get turned into a floating-point value if you're not
doing any parsing? If you just read the input as strings using
readlines then Inf will just be a string like all the other data.
On Sat, Jul 12, 2014 at 11:58 AM, programista wpf
mailto:programista...@gmail.com>> wrote:
no prasing,
for what is parsing ? Like : parse(str; raise=true) ?
Paul ?
W dniu 2014-07-12 19:59, Stefan Karpinski pisze:
You probably shouldn't be parsing these the way you're
parsing them. Are you using parse?
On Sat, Jul 12, 2014 at 9:56 AM, mailto:programista...@gmail.com>> wrote:
Not,
i found this:
it was row with "inf"
inerwacjom
*Inf*
infam
infama
how to defend against such cases? I have a dynamic
dictionaries from the network.
Paul
W dniu sobota, 12 lipca 2014 18:14:39 UTC+2 użytkownik
Stefan Karpinski napisał:
The problem here seems to be that you're comparing
types of values that are incomparable like a float
and a string.
On Sat, Jul 12, 2014 at 7:17 AM, paul analyst
wrote:
I have a very long vector (5*10^6 ) with the
words in a foreign language. I can not sort
julia> sort (y1u)
ERROR: no method isless (Float64, substring
{UTF8String})
in the sort! at sort.jl: 233
in the sort! at sort.jl: 277
in next at string.jl: 630
Probably there is a word reserved for Julia.
How to find them? Where is the list of such words?
Paul
Re: [julia-users] Sort error, How to find reserved word in big text ?
THX, it work!
Paul
W dniu 2014-07-13 09:31, Stefan Karpinski pisze:
readcsv("data.txt", UTF8String) should help.
On Sun, Jul 13, 2014 at 12:15 AM, Paul Analyst <mailto:paul.anal...@mail.com>> wrote:
ok,
now :
julia> data=readcsv("data.txt");
julia> du=unique(data[:,1]);
julia> dus=sort(du);
ERROR: no method isless(Float64, SubString{UTF8String})
in sort! at sort.jl:233
in sort! at sort.jl:277
in next at string.jl:630
julia>
because the data is "inf". How you defend against such situations?
Paul
W dniu 2014-07-13 09:03, John Myles White pisze:
parse isn’t a cure for anything. parse interprets inputs under
the assumption that they are valid Julia code. Your data isn’t
valid Julia code, so you should not use parse.
— John
On Jul 13, 2014, at 12:01 AM, Paul Analyst mailto:paul.anal...@mail.com>> wrote:
At first I did and it was a problem with the "Inf". I realized
that parse a cure for "Inf" and the like.
Paul
W dniu 2014-07-13 08:57, Stefan Karpinski pisze:
You should NOT use parse to parse your data. Is that how you're
doing it?
On Sat, Jul 12, 2014 at 11:54 PM, Paul Analyst
mailto:paul.anal...@mail.com>> wrote:
What about "space" ?
the data:
a,a,conj+interj+prep:nom+qub
aa,aa,interj
AA,AA,subst:pl:acc:m3+subst:pl:acc:n2+subst:pl:acc:p1+subst:pl:dat:m3+subst:pl:dat:n2+subst:pl:dat:p1+subst:pl:gen:m3+subst:pl:gen:n2+subst:pl:gen:p1+subst:pl:inst:m3+subst:pl:inst:n2+subst:pl:inst:p1+subst:pl:loc:m3+subst:pl:loc:n2+subst:pl:loc:p1+subst:pl:nom:m3+subst:pl:nom:n2+subst:pl:nom:p1+subst:pl:voc:m3+subst:pl:voc:n2+subst:pl:voc:p1+subst:sg:acc:m3+subst:sg:acc:n2+subst:sg:dat:m3+subst:sg:dat:n2+subst:sg:gen:m3+subst:sg:gen:n2+subst:sg:inst:m3+subst:sg:inst:n2+subst:sg:loc:m3+subst:sg:loc:n2+subst:sg:nom:m3+subst:sg:nom:n2+subst:sg:voc:m3+subst:sg:voc:n2
aa,*ad acta*,brev:npun
Aachen,Aachen,subst:pl:acc:m3+subst:pl:acc:n2+subst:pl:dat:m3+subst:pl:dat:n2+subst:pl:gen:m3+subst:pl:gen:n2+subst:pl:inst:m3+subst:pl:inst:n2+subst:pl:loc:m3+subst:pl:loc:n2+su
in line 5 Error
julia> for i=1:k, j=1:l
yp[i,j]=parse(y[i,j]; raise=true)
println(i)
end
1
1
2
2
3
3
4
ERROR: ParseError("extra token \"acta\" after end of
expression")
in parse at string.jl:1221
in parse at string.jl:1234
Paul
W dniu 2014-07-12 21:08, Stefan Karpinski pisze:
Yes, parse(str; raise=true) is the kind of thing I mean.
How does Inf get turned into a floating-point value if
you're not doing any parsing? If you just read the input
as strings using readlines then Inf will just be a string
like all the other data.
On Sat, Jul 12, 2014 at 11:58 AM, programista wpf
mailto:programista...@gmail.com>> wrote:
no prasing,
for what is parsing ? Like : parse(str; raise=true) ?
Paul ?
W dniu 2014-07-12 19:59, Stefan Karpinski pisze:
You probably shouldn't be parsing these the way
you're parsing them. Are you using parse?
On Sat, Jul 12, 2014 at 9:56 AM,
mailto:programista...@gmail.com>> wrote:
Not,
i found this:
it was row with "inf"
inerwacjom
*Inf*
infam
infama
how to defend against such cases? I have a
dynamic dictionaries from the network.
Paul
W dniu sobota, 12 lipca 2014 18:14:39 UTC+2
użytkownik Stefan Karpinski napisał:
The problem here seems to be that you're
comparing types of values that are
incomparable like a float and a string.
On Sat, Jul 12, 2014 at 7:17 AM, paul analyst
wrote:
I have a very long vector (5*10^6 ) with
the words in a foreign language. I can
not sort
julia> sort (y1u)
ERROR: no method isless (Float64,
substring {UTF8String})
in the sort! at sort.jl: 233
in the sort! at sort.jl: 277
in next at string.jl: 630
Probably there is a word reserved for
Julia. How to find them? Where is the
list of such words?
Paul
[julia-users] How cartesianmap take into variable ?
Julia Documentation: cartesianmap(f, dims) Given a dims tuple of integers (m, n, ...), call f on all combinations of integers in the ranges 1:m, 1:n, etc. Example: julia> cartesianmap(println, (2,2)) 11 21 12 22 julia>x= cartesianmap(2,2) ERROR: no method cartesianmap(Int64, Int64) How to take variable (array) x= 11 21 12 22 ? Paul
