[julia-users] Re: Graph package
Thanks On Thursday, April 2, 2015 at 10:48:53 AM UTC+1, pip7...@gmail.com wrote: > > Hi > How can I save the following example plot(g) to .gif / .png or .jpg file > > julia> using Graphs > > julia> g = simple_graph(3) > Directed Graph (3 vertices, 0 edges) > > julia> add_edge!(g, 1, 2) > edge [1]: 1 -- 2 > > julia> add_edge!(g, 3, 2) > edge [2]: 3 -- 2 > > julia> add_edge!(g, 3, 1) > edge [3]: 3 -- 1 > > julia> plot(g) > > > Regards > > >
[julia-users] Re: fill array
Hi
I guess what I'm trying to say is that if array "a" started life as
[11,12,13,14] - then if we use "filter(x->x<3, z)" which returns 1,2 - I
would like 1,2 added to array a resulting in "a array" being .
[11,12,13,14,1,2] or [1,2,11,12,13,14]
Regards
On Wednesday, March 18, 2015 at 3:05:54 PM UTC, René Donner wrote:
> I am not sure what you mean - are you expecting a different behavior than
> this? Both z and a are containing what they should.
>
> julia> z = [1,2,3,4]
> 4-element Array{Int64,1}:
> 1
> 2
> 3
> 4
>
> julia> a = filter(x->x<3, z)
> 2-element Array{Int64,1}:
> 1
> 2
>
> julia> z
> 4-element Array{Int64,1}:
> 1
> 2
> 3
> 4
>
> julia> a
> 2-element Array{Int64,1}:
> 1
> 2
>
>
> Am Mittwoch, 18. März 2015 16:01:11 UTC+1 schrieb pip7...@gmail.com:
>>
>> One thing I forgot to ask is what if I wan to keep the array as it
>> is and then add to it ...if I run a = filter(x->x<3, z) ... it overwrites
>> the array.
>> Regards
>>
>> On Wednesday, 18 March 2015 14:04:45 UTC, pip7...@gmail.com wrote:
>>>
>>> Thanks everybody - got it!
>>> Regards
>>>
>>> On Wednesday, 18 March 2015 12:04:48 UTC, René Donner wrote:
or simply
a = filter(x->x<3, z)
Am Mittwoch, 18. März 2015 12:46:52 UTC+1 schrieb Konstantin Markov:
>
> julia> a = [i for i=filter(x->x<3,z)]
> 2-element Array{Any,1}:
> 1
> 2
>
>
> On Wednesday, March 18, 2015 at 8:31:57 PM UTC+9, pip7...@gmail.com
> wrote:
>>
>> Hi
>> I want to fill an array based on a condition - eg
>>
>> a = []
>> z = [1,2,3,4]
>>
>> for i = 1:length(z)
>> if i > 2
>> continue
>> end
>> end
>>
>> so, I would now like to see the values 1 & 2 in my array "a"
>> Regards
>>
>>
>>
>>
>>
[julia-users] Re: join dataframe columns
Johan Thanks for this. I also found that I could use .* to join two columns in a DataFrame. Using a dot star to join! - I found surprising - but it worked. Regards On Sunday, March 1, 2015 at 2:50:42 PM UTC, Johan Sigfrids wrote: > > With a DataFrame like: > > df = DataFrame(Name = ["Test", "Test2"], Name2 = ["A", "B"], Amt=[123,456]) > > you could do something like this: > > df[:Name] = map((x,y) -> string(x, -, y), df[:Name], df[:Name2]) > > Note that you will still have the Name2 column. > > On Sunday, March 1, 2015 at 12:35:01 AM UTC+2, pip7...@gmail.com wrote: >> >> Hi >> How can I join 2 columns in a dataframe. >> >> e.g. >> Dataframe 1 >> >> RowName Name2 Amt >> 1 TestA 123 >> 2 Test2 B456 >> etc >> >> I want to be able to join Name and Name2 and use a separator like - >> eg >> RowName Amt >> 1 Test-A 123 >> 2 Test2-B456 >> >> Regards >> >
[julia-users] Re: Using a function on a group of data
Hi Thanks for the links. Regards On Tuesday, February 24, 2015 at 11:47:34 AM UTC, pgs wrote: > > Hi > I have a txt file which I'm trying to perform a compuation(FUNCTION) on > groups of data - the Grouping being Col1 then Col2. > eg > > Say my txt file has the following > > Col1,Col2,Col3 Col4 > A 15:00 4 8 > A 15:00 6 5 > A 15:30 2 4 > A 15:30 8 7 > B 12:00 5 2 > B 12:00 4 1 > B 18:00 2 6 > B 18:00 1 7 > B 18:00 4 0.5 etc etc > > myfunction = map((x,y) -> x / y * 2, Col3,Col4) > I then want to sum the results of my computation using the function e g > > So, when applying "myfunction"? - the result set is... > A 15:00 1 > A 15:00 2.4 > sum 3.4 > A 15:30 1 > A 15:30 2.28 > sum 3.28 > So, the end game for me is just to see the final "sum" as an output - eg > A 15:00 3.4 > A 15:30 3.28 > etc > is this possible? > > Regards > >
[julia-users] Using a function on a group of data
Hi I have a txt file which I'm trying to perform a compuation(FUNCTION) on groups of data - the Grouping being Col1 then Col2. eg Say my txt file has the following Col1,Col2,Col3 Col4 A 15:00 4 8 A 15:00 6 5 A 15:30 2 4 A 15:30 8 7 B 12:00 5 2 B 12:00 4 1 B 18:00 2 6 B 18:00 1 7 B 18:00 4 0.5 etc etc myfunction = map((x,y) -> x / y * 2, Col3,Col4) I then want to sum the results of my computation using the function e g So, when applying "myfunction"? - the result set is... A 15:00 1 A 15:00 2.4 sum 3.4 A 15:30 1 A 15:30 2.28 sum 3.28 So, the end game for me is just to see the final "sum" as an output - eg A 15:00 3.4 A 15:30 3.28 etc is this possible? Regards
[julia-users] Re: Grouping - Dataframes
Hi This now works - by *(df,:Col1,x->sum(x[:Col2])) - it was my fault as I left out a " in one of the headers in my txt file.* *Thanks* On Sunday, February 22, 2015 at 8:06:59 PM UTC, pgs wrote: > Hi > Is it possible to summarize data in a data frame eg > > Col1 Col2 > A 2 > A 2.5 > B 7 > B 2 > > I would like sum Col2 grouping by Col1 - output would be > A , 4.5 > B,9 > > > Regards > > >
[julia-users] Re: Grouping - Dataframes
Added the by and now getting ... 'by' has no method matching by(::Array(Any,2), ::Symbol, ::Function in include at boot.jl:245 On Sunday, February 22, 2015 at 8:06:59 PM UTC, Philip Sivyer wrote: > Hi > Is it possible to summarize data in a data frame eg > > Col1 Col2 > A 2 > A 2.5 > B 7 > B 2 > > I would like sum Col2 grouping by Col1 - output would be > A , 4.5 > B,9 > > > Regards > > >
