Re: [julia-users] How come (x, y) isn't legal syntax?
I would add that ()(1,2) works; I'm imagining that it changes the context and forces the parser to use the one legal interpretation.
Re: [julia-users] How come (x, y) isn't legal syntax?
Not true, is an undocumented singular case (regrettably). - is a unary operator, too, but nonetheless, -(1,5) gives -4, as it well should. Am Dienstag, 9. September 2014 00:41:01 UTC+2 schrieb Jake Bolewski: Anyt unary operator defined as a `syntatic_unary_operator` https://github.com/jakebolewski/JuliaParser.jl/blob/master/src/lexer.jl#L103 is special cased by the parser and works similarly. On Monday, September 8, 2014 4:31:48 PM UTC-4, Stefan Karpinski wrote: I believe it is because of the use of in ccall as a pseudo-operator to pass the address of a scalar. Jeff will have to confirm or deny this though. On Mon, Sep 8, 2014 at 10:25 PM, Dan Luu dan...@gmail.com wrote: julia 1 | 2 3 julia 1 2 0 julia 1 + 2 3 julia 1 $ 2 3 julia |(1, 2) 3 julia (1, 2) ERROR: unsupported or misplaced expression julia +(1, 2) 3 julia $(1, 2) ERROR: unsupported or misplaced expression $ Is used in some way julia that makes (1, 2) potentially ambiguous? Apologies if this is in the archives; I couldn't figure how to effectively search for '' or 'and'. Dan
Re: [julia-users] How come (x, y) isn't legal syntax?
On Tuesday, September 9, 2014 2:02:03 AM UTC-5, gentlebeldin wrote: Not true, is an undocumented singular case (regrettably). - is a unary operator, too, but nonetheless, -(1,5) gives -4, as it well should. Did you look at the link Jake posted? The `-` operator is not in the class `syntactic_unary_operator`, but listed in `unary_ops`, which by implication doesn't have the special handling: https://github.com/jakebolewski/JuliaParser.jl/blob/aa466d7a84dee73db9cec66dbe631c1e534ebcc0/src/lexer.jl#L89 The problem is that ``, `$`, and `::` are not just operators, but syntax (for instance, `` in `ccall()`, and `$` in expression interpolation), so they require special parser handling, and this can conflict with the normal rules for parsing unary operators.
[julia-users] How come (x, y) isn't legal syntax?
julia 1 | 2 3 julia 1 2 0 julia 1 + 2 3 julia 1 $ 2 3 julia |(1, 2) 3 julia (1, 2) ERROR: unsupported or misplaced expression julia +(1, 2) 3 julia $(1, 2) ERROR: unsupported or misplaced expression $ Is used in some way julia that makes (1, 2) potentially ambiguous? Apologies if this is in the archives; I couldn't figure how to effectively search for '' or 'and'. Dan
Re: [julia-users] How come (x, y) isn't legal syntax?
I believe it is because of the use of in ccall as a pseudo-operator to pass the address of a scalar. Jeff will have to confirm or deny this though. On Mon, Sep 8, 2014 at 10:25 PM, Dan Luu dan...@gmail.com wrote: julia 1 | 2 3 julia 1 2 0 julia 1 + 2 3 julia 1 $ 2 3 julia |(1, 2) 3 julia (1, 2) ERROR: unsupported or misplaced expression julia +(1, 2) 3 julia $(1, 2) ERROR: unsupported or misplaced expression $ Is used in some way julia that makes (1, 2) potentially ambiguous? Apologies if this is in the archives; I couldn't figure how to effectively search for '' or 'and'. Dan
Re: [julia-users] How come (x, y) isn't legal syntax?
Anyt unary operator defined as a `syntatic_unary_operator` https://github.com/jakebolewski/JuliaParser.jl/blob/master/src/lexer.jl#L103 is special cased by the parser and works similarly. On Monday, September 8, 2014 4:31:48 PM UTC-4, Stefan Karpinski wrote: I believe it is because of the use of in ccall as a pseudo-operator to pass the address of a scalar. Jeff will have to confirm or deny this though. On Mon, Sep 8, 2014 at 10:25 PM, Dan Luu dan...@gmail.com javascript: wrote: julia 1 | 2 3 julia 1 2 0 julia 1 + 2 3 julia 1 $ 2 3 julia |(1, 2) 3 julia (1, 2) ERROR: unsupported or misplaced expression julia +(1, 2) 3 julia $(1, 2) ERROR: unsupported or misplaced expression $ Is used in some way julia that makes (1, 2) potentially ambiguous? Apologies if this is in the archives; I couldn't figure how to effectively search for '' or 'and'. Dan
