The reason is and | operators are bitwise in Julia, and have a higher
precedence than == and !=.
julia 1 == 1 3 == 3
false
julia 1 == 1 3 == 3
true
julia (1 == 1) (3 == 3)
true
julia 1 3
1
There are a few issues on this, combining the scalar bitwise and
array-elementwise meanings into the same and | operators is not ideal and
can lead to confusion here. When in doubt use extra parentheses around
conditionals, and use or || for scalar comparisons.
On Tuesday, July 28, 2015 at 10:17:26 PM UTC-7, meib...@163.com wrote:
#R code
f=c(0.5,0.5)
n.al - length(f)
P.1 - P.2 - array(0,dim=rep(n.al,4))
for(a2 in 1:n.al) for(a1 in 1:n.al)
for(a3 in 1:n.al) for(a4 in 1:n.al)
{
if (a1==a3 a2==a4)
{
P.2[a1,a2,a3,a4] - f[a1]*f[a2]
P.1[a1,a2,a3,a4] - f[a1]*f[a2]*(f[a1]+f[a2])/2
}
if (a1==a3 a2!=a4)
{
P.1[a1,a2,a3,a4] - f[a1]*f[a2]*f[a4]/2
}
if (a1!=a3 a2==a4)
{
P.1[a1,a2,a3,a4] - f[a1]*f[a3]*f[a2]/2
}
}
#julia code
f=Array(Float64,1,2)
f[:,:]=0.5
p1=Array(Float64,nal,nal,nal,nal)
p2=Array(Float64,nal,nal,nal,nal)
p1[:,:,:,:]=0.0
p2[:,:,:,:]=0.0
for (a2 = 1:nal) for (a1 = 1:nal)
for (a3 = 1:nal) for (a4 = 1:nal)
if (a1==a3 a2==a4)
p2[a1,a2,a3,a4] = f[a1]*f[a2]
p1[a1,a2,a3,a4] = f[a1]*f[a2]*(f[a1]+f[a2])/2.0
end
if (a1==a3 a2!=a4)
p1[a1,a2,a3,a4] = f[a1]*f[a2]*f[a4]/2.0
end
if (a1!=a3 a2==a4)
p1[a1,a2,a3,a4] = f[a1]*f[a3]*f[a2]/2.0
end
end end
end end
https://lh3.googleusercontent.com/-V-fR1Z3wCS0/VbhSoLSjSjI/AAM/rNp8Wb1-wk8/s1600/Untitled.png
