Re: [julia-users] Metaprogramming and function scope

[Isaiah Norton]

`eval` operates in global scope only:
http://docs.julialang.org/en/release-0.4/manual/metaprogramming/#eval-and-effects

On Tue, Nov 24, 2015 at 1:12 PM, Pieterjan Robbe 
wrote:

> Why can't I parse a function evaluation of a function defined within the
> scope of another function?
> i.e., the following terminates with an UndefVarError: bar not defined:
>
> *function* foo()
>   *function* bar()
> x
>   end
>   *return* eval(parse("bar()"))
> end
>
> x = 7
> foo()
>
> However, I can do
>
> *function* foo()
>   *function* bar()
> x
>   end
>   *return* bar()
> end
>
> x = 7
> foo()
>
> and
>
> *function* foo()
>   *return* eval(parse("bar()"))
> end
>
> *function* bar()
>   x
> end
>
> x = 7
> foo()
>
> Many thanks!
> -Pieterjan
>

Re: [julia-users] Metaprogramming and function scope

[Pieterjan Robbe]

That makes sense :) Is there a workaround? I need to define some (global 
constant) variables, Z1, Z2, Z3 etc. (that's where the parsing comes from) by 
calling a function (bar) that does something with data defined in foo(). I'd 
like to keep this inside a single function, since it's the initialization step 
of a more complex simulation.