Re: [julia-users] Subtraction of the diagonal matrix, how sipler?
Thx, nice. Is the fast way in Julia ? Paul W dniu niedziela, 1 lutego 2015 17:18:03 UTC+1 użytkownik Andreas Noack napisał: This is cheaper: rand(4,4) - 5*I because 5I is a special type that doesn't store all elements. 2015-02-01 11:03 GMT-05:00 paul analyst paul.a...@mail.com javascript: : I have somethink like this : rand(4,4).-eye(4,4)*5 Qestion : how to simpler subtracted from the diagonal value(5) , Without multiplying matrices I have great and I have to simplify the code. Paul
Re: [julia-users] Subtraction of the diagonal matrix, how sipler?
I think so, but it neither take long time julia let A = rand(4,4); @time for i = 1:10^6;A - 5.0*eye(4);end end; elapsed time: 0.177621144 seconds (534 MB allocated, 5.71% gc time in 25 pauses with 0 full sweep) julia let A = rand(4,4); @time for i = 1:10^6;A - 5.0*I;end end; elapsed time: 0.053749097 seconds (167 MB allocated, 5.04% gc time in 8 pauses with 0 full sweep) 2015-02-01 11:49 GMT-05:00 paul analyst paul.anal...@mail.com: Thx, nice. Is the fast way in Julia ? Paul W dniu niedziela, 1 lutego 2015 17:18:03 UTC+1 użytkownik Andreas Noack napisał: This is cheaper: rand(4,4) - 5*I because 5I is a special type that doesn't store all elements. 2015-02-01 11:03 GMT-05:00 paul analyst paul.a...@mail.com: I have somethink like this : rand(4,4).-eye(4,4)*5 Qestion : how to simpler subtracted from the diagonal value(5) , Without multiplying matrices I have great and I have to simplify the code. Paul
Re: [julia-users] Subtraction of the diagonal matrix, how sipler?
This is cheaper: rand(4,4) - 5*I because 5I is a special type that doesn't store all elements. 2015-02-01 11:03 GMT-05:00 paul analyst paul.anal...@mail.com: I have somethink like this : rand(4,4).-eye(4,4)*5 Qestion : how to simpler subtracted from the diagonal value(5) , Without multiplying matrices I have great and I have to simplify the code. Paul
