Re: [LARTC] Re: Not understanding network setup!!

2006-06-04 Thread Jarek Poplawski 

Eliot, Wireless and Server Administrator, Great Lakes Internet wrote:

-Original Message-
From: Jarek Poplawski [mailto:[EMAIL PROTECTED]
Sent: Friday, June 02, 2006 9:57 AM
To: Eliot, Wireless and Server Administrator, Great Lakes Internet
Cc: lartc@mailman.ds9a.nl
Subject: Re: [LARTC] Re: Not understanding network setup!!


...


Maybe we are thinking about something else but I don't think:
If you were using a /30, then ... .5, and .9 would be the
first available addresses in their respective subnets is all
correct.


10.0.0.0/30:

10.0.0.0 - NETWORK ADDRESS
10.0.0.1 - HOST
10.0.0.2 - HOST
10.0.0.3 - BROADCAST ADDRESS

First available address is .1

10.0.0.4/30:

10.0.0.4 - NETWORK ADDRESS
10.0.0.5 - HOST
10.0.0.6 - HOST
10.0.0.7 - BROADCAST ADDRESS

First available address is .5

10.0.0.8/30:

10.0.0.8  - NETWORK ADDRESS
10.0.0.9  - HOST
10.0.0.10 - HOST
10.0.0.11 - BROADCAST ADDRESS

First available address is .9

Thus:

The .1, .5, and .9 would be the first available addresses in their
respective subnets.

Is a true statement. 


How are you interpreting this?



OH! Now I understand! I'm sorry for bothering you and many thanks 
for this clare explaining.


Jarek P.
___
LARTC mailing list
LARTC@mailman.ds9a.nl
http://mailman.ds9a.nl/cgi-bin/mailman/listinfo/lartc

[LARTC] Re: Not understanding network setup!!

2006-06-02 Thread Jarek Poplawski 

Eliot, Wireless and Server Administrator, Great Lakes Internet wrote:

-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
[EMAIL PROTECTED]
Sent: Thursday, June 01, 2006 2:58 PM
To: lartc@mailman.ds9a.nl
Subject: [LARTC] Not understanding network setup!! 


Hi to all,

...

First, 10.0.0.0/31 would be a network address. Second, a 31 bit subnet
is meaningless. It only offers two addresses, the network address at
10.0.0.0 and the broadcast address at 10.0.0.1. That leaves no available
addresses for host addresses. You probably mean /30 instead of /31. If
you were using a /30, then you would run:

ip addr add 10.0.0.1/30 dev eth1
ip addr add 10.0.0.5/30 dev eth2
ip addr add 10.0.0.9/30 dev teql0

The .1, .5, and .9 would be the first available addresses in their
respective subnets.


You probably mean /28 instead of /30:

ip addr add 10.0.0.9/28 dev teql0

Jarek P.

___
LARTC mailing list
LARTC@mailman.ds9a.nl
http://mailman.ds9a.nl/cgi-bin/mailman/listinfo/lartc