BeatStructure in 4/4 time

2012-05-21 Thread Urs Liska
I'm stuck :-(

Why doesn't this work as I expect? .

\version 2.15.36
\time 4/4
\set Timing. BeatStructure = #'(1 1 1 1)
c8 c c c c c c c

This should result in four groups of two beamed notes, isn't it?
But I always get two groups of four notes.

The same problem with 3/4, but with 5/4 I can do any combination without 
problems.

Any ideas?

Thanks
Urs
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Re: BeatStructure in 4/4 time

2012-05-21 Thread Janek Warchoł
On Mon, May 21, 2012 at 3:56 PM, Urs Liska li...@ursliska.de wrote:
 I'm stuck :-(

 Why doesn't this work as I expect? .

 \version 2.15.36
 \time 4/4
 \set Timing. BeatStructure = #'(1 1 1 1)
 c8 c c c c c c c

 you have to clear BeamExceptions if i remember correctly.

HTH,
Janek

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Re: BeatStructure in 4/4 time

2012-05-21 Thread Urs Liska
Thanks, that was it.

OK, it# in the docs, but I had to re-read it three times until I got it :-(

Best
Urs
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Janek Warchoł janek.lilyp...@gmail.com schrieb:

On Mon, May 21, 2012 at 3:56 PM, Urs Liska li...@ursliska.de wrote:
 I'm stuck :-(

 Why doesn't this work as I expect? .

 \version 2.15.36
 \time 4/4
 \set Timing. BeatStructure = #'(1 1 1 1)
 c8 c c c c c c c

you have to clear BeamExceptions if i remember correctly.

HTH,
Janek

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