Re: Hairpin.minimum-length gives wrong output
Thanks, that works brilliantly. It's a bit of a kludge, but will do for now.
I don't see why the original didn't work, and I think it's a bug, so will
report it there.
Best regards,
Peter
mailto:lilyp...@ptoye.com
www.ptoye.com
-
Wednesday, October 30, 2019, 4:06:31 PM, Phil Holmes wrote:
Try s8\sf\> s8-\hide\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
--
Phil Holmes
- Original Message -
From: Peter Toye
To: Phil Holmes; lilypond-user@gnu.org
Sent: Wednesday, October 30, 2019 3:51 PM
Subject: Re: Hairpin.minimum-length gives wrong output
Sorry, a typo. Both lines should have \! rather than \p. What I want is the
first quaver sf and the hairpin to finish before the next quaver, so that the
3rd quaver is at the same dynamic as the 2nd one.
Here's a better MWV
\version "2.19.52"
\language "english"
{
<<
\new Staff {
\time 2/4
\clef "treble"
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
}
\new Dynamics {
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2 2 2
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
\override Hairpin.minimum-length = #10
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2 2 2
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2
}
>>
}
Line 1 has the hairpin too late at both the start and endpoints. Line 2 has a
warning that the hairpin is too small. Line 3 has the end of the hairpin too
late. Line 4 is fine.
Best regards,
Peter
mailto:lilyp...@ptoye.com
www.ptoye.com
-
Wednesday, October 30, 2019, 3:24:52 PM, Phil Holmes wrote:
Not quite sure of the output you want here. Your 2 lines of your example
aren't the same since the top line has a piano dynamic on it and the lower line
doesn't. Is the first quaver supposed to have the sf immediately below it? If
so, where do you expect the p dynamic to be? If it's below the second quaver,
all lily can try to do is space the quavers to fit in the minimum length of
your hairpin, which it does.
--
Phil Holmes
- Original Message -
From: Peter Toye
To: lilypond-user@gnu.org
Sent: Wednesday, October 30, 2019 3:14 PM
Subject: Hairpin.minimum-length gives wrong output
This minimal criminal seems to give wrong output. I want to make sure that the
hairpin lasts for exactly one quaver (1/8 note). The first line gives a warning
message that the hairpin is too short. The second line adjusts the length of
the hairpin but it's now too long.
To try it out you may need to modify the number of notes depending on the paper
size.
\version "2.19.52"
\language "english"
{
<<
\new Staff {
\time 2/4
\clef "treble"
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
}
\new Dynamics {
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
\override Hairpin.minimum-length = #5
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2
}
>>
}
Regards,
Peter
mailto:lilyp...@ptoye.com
www.ptoye.com
Re: Hairpin.minimum-length gives wrong output
ptoye wrote
> What I want is the first quaver sf and the hairpin to finish before the
> next quaver, so that the 3rd quaver is at the same dynamic as the 2nd
> one.
>
> Here's a better MWV
>
> \version "2.19.52"
> \language "english"
> {
> <<
> \new Staff {
> \time 2/4
> \clef "treble"
> c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
> c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
> c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
> c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
> }
> \new Dynamics {
> s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2 2 2
> s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
> \override Hairpin.minimum-length = #10
> s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2 2 2
> s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2
> }
> >>
> }
>
> Line 1 has the hairpin too late at both the start and endpoints. Line 2
> has a warning that the hairpin is too small. Line 3 has the end of the
> hairpin too late. Line 4 is fine.
Hi Peter,
I'm having a hard time to shorten your mail to the part I want to reply.
I'd recommend to use plain text.
Right now I use the nabble-interface, because I failed to do it otherwise.
That's unneeded tedious.
Anyway, single Hairpins (not surrounded by other dynamic signs) should start
at the left of the starting note and end at the right of the target note. If
dynamic signs are present they are centered below their notes and the
Hairpin is printed in between.
For subsequent Hairpins, end/new-start are printed a little left and right
from the corresponding notehead-center.
This is the typesetting rule as far as I can tell.
See LilyPond doing it:
\paper { ragged-right = ##f }
{ b4\> b\! }
{ b4\> b\> b\! }
Thus I think you're wrong saying
"Line 3 has the end of the hairpin too late."
And even your initial quoted statement is not at the lines of usual
typesetting rules.
The Hairpin _is_positioned correctly, although admittedly it looks terrible.
But this is due to the uneven spacing, not a wrong Hairpin.
Here: "Line 1 has the hairpin too late at both the start and endpoints" I'm
not sure what you want instead for the Hairpin-start, wherelse than after
the sforzato should it start?
The endpoint is correct either (see above).
Alas, this line looks terrible as well.
By all means, the Hairpin is too short.
Similiar for line 2 of your example.
So, all these three examples look weird because the Hairpin is not long
enough.
This may be a weakness of LilyPond: A spanner doesn't push it's bounds,
unless forced. P.e. with setting minimum-length to a higher value. This is
not done automagically.
Thus line 4 looks best: The Hairpin is lengthened and positioned between the
two dynamic signs, each centerd below their notes. Although the uneven
spacing is still ugly.
So if you really want the Hairpin to end before the target note, you have to
ensure/set two things
(1) Help LilyPond, make the Hairpin long enough, i.e. set minimum-length to
a suitable value.
(2) For further tweaking use shortern-pair
\paper { ragged-right = ##t }
{
\override Hairpin.shorten-pair = #'(0 . 1.5)
\override Hairpin.minimum-length = #10
b4\> b\!
}
Cheers,
Harm
--
Sent from: http://lilypond.1069038.n5.nabble.com/User-f3.html
Re: Hairpin.minimum-length gives wrong output
Re: Hairpin.minimum-length gives wrong output
Try s8\sf\> s8-\hide\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
--
Phil Holmes
- Original Message -
From: Peter Toye
To: Phil Holmes ; lilypond-user@gnu.org
Sent: Wednesday, October 30, 2019 3:51 PM
Subject: Re: Hairpin.minimum-length gives wrong output
Sorry, a typo. Both lines should have \! rather than \p. What I want is the
first quaver sf and the hairpin to finish before the next quaver, so that the
3rd quaver is at the same dynamic as the 2nd one.
Here's a better MWV
\version "2.19.52"
\language "english"
{
<<
\new Staff {
\time 2/4
\clef "treble"
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
}
\new Dynamics {
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2 2 2
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
\override Hairpin.minimum-length = #10
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2 2 2
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2
}
>>
}
Line 1 has the hairpin too late at both the start and endpoints. Line 2 has a
warning that the hairpin is too small. Line 3 has the end of the hairpin too
late. Line 4 is fine.
Best regards,
Peter
mailto:lilyp...@ptoye.com
www.ptoye.com
-
Wednesday, October 30, 2019, 3:24:52 PM, Phil Holmes wrote:
Not quite sure of the output you want here. Your 2 lines of your example
aren't the same since the top line has a piano dynamic on it and the lower line
doesn't. Is the first quaver supposed to have the sf immediately below it? If
so, where do you expect the p dynamic to be? If it's below the second quaver,
all lily can try to do is space the quavers to fit in the minimum length of
your hairpin, which it does.
--
Phil Holmes
- Original Message -
From: Peter Toye
To: lilypond-user@gnu.org
Sent: Wednesday, October 30, 2019 3:14 PM
Subject: Hairpin.minimum-length gives wrong output
This minimal criminal seems to give wrong output. I want to make sure that
the hairpin lasts for exactly one quaver (1/8 note). The first line gives a
warning message that the hairpin is too short. The second line adjusts the
length of the hairpin but it's now too long.
To try it out you may need to modify the number of notes depending on the
paper size.
\version "2.19.52"
\language "english"
{
<<
\new Staff {
\time 2/4
\clef "treble"
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
}
\new Dynamics {
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
\override Hairpin.minimum-length = #5
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2
}
>>
}
Regards,
Peter
mailto:lilyp...@ptoye.com
www.ptoye.com
Re: Hairpin.minimum-length gives wrong output
Sorry, a typo. Both lines should have \! rather than \p. What I want is the
first quaver sf and the hairpin to finish before the next quaver, so that the
3rd quaver is at the same dynamic as the 2nd one.
Here's a better MWV
\version "2.19.52"
\language "english"
{
<<
\new Staff {
\time 2/4
\clef "treble"
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
}
\new Dynamics {
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2 2 2
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
\override Hairpin.minimum-length = #10
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2 2 2
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2
}
>>
}
Line 1 has the hairpin too late at both the start and endpoints. Line 2 has a
warning that the hairpin is too small. Line 3 has the end of the hairpin too
late. Line 4 is fine.
Best regards,
Peter
mailto:lilyp...@ptoye.com
www.ptoye.com
-
Wednesday, October 30, 2019, 3:24:52 PM, Phil Holmes wrote:
Not quite sure of the output you want here. Your 2 lines of your example
aren't the same since the top line has a piano dynamic on it and the lower line
doesn't. Is the first quaver supposed to have the sf immediately below it? If
so, where do you expect the p dynamic to be? If it's below the second quaver,
all lily can try to do is space the quavers to fit in the minimum length of
your hairpin, which it does.
--
Phil Holmes
- Original Message -
From: Peter Toye
To: lilypond-user@gnu.org
Sent: Wednesday, October 30, 2019 3:14 PM
Subject: Hairpin.minimum-length gives wrong output
This minimal criminal seems to give wrong output. I want to make sure that the
hairpin lasts for exactly one quaver (1/8 note). The first line gives a warning
message that the hairpin is too short. The second line adjusts the length of
the hairpin but it's now too long.
To try it out you may need to modify the number of notes depending on the paper
size.
\version "2.19.52"
\language "english"
{
<<
\new Staff {
\time 2/4
\clef "treble"
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
}
\new Dynamics {
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
\override Hairpin.minimum-length = #5
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2
}
>>
}
Regards,
Peter
mailto:lilyp...@ptoye.com
www.ptoye.com
Re: Hairpin.minimum-length gives wrong output
Hairpin.minimum-length gives wrong output
Not quite sure of the output you want here. Your 2 lines of your example
aren't the same since the top line has a piano dynamic on it and the lower line
doesn't. Is the first quaver supposed to have the sf immediately below it? If
so, where do you expect the p dynamic to be? If it's below the second quaver,
all lily can try to do is space the quavers to fit in the minimum length of
your hairpin, which it does.
--
Phil Holmes
- Original Message -
From: Peter Toye
To: lilypond-user@gnu.org
Sent: Wednesday, October 30, 2019 3:14 PM
Subject: Hairpin.minimum-length gives wrong output
This minimal criminal seems to give wrong output. I want to make sure that the
hairpin lasts for exactly one quaver (1/8 note). The first line gives a warning
message that the hairpin is too short. The second line adjusts the length of
the hairpin but it's now too long.
To try it out you may need to modify the number of notes depending on the paper
size.
\version "2.19.52"
\language "english"
{
<<
\new Staff {
\time 2/4
\clef "treble"
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
}
\new Dynamics {
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
\override Hairpin.minimum-length = #5
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2
}
>>
}
Regards,
Peter
mailto:lilyp...@ptoye.com
www.ptoye.com
Hairpin.minimum-length gives wrong output
This minimal criminal seems to give wrong output. I want to make sure that the
hairpin lasts for exactly one quaver (1/8 note). The first line gives a warning
message that the hairpin is too short. The second line adjusts the length of
the hairpin but it's now too long.
To try it out you may need to modify the number of notes depending on the paper
size.
\version "2.19.52"
\language "english"
{
<<
\new Staff {
\time 2/4
\clef "treble"
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4\break
c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
}
\new Dynamics {
s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2 2 2
\override Hairpin.minimum-length = #5
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2
}
>>
}
Regards,
Peter
mailto:lilyp...@ptoye.com
www.ptoye.com
