Re: problem with substitution
Dear Carl,
thanks for Your explanation!
Now I understand it!
2008/12/22 Carl D. Sorensen c_soren...@byu.edu:
On 12/22/08 2:30 AM, Stefan Thomas kontrapunktste...@googlemail.com
wrote:
Dear Lilypond-users,
I trie to substitute the variable zackigschnell' with APZ', but
without sucess.
What is wrong with the following snippet?
\version 2.11.60
\include rhythmustest.ly
\new Staff { \APZ { c' d' e' f' } }
There's nothing wrong with the snippet.
The problem occurred in rhythmustest.ly.
You had the following:
zackigschnell = #(define-music-function (parser location music) (ly:music?)
#{ \makeRhythm $music 16. 32 #})
APZ = { \zackigschnell }
The way LilyPond substitution works, \zackigschnell needs to be followed by
a music expression. And in your definition of APZ, there is no music
expression following \zackigschnell. If you literally do the substitution,
you'll get
\new Staff { { \zackigschnell } {c' d' e' f' } }
and you can see that there is no music expression for \zackigschnell to
operator on.
If you literally want to just add a new name for a function, the way to do
it is with a scheme trick.
Simply add
#(define APZ zackigschnell)
and now APZ and zackigschnell are the same thing with two different names.
I've tried it on your code, and this works.
Good luck,
Carl
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problem with substitution
Dear Lilypond-users,
I trie to substitute the variable zackigschnell' with APZ', but
without sucess.
What is wrong with the following snippet?
\version 2.11.60
\include rhythmustest.ly
\new Staff { \APZ { c' d' e' f' } }
rhythmustest.ly
Description: Binary data
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lilypond-user@gnu.org
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Re: problem with substitution
On 12/22/08 2:30 AM, Stefan Thomas kontrapunktste...@googlemail.com
wrote:
Dear Lilypond-users,
I trie to substitute the variable zackigschnell' with APZ', but
without sucess.
What is wrong with the following snippet?
\version 2.11.60
\include rhythmustest.ly
\new Staff { \APZ { c' d' e' f' } }
There's nothing wrong with the snippet.
The problem occurred in rhythmustest.ly.
You had the following:
zackigschnell = #(define-music-function (parser location music) (ly:music?)
#{ \makeRhythm $music 16. 32 #})
APZ = { \zackigschnell }
The way LilyPond substitution works, \zackigschnell needs to be followed by
a music expression. And in your definition of APZ, there is no music
expression following \zackigschnell. If you literally do the substitution,
you'll get
\new Staff { { \zackigschnell } {c' d' e' f' } }
and you can see that there is no music expression for \zackigschnell to
operator on.
If you literally want to just add a new name for a function, the way to do
it is with a scheme trick.
Simply add
#(define APZ zackigschnell)
and now APZ and zackigschnell are the same thing with two different names.
I've tried it on your code, and this works.
Good luck,
Carl
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lilypond-user@gnu.org
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