Re: timer ticks in /proc/stat - more differences between SLES and RHEL?

2013-05-17 Thread Rick Troth
The differences you're seeing ... some are lag-time as changes get
rolled into the kernel and utilities, but others may be variances from
a standard.  (or lag-time in keeping up with the standard)

Standard ... is there?  Why ... yes, there is!

   "The Linux Standard Base was created
to lower the overall costs of supporting the Linux platform.
By reducing the differences between individual Linux distributions,
the LSB greatly reduces the costs involved with porting applications
to different distributions, as well as lowers the cost and effort
involved in after-market support of those applications."

http://www.linuxfoundation.org/collaborate/workgroups/lsb

And it appears that IBM, SuSE, and RedHat are all supporting members of the LF.

-- R; <><




On Fri, May 17, 2013 at 1:23 PM, Michael MacIsaac  wrote:
> James, Emmett,
>
> Thanks for the replies.  Good to know that an older and a new RHEL seem to
> come up with the right answer (I assume you both have 2 vCPUs).
>
> Just to be sure, I tried again on my reference system, and got similar
> results:
>
> # cat /etc/redhat-release
>Red Hat Enterprise Linux Server release 6.3 (Santiago)
> # ./getticks
> getting one set of data
> sleeping 5 seconds and getting another set of data
> statOut1 = cpu  13191 57057 57033 4 0 2781 3194 3158 0
> statOut2 = cpu  13191 57057 57033 4 0 2781 3194 3158 0
> nums1 = 13191+57057+57033+4+0+2781+3194+3158+0
> nums2 = 13191+57057+57033+4+0+2781+3194+3158+0
> totalTicks = 0
>
>
> "Mike MacIsaac" 
>
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Re: timer ticks in /proc/stat - more differences between SLES and RHEL?

2013-05-17 Thread Michael MacIsaac
Hello list,

Aha moment - a while back I reported that "vmstat 1 2" was core dumping on
RHEL 6.3. I got a reply this is a known issue and that there is a fix.
This must be the same issue (without a proper tick count, the code might
be trying to divide by 0).  Another mystery solved.

I think it's time to move to RHEL 6.4 ...

Thanks again for all quick replies.

"Mike MacIsaac" 

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Re: Amount of memory in buffers shown by the free command

2013-05-17 Thread Michael MacIsaac
Mark,

Thanks for the reply.  So, it would seem "more correct" to add in the
other two components.  Interesting ...

I guess that explains why on one system I'm looking at apples and on the
other at oranges :))

"Mike MacIsaac" 

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Re: timer ticks in /proc/stat - more differences between SLES and RHEL?

2013-05-17 Thread Michael MacIsaac
James, Emmett,

Thanks for the replies.  Good to know that an older and a new RHEL seem to
come up with the right answer (I assume you both have 2 vCPUs).

Just to be sure, I tried again on my reference system, and got similar
results:

# cat /etc/redhat-release
   Red Hat Enterprise Linux Server release 6.3 (Santiago)
# ./getticks
getting one set of data
sleeping 5 seconds and getting another set of data
statOut1 = cpu  13191 57057 57033 4 0 2781 3194 3158 0
statOut2 = cpu  13191 57057 57033 4 0 2781 3194 3158 0
nums1 = 13191+57057+57033+4+0+2781+3194+3158+0
nums2 = 13191+57057+57033+4+0+2781+3194+3158+0
totalTicks = 0


"Mike MacIsaac" 

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Only 10 business days left! Registration closes at 23:59, May 31 for the 2013 VM Workshop in Indianapolis.

2013-05-17 Thread Mike Walter
Cross-posted to the IBMVM, Linux-390, and IBM-MAIN discussion lists.

The registration deadline is set hard and fast as the end of day May 31, 2013 
due to Indiana University - Purdue University Indianapolis (IUPUI) deadlines.  
Don't delay (besides, the two 2-part Hands-on Labs are expected to  reach their 
maximum capacity of 30 each rather quickly).

Why attend?  Well...

* the 2013 VM Workshop registration fee is only $100, and

* BRAND NEW double occupancy dorm rooms can be reserved as a 3-night 
package for $150 (with additional nights at $50 each), and

* reduced rate Parking passes are available for $20 (a $10 discount), 
and

* a lavish Thursday evening reception and dinner is included, and

* a $65 IUPUI debit card for meals in the Campus Center is included, and

* excellent technical sessions and the same IBM-provided Hands-on Labs 
presented at the bigger conferences, and

* the famous VM Workshop Ugly Hawaiian Shirt Contest is included 
(BYOUHS), and

* famous and infamous speakers delivering up-to-date technical sessions 
on z/VM and Linux on System z topics
all centrally located on the IUPUI campus in downtown Indianapolis, Indiana.

All 37 session slots are now 100% full.  There have been rumors of a few late 
sessions, so some of those below might be replaced by newer sessions of more 
general appeal, and/or... session times adjusted.

You may view each speaker's  full session descriptions by visiting the current 
session agenda and schedule at: http://www.vmworkshop.org/2013/agenda

To learn more about the 2013 VM Workshop, visit:  http://www.vmworkshop.org/2013
You can review all public information at that URL, but to register you'll first 
need to request a VM Workshop ID (used only to minimize spambot attacks on the 
web site).  Once you have been manually granted an ID by an admin, you may 
register for, and pay for (via Paypal) your purchases.

Note: There are only 15 IBM-provided Hands-on lab laptops at each of the 
non-concurrent 'z/VM Install & Config',  and 'Linux on System z Install & 
Config' labs.  Once you have received a workshop ID, you may reserve a seat at 
one and/or the other labs (maximum attendee reservations for each lab = 30).

Best regards,

Mike Walter
On behalf of the 2013 VM Workshop Volunteer Committee



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Re: timer ticks in /proc/stat - more differences between SLES and RHEL?

2013-05-17 Thread Emmett O'Grady
RHEL 6.4

cat /etc/redhat-release;./getticks.sh
Red Hat Enterprise Linux Server release 6.4 (Santiago)

getting one set of data
sleeping 5 seconds and getting another set of data
statOut1 = cpu  31860 18874 14917 835252 84240 869 1430 8480 0
statOut2 = cpu  31869 18874 14924 836234 84242 869 1430 8481 0
nums1 = 31860+18874+14917+835252+84240+869+1430+8480+0
nums2 = 31869+18874+14924+836234+84242+869+1430+8481+0
totalTicks = 1001




-Original Message-
From: Linux on 390 Port [mailto:LINUX-390@VM.MARIST.EDU] On Behalf Of CHAPLIN, 
JAMES (CTR)
Sent: Friday, May 17, 2013 10:59 AM
To: LINUX-390@VM.MARIST.EDU
Subject: Re: timer ticks in /proc/stat - more differences between SLES and RHEL?

Interesting because when I ran the same script on a RHEL 5.9 guest (w/ 2 
vCPUs), we get:

./gettricks.sh
getting one set of data
sleeping 5 seconds and getting another set of data
statOut1 = cpu  60259 128520 96523 256447792 415684 8000 15453 134955
statOut2 = cpu  60259 128520 96524 256448793 415686 8000 15453 134955
nums1 = 60259+128520+96523+256447792+415684+8000+15453+134955
nums2 = 60259+128520+96524+256448793+415686+8000+15453+134955
totalTicks = 1004

Do not have a RHEL  6.3 system to compare with :-(.

James Chaplin
Systems Programmer, MVS, zVM & zLinux
Base Technologies, a CA Technologies Company Supporting the zSeries Platform 
Team



-Original Message-
From: Linux on 390 Port [mailto:LINUX-390@VM.MARIST.EDU] On Behalf Of Michael 
MacIsaac
Sent: Friday, May 17, 2013 10:30 AM
To: LINUX-390@VM.MARIST.EDU
Subject: timer ticks in /proc/stat - more differences between SLES and RHEL?

I'm hacking around with CPU utilization numbers from /proc/stat with this 
little script:

# cat getticks
#!/bin/bash
  echo "getting one set of data"
  statOut1=`egrep '^cpu ' /proc/stat`
  echo "sleeping 5 seconds and getting another set of data"
  sleep 5
  statOut2=`egrep '^cpu ' /proc/stat`
  nums1=`echo "$statOut1" | grep ^cpu | sed -e 's/cpu\s*//g' -e 's/ /+/g'`
  let sum1=$nums1
  nums2=`echo "$statOut2" | grep ^cpu | sed -e 's/cpu\s*//g' -e 's/ /+/g'`
  let sum2=$nums2
  let totalTicks=$sum2-$sum1
  echo "statOut1 = $statOut1"
  echo "statOut2 = $statOut2"
  echo "nums1 = $nums1"
  echo "nums2 = $nums2"
  echo "totalTicks = $totalTicks"


On a SLES 11 SP2 system, with 5 vCPUs, I get the expected output:

# ./getticks
getting one set of data
sleeping 5 seconds and getting another set of data
statOut1 = cpu  251 8 170 857508 145 2 7 32 0 0
statOut2 = cpu  251 8 170 860009 145 2 7 32 0 0
nums1 = 251+8+170+857508+145+2+7+32+0+0
nums2 = 251+8+170+860009+145+2+7+32+0+0
totalTicks = 2501

2501 ~= 5 seconds * 5 CPUs * 100 ticks/sec

On a RHEL 6.3 system (2 vCPUs), I get a *slightly* different number:

# ./getticks
getting one set of data
sleeping 5 seconds and getting another set of data
statOut1 = cpu  13059 57057 56528 4 0 2740 3152 3130 0
statOut2 = cpu  13059 57057 56529 4 0 2740 3152 3130 0
nums1 = 13059+57057+56528+4+0+2740+3152+3130+0
nums2 = 13059+57057+56529+4+0+2740+3152+3130+0
totalTicks = 1

HUH? Does RHEL not count ticks in /proc/stat?

Any help will be appreciated.

"Mike MacIsaac" 

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Re: timer ticks in /proc/stat - more differences between SLES and RHEL?

2013-05-17 Thread CHAPLIN, JAMES (CTR)
Interesting because when I ran the same script on a RHEL 5.9 guest (w/ 2 
vCPUs), we get:

./gettricks.sh
getting one set of data
sleeping 5 seconds and getting another set of data
statOut1 = cpu  60259 128520 96523 256447792 415684 8000 15453 134955
statOut2 = cpu  60259 128520 96524 256448793 415686 8000 15453 134955
nums1 = 60259+128520+96523+256447792+415684+8000+15453+134955
nums2 = 60259+128520+96524+256448793+415686+8000+15453+134955
totalTicks = 1004

Do not have a RHEL  6.3 system to compare with :-(. 

James Chaplin
Systems Programmer, MVS, zVM & zLinux
Base Technologies, a CA Technologies Company
Supporting the zSeries Platform Team
 


-Original Message-
From: Linux on 390 Port [mailto:LINUX-390@VM.MARIST.EDU] On Behalf Of Michael 
MacIsaac
Sent: Friday, May 17, 2013 10:30 AM
To: LINUX-390@VM.MARIST.EDU
Subject: timer ticks in /proc/stat - more differences between SLES and RHEL?

I'm hacking around with CPU utilization numbers from /proc/stat with this 
little script:

# cat getticks
#!/bin/bash
  echo "getting one set of data"
  statOut1=`egrep '^cpu ' /proc/stat`
  echo "sleeping 5 seconds and getting another set of data"
  sleep 5
  statOut2=`egrep '^cpu ' /proc/stat`
  nums1=`echo "$statOut1" | grep ^cpu | sed -e 's/cpu\s*//g' -e 's/ /+/g'`
  let sum1=$nums1
  nums2=`echo "$statOut2" | grep ^cpu | sed -e 's/cpu\s*//g' -e 's/ /+/g'`
  let sum2=$nums2
  let totalTicks=$sum2-$sum1
  echo "statOut1 = $statOut1"
  echo "statOut2 = $statOut2"
  echo "nums1 = $nums1"
  echo "nums2 = $nums2"
  echo "totalTicks = $totalTicks"


On a SLES 11 SP2 system, with 5 vCPUs, I get the expected output:

# ./getticks
getting one set of data
sleeping 5 seconds and getting another set of data
statOut1 = cpu  251 8 170 857508 145 2 7 32 0 0
statOut2 = cpu  251 8 170 860009 145 2 7 32 0 0
nums1 = 251+8+170+857508+145+2+7+32+0+0
nums2 = 251+8+170+860009+145+2+7+32+0+0
totalTicks = 2501

2501 ~= 5 seconds * 5 CPUs * 100 ticks/sec

On a RHEL 6.3 system (2 vCPUs), I get a *slightly* different number:

# ./getticks
getting one set of data
sleeping 5 seconds and getting another set of data
statOut1 = cpu  13059 57057 56528 4 0 2740 3152 3130 0
statOut2 = cpu  13059 57057 56529 4 0 2740 3152 3130 0
nums1 = 13059+57057+56528+4+0+2740+3152+3130+0
nums2 = 13059+57057+56529+4+0+2740+3152+3130+0
totalTicks = 1

HUH? Does RHEL not count ticks in /proc/stat?

Any help will be appreciated.

"Mike MacIsaac" 

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Re: Amount of memory in buffers shown by the free command

2013-05-17 Thread Mark Post
>>> On 5/17/2013 at 08:15 AM, Rob van der Heij  wrote: 
> That explains why it's not in RHEL since it is not part of the upstream
> procps sources. The changelog entry has an innocent description like below.
> 
> * Thu Nov 17 2011 wer...@suse.de
> - Change order of parsing /proc/meminfo to make sure that
>   "Slab" and "SwapCached" fields are found  (bnc#696351)
> 
> I don't think this is a wise change, and I'm surprised a distributor would
> do things like that. I can see that you might want to add swap cache if you
> need to have a single number, but there's more value in having this
> consistent in the distributions.

The actual change came much earlier:
Thu Jul 10 18:24:14 CEST 2008 - wer...@suse.de

- Annoying change in /proc/meminfo makes info about free memory
  useless ... thanks Bart Van Assche for spotting (bnc#405246)

Looking at the bug report, there was quite a bit of discussion about the 
change, and how older versions (or other distribution's versions) would report 
different values.  In the end, it boiled down to the upstream maintainer not 
doing much actual maintaining, and the old behavior being considered by 
everyone to be wrong.  Some people weren't happy about the change in behavior, 
but the SUSE developer at the time decided he'd rather have correct information 
that was inconsistent with older versions, than incorrect information that was 
consistent with older versions.


Mark Post

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timer ticks in /proc/stat - more differences between SLES and RHEL?

2013-05-17 Thread Michael MacIsaac
I'm hacking around with CPU utilization numbers from /proc/stat with this
little script:

# cat getticks
#!/bin/bash
  echo "getting one set of data"
  statOut1=`egrep '^cpu ' /proc/stat`
  echo "sleeping 5 seconds and getting another set of data"
  sleep 5
  statOut2=`egrep '^cpu ' /proc/stat`
  nums1=`echo "$statOut1" | grep ^cpu | sed -e 's/cpu\s*//g' -e 's/ /+/g'`
  let sum1=$nums1
  nums2=`echo "$statOut2" | grep ^cpu | sed -e 's/cpu\s*//g' -e 's/ /+/g'`
  let sum2=$nums2
  let totalTicks=$sum2-$sum1
  echo "statOut1 = $statOut1"
  echo "statOut2 = $statOut2"
  echo "nums1 = $nums1"
  echo "nums2 = $nums2"
  echo "totalTicks = $totalTicks"


On a SLES 11 SP2 system, with 5 vCPUs, I get the expected output:

# ./getticks
getting one set of data
sleeping 5 seconds and getting another set of data
statOut1 = cpu  251 8 170 857508 145 2 7 32 0 0
statOut2 = cpu  251 8 170 860009 145 2 7 32 0 0
nums1 = 251+8+170+857508+145+2+7+32+0+0
nums2 = 251+8+170+860009+145+2+7+32+0+0
totalTicks = 2501

2501 ~= 5 seconds * 5 CPUs * 100 ticks/sec

On a RHEL 6.3 system (2 vCPUs), I get a *slightly* different number:

# ./getticks
getting one set of data
sleeping 5 seconds and getting another set of data
statOut1 = cpu  13059 57057 56528 4 0 2740 3152 3130 0
statOut2 = cpu  13059 57057 56529 4 0 2740 3152 3130 0
nums1 = 13059+57057+56528+4+0+2740+3152+3130+0
nums2 = 13059+57057+56529+4+0+2740+3152+3130+0
totalTicks = 1

HUH? Does RHEL not count ticks in /proc/stat?

Any help will be appreciated.

"Mike MacIsaac" 

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Re: Amount of memory in buffers shown by the free command

2013-05-17 Thread Rob van der Heij
It's Friday, but I still don't feel like installing all the dependencies to
build the procps package...   I believe the smoking gun is on my desk
already:

procps-3.2.7-slab.patch (part of the SUSE add-ons to procps) says

@@ -603,6 +615,7 @@
   }
   kb_swap_used = kb_swap_total - kb_swap_free;
   kb_main_used = kb_main_total - kb_main_free;
+  kb_main_cached += kb_slab_reclaimable + kb_swap_cached + kb_nfs_unstable;
 }

That explains why it's not in RHEL since it is not part of the upstream
procps sources. The changelog entry has an innocent description like below.

* Thu Nov 17 2011 wer...@suse.de
- Change order of parsing /proc/meminfo to make sure that
  "Slab" and "SwapCached" fields are found  (bnc#696351)

I don't think this is a wise change, and I'm surprised a distributor would
do things like that. I can see that you might want to add swap cache if you
need to have a single number, but there's more value in having this
consistent in the distributions.

Rob



On 17 May 2013 12:57, Michael MacIsaac  wrote:

> Alex,
>
> > That is not what I see at my end.
> Wait, what?
>
> You have two RHELs and they agree with my RHEL - the value for "Cached" in
> /proc/meminfo is also shown in "free".  It's SLES's "free" that seems to
> add the "Cached" and "SReclaimable" values (and as Rob points out,
> possibly also "SwapCached").
>
> "Mike MacIsaac" 
>
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Re: Amount of memory in buffers shown by the free command

2013-05-17 Thread Michael MacIsaac
Alex,

> That is not what I see at my end.
Wait, what?

You have two RHELs and they agree with my RHEL - the value for "Cached" in
/proc/meminfo is also shown in "free".  It's SLES's "free" that seems to
add the "Cached" and "SReclaimable" values (and as Rob points out,
possibly also "SwapCached").

"Mike MacIsaac" 

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Re: Amount of memory in buffers shown by the free command

2013-05-17 Thread Rob van der Heij
On 17 May 2013 01:55, Suthammanont, Alex C <
alex.suthamman...@bankofamerica.com> wrote:

> Mike & Rob,
> That is not what I see at my end. Below are sample of RHEL 5.9 and RHEL
> 6.3.
> In both cases, the number of cached from the 'free' command matches to the
> number of cached found in /proc/meminfo. Strange but true..


You did not show the "SwapCached:" entry from /proc/meminfo in your output.
If that is 0, I could still be correct to expect that "free" shows us the
sum of Cached and SwapCached.

I don't see what Mike's slab reclaimable would have to do with this, unless
some ambitious soul tried to stuff 3 numbers into one and hoped to do us a
favor. After all, some look at the 2nd line in "free" for what they could
available when it has to be, so by sneaking other numbers into the "cached"
value you find that "free" will include that into the "+/-" cache numbers.
Wish even more I had the time to investigate. From earlier experiments in
http://zvmperf.wordpress.com/2013/01/31/the-nocache-approach/ I still have
tools that tell me *which* files are in cache, so we should be able to get
the picture right...

Rob

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