Re: [PATCH v3] fs/locks: print full locks information

2021-03-10 Thread Luo Longjun



在 2021/3/9 21:37, Jeff Layton 写道:

On Thu, 2021-02-25 at 22:58 -0500, Luo Longjun wrote:

Commit fd7732e033e3 ("fs/locks: create a tree of dependent requests.")
has put blocked locks into a tree.

So, with a for loop, we can't check all locks information.

To solve this problem, we should traverse the tree.

Signed-off-by: Luo Longjun 
---
  fs/locks.c | 65 ++
  1 file changed, 56 insertions(+), 9 deletions(-)

diff --git a/fs/locks.c b/fs/locks.c
index 99ca97e81b7a..ecaecd1f1b58 100644
--- a/fs/locks.c
+++ b/fs/locks.c
@@ -2828,7 +2828,7 @@ struct locks_iterator {
  };
  




  static void lock_get_status(struct seq_file *f, struct file_lock *fl,
-   loff_t id, char *pfx)
+   loff_t id, char *pfx, int repeat)
  {
    struct inode *inode = NULL;
    unsigned int fl_pid;
@@ -2844,7 +2844,11 @@ static void lock_get_status(struct seq_file *f, struct 
file_lock *fl,
    if (fl->fl_file != NULL)
    inode = locks_inode(fl->fl_file);
  




-   seq_printf(f, "%lld:%s ", id, pfx);
+   seq_printf(f, "%lld: ", id);
+
+   if (repeat)
+   seq_printf(f, "%*s", repeat - 1 + (int)strlen(pfx), pfx);

Shouldn't that be "%.*s" ?

Also, isn't this likely to end up walking past the end of "pfx" (or even
ending up at an address before the buffer)? You have this below:

 lock_get_status(f, fl, *id, "", 0);

...so the "length" value you're passing into the format there is going
to be -1. It also seems like if you get a large "level" value in
locks_show, then you'll end up with a length that is much longer than
the actual string.


In my understanding, the difference of "%*s" and "%.*s" is that, "%*s" 
specifies the minimal filed width while "%.*s" specifies the precision 
of the string.


Here, I use "%*s", because I want to print locks information in the 
follwing format:


2: FLOCK  ADVISORY  WRITE 110 00:02:493 0 EOF
2: -> FLOCK  ADVISORY  WRITE 111 00:02:493 0 EOF
2:  -> FLOCK  ADVISORY  WRITE 112 00:02:493 0 EOF
2:   -> FLOCK  ADVISORY  WRITE 113 00:02:493 0 EOF
2:    -> FLOCK  ADVISORY  WRITE 114 00:02:493 0 EOF

And also, there is another way to show there information, in the format 
like:


60: FLOCK  ADVISORY  WRITE 23350 08:02:4456514 0 EOF
60: -> FLOCK  ADVISORY  WRITE 23356 08:02:4456514 0 EOF
60: -> FLOCK  ADVISORY  WRITE 24217 08:02:4456514 0 EOF
60: -> FLOCK  ADVISORY  WRITE 24239 08:02:4456514 0 EOF

I think both formats are acceptable, but the first format shows 
competition relationships between these locks.


In the following code:


lock_get_status(f, fl, *id, "", 0);


repeat is 0, and in the function:

+ if (repeat)
+   seq_printf(f, "%*s", repeat - 1 + (int)strlen(pfx), pfx);

The if branch will not take effect, so it could not be -1.


+
    if (IS_POSIX(fl)) {
    if (fl->fl_flags & FL_ACCESS)
    seq_puts(f, "ACCESS");
@@ -2906,21 +2910,64 @@ static void lock_get_status(struct seq_file *f, struct 
file_lock *fl,
    }
  }
  




+static struct file_lock *get_next_blocked_member(struct file_lock *node)
+{
+   struct file_lock *tmp;
+
+   /* NULL node or root node */
+   if (node == NULL || node->fl_blocker == NULL)
+   return NULL;
+
+   /* Next member in the linked list could be itself */
+   tmp = list_next_entry(node, fl_blocked_member);
+   if (list_entry_is_head(tmp, >fl_blocker->fl_blocked_requests, 
fl_blocked_member)
+   || tmp == node) {
+   return NULL;
+   }
+
+   return tmp;
+}
+
  static int locks_show(struct seq_file *f, void *v)
  {
    struct locks_iterator *iter = f->private;
-   struct file_lock *fl, *bfl;
+   struct file_lock *cur, *tmp;
    struct pid_namespace *proc_pidns = 
proc_pid_ns(file_inode(f->file)->i_sb);
+   int level = 0;
  




-   fl = hlist_entry(v, struct file_lock, fl_link);
+   cur = hlist_entry(v, struct file_lock, fl_link);
  




-   if (locks_translate_pid(fl, proc_pidns) == 0)
+   if (locks_translate_pid(cur, proc_pidns) == 0)
    return 0;
  




-   lock_get_status(f, fl, iter->li_pos, "");
+   /* View this crossed linked list as a binary tree, the first member of 
fl_blocked_requests
+* is the left child of current node, the next silibing in 
fl_blocked_member is the
+* right child, we can alse get the parent of current node from 
fl_blocker, so this
+* question becomes traversal of a binary tree
+*/
+   while (cur != NULL) {
+   if (level)
+   lock_get_status(f, cur, iter->li_pos, "-> ", level);
+   el

[PATCH v3] fs/locks: print full locks information

2021-02-25 Thread Luo Longjun
Commit fd7732e033e3 ("fs/locks: create a tree of dependent requests.")
has put blocked locks into a tree.

So, with a for loop, we can't check all locks information.

To solve this problem, we should traverse the tree.

Signed-off-by: Luo Longjun 
---
 fs/locks.c | 65 ++
 1 file changed, 56 insertions(+), 9 deletions(-)

diff --git a/fs/locks.c b/fs/locks.c
index 99ca97e81b7a..ecaecd1f1b58 100644
--- a/fs/locks.c
+++ b/fs/locks.c
@@ -2828,7 +2828,7 @@ struct locks_iterator {
 };
 
 static void lock_get_status(struct seq_file *f, struct file_lock *fl,
-   loff_t id, char *pfx)
+   loff_t id, char *pfx, int repeat)
 {
struct inode *inode = NULL;
unsigned int fl_pid;
@@ -2844,7 +2844,11 @@ static void lock_get_status(struct seq_file *f, struct 
file_lock *fl,
if (fl->fl_file != NULL)
inode = locks_inode(fl->fl_file);
 
-   seq_printf(f, "%lld:%s ", id, pfx);
+   seq_printf(f, "%lld: ", id);
+
+   if (repeat)
+   seq_printf(f, "%*s", repeat - 1 + (int)strlen(pfx), pfx);
+
if (IS_POSIX(fl)) {
if (fl->fl_flags & FL_ACCESS)
seq_puts(f, "ACCESS");
@@ -2906,21 +2910,64 @@ static void lock_get_status(struct seq_file *f, struct 
file_lock *fl,
}
 }
 
+static struct file_lock *get_next_blocked_member(struct file_lock *node)
+{
+   struct file_lock *tmp;
+
+   /* NULL node or root node */
+   if (node == NULL || node->fl_blocker == NULL)
+   return NULL;
+
+   /* Next member in the linked list could be itself */
+   tmp = list_next_entry(node, fl_blocked_member);
+   if (list_entry_is_head(tmp, >fl_blocker->fl_blocked_requests, 
fl_blocked_member)
+   || tmp == node) {
+   return NULL;
+   }
+
+   return tmp;
+}
+
 static int locks_show(struct seq_file *f, void *v)
 {
struct locks_iterator *iter = f->private;
-   struct file_lock *fl, *bfl;
+   struct file_lock *cur, *tmp;
struct pid_namespace *proc_pidns = 
proc_pid_ns(file_inode(f->file)->i_sb);
+   int level = 0;
 
-   fl = hlist_entry(v, struct file_lock, fl_link);
+   cur = hlist_entry(v, struct file_lock, fl_link);
 
-   if (locks_translate_pid(fl, proc_pidns) == 0)
+   if (locks_translate_pid(cur, proc_pidns) == 0)
return 0;
 
-   lock_get_status(f, fl, iter->li_pos, "");
+   /* View this crossed linked list as a binary tree, the first member of 
fl_blocked_requests
+* is the left child of current node, the next silibing in 
fl_blocked_member is the
+* right child, we can alse get the parent of current node from 
fl_blocker, so this
+* question becomes traversal of a binary tree
+*/
+   while (cur != NULL) {
+   if (level)
+   lock_get_status(f, cur, iter->li_pos, "-> ", level);
+   else
+   lock_get_status(f, cur, iter->li_pos, "", level);
 
-   list_for_each_entry(bfl, >fl_blocked_requests, fl_blocked_member)
-   lock_get_status(f, bfl, iter->li_pos, " ->");
+   if (!list_empty(>fl_blocked_requests)) {
+   /* Turn left */
+   cur = 
list_first_entry_or_null(>fl_blocked_requests,
+   struct file_lock, fl_blocked_member);
+   level++;
+   } else {
+   /* Turn right */
+   tmp = get_next_blocked_member(cur);
+   /* Fall back to parent node */
+   while (tmp == NULL && cur->fl_blocker != NULL) {
+   cur = cur->fl_blocker;
+   level--;
+   tmp = get_next_blocked_member(cur);
+   }
+   cur = tmp;
+   }
+   }
 
return 0;
 }
@@ -2941,7 +2988,7 @@ static void __show_fd_locks(struct seq_file *f,
 
(*id)++;
seq_puts(f, "lock:\t");
-   lock_get_status(f, fl, *id, "");
+   lock_get_status(f, fl, *id, "", 0);
}
 }
 
-- 
2.17.1



[PATCH v2 02/24] fs/locks: print full locks information

2021-02-24 Thread Luo Longjun
Commit fd7732e033e3 ("fs/locks: create a tree of dependent requests.")
has put blocked locks into a tree.

So, with a for loop, we can't check all locks information.

To solve this problem, we should traverse the tree by non-recursion DFS.

Signed-off-by: Luo Longjun 
---
 fs/locks.c | 75 --
 1 file changed, 67 insertions(+), 8 deletions(-)

diff --git a/fs/locks.c b/fs/locks.c
index 99ca97e81b7a..fdf240626777 100644
--- a/fs/locks.c
+++ b/fs/locks.c
@@ -2827,8 +2827,14 @@ struct locks_iterator {
loff_t  li_pos;
 };
 
+struct locks_traverse_list {
+   struct list_head head;
+   struct file_lock *lock;
+   int level;
+};
+
 static void lock_get_status(struct seq_file *f, struct file_lock *fl,
-   loff_t id, char *pfx)
+   loff_t id, char *pfx, int repeat)
 {
struct inode *inode = NULL;
unsigned int fl_pid;
@@ -2844,7 +2850,11 @@ static void lock_get_status(struct seq_file *f, struct 
file_lock *fl,
if (fl->fl_file != NULL)
inode = locks_inode(fl->fl_file);
 
-   seq_printf(f, "%lld:%s ", id, pfx);
+   seq_printf(f, "%lld: ", id);
+
+   if (repeat)
+   seq_printf(f, "%*s", repeat - 1 + strlen(pfx), pfx);
+
if (IS_POSIX(fl)) {
if (fl->fl_flags & FL_ACCESS)
seq_puts(f, "ACCESS");
@@ -2912,17 +2922,66 @@ static int locks_show(struct seq_file *f, void *v)
struct file_lock *fl, *bfl;
struct pid_namespace *proc_pidns = 
proc_pid_ns(file_inode(f->file)->i_sb);
 
+   struct list_head root;
+   struct list_head *tail = 
+   struct list_head *pos, *tmp;
+   struct locks_traverse_list *node, *node_child;
+
+   int ret = 0;
+
fl = hlist_entry(v, struct file_lock, fl_link);
 
if (locks_translate_pid(fl, proc_pidns) == 0)
-   return 0;
+   return ret;
+
+   INIT_LIST_HEAD();
 
-   lock_get_status(f, fl, iter->li_pos, "");
+   node = kmalloc(sizeof(struct locks_traverse_list), GFP_KERNEL);
+   if (!node) {
+   ret = -ENOMEM;
+   goto out;
+   }
 
-   list_for_each_entry(bfl, >fl_blocked_requests, fl_blocked_member)
-   lock_get_status(f, bfl, iter->li_pos, " ->");
+   node->level = 0;
+   node->lock = fl;
+   list_add(>head, tail);
+   tail = >head;
 
-   return 0;
+   while (tail != ) {
+   node = list_entry(tail, struct locks_traverse_list, head);
+   if (!node->level)
+   lock_get_status(f, node->lock, iter->li_pos, "", 
node->level);
+   else
+   lock_get_status(f, node->lock, iter->li_pos, "-> ", 
node->level);
+
+   tmp = tail->prev;
+   list_del(tail);
+   tail = tmp;
+
+   list_for_each_entry_reverse(bfl, 
>lock->fl_blocked_requests,
+   fl_blocked_member) {
+   node_child = kmalloc(sizeof(struct 
locks_traverse_list), GFP_KERNEL);
+   if (!node_child) {
+   ret = -ENOMEM;
+   goto out;
+   }
+
+   node_child->level = node->level + 1;
+   node_child->lock = bfl;
+   list_add(_child->head, tail);
+   tail = _child->head;
+   }
+   kfree(node);
+   }
+
+out:
+   list_for_each_safe(pos, tmp, ) {
+   node = list_entry(pos, struct locks_traverse_list, head);
+   list_del(pos);
+   if (!node)
+   kfree(node);
+   }
+   return ret;
 }
 
 static void __show_fd_locks(struct seq_file *f,
@@ -2941,7 +3000,7 @@ static void __show_fd_locks(struct seq_file *f,
 
(*id)++;
seq_puts(f, "lock:\t");
-   lock_get_status(f, fl, *id, "");
+   lock_get_status(f, fl, *id, "", 0);
}
 }
 
-- 
2.17.1



[PATCH] fs/locks: print full locks information

2021-02-20 Thread Luo Longjun
Commit fd7732e033e3 ("fs/locks: create a tree of dependent requests.")
has put blocked locks into a tree.

So, with a for loop, we can't check all locks information.

To solve this problem, we should traverse the tree by DFS.

Signed-off-by: Luo Longjun 
---
 fs/locks.c | 30 +-
 1 file changed, 25 insertions(+), 5 deletions(-)

diff --git a/fs/locks.c b/fs/locks.c
index 99ca97e81b7a..1f7b6683ed54 100644
--- a/fs/locks.c
+++ b/fs/locks.c
@@ -2828,9 +2828,10 @@ struct locks_iterator {
 };
 
 static void lock_get_status(struct seq_file *f, struct file_lock *fl,
-   loff_t id, char *pfx)
+   loff_t id, char *pfx, int repeat)
 {
struct inode *inode = NULL;
+   int i;
unsigned int fl_pid;
struct pid_namespace *proc_pidns = 
proc_pid_ns(file_inode(f->file)->i_sb);
 
@@ -2844,7 +2845,13 @@ static void lock_get_status(struct seq_file *f, struct 
file_lock *fl,
if (fl->fl_file != NULL)
inode = locks_inode(fl->fl_file);
 
-   seq_printf(f, "%lld:%s ", id, pfx);
+   seq_printf(f, "%lld: ", id);
+   for (i = 1; i < repeat; i++)
+   seq_puts(f, " ");
+
+   if (repeat)
+   seq_printf(f, "%s", pfx);
+
if (IS_POSIX(fl)) {
if (fl->fl_flags & FL_ACCESS)
seq_puts(f, "ACCESS");
@@ -2906,6 +2913,19 @@ static void lock_get_status(struct seq_file *f, struct 
file_lock *fl,
}
 }
 
+static int __locks_show(struct seq_file *f, struct file_lock *fl, int level)
+{
+   struct locks_iterator *iter = f->private;
+   struct file_lock *bfl;
+
+   lock_get_status(f, fl, iter->li_pos, "-> ", level);
+
+   list_for_each_entry(bfl, >fl_blocked_requests, fl_blocked_member)
+   __locks_show(f, bfl, level + 1);
+
+   return 0;
+}
+
 static int locks_show(struct seq_file *f, void *v)
 {
struct locks_iterator *iter = f->private;
@@ -2917,10 +2937,10 @@ static int locks_show(struct seq_file *f, void *v)
if (locks_translate_pid(fl, proc_pidns) == 0)
return 0;
 
-   lock_get_status(f, fl, iter->li_pos, "");
+   lock_get_status(f, fl, iter->li_pos, "", 0);
 
list_for_each_entry(bfl, >fl_blocked_requests, fl_blocked_member)
-   lock_get_status(f, bfl, iter->li_pos, " ->");
+   __locks_show(f, bfl, 1);
 
return 0;
 }
@@ -2941,7 +2961,7 @@ static void __show_fd_locks(struct seq_file *f,
 
(*id)++;
seq_puts(f, "lock:\t");
-   lock_get_status(f, fl, *id, "");
+   lock_get_status(f, fl, *id, "", 0);
}
 }
 
-- 
2.17.1