Re: PID of init != 1 when initrd with pivot_root
On Tue, 5 Jun 2001, W. Michael Petullo wrote: > > But the problem still remains. How do I make my /sbin/init run with PID 1 > > using initial ramdisk under the new root change mechanism? I don't want to > > use the old change_root mechanism... > > I had the same problem when doing some development for mkCDrec. > This project uses busybox, whose init does not run if its PID != 1. > I asked the busybox folks same question you did and never got a response. Maybe I'm wrong here, but I had the same problem at some point and my solution was to rename /linuxrc (to /linux, and booting with init=/linux). I believe the code which special cases /linuxrc might be in the way here. Maybe you want to try this, if it helps I think Documentation/initrd.txt needs to be updated. --Kai - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to [EMAIL PROTECTED] More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
Re: PID of init != 1 when initrd with pivot_root
> > But the problem still remains. How do I make my /sbin/init run with PID 1 > > using initial ramdisk under the new root change mechanism? I don't want to > > use the old change_root mechanism... > > I had the same problem when doing some development for mkCDrec. > This project uses busybox, whose init does not run if its PID != 1. > I asked the busybox folks same question you did and never got a response. > > As a kludge, and after looking at the busybox source code, I renamed init > to linuxrc. In this case the program is functionally equivalent to init, > except that it does not do the PID == 1 check. > > An excerpt from my real linuxrc: > > echo Pivot_root: my PID is $$ > # exec /usr/sbin/chroot . /sbin/init < dev/console > dev/console 2>&1 > # Okay, try this: > exec /usr/sbin/chroot . /sbin/linuxrc < /dev/console > /dev/console 2>&1 > > /sbin/linuxrc is actually init, renamed. > I fugured it out. The Documentation/initrd.txt says to use root=/dev/rd/0 with devfs. Well, that's wrong. You should use root=/dev/ram0 even with devfs no matter what the documentation says. And my linuxrc finaly runs with PID == 1. Ivan Vadovic - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to [EMAIL PROTECTED] More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
Re: PID of init != 1 when initrd with pivot_root
>>> Well, I upgraded and found pivot_root and the problem is that how do I make >>> init run with PID 1. My linuxrc gets PID 7. >>> >>> 1 ?00:03:05 swapper >>> ... >>> 7 ?00:00:00 linuxrc >>> >>> init doesn't like running with any other PID than 1. I could probably revert >>> to the not so old way of doing things and exit linuxrc and let the kernel >>> change root. But then I wouldn't be able to mount root over samba :-(. >>> >>> ... >> This is this way for backwards bug compatibility. Use the following >> command line options to make it behave properly: >> >> ram=/dev/ram0 init=/linuxrc > ... > > But the problem still remains. How do I make my /sbin/init run with PID 1 > using initial ramdisk under the new root change mechanism? I don't want to > use the old change_root mechanism... I had the same problem when doing some development for mkCDrec. This project uses busybox, whose init does not run if its PID != 1. I asked the busybox folks same question you did and never got a response. As a kludge, and after looking at the busybox source code, I renamed init to linuxrc. In this case the program is functionally equivalent to init, except that it does not do the PID == 1 check. An excerpt from my real linuxrc: echo Pivot_root: my PID is $$ # exec /usr/sbin/chroot . /sbin/init < dev/console > dev/console 2>&1 # Okay, try this: exec /usr/sbin/chroot . /sbin/linuxrc < /dev/console > /dev/console 2>&1 /sbin/linuxrc is actually init, renamed. I am sure this is not the preferred method. Please let me know if you find the correct solution. -- W. Michael Petullo :wq - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to [EMAIL PROTECTED] More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
Re: PID of init != 1 when initrd with pivot_root
> > Well, I upgraded and found pivot_root and the problem is that how do I make init > > run with PID 1. My linuxrc gets PID 7. > > > > 1 ?00:03:05 swapper > > 2 ?00:00:00 keventd > > 3 ?00:00:00 kswapd > > 4 ?00:00:00 kreclaimd > > 5 ?00:00:00 bdflush > > 6 ?00:00:00 kupdated > > 7 ?00:00:00 linuxrc > > > > init doesn't like running with any other PID than 1. I could probably revert to > > the not so old way of doing things and exit linuxrc and let the kernel change > > root. But then I wouldn't be able to mount root over samba :-(. ( not that I > > have any samba shares :-) > > This is this way for backwards bug compatibility. Use the following > command line options to make it behave properly: > > ram=/dev/ram0 init=/linuxrc That's what I did, almost. I think you meant root=/dev/rd/0 init=/linuxrc ( with devfs) though init parameter is made redundant by the new "root change mechanism" pivot_root. But the problem still remains. How do I make my /sbin/init run with PID 1 using initial ramdisk under the new root change mechanism? I don't want to use the old change_root mechanism since the Documentation/initrd.txt says: Obsolete root change mechanism -- The following mechanism was used before the introduction of pivot_root. Current kernels still support it, but you should _not_ rely on its continued availability. ... This old, deprecated mechanism is commonly called "change_root", while the new, supported mechanism is called "pivot_root". -- Ivan Vadovic - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to [EMAIL PROTECTED] More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
Re: PID of init != 1 when initrd with pivot_root
Followup to: <[EMAIL PROTECTED]> By author:Ivan <[EMAIL PROTECTED]> In newsgroup: linux.dev.kernel > > Well, I upgraded and found pivot_root and the problem is that how do I make init > run with PID 1. My linuxrc gets PID 7. > > 1 ?00:03:05 swapper > 2 ?00:00:00 keventd > 3 ?00:00:00 kswapd > 4 ?00:00:00 kreclaimd > 5 ?00:00:00 bdflush > 6 ?00:00:00 kupdated > 7 ?00:00:00 linuxrc > > init doesn't like running with any other PID than 1. I could probably revert to > the not so old way of doing things and exit linuxrc and let the kernel change > root. But then I wouldn't be able to mount root over samba :-(. ( not that I > have any samba shares :-) > This is this way for backwards bug compatibility. Use the following command line options to make it behave properly: ram=/dev/ram0 init=/linuxrc -hpa -- <[EMAIL PROTECTED]> at work, <[EMAIL PROTECTED]> in private! "Unix gives you enough rope to shoot yourself in the foot." http://www.zytor.com/~hpa/puzzle.txt - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to [EMAIL PROTECTED] More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
PID of init != 1 when initrd with pivot_root
Well, I upgraded and found pivot_root and the problem is that how do I make init run with PID 1. My linuxrc gets PID 7. 1 ?00:03:05 swapper 2 ?00:00:00 keventd 3 ?00:00:00 kswapd 4 ?00:00:00 kreclaimd 5 ?00:00:00 bdflush 6 ?00:00:00 kupdated 7 ?00:00:00 linuxrc init doesn't like running with any other PID than 1. I could probably revert to the not so old way of doing things and exit linuxrc and let the kernel change root. But then I wouldn't be able to mount root over samba :-(. ( not that I have any samba shares :-) Ivan Vadovic - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to [EMAIL PROTECTED] More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
