Re: [lldb-dev] 'breakpoint delete' vs. 'breakpoint disable'

[Greg Clayton via lldb-dev]

Breakpoint disable will keep the breakpoint around and all of its locations. 
Breakpoint delete will delete it. Shouldn't make a difference and one doesn't 
have to happen before the other. Sounds like you found a bug. When things crash 
it would be good to attach a stack backtrace of why LLDB is crashing. That will 
help us to see what us causing the issue.

Greg Clayton


> On Feb 16, 2018, at 6:13 AM, Dmitry Antipov via lldb-dev 
>  wrote:
> 
> While operating on a breakpoints, is it correct to use 'breakpoint delete' 
> without
> previous 'breakpoint disable'? With this scenario, I'm observing 6.0.0-rc2 
> crash with:
> 
> $ /home/dantipov/.local/llvm-6.0.0/bin/lldb t-thread2
> (lldb) target create "t-thread2"
> Current executable set to 't-thread2' (x86_64).
> (lldb) breakpoint set -n g
> Breakpoint 1: where = t-thread2`g(int) + 7 at t-thread2.cc:9, address = 
> 0x00400d0e
> (lldb) run
> Process 19195 launched: '/home/dantipov/tmp/t-thread2' (x86_64)
> Process 19195 stopped
> * thread #2, name = 't-thread2', stop reason = breakpoint 1.1
>frame #0: 0x00400d0e t-thread2`g(v=0) at t-thread2.cc:9
>   6   g (int v)
>   7   {
>   8 (void) v;
> -> 9  }
>   10  
>   11  void
>   12  f (int v)
> (lldb) process continue
> Process 19195 resuming
> Process 19195 stopped
> * thread #3, name = 't-thread2', stop reason = breakpoint 1.1
>frame #0: 0x00400d0e t-thread2`g(v=1) at t-thread2.cc:9
>   6   g (int v)
>   7   {
>   8 (void) v;
> -> 9  }
>   10  
>   11  void
>   12  f (int v)
> (lldb) process continue
> Process 19195 resuming
> Process 19195 stopped
> * thread #2, name = 't-thread2', stop reason = breakpoint 1.1
>frame #0: 0x00400d0e t-thread2`g(v=0) at t-thread2.cc:9
>   6   g (int v)
>   7   {
>   8 (void) v;
> -> 9  }
>   10  
>   11  void
>   12  f (int v)
> (lldb) breakpoint delete
> About to delete all breakpoints, do you want to do that?: [Y/n] Y
> All breakpoints removed. (1 breakpoint)
> (lldb) process continue
> Process 19195 resuming
> Segmentation fault (core dumped)
> 
> There is no crash if 'breakpoint disable' was issued before 'breakpoint 
> delete'.
> Sample program attached.
> 
> Dmitry
> 
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[lldb-dev] 'breakpoint delete' vs. 'breakpoint disable'

[Dmitry Antipov via lldb-dev]

While operating on a breakpoints, is it correct to use 'breakpoint delete' 
without
previous 'breakpoint disable'? With this scenario, I'm observing 6.0.0-rc2 
crash with:

$ /home/dantipov/.local/llvm-6.0.0/bin/lldb t-thread2
(lldb) target create "t-thread2"
Current executable set to 't-thread2' (x86_64).
(lldb) breakpoint set -n g
Breakpoint 1: where = t-thread2`g(int) + 7 at t-thread2.cc:9, address = 
0x00400d0e
(lldb) run
Process 19195 launched: '/home/dantipov/tmp/t-thread2' (x86_64)
Process 19195 stopped
* thread #2, name = 't-thread2', stop reason = breakpoint 1.1
frame #0: 0x00400d0e t-thread2`g(v=0) at t-thread2.cc:9
   6g (int v)
   7{
   8  (void) v;
-> 9 }
   10   
   11   void
   12   f (int v)
(lldb) process continue
Process 19195 resuming
Process 19195 stopped
* thread #3, name = 't-thread2', stop reason = breakpoint 1.1
frame #0: 0x00400d0e t-thread2`g(v=1) at t-thread2.cc:9
   6g (int v)
   7{
   8  (void) v;
-> 9 }
   10   
   11   void
   12   f (int v)
(lldb) process continue
Process 19195 resuming
Process 19195 stopped
* thread #2, name = 't-thread2', stop reason = breakpoint 1.1
frame #0: 0x00400d0e t-thread2`g(v=0) at t-thread2.cc:9
   6g (int v)
   7{
   8  (void) v;
-> 9 }
   10   
   11   void
   12   f (int v)
(lldb) breakpoint delete
About to delete all breakpoints, do you want to do that?: [Y/n] Y
All breakpoints removed. (1 breakpoint)
(lldb) process continue
Process 19195 resuming
Segmentation fault (core dumped)

There is no crash if 'breakpoint disable' was issued before 'breakpoint delete'.
Sample program attached.

Dmitry

---
This email message is for the sole use of the intended recipient(s) and may 
contain
confidential information.  Any unauthorized review, use, disclosure or 
distribution
is prohibited.  If you are not the intended recipient, please contact the 
sender by
reply email and destroy all copies of the original message.
---
#include 
#include 
#include 

void
g (int v)
{
  (void) v;
}

void
f (int v)
{
  while (true)
{
  g (v);
  std::this_thread::sleep_for (std::chrono::milliseconds (100 + std::rand () % 100));
}
}

int
main (int argc, char *argv[])
{
  auto max = argc > 1 ? std::atoi (argv[1]) : 2;

  std::vector T;
  for (auto i = 0; i < max; i++)
T.push_back (new std::thread (f, i));
  for (auto : T)
t->join ();

  return 0;
}
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