RE: lug-bg: Red Hat 7.2, kernel 2.4.7, perror bug

2002-06-27 Thread Nikolai Abromov

am.. 
normalno, perror si formatira errnomer i si go print kato message
princip taka kakto e polzvana v tazi programa e greshno, i absoliutno
bezsmisleno


br,nick 



-Original Message-
From: Radoslav Savov [mailto:[EMAIL PROTECTED]]
Sent: Thursday, June 27, 2002 5:23 AM
To: [EMAIL PROTECTED]
Subject: lug-bg: Red Hat 7.2, kernel 2.4.7, perror bug 


main ()

{
perror("nothing");
perror("perror");

}

rezultat:

nothing: Success
perror: Illegal seek



Obru6tenieto kum perror() predizwikwa gre6ka ?!
Kak da go oprawq?


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Re: lug-bg: Red Hat 7.2, kernel 2.4.7, perror bug

2002-06-26 Thread Alexander Atanasov

On Wed, 26 Jun 2002, Radoslav Savov wrote:

> main ()
> 
> {
>   perror("nothing");
>   perror("perror");
> 
> }
> 
> rezultat:
> 
> nothing: Success
> perror: Illegal seek
> 
> 
> 
> Obru6tenieto kum perror() predizwikwa gre6ka ?!
> Kak da go oprawq?

Ot man perror:
Note that  errno  is undefined after a successful library call:
   this call may well change this variable,  even  though  it
   succeeds,  for  example  because  it  internally used some
   other library function that failed.

TR: Sled uspesheno izvikvane na funkcia ot lib errno e v nevalidno
systoianie ...
Ot koeto sledva che vtoroto perror moje da vadi kakvoto si iska.
ako ti triabva da go zapazish moje da probvash slednoto:
int main()
{
int errno_save;
errno_save = errno;
perror("nothing");
errno = errno_save;
perror("perror");
}

Tova ne sym siguren dali raboti ako e v thread.

-- 
have fun,
alex


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