[Mailman-Users] Re: [ext] List_Members from Command Line Permission
On 6/28/2024 12:06 PM, Ralf Hildebrandt via Mailman-Users wrote: * Dennis Putnam: I am developing a script that gets a list of members from a mailing list (mailman 2.1.15). I'm using popen (in python 2.7.5) to issue the command. However, even though I am running it as admin for that list, I'm getting a permissions error. How/what do I need to set in order to run that command? def getUsers(): "This function returns a list of users from mailman" p=subprocess.Popen(["/usr/lib/mailman/bin/list_members","listname"],stdout=subprocess.PIPE) lines=p.stdout.readlines() p.wait return(lines) I guess the script must run as user "mailman" or "root" Which error messag exactly? Hi Talf, Thanks for the reply. Here is the python traceback.Traceback (most recent call last): File "/usr/lib/mailman/bin/list_members", line 286, in main() File "/usr/lib/mailman/bin/list_members", line 230, in main mlist = MailList.MailList(listname, lock=False) File "/usr/lib/mailman/Mailman/MailList.py", line 130, in __init__ self.Load() File "/usr/lib/mailman/Mailman/MailList.py", line 655, in Load dict, e = self.__load(file) File "/usr/lib/mailman/Mailman/MailList.py", line 620, in __load fp = open(dbfile) IOError: [Errno 13] Permission denied: '/var/lib/mailman/lists/cufsalumni/config.pck' I didn't think about running it as mailman (really dumb). Yes it works if run as mailman. Thanks again. OpenPGP_signature.asc Description: OpenPGP digital signature -- Mailman-Users mailing list -- mailman-users@python.org To unsubscribe send an email to mailman-users-le...@python.org https://mail.python.org/mailman3/lists/mailman-users.python.org/ Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: https://www.mail-archive.com/mailman-users@python.org/ https://mail.python.org/archives/list/mailman-users@python.org/ Member address: arch...@jab.org
[Mailman-Users] Re: List_Members from Command Line Permission
On 6/28/24 9:02 AM, Dennis Putnam wrote: My apologies if this is a duplicate but since I have received nothing back I am assuming this did not get through the first time. I am guessing I need to somehow provide a password but the list_members command does not seem to have that as an option. There are many reasons why you might not receive a response to a post within 2 days. If you are really concerned that your post didn't reach the list, you can always check the archives where you would find it at https://mail.python.org/archives/list/mailman-users@python.org/message/46IJ7BKJSP2FNDCWV4O2XIERPHP256LK/ I am developing a script that gets a list of members from a mailing list (mailman 2.1.15). I'm using popen (in python 2.7.5) to issue the command. However, even though I am running it as admin for that list, I'm getting a permissions error. How/what do I need to set in order to run that command? def getUsers(): "This function returns a list of users from mailman" p=subprocess.Popen(["/usr/lib/mailman/bin/list_members","listname"],stdout=subprocess.PIPE) lines=p.stdout.readlines() p.wait The above should be `p.wait()`, not `p.wait` and should precede the `lines=p.stdout.readlines()` statement. return(lines) For the permissions issue, you need to run this as the Mailman user or possibly the web server user, i.e. a user that has permission to read the list's config.pck. -- Mark Sapiro The highway is for gamblers, San Francisco Bay Area, Californiabetter use your sense - B. Dylan -- Mailman-Users mailing list -- mailman-users@python.org To unsubscribe send an email to mailman-users-le...@python.org https://mail.python.org/mailman3/lists/mailman-users.python.org/ Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: https://www.mail-archive.com/mailman-users@python.org/ https://mail.python.org/archives/list/mailman-users@python.org/ Member address: arch...@mail-archive.com
[Mailman-Users] Re: [ext] List_Members from Command Line Permission
* Dennis Putnam : > I am developing a script that gets a list of members from a mailing list > (mailman 2.1.15). I'm using popen (in python 2.7.5) to issue the command. > However, even though I am running it as admin for that list, I'm getting a > permissions error. How/what do I need to set in order to run that command? > > def getUsers(): > "This function returns a list of users from mailman" > p=subprocess.Popen(["/usr/lib/mailman/bin/list_members","listname"],stdout=subprocess.PIPE) > lines=p.stdout.readlines() > p.wait > return(lines) I guess the script must run as user "mailman" or "root" Which error messag exactly? -- Ralf Hildebrandt Charité - Universitätsmedizin Berlin Geschäftsbereich IT | Abteilung Netz | Netzwerk-Administration Invalidenstraße 120/121 | D-10115 Berlin Tel. +49 30 450 570 155 ralf.hildebra...@charite.de https://www.charite.de signature.asc Description: PGP signature -- Mailman-Users mailing list -- mailman-users@python.org To unsubscribe send an email to mailman-users-le...@python.org https://mail.python.org/mailman3/lists/mailman-users.python.org/ Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: https://www.mail-archive.com/mailman-users@python.org/ https://mail.python.org/archives/list/mailman-users@python.org/ Member address: arch...@jab.org
[Mailman-Users] List_Members from Command Line Permission
My apologies if this is a duplicate but since I have received nothing back I am assuming this did not get through the first time. I am guessing I need to somehow provide a password but the list_members command does not seem to have that as an option. I am developing a script that gets a list of members from a mailing list (mailman 2.1.15). I'm using popen (in python 2.7.5) to issue the command. However, even though I am running it as admin for that list, I'm getting a permissions error. How/what do I need to set in order to run that command? def getUsers(): "This function returns a list of users from mailman" p=subprocess.Popen(["/usr/lib/mailman/bin/list_members","listname"],stdout=subprocess.PIPE) lines=p.stdout.readlines() p.wait return(lines) OpenPGP_signature.asc Description: OpenPGP digital signature -- Mailman-Users mailing list -- mailman-users@python.org To unsubscribe send an email to mailman-users-le...@python.org https://mail.python.org/mailman3/lists/mailman-users.python.org/ Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: https://www.mail-archive.com/mailman-users@python.org/ https://mail.python.org/archives/list/mailman-users@python.org/ Member address: arch...@jab.org
