[Mailman-Users] Re: Question on outputting all lists and list owners and a process for batch disabling of lists without an owner
>> ...which I found googling ‘how to disable a mailman 2 list’ because I’d like >> to know how, too, since we do occasionally have need to do this.) > The method in that thread is simply moving the lists/ aside. That > is one way to disable a list, but there are others depending on what you > actually want. ... To disable a list: chmod 000 $PATH/lists/ And to re-enable it: chmod 2775 $PATH/lists/ -- Mailman-Users mailing list -- mailman-users@python.org To unsubscribe send an email to mailman-users-le...@python.org https://mail.python.org/mailman3/lists/mailman-users.python.org/ Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: https://www.mail-archive.com/mailman-users@python.org/ https://mail.python.org/archives/list/mailman-users@python.org/
[Mailman-Users] Re: Question on outputting all lists and list owners and a process for batch disabling of lists without an owner
Thanks very much Bruce and Mark!
Much appreciated,
John
On 5/27/22, 1:53 PM, "Mark Sapiro" wrote:
On 5/27/22 12:47, Bruce Johnson via Mailman-Users wrote:
> Well some guy named Mark supported one method in the past 8-) (which I
found googling ‘how to disable a mailman 2 list’ because I’d like to know how,
too, since we do occasionally have need to do this.)
>
>
https://urldefense.com/v3/__https://mail.python.org/pipermail/mailman-users/2010-September/070283.html__;!!C5qS4YX3!AJcsaCQavpDgwaaIVqilPzNAu0rJ_NfoDw_GIKESav0V0oT2bK06YElcB7px4bxmW9JrUvOMkdrHNRxH$
The method in that thread is simply moving the lists/ aside.
That is one way to disable a list, but there are others depending on
what you actually want. For that, this withlist script will do it.
```
import os
from Mailman import Site
BACKUP_DIR = 'path to a mailman writable directory'
def no_owner(mlist)
if len mlist.owner == 0:
print('List %s has no owners, disabling.' % mlist.real_name)
src = Site.get_listpath(mlist.internal_name())
dst = os.path.join(BACKUP_DIR, mlist.internal_name())
os.rename(src, dst)
```
BACKUP_DIR is set to the full path of the directory in which to save the
list configurations. To avoid potential issues with os.rename,
BACKUP_DIR should be on the same file system as Mailman's lists/ directory.
--
Mark Sapiro The highway is for gamblers,
San Francisco Bay Area, Californiabetter use your sense - B. Dylan
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[Mailman-Users] Re: Question on outputting all lists and list owners and a process for batch disabling of lists without an owner
On 5/27/22 12:47, Bruce Johnson via Mailman-Users wrote:
Well some guy named Mark supported one method in the past 8-) (which I found
googling ‘how to disable a mailman 2 list’ because I’d like to know how, too,
since we do occasionally have need to do this.)
https://mail.python.org/pipermail/mailman-users/2010-September/070283.html
The method in that thread is simply moving the lists/ aside.
That is one way to disable a list, but there are others depending on
what you actually want. For that, this withlist script will do it.
```
import os
from Mailman import Site
BACKUP_DIR = 'path to a mailman writable directory'
def no_owner(mlist)
if len mlist.owner == 0:
print('List %s has no owners, disabling.' % mlist.real_name)
src = Site.get_listpath(mlist.internal_name())
dst = os.path.join(BACKUP_DIR, mlist.internal_name())
os.rename(src, dst)
```
BACKUP_DIR is set to the full path of the directory in which to save the
list configurations. To avoid potential issues with os.rename,
BACKUP_DIR should be on the same file system as Mailman's lists/ directory.
--
Mark Sapiro The highway is for gamblers,
San Francisco Bay Area, Californiabetter use your sense - B. Dylan
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[Mailman-Users] Re: Question on outputting all lists and list owners and a process for batch disabling of lists without an owner
Well some guy named Mark supported one method in the past 8-) (which I found
googling ‘how to disable a mailman 2 list’ because I’d like to know how, too,
since we do occasionally have need to do this.)
https://mail.python.org/pipermail/mailman-users/2010-September/070283.html
Since he appears to have shell access using the script you gave would let him
move the list directory to someplace like /path/to/mailman/lists/[listname] to
/path/to/mailman/disabled lists/[listname]
That would let him re-enable the list without having to recreate everything.
On May 27, 2022, at 11:49 AM, Mark Sapiro
mailto:m...@msapiro.net>> wrote:
On 5/27/22 10:22, John Lake wrote:
Our security department has asked me to canvas all of our lists (4,237!)—and if
a list owner value is not defined they want me to disable the list.
1. Can I combine the list_lists and list_owners commands to output both
(hopefully linked) values as a .csv?
`list_owners -w` will list the owners by list name. If a list has no owners,
only the list name will be output for that list. You could then process that
file to identify the lists with no owners.
2. Is there a script that any of you have leveraged to batch disable lists
without a defined owner?
What do you mean by `disable`?
A withlist script like
```
def no_owner(mlist)
if len mlist.owner == 0:
if not mlist.Locked:
mlist.Lock
print('List %s has no owners, disabling.' % mlist.real_name)
mlist.Save()
mlist.Unlock()
```
saved as no_owner.py in Mailman's bin/ directory and run via
```
bin/withlist -a -r no_owner
```
You could omit the code
```
if not mlist.Locked:
mlist.Lock
mlist.Save()
mlist.Unlock()
```
I.e., just leave the print statement in the `if len mlist.owner == 0:` clause
to just print the names of lists with no owner.
--
Mark Sapiro mailto:m...@msapiro.net>>The highway is
for gamblers,
San Francisco Bay Area, Californiabetter use your sense - B. Dylan
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mailman-users@python.org
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mailman-users-le...@python.org
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--
Bruce Johnson
University of Arizona
College of Pharmacy
Information Technology Group
Institutions do not have opinions, merely customs
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[Mailman-Users] Re: Question on outputting all lists and list owners and a process for batch disabling of lists without an owner
On 5/27/22 10:22, John Lake wrote:
Our security department has asked me to canvas all of our lists (4,237!)—and if
a list owner value is not defined they want me to disable the list.
1. Can I combine the list_lists and list_owners commands to output both
(hopefully linked) values as a .csv?
`list_owners -w` will list the owners by list name. If a list has no
owners, only the list name will be output for that list. You could then
process that file to identify the lists with no owners.
2. Is there a script that any of you have leveraged to batch disable lists
without a defined owner?
What do you mean by `disable`?
A withlist script like
```
def no_owner(mlist)
if len mlist.owner == 0:
if not mlist.Locked:
mlist.Lock
print('List %s has no owners, disabling.' % mlist.real_name)
that meant>
mlist.Save()
mlist.Unlock()
```
saved as no_owner.py in Mailman's bin/ directory and run via
```
bin/withlist -a -r no_owner
```
You could omit the code
```
if not mlist.Locked:
mlist.Lock
that meant>
mlist.Save()
mlist.Unlock()
```
I.e., just leave the print statement in the `if len mlist.owner == 0:`
clause to just print the names of lists with no owner.
--
Mark Sapiro The highway is for gamblers,
San Francisco Bay Area, Californiabetter use your sense - B. Dylan
--
Mailman-Users mailing list -- mailman-users@python.org
To unsubscribe send an email to mailman-users-le...@python.org
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