[Matplotlib-users] Legend grows in wrong direction
Hi, I've tried placing a legend using the loc = (x,y) .. and the legend is moved where I want it. the problem is, when I add new lines to the plot.. the legend grows, but upwards.. so the lower left point of the legend box is constant.. but that's not the logical way for a legend box to grow.. shouldn't it grow downwards, just like when I use the standard loc = 1 (upper right position) . Is there a way to change this behaviour? -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] pylab_examples image_clip_path.py not working for pdf
See http://matplotlib.sourceforge.net/examples/pylab_examples/image_clip_path.html ... and click on pdf Any ideas? Haibao -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Keeping a zoomed view when adding to a plot
I have an app which adds data to a plot. Everything is working, but when I add data to a plot that was zoomed in, it switches the display to a zoomed out view. Here's a code snippet: class MyPlotFrame(Frame): def __init__(self): Frame.__init__(self,None,-1, 'My Super Frame',size=(550,350)) self.SetBackgroundColour(NamedColor(WHITE)) self.figure = Figure() self.axes = self.figure.add_subplot(111) t = arange(0.0,3.0,0.01) s = sin(2*pi*t) self.axes.plot(t,s) self.axes.grid() self.canvas = FigureCanvas(self, -1, self.figure) self.sizer = BoxSizer(VERTICAL) self.sizer.Add(self.canvas, 1, LEFT | TOP | GROW) self.SetSizer(self.sizer) self.Fit() self.add_toolbar() # comment this out for no toolbar def addData(self, xdata, ydata): # Need to save off current zoom level before adding new plot data # But don't know how self.axes.plot(xdata, ydata) # Restore view here, then redraw self.canvas.draw() def add_toolbar(self): self.toolbar = NavigationToolbar2Wx(self.canvas) self.toolbar.Realize() # Snipped some stuff for checking if on a Mac or Windows self.toolbar.update() def OnPaint(self, event): self.canvas.draw() I can't find any examples or docs on maintaining my zoom of the plot. In matlab, I know how to do this, but I'm not sure what to do here. Can someone please advise? Thanks, Aaron R -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Bug in Fill_Between?
Just a follow-up: I managed to interpolate this problem away... interpolated = [] iinds = [] for i in range(len(stockData.rinds)-1): interpolated.append(s[stockData.rinds[i]]) iinds.append(stockData.inds[i]) interpolated.append((s[stockData.rinds[i]]*3. + s[stockData.rinds[i]+1])/4) iinds.append(stockData.inds[i] + 0.25) interpolated.append((s[stockData.rinds[i]] + s[stockData.rinds[i]+1])/2) iinds.append(stockData.inds[i] + 0.5) interpolated.append((s[stockData.rinds[i]] + 3.* s[stockData.rinds[i]+1])/4) iinds.append(stockData.inds[i] + 0.75) interpolated.append(s[stockData.rinds[len(stockData.rinds)-1]]) iinds.append(stockData.inds[len(stockData.inds)-1]) interpolated = array(interpolated) ax.fill_between(iinds, interpolated, 50-thresh, where=interpolated50-thresh, color=color, alpha=0.3 ) It would be nice to see this taken care of intelligently inside the fill_between routine, but I wouldn't know how to do it for the general case. Maybe this post will allow future users with a similar problem to find their answer. -Ryan From: Ryan Wagner Sent: Wednesday, February 25, 2009 5:06 PM To: 'matplotlib-users@lists.sourceforge.net' Subject: Bug in Fill_Between? Is this a bug in fill_between, or is there a known workaround? In the attached picture, I'm calling fill_between as follows, and I can't fill the entire area between the line (50+thresh) and the signal, s. I realize that the areas that aren't filled are boundary conditions, but there should be some sort of interpolation I can do to fix this I would think... ax.fill_between(stockData.inds, s[stockData.rinds], 50+thresh, where=s[stockData.rinds]50+thresh, color=color, alpha=0.3 ) So for example: stockData.inds = range(6), s[stockData.rinds] = [20,30,70,80,40,20] and thresh = 0. I need the areas filled with color where stockData.rinds is greater than 50. It does fully fill in the xrange(2,3), but the border conditions xrange(1,2) and xrange(3,4) are not fully filled under the line. I had the same problem with fill_over and was hoping it would be resolved with the move to fill_between. Any ideas? -Ryan -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Keeping a zoomed view when adding to a plot
Aaron R wrote: I have an app which adds data to a plot. Everything is working, but when I add data to a plot that was zoomed in, it switches the display to a zoomed out view. def addData(self, xdata, ydata): # Need to save off current zoom level before adding new plot data # But don't know how Try this: self.axes.set_autoscale_on(False) Eric self.axes.plot(xdata, ydata) # Restore view here, then redraw self.canvas.draw() -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] polar graph
Hi, i'm wondering if there is an easy way to fill the background in a polar graph with a specific color. If I were making a pie graph, it'd be something like: pie([70,20,10]), where the first 70% is green, the next 20, yellow, and the last 10, red. I've been experimenting with polar graphs using some random data and i've gotten close to what I want, but it'd be neat to have a color in the background. Here's what I have now. it's a polar scatter plot, much like what is found in the gallery, but with a few changes. from pylab import * import numpy as np snp=[] for i in range(0,65): snp.append(np.random.randint(35,122)) tempTuple=array(snp) r = tempTuple/10 theta = ((tempTuple*2.9508)*pi)/180 area = r**2*(tempTuple/5.4) colors = theta ax = subplot(111, polar=True) c = scatter(theta, r, c=colors, s=area) c.set_alpha(0.75) show() -- View this message in context: http://www.nabble.com/polar-graph-tp22230232p22230232.html Sent from the matplotlib - users mailing list archive at Nabble.com. -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Check if figure exists
Hi, If I have a figure: h = pp.figure(num=14) What is the best way to check to see if Figure 14 exists? I'm writing a function that adds plots to a figure window. I want the function to check if the figure exists, and if so, turn off autoscaling (using Eric's suggested axes.set_autoscale_on(False)) in case the user has zoomed. -- Christopher Brown, Ph.D. Department of Speech and Hearing Science Arizona State University -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Legend grows in wrong direction
On Thu, Feb 26, 2009 at 4:51 AM, Søren Nielsen soren.skou.niel...@gmail.com wrote: I've tried placing a legend using the loc = (x,y) .. and the legend is moved where I want it. the problem is, when I add new lines to the plot.. the legend grows, but upwards.. so the lower left point of the legend box is constant.. but that's not the logical way for a legend box to grow.. shouldn't it grow downwards, just like when I use the standard loc = 1 (upper right position) . Well, technically, legend never grows. Whenever you call legend(), a new legend instance is created and the old one is just destroyed. Anyhow, as far as I can tell, the (x,y) coordinates given to the *loc* parameter has been the coordinate of the lower left corner of the legend (but I don't think this is clearly specified in the documentation). Therefore, I don't think it is a good idea to make the legend grow(?) downward while you're supplying a fixed coordinate of the lower left corner. This is hardly possible and it seems to make little sense to me. Anyhow, I just submitted a patch to the svn that add an optional *bbox_to_anchor* argument for the legend class. This lets you specify the bbox that the legend will be anchored (the default is the bbox of the parent). For example, legend(loc=upper left, bbox_to_anchor=[0.0, 0.5]) will create an legend with its upper left corner at (0.0, 0.5), and it will grow downward. Note that when len(bbox_to_anchor)==2, a bbox with zero width and zero height is created. I hope this suits your need. -JJ -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] pylab_examples image_clip_path.py not working for pdf
Haibao Tang tanghai...@gmail.com writes: Any ideas? Yes, image clipping was unimplemented in the pdf backend. I added an implementation (both on the trunk and on the 0.98.5 branch) that at least gets this example and the dolphin right - please test it if you have some other use case. -- Jouni K. Seppänen http://www.iki.fi/jks -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] polar graph
I made a little more progress, but i'm not sure i'm doing this the right way.
Suggestions?
from pylab import *
import numpy as np
#generate random temperature data
snp=[]
for i in range(0,65):
snp.append(np.random.randint(35,122))
#hide the labels. I don't want them.
rc('xtick', labelsize=0)
rc('ytick', labelsize=0)
fig=figure(figsize=(8,8),facecolor='0.0')
ax = fig.add_subplot(111,polar=True,frameon=False)
tempTuple=array(snp)
r = tempTuple/10
theta = ((tempTuple*2.9508)*pi)/180
area = r**2*(tempTuple/5.4)
colors = theta
#this is the fancy green,yellow,red background
#it's actually a scatter plot that sits behind (zorder)
#of the rest of the scatter plots.
#radius
r1 = 0.7 # 20%
r2 = r1 + 0.2 # 40%
# define some sizes of the scatter marker
sizes = [55000]
x = [0] + np.cos(np.linspace(0, 2*math.pi*r1, 100)).tolist()
y = [0] + np.sin(np.linspace(0, 2*math.pi*r1, 100)).tolist()
xy1 = zip(x,y)
x = [0] + np.cos(np.linspace(2*math.pi*r1, 2*math.pi*r2, 100)).tolist()
y = [0] + np.sin(np.linspace(2*math.pi*r1, 2*math.pi*r2, 100)).tolist()
xy2 = zip(x,y)
x = [0] + np.cos(np.linspace(2*math.pi*r2, 2*math.pi, 100)).tolist()
y = [0] + np.sin(np.linspace(2*math.pi*r2, 2*math.pi, 100)).tolist()
xy3 = zip(x,y)
ax.scatter([0,0,0], [0,0,0], marker=(xy1,0), s=sizes,
facecolor='green',alpha=.25,zorder=1)
ax.scatter([0,0,0], [0,0,0], marker=(xy2,0), s=sizes, facecolor='yellow'
,alpha=.25,zorder=1)
ax.scatter([0,0,0], [0,0,0], marker=(xy3,0), s=sizes,
facecolor='red',alpha=.25,zorder=1)
ax.scatter(theta, r, c=colors, s=area,zorder=2)
ax.grid(False)
show()
--
View this message in context:
http://www.nabble.com/polar-graph-tp22230232p22234721.html
Sent from the matplotlib - users mailing list archive at Nabble.com.
--
Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA
-OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise
-Strategies to boost innovation and cut costs with open source participation
-Receive a $600 discount off the registration fee with the source code: SFAD
http://p.sf.net/sfu/XcvMzF8H
___
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Re: [Matplotlib-users] Legend grows in wrong direction
Thanks JJ! It does, and you are exactly right, letting the legend grow downward while holding the value of the lower left corner doesn't make sense.. I tried calculating an offset, but the patch is a much nicer fix! Soren On Thu, Feb 26, 2009 at 9:27 PM, Jae-Joon Lee lee.j.j...@gmail.com wrote: On Thu, Feb 26, 2009 at 4:51 AM, Søren Nielsen soren.skou.niel...@gmail.com wrote: I've tried placing a legend using the loc = (x,y) .. and the legend is moved where I want it. the problem is, when I add new lines to the plot.. the legend grows, but upwards.. so the lower left point of the legend box is constant.. but that's not the logical way for a legend box to grow.. shouldn't it grow downwards, just like when I use the standard loc = 1 (upper right position) . Well, technically, legend never grows. Whenever you call legend(), a new legend instance is created and the old one is just destroyed. Anyhow, as far as I can tell, the (x,y) coordinates given to the *loc* parameter has been the coordinate of the lower left corner of the legend (but I don't think this is clearly specified in the documentation). Therefore, I don't think it is a good idea to make the legend grow(?) downward while you're supplying a fixed coordinate of the lower left corner. This is hardly possible and it seems to make little sense to me. Anyhow, I just submitted a patch to the svn that add an optional *bbox_to_anchor* argument for the legend class. This lets you specify the bbox that the legend will be anchored (the default is the bbox of the parent). For example, legend(loc=upper left, bbox_to_anchor=[0.0, 0.5]) will create an legend with its upper left corner at (0.0, 0.5), and it will grow downward. Note that when len(bbox_to_anchor)==2, a bbox with zero width and zero height is created. I hope this suits your need. -JJ -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
