Re: [Matplotlib-users] contourf() for proper plotting purpose
You can use the 'origin' keyword: pl.controuf(Matrix, origin='lower') or pl.controuf(Matrix, origin='upper') Nicolas On May 23, 2013, at 7:27 AM, Bakhtiyor Zokhidov bakhtiyor_zokhi...@mail.ru wrote: Hi, I have following code: import numpy as np import pylab as pl Matrix(10,10) = np.array([[ 4.5, 4.5, 4.5, 3.4, 2.5, 3.9, 3.4, 3.4, 2.2, 3.9], [ 3.9, 4.5, 5.2, 4.5, 3.4, 3.4, 2.2, 2.9, 3.4, 3.4], [ 3.9, 3.9, 2.5, 2.2, 1.9, 1.2, 1.2, 1.4, 2.5, 2.9], [ 3.4, 3.9, 2.9, 2.2, 1.2, 1.4, 1.7, 1.4, 1.9, 2.2], [ 2.5, 3.4, 2.2, 1.4, 1.2, 1.2, 1.7, 0.8, 1.9, 1.7], [ 2.5, 2.2, 2.5, 1.2, 1.2, 0.9, 1.7, 1.7, 1.4, 1.9], [ 2.2, 2.2, 3.4, 1.7, 0.9, 0.9, 0.9, 1.2, 1.7, 1.9], [ 2.9, 1.9, 1.9, 1.4, 1.1, 0.9, 1.2, 1.1, 1.7, 1.9], [ 2.9, 1.7, 2.2, 1.4, 1.1, 0.9, 1.1, 0.8, 1.1, 1.9], [ 2.5, 1.9, 1.7, 1.2, 1.4, 0.8, 1.1, 0.8, 1.4, 1.7]]) pl.contourf(Matrix) pl.show() The problem is that that plots reversely, in other words top values are below, bottom values are top!! How can I plot it properly? -- Bakhtiyor Zokhidov -- Try New Relic Now We'll Send You this Cool Shirt New Relic is the only SaaS-based application performance monitoring service that delivers powerful full stack analytics. Optimize and monitor your browser, app, servers with just a few lines of code. Try New Relic and get this awesome Nerd Life shirt! http://p.sf.net/sfu/newrelic_d2d_may___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Try New Relic Now We'll Send You this Cool Shirt New Relic is the only SaaS-based application performance monitoring service that delivers powerful full stack analytics. Optimize and monitor your browser, app, servers with just a few lines of code. Try New Relic and get this awesome Nerd Life shirt! http://p.sf.net/sfu/newrelic_d2d_may ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] scatter_hist.py: broken Example on MPL website
Hi, I just hit a broken example at http://matplotlib.org/examples/pylab_examples/scatter_hist.html?highlight=scatter $ python scatter_hist.py Traceback (most recent call last): File scatter_hist.py, line 44, in module axHisty.hist(y, bins=bins, orientation='horizontal') File /usr/lib64/python2.7/site-packages/matplotlib/axes.py, line 8180, in hist color=c, bottom=bottom) TypeError: barh() got multiple values for keyword argument 'bottom' $ I have mpl-1.2.1. Hope this helps. Martin -- Try New Relic Now We'll Send You this Cool Shirt New Relic is the only SaaS-based application performance monitoring service that delivers powerful full stack analytics. Optimize and monitor your browser, app, servers with just a few lines of code. Try New Relic and get this awesome Nerd Life shirt! http://p.sf.net/sfu/newrelic_d2d_may ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Making space for a long legend outside of a barchart
Hi Chao,
I spent some time to figure out why I cannot replace ax1.hist() with
ax1.scatter().
It seems hist() returns list of 'Rectangle' (sadly if there is just one, it
does return
just the 'Rectangle' (not wrapped in a list) ... somewhere a trick
a = [a, ]
is likely needed.
Anyway, my problem is that scatter() returns 'PathCollection' object, whatever
that is.
How can I grab handles to individual legend items to move them under ax2 like
in your
hist-plot example?
Thank you for your help,
Martin
ChaoYue wrote:
Dear Martin,
I worked out a similar example for your reference as I don't catch your
example very well.
fig = plt.figure()
ax1 = fig.add_subplot(211)
ax2 = fig.add_subplot(212)
arrlist = [np.random.normal(size=100) for i in range(50)]
ret = ax1.hist(arrlist,histtype='barstacked')
reclist = [patchlist[0] for patchlist in ret[2]]
labellist = ['data'+str(i) for i in range(50)]
ax2.legend(reclist,labellist,loc='upper
left',bbox_to_anchor=(0,0,1,1),borderaxespad=0.,ncol=5,mode='expand')
ax2.set_frame_on(False)
ax2.tick_params(bottom='off',left='off',right='off',top='off')
plt.setp(ax2.get_yticklabels(),visible=False)
plt.setp(ax2.get_xticklabels(),visible=False)
you're asking some object-oriented way, I personally don't think using pylab
and set_tight_layout are the good way
to be object-oriented as pylab is only a bounding wrapper by my
understanding (maybe I am wrong!). legend and
hist are all matplotlib.axes.Axes method.
Also, I think it's unrealistic to ask the figure do a nice job for you if
there are 50 legned handlers and you want to show
them in 2 columns with a very high width/height ratio of the figure
hope it could be of a bit help,
cheers,
Chao
On Mon, May 20, 2013 at 6:43 PM, Martin Mokrejs [via matplotlib] [hidden
email] /user/SendEmail.jtp?type=nodenode=41102i=0 wrote:
Hi Ben,
Benjamin Root wrote:
On Mon, May 20, 2013 at 12:02 PM, Martin Mokrejs [hidden email]
http://user/SendEmail.jtp?type=nodenode=41090i=0 mailto:[hidden email]
http://user/SendEmail.jtp?type=nodenode=41090i=1 wrote:
Hi,
I am having trouble to get space allocated for a long legend text,
lets say spanning 2/3 - 3/4 of the whole output. I would like to
have
stacked barchart as 1st subplot and the place of remaining 3
subplots
to be actually allocated by the legend. Alternatively, could I get
the
legend saved into a separate figure?
Or could the space for legend text be allocated automatically
minimizing
output figure size? For example, the width would be 1120px while
height
be multiples of 840px (840 for each subplot)?
Attached is a quick example. It shows also that I tried
tight_layout()
but wasn't successful with this either. I would be glad for some
help,
ideally converting the whole thing into an object-oriented approach.
I am generating several figures in a row and would like to
clear()/del()
any previously used data ASAP.
Thank you,
Martin
Am using mpl-1.2.2
Try fig.savefig('foobar.png', bbox_inches='tight') when saving the
image. It will make the figure size such that all the visible
elements of the figure will fit into the saved output. tight_layout()
is meant to make sure the elements don't overlap each other, but does
nothing about making sure nothing gets clipped.
Ah, would be nice to make this clear in the docs. So far was doing
import pylab
F = pylab.gcf()
F.set_tight_layout(True)
which as you say does not help the way I thought.
Unfortunately, while
fig.savefig('foobar.png', bbox_inches='tight')
helped to get everything into the .png file (attached), the barchart
itself
should span according to the code I posted just 1/2 of the figure. But
somehow
it is enlarged and rescaled so that it occupies *more than* 1/2 of the
figure.
What in pylab is resizing my image? Note: the final image is 625x1075.
Martin
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Re: [Matplotlib-users] Making space for a long legend outside of a barchart
Hi Martin,
I am not sure that I understand your question very well.
For a single scatter() plot, I guess I agree with you, you need to put it
in [] because
legend() function must receive iterable as far as I understand.
I don't think scatter() allows you to pass a series of group of (x,y) data
as plot().
So probably if you want to scatter more than one groups of data, you need
to:
handle_list = []
label_list = []
for (x,y) in zip(xdata_list, ydata_list):
d = ax1.scatter(x,y)
handle_list.append(x)
label_list.append()
ax2.legend(handle_list,label_list,...)
This is what I could think of, perhaps others have better ways.
cheers,
Chao
On Thu, May 23, 2013 at 4:57 PM, Martin Mokrejs [via matplotlib]
ml-node+s1069221n41114...@n5.nabble.com wrote:
Hi Chao,
I spent some time to figure out why I cannot replace ax1.hist() with
ax1.scatter().
It seems hist() returns list of 'Rectangle' (sadly if there is just one,
it does return
just the 'Rectangle' (not wrapped in a list) ... somewhere a trick
a = [a, ]
is likely needed.
Anyway, my problem is that scatter() returns 'PathCollection' object,
whatever that is.
How can I grab handles to individual legend items to move them under ax2
like in your
hist-plot example?
Thank you for your help,
Martin
ChaoYue wrote:
Dear Martin,
I worked out a similar example for your reference as I don't catch your
example very well.
fig = plt.figure()
ax1 = fig.add_subplot(211)
ax2 = fig.add_subplot(212)
arrlist = [np.random.normal(size=100) for i in range(50)]
ret = ax1.hist(arrlist,histtype='barstacked')
reclist = [patchlist[0] for patchlist in ret[2]]
labellist = ['data'+str(i) for i in range(50)]
ax2.legend(reclist,labellist,loc='upper
left',bbox_to_anchor=(0,0,1,1),borderaxespad=0.,ncol=5,mode='expand')
ax2.set_frame_on(False)
ax2.tick_params(bottom='off',left='off',right='off',top='off')
plt.setp(ax2.get_yticklabels(),visible=False)
plt.setp(ax2.get_xticklabels(),visible=False)
you're asking some object-oriented way, I personally don't think using
pylab and set_tight_layout are the good way
to be object-oriented as pylab is only a bounding wrapper by my
understanding (maybe I am wrong!). legend and
hist are all matplotlib.axes.Axes method.
Also, I think it's unrealistic to ask the figure do a nice job for you
if there are 50 legned handlers and you want to show
them in 2 columns with a very high width/height ratio of the figure
hope it could be of a bit help,
cheers,
Chao
On Mon, May 20, 2013 at 6:43 PM, Martin Mokrejs [via matplotlib]
[hidden email] /user/SendEmail.jtp?type=nodenode=41102i=0 wrote:
Hi Ben,
Benjamin Root wrote:
On Mon, May 20, 2013 at 12:02 PM, Martin Mokrejs [hidden email]
http://user/SendEmail.jtp?type=nodenode=41090i=0 mailto:[hidden
email] http://user/SendEmail.jtp?type=nodenode=41090i=1 wrote:
Hi,
I am having trouble to get space allocated for a long legend
text,
lets say spanning 2/3 - 3/4 of the whole output. I would like
to have
stacked barchart as 1st subplot and the place of remaining 3
subplots
to be actually allocated by the legend. Alternatively, could I
get the
legend saved into a separate figure?
Or could the space for legend text be allocated automatically
minimizing
output figure size? For example, the width would be 1120px
while height
be multiples of 840px (840 for each subplot)?
Attached is a quick example. It shows also that I tried
tight_layout()
but wasn't successful with this either. I would be glad for
some help,
ideally converting the whole thing into an object-oriented
approach.
I am generating several figures in a row and would like to
clear()/del()
any previously used data ASAP.
Thank you,
Martin
Am using mpl-1.2.2
Try fig.savefig('foobar.png', bbox_inches='tight') when saving
the
image. It will make the figure size such that all the visible
elements of the figure will fit into the saved output.
tight_layout()
is meant to make sure the elements don't overlap each other, but
does
nothing about making sure nothing gets clipped.
Ah, would be nice to make this clear in the docs. So far was doing
import pylab
F = pylab.gcf()
F.set_tight_layout(True)
which as you say does not help the way I thought.
Unfortunately, while
fig.savefig('foobar.png', bbox_inches='tight')
helped to get everything into the .png file (attached), the barchart
itself
should span according to the code I posted just 1/2 of the figure.
But somehow
it is enlarged and rescaled so that it occupies *more than* 1/2 of
the figure.
Re: [Matplotlib-users] why legend does not show in matplotlib-1.2.1 py2.7
Sorry I have to be so brief, but just like the error says, you fed the
legend function the wedges returned by the pie command. But legend can't
handle wedges. As the proxy artist tutorial hints, you need to feed it
rectangles created manually (i.e., outside of any plotting commands).
Hope that gets you started,
-paul
On Wed, May 22, 2013 at 8:06 AM, oyster lepto.pyt...@gmail.com wrote:
the following code runs ok with py2.4 and matplotlib.0.98.3
however no legend appears with py2.7.3 and matplotlib-1.2.1/1.3. and I get
[quote]
e:\prg\py\python-2.7.3\lib\site-packages\_matplotlib\matplotlib\legend.py:629:
U
serWarning: Legend does not support [matplotlib.patches.Wedge object at
0x03842
0F0, matplotlib.patches.Wedge object at 0x03842530,
matplotlib.patches.Wedge
object at 0x03842930, matplotlib.patches.Wedge object at 0x03842D30,
matplo
tlib.patches.Wedge object at 0x038B0150]
Use proxy artist instead.
http://matplotlib.sourceforge.net/users/legend_guide.html#using-proxy-artist
(str(orig_handle),))
e:\prg\py\python-2.7.3\lib\site-packages\_matplotlib\matplotlib\legend.py:629:
U
serWarning: Legend does not support [matplotlib.text.Text object at
0x03842310
, matplotlib.text.Text object at 0x03842750, matplotlib.text.Text
object at 0
x03842B50, matplotlib.text.Text object at 0x03842F50,
matplotlib.text.Text o
bject at 0x038B0370]
Use proxy artist instead.
http://matplotlib.sourceforge.net/users/legend_guide.html#using-proxy-artist
(str(orig_handle),))
[/quote]
what's the matter? thanks
[code]
#coding=utf-8
from pylab import *
val2010 = [2, 10, 20, 15, 3]
figure()
pie2010=pie(val2010, labels=[u'%i persons' % i for i in val2010])
plt.legend( (pie2010), [u'60', u'60~70', u'70~80', u'80~90',
u'90~100'], loc = 'best', bbox_to_anchor = (0.90, 0.75) )
axis('equal')
show()
[/code]
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Re: [Matplotlib-users] why legend does not show in matplotlib-1.2.1 py2.7
I do not have any access to mpl 0.98 so I cannot tell for sure. My guess is
that you have been using a feature that has not been intended, that has
fixed at some point. The first argument to legend should be a list of
artists. And pie2010 is a tuple of a list of patches and a list of texts,
i.e., they are not compatible with the current implementation of legend.
Maybe the below is what you wanted?
plt.legend( (pie2010[0]), ...)
Regards,
-JJ
On Fri, May 24, 2013 at 6:19 AM, Paul Hobson pmhob...@gmail.com wrote:
Sorry I have to be so brief, but just like the error says, you fed the
legend function the wedges returned by the pie command. But legend can't
handle wedges. As the proxy artist tutorial hints, you need to feed it
rectangles created manually (i.e., outside of any plotting commands).
Hope that gets you started,
-paul
On Wed, May 22, 2013 at 8:06 AM, oyster lepto.pyt...@gmail.com wrote:
the following code runs ok with py2.4 and matplotlib.0.98.3
however no legend appears with py2.7.3 and matplotlib-1.2.1/1.3. and I get
[quote]
e:\prg\py\python-2.7.3\lib\site-packages\_matplotlib\matplotlib\legend.py:629:
U
serWarning: Legend does not support [matplotlib.patches.Wedge object at
0x03842
0F0, matplotlib.patches.Wedge object at 0x03842530,
matplotlib.patches.Wedge
object at 0x03842930, matplotlib.patches.Wedge object at 0x03842D30,
matplo
tlib.patches.Wedge object at 0x038B0150]
Use proxy artist instead.
http://matplotlib.sourceforge.net/users/legend_guide.html#using-proxy-artist
(str(orig_handle),))
e:\prg\py\python-2.7.3\lib\site-packages\_matplotlib\matplotlib\legend.py:629:
U
serWarning: Legend does not support [matplotlib.text.Text object at
0x03842310
, matplotlib.text.Text object at 0x03842750, matplotlib.text.Text
object at 0
x03842B50, matplotlib.text.Text object at 0x03842F50,
matplotlib.text.Text o
bject at 0x038B0370]
Use proxy artist instead.
http://matplotlib.sourceforge.net/users/legend_guide.html#using-proxy-artist
(str(orig_handle),))
[/quote]
what's the matter? thanks
[code]
#coding=utf-8
from pylab import *
val2010 = [2, 10, 20, 15, 3]
figure()
pie2010=pie(val2010, labels=[u'%i persons' % i for i in val2010])
plt.legend( (pie2010), [u'60', u'60~70', u'70~80', u'80~90',
u'90~100'], loc = 'best', bbox_to_anchor = (0.90, 0.75) )
axis('equal')
show()
[/code]
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