[Matplotlib-users] Sigmoid Curve Fitting
Hi, Does Matplotlib/Numpy/Scipy contain the ability to fit a sigmoid curve to a set of data points? Regards, Chris -- Start uncovering the many advantages of virtual appliances and start using them to simplify application deployment and accelerate your shift to cloud computing. http://p.sf.net/sfu/novell-sfdev2dev ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Sigmoid Curve Fitting
Thank you. I'll try investigating Scipy further. I've already tried applying some least-squares code for Numpy (http://pingswept.org/2009/01/24/least-squares-polynomial-fitting-in-python/) to my sigmoid data, but it only seems to fit parabolas. I had already encountered zunzun.com while Googling the problem. I'm not sure what to make of it, although it seems to be an online curve-fitting service. Unfortunately, my usage requires the ability to run the process locally. Regards, Chris On Mon, Sep 20, 2010 at 6:35 PM, Gökhan Sever gokhanse...@gmail.com wrote: On Mon, Sep 20, 2010 at 3:36 PM, Chris Spencer chriss...@gmail.com wrote: Hi, Does Matplotlib/Numpy/Scipy contain the ability to fit a sigmoid curve to a set of data points? You could also experiment at zunzun.com. Choose 2D sigmoidal from the 2D function scroll list. -- Gökhan -- Start uncovering the many advantages of virtual appliances and start using them to simplify application deployment and accelerate your shift to cloud computing. http://p.sf.net/sfu/novell-sfdev2dev ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Setting Relative Heights For Figure Rows
I wanted to display my figure legend below my figure in the second row, so I used subplot(211) to create two rows. However, this creates two rows of equal height, so my graph is crammed into half the figure height in the first row, while my tiny legend barely fills up any of the second row. How do you specify relative heights of each row? For example, I'd like to specify the first row takes 80% of the figure height, while the second takes 20%. I've searched the docs, but I can't find anything. Is this possible? Regards, Chris -- This SF.Net email is sponsored by the Verizon Developer Community Take advantage of Verizon's best-in-class app development support A streamlined, 14 day to market process makes app distribution fast and easy Join now and get one step closer to millions of Verizon customers http://p.sf.net/sfu/verizon-dev2dev ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Stopping Legend From Overlapping the Graph
Awesome, thanks. That works perfectly. Chris On Sun, Jun 28, 2009 at 12:16 AM, Jae-Joon Leelee.j.j...@gmail.com wrote: sorry. As guillaume has mentioned, you need to install mpl from svn. Here is some workaround you can try. I guess it would work with 0.98.5.3. Basically, you create a separate axes for a legend. ax1 = axes([0.1, 0.2,0.8, 0.7]) p1, = ax1.plot([1,2,3]) p2, = ax1.plot([3,2,1]) ax2 = axes([0.1, 0.1, 0.8, 0.01], frameon=False) ax2.xaxis.set_visible(False) ax2.yaxis.set_visible(False) l = ax2.legend([p1, p2], [Legend1, Legend2], mode=expand, ncol=2, borderaxespad=0.) -JJ On Sat, Jun 27, 2009 at 6:00 PM, Chris Spencerchriss...@gmail.com wrote: Thanks. Is that some sort of blending edge feature? I just installed 0.98.5.3, but the sample code gives me the error: TypeError: __init__() got an unexpected keyword argument 'bbox_to_anchor' On Thu, Jun 25, 2009 at 10:20 PM, Jae-Joon Leelee.j.j...@gmail.com wrote: The linked page below shows how you put the legend above the graph. http://matplotlib.sourceforge.net/users/plotting/legend.html#legend-location You can put it below the axes by adjusting the bbox_to_anchor parameter. Try something like bbox_to_anchor=(0., -0.1, 1., -0.1), loc=1 Make sure to adjust the suplot parameter (or axes location) to make enough room for the legend. -JJ On Thu, Jun 25, 2009 at 9:22 PM, Chris Spencerchriss...@gmail.com wrote: How do you show the legend below the graph, so it doesn't overlap at all with the graph? The docs for the legend() loc parameter only seem to specify where *on* the graph you want it to show, which is driving me nuts because even using best, it usually hides some of my data. I want to see *all* of my graph, as well as the legend. Is there any way to do this with pylab? Any help is appreciated. Chris -- ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Stopping Legend From Overlapping the Graph
Thanks. Is that some sort of blending edge feature? I just installed 0.98.5.3, but the sample code gives me the error: TypeError: __init__() got an unexpected keyword argument 'bbox_to_anchor' On Thu, Jun 25, 2009 at 10:20 PM, Jae-Joon Leelee.j.j...@gmail.com wrote: The linked page below shows how you put the legend above the graph. http://matplotlib.sourceforge.net/users/plotting/legend.html#legend-location You can put it below the axes by adjusting the bbox_to_anchor parameter. Try something like bbox_to_anchor=(0., -0.1, 1., -0.1), loc=1 Make sure to adjust the suplot parameter (or axes location) to make enough room for the legend. -JJ On Thu, Jun 25, 2009 at 9:22 PM, Chris Spencerchriss...@gmail.com wrote: How do you show the legend below the graph, so it doesn't overlap at all with the graph? The docs for the legend() loc parameter only seem to specify where *on* the graph you want it to show, which is driving me nuts because even using best, it usually hides some of my data. I want to see *all* of my graph, as well as the legend. Is there any way to do this with pylab? Any help is appreciated. Chris -- ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Stopping Legend From Overlapping the Graph
How do you show the legend below the graph, so it doesn't overlap at all with the graph? The docs for the legend() loc parameter only seem to specify where *on* the graph you want it to show, which is driving me nuts because even using best, it usually hides some of my data. I want to see *all* of my graph, as well as the legend. Is there any way to do this with pylab? Any help is appreciated. Chris -- ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Unable to Plot Date Axis Due To TypeError: a float is required
I'm getting a nonsensical error when attempting to make a simple plot with a date axis. Googling shows this similar errors, but none with a date axis. What could be causing this? import datetime from pylab import figure, show fig = figure() ax = fig.add_subplot(111) dates = [datetime.date(2008, 1, 30),datetime.date(2008, 1, 31)] values = [10.25, 10.0] ax.plot_date(dates, values)#, '-') Traceback (most recent call last): File stdin, line 1, in module File /usr/lib/python2.5/site-packages/matplotlib/axes.py, line 2585, in plot_date ret = self.plot(x, y, fmt, **kwargs) File /usr/lib/python2.5/site-packages/matplotlib/axes.py, line 2535, in plot for line in self._get_lines(*args, **kwargs): File /usr/lib/python2.5/site-packages/matplotlib/axes.py, line 428, in _grab_next_args for seg in self._plot_3_args(remaining, **kwargs): File /usr/lib/python2.5/site-packages/matplotlib/axes.py, line 404, in _plot_3_args func(x[:,j], y[:,j]) File /usr/lib/python2.5/site-packages/matplotlib/axes.py, line 385, in makeline axes=self.axes, File /usr/lib/python2.5/site-packages/matplotlib/lines.py, line 226, in __init__ self.set_data(xdata, ydata) File /usr/lib/python2.5/site-packages/matplotlib/lines.py, line 315, in set_data self.recache() File /usr/lib/python2.5/site-packages/matplotlib/lines.py, line 320, in recache x = ma.asarray(self.convert_xunits(self._xorig), Float) File /usr/lib/python2.5/site-packages/numpy/core/ma.py, line 2122, in asarray return array(data, dtype=dtype, copy=0) File /usr/lib/python2.5/site-packages/numpy/core/ma.py, line 573, in __init__ self._data = c.astype(tc) TypeError: a float is required - This SF.net email is sponsored by: Microsoft Defy all challenges. Microsoft(R) Visual Studio 2008. http://clk.atdmt.com/MRT/go/vse012070mrt/direct/01/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
