Re: [Matplotlib-users] contourf() for "proper plotting purpose"

2013-05-22 Thread Nicolas Rougier


You can use the 'origin' keyword:

pl.controuf(Matrix, origin='lower')
or
pl.controuf(Matrix, origin='upper')


Nicolas


On May 23, 2013, at 7:27 AM, Bakhtiyor Zokhidov  
wrote:

> Hi,
> 
> I have following code:
> 
> import numpy as np
> import pylab as pl
> 
> Matrix(10,10) = 
> np.array([[ 4.5, 4.5, 4.5, 3.4, 2.5, 3.9, 3.4, 3.4, 2.2, 3.9],
> [ 3.9, 4.5, 5.2, 4.5, 3.4, 3.4, 2.2, 2.9, 3.4, 3.4],
> [ 3.9, 3.9, 2.5, 2.2, 1.9, 1.2, 1.2, 1.4, 2.5, 2.9],
> [ 3.4, 3.9, 2.9, 2.2, 1.2, 1.4, 1.7, 1.4, 1.9, 2.2],
> [ 2.5, 3.4, 2.2, 1.4, 1.2, 1.2, 1.7, 0.8, 1.9, 1.7],
> [ 2.5, 2.2, 2.5, 1.2, 1.2, 0.9, 1.7, 1.7, 1.4, 1.9],
> [ 2.2, 2.2, 3.4, 1.7, 0.9, 0.9, 0.9, 1.2, 1.7, 1.9],
> [ 2.9, 1.9, 1.9, 1.4, 1.1, 0.9, 1.2, 1.1, 1.7, 1.9],
> [ 2.9, 1.7, 2.2, 1.4, 1.1, 0.9, 1.1, 0.8, 1.1, 1.9],
> [ 2.5, 1.9, 1.7, 1.2, 1.4, 0.8, 1.1, 0.8, 1.4, 1.7]])
> 
> pl.contourf(Matrix)
> pl.show()
> 
> The problem is that that plots reversely, in other words top values are 
> below, bottom values are top!!
> 
> How can I plot it properly?
> 
> 
> -- 
> Bakhtiyor Zokhidov
> --
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[Matplotlib-users] contourf() for "proper plotting purpose"

2013-05-22 Thread Bakhtiyor Zokhidov
 Hi,

I have following code:

import numpy as np
import pylab as pl

Matrix(10,10) = 
np.array([[ 4.5, 4.5, 4.5, 3.4, 2.5, 3.9, 3.4, 3.4, 2.2, 3.9],
[ 3.9, 4.5, 5.2, 4.5, 3.4, 3.4, 2.2, 2.9, 3.4, 3.4],
[ 3.9, 3.9, 2.5, 2.2, 1.9, 1.2, 1.2, 1.4, 2.5, 2.9],
[ 3.4, 3.9, 2.9, 2.2, 1.2, 1.4, 1.7, 1.4, 1.9, 2.2],
[ 2.5, 3.4, 2.2, 1.4, 1.2, 1.2, 1.7, 0.8, 1.9, 1.7],
[ 2.5, 2.2, 2.5, 1.2, 1.2, 0.9, 1.7, 1.7, 1.4, 1.9],
[ 2.2, 2.2, 3.4, 1.7, 0.9, 0.9, 0.9, 1.2, 1.7, 1.9],
[ 2.9, 1.9, 1.9, 1.4, 1.1, 0.9, 1.2, 1.1, 1.7, 1.9],
[ 2.9, 1.7, 2.2, 1.4, 1.1, 0.9, 1.1, 0.8, 1.1, 1.9],
[ 2.5, 1.9, 1.7, 1.2, 1.4, 0.8, 1.1, 0.8, 1.4, 1.7]]) pl.contourf(Matrix)
pl.show()

The problem is that that plots reversely, in other words top values are below, 
bottom values are top!!

How can I plot it properly?


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Bakhtiyor Zokhidov--
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