Re: [Matplotlib-users] nonlinear axes for imshow
Hi JJ, thanks a lot for your help. I think that http://matplotlib.sourceforge.net/examples/axes_grid/demo_curvelinear_grid.html has everything I need, I'll try it out. The coordinates given by the mouse are off, but that seems to be the case even for the far more elaborate "custom scale/projection" example ( examples/api/custom_scale_example.py ), and it's not that important. Thanks, cheers Thomas >It depends on how far you want to go. > >* Manually setting ticks is a easiest solution, I guess. > >* The next step would be to create your custom tick locator & formatter > >http://matplotlib.sourceforge.net/api/ticker_api.html > >While this is not that difficult, you will need to spend some time. > >* axes_grid toolkit has limited support for arbitrary coordinate system. > >http://matplotlib.sourceforge.net/examples/axes_grid/demo_curvelinear_grid.html > >* create your own projection. > >http://matplotlib.sourceforge.net/devel/add_new_projection.html > >Unless you're familiar with matplotlib and some of it internals, the >last two options is not recommended. >Regards, > >-JJ -- View this message in context: http://www.nabble.com/nonlinear-axes-for-imshow-tp25853828p25891899.html Sent from the matplotlib - users mailing list archive at Nabble.com. -- Come build with us! The BlackBerry(R) Developer Conference in SF, CA is the only developer event you need to attend this year. Jumpstart your developing skills, take BlackBerry mobile applications to market and stay ahead of the curve. Join us from November 9 - 12, 2009. Register now! http://p.sf.net/sfu/devconference ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] nonlinear axes for imshow
On Tue, Oct 13, 2009 at 2:48 AM, thkoe002 wrote: > > Hi Eric, > > thanks for the help, but this doesn't do what I want. > I don't want to change the image in any way, I just want the axes to have a > decreasing spacing. I made a small example with ms paint to clarify. > > http://www.nabble.com/file/p25867951/axes.png > > I could do this with ax.set_xticks() and ax.set_xticklabels(), but I was > wondering if there is a way that also changes the whole coordinate system > and not only the labeling. For example, the position of the mouse pointer > will not be shown anymore when I use custom ax.set_xticklabels(). > It depends on how far you want to go. * Manually setting ticks is a easiest solution, I guess. * The next step would be to create your custom tick locator & formatter http://matplotlib.sourceforge.net/api/ticker_api.html While this is not that difficult, you will need to spend some time. * axes_grid toolkit has limited support for arbitrary coordinate system. http://matplotlib.sourceforge.net/examples/axes_grid/demo_curvelinear_grid.html * create your own projection. http://matplotlib.sourceforge.net/devel/add_new_projection.html Unless you're familiar with matplotlib and some of it internals, the last two options is not recommended. Regards, -JJ > Cheers > > Thomas > > > > efiring wrote: >> >> thkoe002 wrote: >>> Hello, >>> >>> I have the following problem. I want the axes (only the y-axis, to be >>> exact) >>> of a imshow() graph to be nonlinear. By default, the axis goes linearily >>> from 0 to (number of pixels). With the [extent] keyword, I can change >>> that >>> to going linearly from (arbitrary start) to (arbitrary end). Now, I'd >>> like >>> the axis to be dependend on a (bijective) arbitrary function, for example >>> y=p^2 (when p is the pixel number and y the y-axis coordinate). >>> How can I achieve this? >>> Thanks a lot, cheers >>> >>> Thomas >> >> See >> http://matplotlib.sourceforge.net/examples/pylab_examples/image_nonuniform.html >> >> Eric >> >> -- >> Come build with us! The BlackBerry(R) Developer Conference in SF, CA >> is the only developer event you need to attend this year. Jumpstart your >> developing skills, take BlackBerry mobile applications to market and stay >> ahead of the curve. Join us from November 9 - 12, 2009. Register now! >> http://p.sf.net/sfu/devconference >> ___ >> Matplotlib-users mailing list >> Matplotlib-users@lists.sourceforge.net >> https://lists.sourceforge.net/lists/listinfo/matplotlib-users >> >> > > -- > View this message in context: > http://www.nabble.com/nonlinear-axes-for-imshow-tp25853828p25867951.html > Sent from the matplotlib - users mailing list archive at Nabble.com. > > > -- > Come build with us! The BlackBerry(R) Developer Conference in SF, CA > is the only developer event you need to attend this year. Jumpstart your > developing skills, take BlackBerry mobile applications to market and stay > ahead of the curve. Join us from November 9 - 12, 2009. Register now! > http://p.sf.net/sfu/devconference > ___ > Matplotlib-users mailing list > Matplotlib-users@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > -- Come build with us! The BlackBerry(R) Developer Conference in SF, CA is the only developer event you need to attend this year. Jumpstart your developing skills, take BlackBerry mobile applications to market and stay ahead of the curve. Join us from November 9 - 12, 2009. Register now! http://p.sf.net/sfu/devconference ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] nonlinear axes for imshow
Hi Eric, thanks for the help, but this doesn't do what I want. I don't want to change the image in any way, I just want the axes to have a decreasing spacing. I made a small example with ms paint to clarify. http://www.nabble.com/file/p25867951/axes.png I could do this with ax.set_xticks() and ax.set_xticklabels(), but I was wondering if there is a way that also changes the whole coordinate system and not only the labeling. For example, the position of the mouse pointer will not be shown anymore when I use custom ax.set_xticklabels(). Cheers Thomas efiring wrote: > > thkoe002 wrote: >> Hello, >> >> I have the following problem. I want the axes (only the y-axis, to be >> exact) >> of a imshow() graph to be nonlinear. By default, the axis goes linearily >> from 0 to (number of pixels). With the [extent] keyword, I can change >> that >> to going linearly from (arbitrary start) to (arbitrary end). Now, I'd >> like >> the axis to be dependend on a (bijective) arbitrary function, for example >> y=p^2 (when p is the pixel number and y the y-axis coordinate). >> How can I achieve this? >> Thanks a lot, cheers >> >> Thomas > > See > http://matplotlib.sourceforge.net/examples/pylab_examples/image_nonuniform.html > > Eric > > -- > Come build with us! The BlackBerry(R) Developer Conference in SF, CA > is the only developer event you need to attend this year. Jumpstart your > developing skills, take BlackBerry mobile applications to market and stay > ahead of the curve. Join us from November 9 - 12, 2009. Register now! > http://p.sf.net/sfu/devconference > ___ > Matplotlib-users mailing list > Matplotlib-users@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > > -- View this message in context: http://www.nabble.com/nonlinear-axes-for-imshow-tp25853828p25867951.html Sent from the matplotlib - users mailing list archive at Nabble.com. -- Come build with us! The BlackBerry(R) Developer Conference in SF, CA is the only developer event you need to attend this year. Jumpstart your developing skills, take BlackBerry mobile applications to market and stay ahead of the curve. Join us from November 9 - 12, 2009. Register now! http://p.sf.net/sfu/devconference ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] nonlinear axes for imshow
thkoe002 wrote: > Hello, > > I have the following problem. I want the axes (only the y-axis, to be exact) > of a imshow() graph to be nonlinear. By default, the axis goes linearily > from 0 to (number of pixels). With the [extent] keyword, I can change that > to going linearly from (arbitrary start) to (arbitrary end). Now, I'd like > the axis to be dependend on a (bijective) arbitrary function, for example > y=p^2 (when p is the pixel number and y the y-axis coordinate). > How can I achieve this? > Thanks a lot, cheers > > Thomas See http://matplotlib.sourceforge.net/examples/pylab_examples/image_nonuniform.html Eric -- Come build with us! The BlackBerry(R) Developer Conference in SF, CA is the only developer event you need to attend this year. Jumpstart your developing skills, take BlackBerry mobile applications to market and stay ahead of the curve. Join us from November 9 - 12, 2009. Register now! http://p.sf.net/sfu/devconference ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] nonlinear axes for imshow
Hello, I have the following problem. I want the axes (only the y-axis, to be exact) of a imshow() graph to be nonlinear. By default, the axis goes linearily from 0 to (number of pixels). With the [extent] keyword, I can change that to going linearly from (arbitrary start) to (arbitrary end). Now, I'd like the axis to be dependend on a (bijective) arbitrary function, for example y=p^2 (when p is the pixel number and y the y-axis coordinate). How can I achieve this? Thanks a lot, cheers Thomas -- View this message in context: http://www.nabble.com/nonlinear-axes-for-imshow-tp25853828p25853828.html Sent from the matplotlib - users mailing list archive at Nabble.com. -- Come build with us! The BlackBerry(R) Developer Conference in SF, CA is the only developer event you need to attend this year. Jumpstart your developing skills, take BlackBerry mobile applications to market and stay ahead of the curve. Join us from November 9 - 12, 2009. Register now! http://p.sf.net/sfu/devconference ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
